1)Trong 1 c\u00e2u th\u01b0\u1eddng c\u00f3 3 \u0111\u00e1p \u00e1n g\u1ea7n gi\u1ed1ng nhau, 1 trong 3 ch\u1eafc ch\u1eafn l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang, c\u00f3 th\u1ec3 lo\u1ea1i ngay \u0111\u00e1p \u00e1n c\u00f2n l\u1ea1i.<\/strong><\/em>
\nV\u00ed d\u1ee5 : A. Chu k\u1ef3 4, nh\u00f3m IIA
\nB. Chu k\u1ef3 4, nh\u00f3m VIIIB
\nC. Chu k\u1ef3 3, nh\u00f3m VIB
\nD. Chu k\u1ef3 4, nh\u00f3m VIIIA<\/p>\n\u1ede \u0111\u00e2y th\u1ea5y ngay \u0111\u00e1p \u00e1n C kh\u00e1c h\u1eb3n v\u1edbi c\u00e1c \u0111\u00e1p \u00e1n c\u00f2n l\u1ea1i (c\u00f3 ch\u1eef Chu k\u1ef3 3), n\u00f3 s\u1ebd l\u00e0 \u0111\u00e1p \u00e1n sai.<\/p>\n
C\u01a1 s\u1edf: \u0111\u1ec3 th\u00ed sinh kh\u00f4ng th\u1ec3 ch\u1ecdn \u0111\u01b0\u1ee3c ngay 1 \u0111\u00e1p \u00e1n ch\u1ec9 v\u1edbi vi\u1ec7c t\u00ednh 1 d\u1eef ki\u1ec7n, xung quanh \u0111\u00e1p \u00e1n \u0111\u00fang s\u1ebd c\u00f3 1 v\u00e0i \u0111\u00e1p \u00e1n gi\u1ed1ng n\u00f3. V\u00e0 \u0111\u00e1p \u00e1n kh\u00f4ng \u0111\u01b0\u1ee3c “ng\u1ee5y trang” ch\u1eafc ch\u1eafn l\u00e0 \u0111\u00e1p \u00e1n sai.<\/p>\n
2) \u0110\u00e1p \u00e1n lo\u1ea1i \u0111\u01b0\u1ee3c l\u1eadp t\u1ee9c s\u1ebd th\u01b0\u1eddng c\u00f3 1 ph\u1ea7n \u0111\u00fang<\/strong><\/em>
\nV\u1eabn v\u1edbi v\u00ed d\u1ee5 tr\u00ean, \u0111\u00e1p \u00e1n C b\u1ecb lo\u1ea1i mang ph\u1ea7n sai l\u00e0 “chu k\u1ef3 3”, v\u1eady th\u00ec ph\u1ea7n “nh\u00f3m VIB” c\u1ee7a n\u00f3 s\u1ebd l\u00e0 ph\u1ea7n \u0111\u00fang. V\u00ec th\u1ebf c\u00f3 th\u1ec3 khoanh ngay \u0111\u00e1p \u00e1n B. v\u00ec n\u00f3 c\u00f3 ph\u1ea7n cu\u1ed1i kh\u00e1 gi\u1ed1ng, v\u1edbi ch\u1eef …B.
\n1 v\u00ed d\u1ee5 kh\u00e1c
\nA. 4,9 v\u00e0 glixerol
\nB. 4,9 v\u00e0 propan-1,3-\u0111iol
\nC. 9,8 v\u00e0 propan-1,2-\u0111iol
\nD. 4,9 v\u00e0 propan-1,2-\u0111iol<\/p>\nLo\u1ea1i ngay \u0111\u00e1p \u00e1n C v\u00ec c\u00f3 ph\u1ea7n “9,8” c\u00f3 v\u1ebb “khang kh\u00e1c”, \u0111i c\u00f9ng v\u1edbi n\u00f3 l\u00e0 propan-1,2-\u0111iol, v\u1eady d\u1eef ki\u1ec7n \u0111\u00fang l\u00e0 propan-1,2-\u0111iol
\nT\u1eeb \u0111\u00e2y suy ra D l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang<\/p>\n
3) D\u1eef ki\u1ec7n n\u00e0o xu\u1ea5t hi\u1ec7n nhi\u1ec1u l\u1ea7n trong c\u00e1c \u0111\u00e1p \u00e1n th\u00ec d\u1eef ki\u1ec7n \u0111\u00f3 l\u00e0 d\u1eef ki\u1ec7n \u0111\u00fang, \u0111\u00e2y l\u00e0 quy lu\u1eadt R\u1ea4T QUAN TR\u1eccNG, c\u00e1c b\u1ea1n ch\u00fa \u00fd…<\/strong><\/em>
\nV\u00ed d\u1ee5
\nA. Zn(NO3)2 v\u00e0 Fe(NO3)2
\nB. Zn(NO3)2 v\u00e0 AgNO3
\nC. Fe(NO3)2 v\u00e0 AgNO3
\nD. Fe(NO3)3 v\u00e0 Zn(NO3)2<\/p>\nD\u1ec5 th\u1ea5y Zn(NO3)2 xu\u1ea5t hi\u1ec7n 3 l\u1ea7n \u1edf c\u00e1c \u0111\u00e1p \u00e1n A, B v\u00e0 D, v\u1eady 1 trong 3 \u0111\u00e1p \u00e1n n\u00e0y l\u00e0 \u0111\u00fang.
\n\u00c1p d\u1ee5ng c\u00f9ng v\u1edbi b\u00ed k\u00edp s\u1ed1 2, \u0111\u00e1p \u00e1n C b\u1ecb lo\u1ea1i s\u1ebd c\u00f3 1 ph\u1ea7n \u0111\u00fang, v\u1eady ph\u1ea7n \u0111\u00fang \u0111\u00f3 c\u00f3 th\u1ec3 l\u00e0 Fe(NO3)2 ho\u1eb7c AgNO3. T\u1eeb \u0111\u00e2y suy ra \u0111\u00e1p \u00e1n A ho\u1eb7c B \u0111\u00fang (v\u00ec sao th\u00ec d\u1ec5 hi\u1ec3u r\u1ed3i \u0111\u00fang ko?)
\nC\u01a1 h\u1ed9i ch\u1ecdn l\u1ef1a l\u00fac n\u00e0y l\u00e0 50:50, nh\u01b0ng k sao, v\u1eabn t\u1ed1t h\u01a1n l\u00e0 1:3 \u0111\u1ea5y nh\u1ec9.<\/p>\n
V\u00ed d\u1ee5 kh\u00e1c:
\nA. Al, Fe, Cr
\nB. Mg, Zn, Cu
\nC. Ba, Ag, Au
\nD. Fe, Cu, Ag<\/p>\n
G\u1eb7p c\u00e2u n\u00e0y m\u00e0 kh\u00f4ng t\u00ednh \u0111\u01b0\u1ee3c th\u00ec \u0111\u1ebfm s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n c\u1ee7a c\u00e1c d\u1eef ki\u1ec7n ra nh\u00e9, \u1edf \u0111\u00e2y c\u00f3 th\u1ec3 th\u1ea5y: Al, Zn, Au, Ba, Al xu\u1ea5t hi\u1ec7n 1 l\u1ea7n trong 4 \u0111\u00e1p \u00e1n. Nh\u01b0ng Fe, Cu, Ag th\u00ec xu\u1ea5t hi\u1ec7n nh\u1eefng 2 l\u1ea7n.
\nV\u1eady \u0111\u00e1p \u00e1n D. Fe, Cu, Ag l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang.<\/p>\n
4) 2 \u0111\u00e1p \u00e1n n\u00e0o g\u1ea7n gi\u1ed1ng (na n\u00e1) nhau, 1 trong 2 th\u01b0\u1eddng \u0111\u00fang<\/strong><\/em><\/p>\nA. m = 2a – V\/22,4
\nB. m = 2a – V\/11,2
\nC. m = 2a – V\/5,6
\nD. m = 2a + V\/5,6<\/p>\n
C ho\u1eb7c D s\u1ebd l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang v\u00ec kh\u00e1 gi\u1ed1ng nhau
\nLo\u1ea1i D v\u00ec 3 \u0111\u00e1p \u00e1n c\u00f2n l\u1ea1i \u0111\u1ec1u xu\u1ea5t hi\u1ec7n d\u1ea5u + c\u00f2n 3 \u0111\u00e1p \u00e1n c\u00f2n l\u1ea1i \u0111\u1ec1u xu\u1ea5t hi\u1ec7n d\u1ea5u –
\nV\u1eady >> Ch\u1ecdn C<\/p>\n
5) N\u1ebfu th\u1ea5y 2-3 \u0111\u00e1p \u00e1n c\u00f3 li\u00ean quan m\u1eadt thi\u1ebft t\u1edbi nhau nh\u01b0 “g\u1ea5p \u0111\u00f4i nhau”, “h\u01a1n k\u00e9m nhau 10 l\u1ea7n”, th\u00ec 1 trong s\u1ed1 ch\u00fang s\u1ebd l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang.<\/strong><\/em><\/p>\nVd : A. 15 B. 20 C. 13,5 D. 30<\/p>\n
D\u1ec5 th\u1ea5y 30 g\u1ea5p \u0111\u00f4i 15, v\u1eady 1 trong 2 s\u1ebd l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang.<\/p>\n
6) N\u1ebfu c\u00e1c \u0111\u00e1p \u00e1n xu\u1ea5t hi\u1ec7n %, nh\u1eefng \u0111\u00e1p \u00e1n n\u00e0o c\u1ed9ng v\u1edbi nhau b\u1eb1ng 100% th\u01b0\u1eddng l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang<\/strong><\/em><\/p>\nVD: A. 40% B.60% C. 27,27% D.50%
\nD\u1ec5 th\u1ea5y 40% + 60% = 100%, v\u1eady A ho\u1eb7c B l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang.
\n7) V\u1edbi nh\u1eefng c\u00e2u h\u1ecfi d\u1ea1ng t\u00ednh pH, h\u00e3y ch\u1ecdn nh\u1eefng \u0111\u00e1p \u00e1n mang 1 trong c\u00e1c gi\u00e1 tr\u1ecb sau:
\n1, 2, 12, 13
\n8) N\u1ebfu b\u1eaft bu\u1ed9c ph\u1ea3i khoanh b\u1eeba m\u00e0 kh\u00f4ng th\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c s\u1ef1 l\u1ef1a ch\u1ecdn n\u00e0o \u0111\u1ec3 lo\u1ea1i tr\u1eeb, h\u00e3y ch\u1ecdn c\u00e1c \u0111\u00e1p \u00e1n “kh\u00f4ng ph\u1ea3i l\u1edbn nh\u1ea5t m\u00e0 c\u0169ng kh\u00f4ng ph\u1ea3i nh\u1ecf nh\u1ea5t” (v\u00ec m\u00ecnh th\u1ea5y t\u1ec9 l\u1ec7 tr\u00fang c\u00e1c \u0111\u00e1p \u00e1n n\u00e0y th\u01b0\u1eddng cao h\u01a1n).<\/strong><\/em><\/p>\n* C\u00e1c c\u00e2u h\u1ecfi l\u00fd thuy\u1ebft:<\/strong>
\n– C\u00e1c \u0111\u00e1p \u00e1n g\u1ea7n nh\u01b0 gi\u1ed1ng nhau ho\u00e0n to\u00e0n, 1 trong s\u1ed1 ch\u00fang th\u01b0\u1eddng l\u00e0 \u0111\u00fang<\/p>\n– C\u00e1c \u0111\u00e1p \u00e1n c\u00f3 ngh\u0129a \u0111\u1ed1i l\u1eadp nhau (v\u00ed d\u1ee5 nh\u01b0 m\u1ed9t c\u00e1i kh\u1eb3ng \u0111\u1ecbnh c\u00f3, m\u1ed9t c\u00e1i kh\u1eb3ng \u0111\u1ecbnh kh\u00f4ng) th\u00ec m\u1ed9t trong 2 th\u01b0\u1eddng l\u00e0 \u0111\u00fang<\/p>\n
– \u0110\u00e1p \u00e1n c\u00f3 nh\u1eefng t\u1eeb “lu\u00f4n lu\u00f4n”, “duy nh\u1ea5t”, “ho\u00e0n to\u00e0n kh\u00f4ng”, “ch\u1ec9 c\u00f3…”, “ch\u1eafc ch\u1eafn” th\u01b0\u1eddng sai.<\/p>\n
– \u0110\u00e1p \u00e1n mang c\u00e1c c\u1ee5m t\u1eeb “c\u00f3 th\u1ec3”, “t\u00f9y tr\u01b0\u1eddng h\u1ee3p”, “ho\u1eb7c”, “c\u00f3 l\u1ebd”, “\u0111\u00f4i khi” th\u01b0\u1eddng \u0111\u00fang<\/p>\n
– C\u00e1c c\u00e2u d\u00e0i v\u00e0 di\u1ec5n \u0111\u1ea1t t\u1ec9 m\u1ec9 h\u01a1n h\u1eb3n nh\u1eefng c\u00e2u c\u00f2n l\u1ea1i th\u01b0\u1eddng \u0111\u00fang.<\/p>\n","protected":false},"excerpt":{"rendered":"
\u0110\u1ed1i v\u1edbi c\u00e2u h\u1ecfi b\u00e0i t\u1eadp 1)Trong 1 c\u00e2u th\u01b0\u1eddng c\u00f3 3 \u0111\u00e1p \u00e1n g\u1ea7n gi\u1ed1ng nhau, 1 trong 3 ch\u1eafc ch\u1eafn l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang, c\u00f3 th\u1ec3 lo\u1ea1i ngay \u0111\u00e1p \u00e1n c\u00f2n l\u1ea1i. V\u00ed d\u1ee5 : A. Chu k\u1ef3 4, nh\u00f3m IIA B. Chu k\u1ef3 4, nh\u00f3m VIIIB C. Chu k\u1ef3 3, nh\u00f3m VIB […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[159],"tags":[],"yoast_head":"\n
M\u1eb9o "\u0111i\u1ec1n b\u1eeba" \u0111\u00e1p \u00e1n b\u00e0i thi tr\u1eafc nghi\u1ec7m Ho\u00e1 h\u1ecdc<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/meo-dien-bua-dap-an-bai-thi-trac-nghiem-hoa-hoc\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"M\u1eb9o "\u0111i\u1ec1n b\u1eeba" \u0111\u00e1p \u00e1n b\u00e0i thi tr\u1eafc nghi\u1ec7m Ho\u00e1 h\u1ecdc\" \/>\n<meta property=\"og:description\" content=\"\u0110\u1ed1i v\u1edbi c\u00e2u h\u1ecfi b\u00e0i t\u1eadp 1)Trong 1 c\u00e2u th\u01b0\u1eddng c\u00f3 3 \u0111\u00e1p \u00e1n g\u1ea7n gi\u1ed1ng nhau, 1 trong 3 ch\u1eafc ch\u1eafn l\u00e0 \u0111\u00e1p \u00e1n \u0111\u00fang, c\u00f3 th\u1ec3 lo\u1ea1i ngay \u0111\u00e1p \u00e1n c\u00f2n l\u1ea1i. V\u00ed d\u1ee5 : A. Chu k\u1ef3 4, nh\u00f3m IIA B. Chu k\u1ef3 4, nh\u00f3m VIIIB C. 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V\u00ed d\u1ee5 : A. Chu k\u1ef3 4, nh\u00f3m IIA B. Chu k\u1ef3 4, nh\u00f3m VIIIB C. 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