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{"id":7512,"date":"2016-12-19T03:16:17","date_gmt":"2016-12-19T03:16:17","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=7512"},"modified":"2016-12-19T03:19:43","modified_gmt":"2016-12-19T03:19:43","slug":"hoa-hoc-phuong-phap-bao-toan-dien-tich-hay-va-day-du","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/hoa-hoc-phuong-phap-bao-toan-dien-tich-hay-va-day-du\/","title":{"rendered":"[Ho\u00e1 h\u1ecdc] Ph\u01b0\u01a1ng ph\u00e1p b\u1ea3o to\u00e0n \u0111i\u1ec7n t\u00edch (hay v\u00e0 \u0111\u1ea7y \u0111\u1ee7)"},"content":{"rendered":"

B\u00e0i vi\u1ebft gi\u1edbi thi\u1ec7u chi ti\u1ebft v\u1ec1 pp b\u1ea3o to\u00e0n \u0111i\u1ec7n t\u00edch v\u00e0 c\u00e1c \u1ee9ng d\u1ee5ng c\u1ee7a pp n\u00e0y trong gi\u1ea3i c\u00e1c b\u00e0i t\u1eadp s\u1ef1 \u0111i\u1ec7n li.<\/p>\n

B\u1ea2O TO\u00c0N \u0110I\u1ec6N T\u00cdCH<\/strong><\/p>\n

Nguy\u00ean t\u1eafc : <\/strong>T\u1ed5ng \u0111i\u1ec7n t\u00edch d\u01b0\u01a1ng lu\u00f4n lu\u00f4n b\u1eb1ng t\u1ed5ng \u0111i\u1ec7n t\u00edch \u00e2m, v\u00ec th\u1ebf dung d\u1ecbch lu\u00f4n lu\u00f4n trung h\u00f2a v\u1ec1 \u0111i\u1ec7n.<\/p>\n

S + = S –<\/p>\n

VD1 <\/u><\/strong>:<\/strong> M\u1ed9t dd ch\u1ee9a a mol K+, b mol Fe3+, c mol Cl-, d mol SO42- . Bi\u1ec3u th\u1ee9c li\u00ean h\u1ec7 gi\u1eefa c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng tr\u00ean l\u00e0:<\/p>\n

A) 2a + b = 2c + d\u00a0 B) a + 3b = c + 2d<\/strong><\/p>\n

C) 3a + b = 2c + d\u00a0 D) a + 2b = c + 2d<\/p>\n

Gi\u1ea3i : <\/strong>S n \u0111t + = a + 3b v\u00e0 S n \u0111t \u2013 = c + 2d<\/p>\n

VD2<\/u><\/strong> : <\/strong>K\u1ebft qu\u1ea3 x\u00e1c \u0111\u1ecbnh n\u1ed3ng \u0111\u1ed9 mlo\/l c\u1ee7a c\u00e1c ion trong dd nh\u01b0 sau: Na+(0,05); Ca2+(0,01) ; NO3-(0,04); HCO3-(0,025) . H\u1ecfi k\u1ebft qu\u1ea3 tr\u00ean \u0111\u00fang hay sai, t\u1ea1i sao?<\/p>\n

Gi\u1ea3i :<\/strong> Theo \u0110LBT\u0110T<\/strong><\/p>\n

S + = 0,05 + 0,02 = 0,07<\/p>\n

S – = 0,04 + 0,025 = 0,065<\/p>\n

\u00e0 K\u1ebft qu\u1ea3 ph\u00e2n t\u00edch tr\u00ean l\u00e0 sai<\/p>\n

VD 3<\/u><\/strong>: C\u00f4 c\u1ea1n dung d\u1ecbch c\u00f3 ch\u1ee9a 0,2 mol Mg2+; 0,1 mol Al3+, v\u00e0 ion NO3- th\u00ec thu \u0111\u01b0\u1ee3c bao nhi\u00eau gam mu\u1ed1i khan l\u00e0 :<\/p>\n

A. 55,3 gam \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 59,5 gam<\/p>\n

C. 50,9 gam \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0,59 gam<\/p>\n

Gi\u1ea3i <\/u><\/strong>: Theo \u0110LBT \u0111i\u1ec7n t\u00edch: 0.2 *2 + 0.1 *3 = n NO3-= 0,7 mol<\/p>\n

\u00e0 m mu\u1ed1i = 24*0,2 + 27*0,1 + 0,7*62= 50,9 gam \u00e0 ch\u1ecdn C<\/strong><\/p>\n

VD4 <\/u><\/strong>: <\/strong>M\u1ed9t dung d\u1ecbch c\u00f3 ch\u1ee9a 2 Cation l\u00e0 Fe2+ (0,1 mol) v\u00e0 Al3+ (0,2 mol) v\u00e0 2 Anion l\u00e0 Cl- (x mol) v\u00e0\u00a0SO42- (y mol). Khi c\u00f4 c\u1ea1n dung d\u1ecbch thu \u0111\u01b0\u1ee3c 46,9 gam ch\u1ea5t r\u1eafn khan. ( <\/strong>Bi\u1ebft Fe = 56, Al = 27, Cl = 35,5; S = 32, O = 16). Gi\u00e1 tr\u1ecb x, y trong c\u00e2u tr\u00ean l\u1ea7n l\u01b0\u1ee3t l\u00e0:<\/p>\n

A) 0,1 ; 0,2 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B) 0,2 ; 0,3<\/p>\n

C) 0,3 : 0,1 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D) 0,3 : 0,2<\/p>\n

Gi\u1ea3i : Theo \u0110LBT\u0110T : <\/strong>2.0,1 + 3.0,2 = x + 2y<\/p>\n

\u0110LBTKL :<\/strong><\/p>\n

m mu\u1ed1i = S m cation KL + S m anion g\u1ed1c axit<\/p>\n

= <\/strong>56.0,1 + 27.0,2 +35,5 . x + 96 .y = 46,9<\/p>\n

\u00e0 <\/strong>x = 0,2 ; y = 0,3 \u00e0 B<\/strong><\/p>\n