\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia 2017 m\u00f4n To\u00e1n – THPT Ba \u0110\u00ecnh, t\u1ec9nh Thanh H\u00f3a t\u1ed5 ch\u1ee9c l\u1ea7n 1 theo h\u00ecnh th\u1ee9c thi tr\u1eafc nghi\u1ec7m 50 c\u00e2u\/90 ph\u00fat<\/p>\n
C\u00e2u 9. Cho h\u00e0m s\u1ed1\u00a0 y = -x3<\/sup> + 3x2<\/sup> \u2013 5x + 1 (1)<\/p>\n Ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m u\u1ed1n c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (1) l\u00e0:<\/p>\n A. y = -2x \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. y = 2x + 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. y = 4x \u2013 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. y = -2x + 4<\/p>\n <\/p>\n <\/p>\n <\/p>\n <\/p>\n Theo Tuyensinh247<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia 2017 m\u00f4n To\u00e1n – THPT Ba \u0110\u00ecnh, t\u1ec9nh Thanh H\u00f3a t\u1ed5 ch\u1ee9c l\u1ea7n 1 theo h\u00ecnh th\u1ee9c thi tr\u1eafc nghi\u1ec7m 50 c\u00e2u\/90 ph\u00fat C\u00e2u 9. Cho h\u00e0m s\u1ed1\u00a0 y = -x3 + 3×2 \u2013 5x + 1 (1) Ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m u\u1ed1n c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (1) […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[28],"tags":[],"yoast_head":"\n