\u0110\u1ec1 thi cu\u1ed1i h\u1ecdc k\u00ec 1 m\u00f4n To\u00e1n l\u1edbp 12 c\u1ee7a tr\u01b0\u1eddng THPT Th\u00e1i H\u00f2a n\u0103m 2016-2017, c\u00e1c em c\u00f9ng xem chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/p>\n

C\u00e2u 9:<\/strong> Cho h\u00e0m s\u1ed1 y = \u2013x^{3<\/sup> + 3x2<\/sup> \u2013 3x + 1, m\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang?<\/p>\n}

A<\/strong>.\u00a0 H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn ;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B<\/strong>.\u00a0 H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn;<\/p>\n

C<\/strong>.\u00a0 H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 1;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D.<\/strong>\u00a0 H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 1.<\/p>\n

C\u00e2u 12:<\/strong> Cho h\u00e0m s\u1ed1 y = (3x+1)\/(1-2x). Kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y \u0111\u00fang?<\/strong><\/p>\n

A. <\/strong>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = 3;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. <\/strong>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 ;<\/p>\n

C<\/strong>. <\/strong>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 kh\u00f4ng c\u00f3 ti\u1ec7m c\u1eadn ngang\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D<\/strong>. <\/strong>\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = -3\/2<\/p>\n

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Theo Tuyensinh247<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

\u0110\u1ec1 thi cu\u1ed1i h\u1ecdc k\u00ec 1 m\u00f4n To\u00e1n l\u1edbp 12 c\u1ee7a tr\u01b0\u1eddng THPT Th\u00e1i H\u00f2a n\u0103m 2016-2017, c\u00e1c em c\u00f9ng xem chi ti\u1ebft t\u1ea1i \u0111\u00e2y: C\u00e2u 9: Cho h\u00e0m s\u1ed1 y = \u2013x3 + 3×2 \u2013 3x + 1, m\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang? A.\u00a0 H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn ;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B.\u00a0 […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[167],"tags":[],"yoast_head":"\n