Tr\u01b0\u01a1\u0300ng THPT Nguy\u00ea\u0303n Tr\u01b0\u01a1\u0300ng T\u00f4\u0323 t\u00f4\u0309 ch\u01b0\u0301c ky\u0300 thi th\u01b0\u0309 m\u00f4n Sinh n\u0103m 2017 cho ca\u0301c em ho\u0323c sinh l\u01a1\u0301p 12, ca\u0301c em theo do\u0303i \u0111\u00ea\u0300 thi va\u0300 \u0111a\u0301p a\u0301n b\u00ean d\u01b0\u01a1\u0301i \u0111\u00e2y:<\/p>\n

S\u1ede GI\u00c1O D\u1ee4C V\u00c0 \u0110\u00c0O T\u1ea0O B\u00ccNH \u0110\u1ecaNH\u00a0\u00a0 \u00a0 \u00a0 \u00a0<\/strong><\/p>\n

TR\u01af\u1edcNG THPT NGUY\u1ec4N TR\u01af\u1edcNG T\u1ed8\u00a0<\/strong><\/p>\n

\u0110\u1ec0 THI TH\u1eec THPT QU\u1ed0C GIA N\u0102M 2017<\/strong><\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B\u00e0i thi: Khoa h\u1ecdc t\u1ef1 nhi\u00ean; M\u00f4n Sinh h\u1ecdc<\/strong><\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0<\/strong> \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Th\u1eddi gian l\u00e0m b\u00e0i: 50 ph\u00fat, kh\u00f4ng k\u1ec3 th\u1eddi gian ph\u00e1t \u0111\u1ec1<\/em><\/p>\n

C\u00e2u 1:<\/strong> Gen l\u00e0 m\u1ed9t \u0111o\u1ea1n ADN:<\/strong><\/p>\n

A. <\/strong>ch\u1ee9a c\u00e1c b\u1ed9 3 m\u00e3 h\u00f3a c\u00e1c axitamin.<\/p>\n

B. <\/u><\/strong>mang th\u00f4ng tin m\u00e3 h\u00f3a cho m\u1ed9t s\u1ea3n ph\u1ea9m x\u00e1c \u0111\u1ecbnh l\u00e0 chu\u1ed7i polip\u00e9pt\u00edt hay ARN.<\/u><\/u><\/p>\n

C. <\/strong>mang th\u00f4ng tin di truy\u1ec1n.<\/p>\n

D. <\/strong>mang th\u00f4ng tin c\u1ea5u tr\u00fac c\u1ee7a ph\u00e2n t\u1eed pr\u00f4t\u00eain.<\/p>\n

C\u00e2u<\/strong> 2: C\u00e1c m\u1ea1ch \u0111\u01a1n m\u1edbi \u0111\u01b0\u1ee3c t\u1ed5ng h\u1ee3p trong qu\u00e1 tr\u00ecnh nh\u00e2n \u0111\u00f4i c\u1ee7a ph\u00e2n t\u1eed ADN h\u00ecnh th\u00e0nh theo chi\u1ec1u:<\/strong><\/p>\n

A. <\/strong>c\u00f9ng chi\u1ec1u v\u1edbi chi\u1ec1u th\u00e1o xo\u1eafn c\u1ee7a ADN \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. <\/strong>3′ \u0111\u1ebfn 5′<\/p>\n

C. <\/u><\/strong>5′ \u0111\u1ebfn 3′<\/u>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. <\/strong>c\u00f9ng chi\u1ec1u v\u1edbi m\u1ea1ch khu\u00f4n<\/p>\n

C\u00e2u 3:<\/strong> M\u1ed7i b\u1ed9 ba m\u00e3 h\u00f3a cho 1 axitamin, \u0111\u00e2y l\u00e0 \u0111\u1eb7c \u0111i\u1ec3m n\u00e0o c\u1ee7a m\u00e3 di truy\u1ec1n<\/strong><\/p>\n

A. <\/strong>T\u00ednh li\u00ean t\u1ee5c \u00a0 \u00a0B. <\/strong>T\u00ednh tho\u00e1i ho\u00e1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. <\/u><\/strong>T\u00ednh \u0111\u1eb7c hi\u1ec7u<\/u>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. <\/strong>T\u00ednh ph\u1ed5 bi\u1ebfn<\/p>\n

C\u00e2u 4:<\/strong> S\u1ef1 gi\u1ed1ng nhau c\u1ee7a hai qu\u00e1 tr\u00ecnh nh\u00e2n \u0111\u00f4i v\u00e0 phi\u00ean m\u00e3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y \u0111\u00fang:<\/strong><\/p>\n

A. <\/strong>C\u1ea3 hai qu\u00e1 tr\u00ecnh trong m\u1ed9t chu k\u00ec t\u1ebf b\u00e0o c\u00f3 th\u1ec3 th\u1ef1c hi\u1ec7n nhi\u1ec1u l\u1ea7n<\/p>\n

B. <\/u><\/strong>Vi\u1ec7c l\u1eafp gh\u00e9p c\u00e1c \u0111\u01a1n ph\u00e2n \u0111\u01b0\u1ee3c th\u1ef1c hi\u1ec7n tr\u00ean c\u01a1 s\u1edf nguy\u00ean t\u1eafc b\u1ed1 sung<\/u><\/u><\/p>\n

C. <\/strong>\u0111\u1ec1u di\u1ec5n ra c\u00f3 s\u1ef1 ti\u1ebfp x\u00fac c\u1ee7a c\u00e1c enzim ADN p\u00f4limeraza, em zim c\u1eaft<\/p>\n

D. <\/strong>th\u1ef1c hi\u1ec7n tr\u00ean to\u00e0n b\u1ed9 ph\u00e2n t\u1eed ADN<\/p>\n

C\u00e2u 5:<\/strong> Lo\u1ea1i \u0111\u1ed9t bi\u1ebfn gen n\u00e0o x\u1ea3y ra l\u00e0m t\u0103ng 2 li\u00ean k\u1ebft hi\u0111r\u00f4 c\u1ee7a gen<\/strong><\/p>\n

A. <\/u><\/strong>th\u00eam 1 c\u1eb7p nucl\u00ea\u00f4tit A=T<\/u>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. <\/strong>Thay th\u1ebf 1 c\u1eb7p A – T b\u1eb1ng 1 c\u1eb7p G – X<\/p>\n

C. <\/strong>Thay th\u1ebf 2c\u1eb7p A – T b\u1eb1ng 2 c\u1eb7p T – A \u00a0 \u00a0 \u00a0 \u00a0\u00a0D. <\/strong>M\u1ea5t 1 c\u1eb7p nucl\u00ea\u00f4tit A=T<\/p>\n

C\u00e2u 6:<\/strong> M\u1ed9t gen c\u00f3 chi\u1ec1u d\u00e0i 5100 <\/strong>\u00c5<\/strong> v\u00e0 c\u00f3 3.900 li\u00ean k\u1ebft hi\u0111r\u00f4. S\u1ed1 l\u01b0\u1ee3ng t\u1eebng lo\u1ea1i nu c\u1ee7a gen n\u00f3i tr\u00ean b\u1eb1ng:<\/strong><\/p>\n

A. <\/strong>A = T = 900,\u00a0\u00a0 G = X = 60 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. <\/u><\/strong>A = T = 600,\u00a0\u00a0 G = X = 900<\/u><\/p>\n

C. <\/strong>A = T = 720,\u00a0\u00a0 G = X = 480 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. <\/strong>A = T = 480,\u00a0\u00a0 G = X = 720<\/p>\n

HD: 2A + 2G = 2X5100\/3,4 (1)<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2A + 3G = 3900 (2)<\/p>\n

Gi\u1ea2I (1) v\u00e0 (2), t\u00ecm \u0111\u01b0\u1ee3c A = T = 600,\u00a0\u00a0 G = X = 900<\/u><\/p>\n

C\u00e2u 7:<\/strong> \u00a0H\u00e3y x\u00e1c \u0111\u1ecbnh \u00fd n\u00e0o kh\u00f4ng \u0111\u00fang khi n\u00f3i v\u1ec1 c\u01a1 ch\u1ebf h\u00ecnh th\u00e0nh th\u1ec3 t\u1ef1 \u0111a b\u1ed9i \u00a0l\u00e0:<\/strong><\/p>\n

A. <\/strong>Giao t\u1eed b\u00ecnh th\u01b0\u1eddng k\u1ebft h\u1ee3p v\u1edbi giao t\u1eed b\u1ea5t th\u01b0\u1eddng<\/p>\n

B. <\/u><\/strong>Giao t\u1eed b\u00ecnh th\u01b0\u1eddng k\u1ebft h\u1ee3p v\u1edbi giao t\u1eed b\u00ecnh th\u01b0\u1eddng<\/u><\/u><\/p>\n

C. <\/strong>Giao t\u1eed b\u1ea5t th\u01b0\u1eddng k\u1ebft h\u1ee3p v\u1edbi giao t\u1eed b\u1ea5t th\u01b0\u1eddng<\/p>\n

D. <\/strong>Trong l\u1ea7n nguy\u00ean ph\u00e2n \u0111\u1ea7u ti\u00ean c\u1ee7a h\u1ee3p t\u1eed, n\u1ebfu t\u1ea5t c\u1ea3 c\u00e1c NST kh\u00f4ng ph\u00e2n li<\/p>\n

C\u00e2u 8:<\/strong> X\u00e9t 2 NST kh\u00f4ng t\u01b0\u01a1ng \u0111\u1ed3ng mang c\u00e1c \u0111o\u1ea1n l\u1ea7n l\u01b0\u1ee3t l\u00e0: ABCDEG.HIK. Sau \u0111\u1ed9t bi\u1ebfn \u0111\u00e3 xu\u1ea5t hi\u1ec7n NST c\u00f3 c\u1ea5u tr\u00fac: ABCDH. GEIK. \u0110\u00e2y l\u00e0 d\u1ea1ng \u0111\u1ed9t bi\u1ebfn:<\/strong><\/p>\n

A. <\/strong>L\u1eb7p \u0111o\u1ea1n. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. <\/strong>Chuy\u1ec3n \u0111o\u1ea1n. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. <\/u><\/strong>\u0110\u1ea3o \u0111o\u1ea1n.<\/u>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. <\/strong>M\u1ea5t \u0111o\u1ea1n.<\/p>\n

C\u00e2u 9:<\/strong> \u1ede ng\u01b0\u1eddi, \u0111\u1ed9t bi\u1ebfn m\u1ea5t m\u1ed9t ph\u1ea7n vai ng\u1eafn nhi\u1ec5m s\u1eafc th\u1ec3 s\u1ed1 5 g\u00e2y n\u00ean h\u1ed9i ch\u1ee9ng<\/strong><\/p>\n

A. <\/strong>AIDS \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. <\/u><\/strong>ti\u1ebfng m\u00e8o k\u00eau<\/u>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. <\/strong>\u0110ao\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. <\/strong>T\u01a1cn\u01a1<\/p>\n

\n

C\u00e2u 10:<\/strong> Theo Men\u0111en, v\u1edbi n c\u1eb7p gen d\u1ecb h\u1ee3p ph\u00e2n li \u0111\u1ed9c l\u1eadp th\u00ec t\u1ec9 l\u1ec7 ph\u00e2n li ki\u1ec3u gen \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh theo c\u00f4ng th\u1ee9c n\u00e0o?<\/strong><\/p>\n

A. <\/strong>T\u1ec9 l\u1ec7 ph\u00e2n li ki\u1ec3u gen l\u00e0 ( 1\u00a0 :\u00a0 3\u00a0 :\u00a0 1)^{n<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. <\/strong>T\u1ec9 l\u1ec7 ph\u00e2n li ki\u1ec3u gen l\u00e0 ( 3\u00a0 : 1)n<\/sup><\/p>\n}

C. <\/u><\/strong>T\u1ec9 l\u1ec7 ph\u00e2n li ki\u1ec3u gen l\u00e0 ( 1\u00a0 :\u00a0 2\u00a0 :\u00a0 1)^{n<\/sup><\/u>\u00a0 \u00a0 \u00a0 \u00a0D. <\/strong>T\u1ec9 l\u1ec7 ph\u00e2n li ki\u1ec3u gen l\u00e0 ( 1\u00a0 :\u00a0 4\u00a0 :\u00a0 1)n<\/sup><\/p>\n}

C\u00e2u 11:<\/strong> \u1ede ru\u1ed3i gi\u1ea5m, gen quy \u0111\u1ecbnh m\u00e0u m\u1eaft n\u1eb1m tr\u00ean NST gi\u1edbi t\u00ednh X, kh\u00f4ng c\u00f3 alen t\u01b0\u01a1ng \u1ee9ng tr\u00ean Y. A quy \u0111\u1ecbnh m\u1eaft \u0111\u1ecf, a quy \u0111\u1ecbnh m\u1eaft tr\u1eafng, n\u1ebfu ru\u1ed3i m\u1eaft \u0111\u1ecf giao ph\u1ed1i v\u1edbi ru\u1ed3i m\u1eaft \u0111\u1ecf cho t\u1ec9 l\u1ec7 ru\u1ed3i m\u1eaft tr\u1eafng l\u00e0 \u00bc th\u00ec ki\u1ec3u gen c\u1ee7a ru\u1ed3i m\u1eaft \u0111\u1ecf b\u1ed1, m\u1eb9 l\u00e0<\/strong><\/p>\n

A. <\/strong>X^{a<\/sup>Y, XA<\/sup> Xa<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. <\/strong>Xa<\/sup>Y, XA<\/sup> XA<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. <\/strong>XA<\/sup>Y, XA<\/sup> XA<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. <\/u><\/strong>XA<\/sup>Y, XA<\/sup> Xa<\/sup><\/u><\/p>\n}

HD: Ru\u1ed3i m\u1eaft tr\u1eafng chi\u1ebfm \u00bc. C\u00f3 4 t\u1ed5 h\u1ee3p do 2 giao t\u1eed x 2 giao t\u1eed .Loai ph\u01b0\u01a1ng \u00e1n C, B.<\/p>\n

V\u00ec theo gi\u1ea3 thuy\u1ebft ru\u1ed3i m\u1eaft \u0111\u1ecf giao ph\u1ed1i v\u1edbi ru\u1ed3i m\u1eaft \u0111\u1ecf, suy ra ch\u1ecdn ph\u01b0\u01a1ng \u00e1n D.<\/p>\n

C\u00e2u 12:<\/strong> \u0110i\u1ec1u ki\u1ec7n nghi\u1ec7m \u0111\u00fang \u0111\u1eb7c tr\u01b0ng c\u1ee7a quy lu\u1eadt ph\u00e2n ly \u0111\u1ed9c l\u1eadp?<\/strong><\/p>\n

A. <\/strong>C\u00e1c giao t\u1eed v\u00e0 c\u00e1c h\u1ee3p t\u1eed c\u00f3 s\u1ee9c s\u1ed1ng nh\u01b0 nhau. S\u1ef1 bi\u1ec3u hi\u1ec7n ho\u00e0n to\u00e0n c\u1ee7a t\u00ednh tr\u1ea1ng.<\/p>\n

B. <\/strong>S\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 \u1edf c\u00e1c th\u1ebf h\u1ec7 lai ph\u1ea3i \u0111\u1ee7 l\u1edbn \u0111\u1ec3 s\u1ed1 li\u1ec7u th\u1ed1ng k\u00ea \u0111\u01b0\u1ee3c ch\u00ednh x\u00e1c.<\/p>\n

\n

C. <\/u><\/strong>m\u1ed7i c\u1eb7p gen n\u1eb1m tr\u00ean m\u1ed9t c\u1eb7p NST t\u01b0\u01a1ng \u0111\u1ed3ng.<\/u><\/u><\/p>\n

D. <\/strong>S\u1ef1 ph\u00e2n li NST nh\u01b0 nhau khi t\u1ea1o giao t\u1eed v\u00e0 s\u1ef1 k\u1ebft h\u1ee3p ng\u1eabu nhi\u00ean c\u1ee7a c\u00e1c ki\u1ec3u giao t\u1eed khi th\u1ee5 tinh.<\/p>\n

C\u00e2u 13:<\/strong> C\u00e1c ch\u1eef in hoa l\u00e0 alen tr\u1ed9i v\u00e0 ch\u1eef th\u01b0\u1eddng l\u00e0 alen l\u1eb7n. M\u1ed7i gen quy \u0111\u1ecbnh 1 t\u00ednh tr\u1ea1ng. Th\u1ef1c hi\u1ec7n ph\u00e9p lai: P: \u2640 AaBbCcDd \u2642 AabbCcDd. T\u1ec9 l\u1ec7 ph\u00e2n li \u1edf F1 v\u1ec1 ki\u1ec3u gen kh\u00f4ng gi\u1ed1ng c\u1ea3 cha l\u1eabn m\u1eb9 l\u00e0<\/strong><\/p>\n

A. <\/strong>1\/4. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. <\/u><\/strong>7\/8.<\/u>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. <\/strong>1\/16. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0D. <\/strong>1\/32.<\/p>\n

HD:<\/strong><\/p>\n

T\u1ec9 l\u1ec7 ki\u1ec3u gen gi\u1ed1ng m\u1eb9 = 1\/2×1\/2×1\/2×1\/2 = 1\/16<\/p>\n

T\u1ec9 l\u1ec7 ki\u1ec3u gen gi\u1ed1ng b\u1ed1 = 1\/2×1\/2×1\/2×1\/2 = 1\/16<\/p>\n

T\u1ec9 l\u1ec7 ki\u1ec3u gen gi\u1ed1ng m\u1eb9 hay b\u1ed1 = 1\/16+1\/16 = 1\/8<\/p>\n

T\u1ec9 l\u1ec7 ki\u1ec3u gen kh\u00f4ng gi\u1ed1ng c\u1ea3 m\u1eb9 v\u00e0 b\u1ed1 = 1- 1\/8 = 7\/8<\/p>\n

C\u00e2u 14:<\/strong> C\u00e1c ch\u1eef in hoa l\u00e0 alen tr\u1ed9i v\u00e0 ch\u1eef th\u01b0\u1eddng l\u00e0 alen l\u1eb7n. M\u1ed7i gen quy \u0111\u1ecbnh 1 t\u00ednh tr\u1ea1ng. Cho c\u00e1 th\u1ec3 mang ki\u1ec3u gen AaBbDDEeFf t\u1ef1 th\u1ee5 ph\u1ea5n th\u00ec s\u1ed1 t\u1ed5 h\u1ee3p giao t\u1eed( ki\u1ec3u t\u1ed5 h\u1ee3p) t\u1ed1i \u0111a l\u00e0<\/strong><\/p>\n

A. <\/strong>32 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. <\/strong>64 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0C. <\/strong>128 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. <\/u><\/strong>256<\/u><\/u><\/p>\n

HD: S\u1ed1 t\u1ed5 h\u1ee3p = S\u1ed1 giao t\u1eed x s\u1ed1 giao t\u1eed = 2^{4\u00a0 <\/sup>x \u00a024\u00a0 <\/sup>=\u00a0 256<\/p>\n}

C\u00e2u 15:<\/strong> Ph\u01b0\u01a1ng ph\u00e1p nghi\u00ean c\u1ee9u c\u1ee7a Men\u0111en g\u1ed3m c\u00e1c n\u1ed9i dung theo tr\u1eadt t\u1ef1:<\/strong><\/p>\n

1 \u2013 S\u1eed d\u1ee5ng to\u00e1n x\u00e1c su\u1ea5t \u0111\u1ec3 ph\u00e2n t\u00edch k\u1ebft qu\u1ea3 lai.<\/p>\n

\u00a02 \u2013 Lai c\u00e1c d\u00f2ng thu\u1ea7n v\u00e0 ph\u00e2n t\u00edch c\u00e1c k\u1ebft qu\u1ea3 F1, F2, F3.<\/p>\n

3 \u2013 Ti\u1ebfn h\u00e0nh th\u00ed nghi\u1ec7m ch\u1ee9ng minh.<\/p>\n

\u00a04 \u2013 T\u1ea1o c\u00e1c d\u00f2ng thu\u1ea7n b\u1eb1ng t\u1ef1 th\u1ee5 ph\u1ea5n.<\/p>\n

A. <\/strong>4 2 3 1. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. <\/u><\/strong>4 2 1 3.<\/u>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0C. <\/strong>4 3 2 1. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0D. <\/strong>4 1 2 3.<\/p>\n

C\u00e2u 16<\/strong>: Khi cho chu\u1ed9t l\u00f4ng x\u00e1m n\u00e2u giao ph\u1ed1i v\u1edbi chu\u1ed9t l\u00f4ng tr\u1eafng (ki\u1ec3u gen \u0111\u1ed3ng h\u1ee3p l\u1eb7n) \u0111\u01b0\u1ee3c 48 con l\u00f4ng xam n\u00e2u, 99 con l\u00f4ng tr\u1eafng v\u00e0 51 con l\u00f4ng \u0111en. Cho chu\u1ed9t l\u00f4ng \u0111en v\u00e0 l\u00f4ng tr\u1eafng \u0111\u1ec1u thu\u1ea7n ch\u1ee7ng giao ph\u1ed1i v\u1edbi nhau \u0111\u01b0\u1ee3c F1 to\u00e0n chu\u1ed9t l\u00f4ng x\u00e1m. Cho chu\u1ed9t F1 ti\u1ebfp t\u1ee5c giao ph\u1ed1i v\u1edbi nhau th\u00ec s\u1ef1 ph\u00e2n li ki\u1ec3u h\u00ecnh \u1edf F2 nh\u01b0 th\u1ebf n\u00e0o?<\/p>\n

A. 9 l\u00f4ng x\u00e1m n\u00e2u : 3 l\u00f4ng \u0111en : 4 l\u00f4ng tr\u1eafng.<\/u><\/p>\n

B. 12 l\u00f4ng x\u00e1m n\u00e2u : 3 l\u00f4ng \u0111en : 1 l\u00f4ng tr\u1eafng.<\/p>\n

C. 9 l\u00f4ng x\u00e1m n\u00e2u : 1 l\u00f4ng \u0111en : 1 l\u00f4ng tr\u1eafng.<\/p>\n

D. 9 l\u00f4ng x\u00e1m n\u00e2u : 4 l\u00f4ng \u0111en : 5 l\u00f4ng tr\u1eafng.<\/p>\n

HD: <\/strong>P : x\u00e1m x tr\u1eafng(\u0111\u1ed3ng h\u1ee3p l\u1eb7n)<\/p>\n

F1: 48 n\u00e2u (1) : 99 tr\u1eafng (2) : 51 \u0111en(1)<\/p>\n

F1 c\u00f3 t\u1ed5 h\u1ee3p = 4 giao t\u1eed P x 1 giao t\u1eed P(\u0111\u1ed3ng h\u1ee3p l\u1eb7n)<\/p>\n

->X\u00e1m P cho 4 lo\u1ea1i giao t\u1eed ->x\u00e1m d\u1ecb h\u1ee3p 2 c\u1eb7p gen.<\/p>\n

-> tr\u1eafng : aabb, A-bb; \u0111en: aaB-, x\u00e1m: A-B-<\/p>\n

P(t\/c): \u0111en x tr\u1eafng ->x\u00e1m<\/p>\n

aaBB xAAbb -> F1: AaBb x AaBb -> F2 : 9 A-B : x\u00e1m; 3 aaB-: \u0111en; 4 (3A-bb, 1aabb): tr\u1eafng<\/p>\n

C\u00e2u 17:<\/strong> Cho giao ph\u1ea5n gi\u1eefa c\u00e2y hoa \u0111\u1ecf thu\u1ea7n ch\u1ee7ng v\u1edbi c\u00e2y hoa tr\u1eafng \u0111\u01b0\u1ee3c F1 hoa \u0111\u1ecf, cho F1 t\u1ef1 th\u1ee5 ph\u1ea5n th\u00ec ki\u1ec3u h\u00ecnh \u1edf c\u00e2y F2 l\u00e0 3 hoa \u0111\u1ecf : 1 hoa tr\u1eafng. C\u00e1ch lai n\u00e0o sau \u0111\u00e2y kh\u00f4ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c ki\u1ec3u gen c\u1ee7a c\u00e2y hoa \u0111\u1ecf F2?<\/strong><\/p>\n

A. <\/strong>Lai ph\u00e2n t\u00edch c\u00e2y hoa \u0111\u1ecf F2.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. <\/strong>Lai c\u00e2y hoa \u0111\u1ecf F2 v\u1edbi c\u00e2y F1 .<\/p>\n

C. <\/strong>Cho c\u00e2y hoa \u0111\u1ecf F2 t\u1ef1 th\u1ee5 ph\u1ea5n.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. <\/u><\/strong>Lai c\u00e2y hoa \u0111\u1ecf F2 v\u1edbi c\u00e2y hoa \u0111\u1ecf P.<\/u><\/u><\/p>\n

C\u00e2u 18:<\/strong> \u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt, gen quy \u0111\u1ecbnh h\u1ea1t d\u00e0i tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen quy \u0111\u1ecbnh h\u1ea1t tr\u00f2n; gen quy \u0111\u1ecbnh h\u1ea1t ch\u00edn s\u1edbm tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen quy \u0111\u1ecbnh h\u1ea1t ch\u00edn mu\u1ed9n. Cho c\u00e1c c\u00e2y c\u00f3 ki\u1ec3u gen gi\u1ed1ng nhau v\u00e0 d\u1ecb h\u1ee3p t\u1eed v\u1ec1 2 c\u1eb7p gen t\u1ef1 th\u1ee5 ph\u1ea5n, \u1edf \u0111\u1eddi con thu \u0111\u01b0\u1ee3c 4000 c\u00e2y, trong \u0111\u00f3 c\u00f3 160 c\u00e2y c\u00f3 ki\u1ec3u h\u00ecnh h\u1ea1t tr\u00f2n, ch\u00edn mu\u1ed9n. Bi\u1ebft r\u1eb1ng kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn x\u1ea3y ra, qu\u00e1 tr\u00ecnh ph\u00e1t sinh giao t\u1eed \u0111\u1ef1c v\u00e0 giao t\u1eed c\u00e1i x\u1ea3y ra ho\u00e1n v\u1ecb gen v\u1edbi t\u1ea7n s\u1ed1 b\u1eb1ng nhau. Theo l\u00ed thuy\u1ebft, s\u1ed1 c\u00e2y c\u00f3 ki\u1ec3u h\u00ecnh h\u1ea1t d\u00e0i, ch\u00edn s\u1edbm \u1edf \u0111\u1eddi con l\u00e0:<\/p>\n

A.<\/strong> 840\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. <\/strong>3840 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0C. 2160<\/u>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0D. <\/strong>2000<\/p>\n

HD: <\/strong>tr\u00f2n,ch\u00edn mu\u1ed9n = 160\/4000 = 0.04 (ab\/ab) -> ab = 0.2 , f = 40%<\/p>\n

T\u1ec9 l\u1ec7 H\u1ea1t d\u00e0i, ch\u00edn s\u1edbm = 0.5 + 0.04 = 0.54<\/p>\n

S\u1ed1 c\u00e2y H\u1ea1t d\u00e0i, ch\u00edn s\u1edbm = 0.54 x 4000 = 2160<\/p>\n

\u00a0<\/strong>C\u00e2u 19:<\/strong> \u1ede ng\u01b0\u1eddi, gen quy \u0111\u1ecbnh m\u00f9 m\u00e0u \u0111\u1ecf l\u1ee5c n\u1eb1m tr\u00ean NST X, kh\u00f4ng c\u00f3 alen tr\u00ean Y. B\u1ed1 b\u1ecb b\u1ec7nh, m\u1eb9 b\u00ecnh th\u01b0\u1eddng, h\u1ecd c\u00f3 ng\u01b0\u1eddi con trai b\u1ecb b\u1ec7nh m\u00f9 m\u00e0u \u0111\u1ecf l\u1ee5c. X\u00e1c su\u1ea5t h\u1ecd sinh \u0111\u1ee9a con th\u1ee9 hai l\u00e0 con g\u00e1i b\u1ecb b\u1ec7nh m\u00f9 m\u00e0u l\u00e0<\/strong><\/p>\n

A. <\/strong>25% \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. <\/u><\/strong>12,5%<\/u>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0C. <\/strong>50% \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0D. <\/strong>75%<\/p>\n

\u00a0<\/strong>HD: P :\u00a0 <\/strong>X^{a<\/sup>Y x m\u1eb9 b\u00ecnh th\u01b0\u1eddng (XA<\/sup> XA<\/sup> , XA<\/sup> Xa<\/sup>)<\/p>\n}

Con trai b\u1ecb b\u1ec7nh X^{a<\/sup>Y nh\u1eadn Xa<\/sup> t\u1eeb m\u1eb9 -> m\u1eb9 XA<\/sup> Xa<\/sup><\/p>\n}

P :\u00a0 <\/strong>X^{a<\/sup>Y x XA<\/sup> Xa<\/sup><\/p>\n}

F: \u00a0 1\/4 X^{A<\/sup>Y, 1\/4Xa<\/sup>Y,\u00a0 1\/4Xa<\/sup>Xa<\/sup>, \u00a01\/4XA<\/sup> Xa<\/sup><\/p>\n}

X\u00e1c su\u1ea5t h\u1ecd sinh \u0111\u1ee9a con th\u1ee9 hai l\u00e0 con g\u00e1i b\u1ecb b\u1ec7nh m\u00f9 m\u00e0u l\u00e0:. \u00bd x \u00bc\u00a0 = 1\/8 = 12.5%<\/p>\n

C\u00e2u 20<\/strong>:<\/strong> M\u1ed9t qu\u1ea7n th\u1ec3 c\u00f3 c\u1ea5u tr\u00fac di truy\u1ec1n 0,04 AA + 0,32 Aa + 0,64 aa = 1. T\u1ea7n s\u1ed1 t\u01b0\u01a1ng \u0111\u1ed1i c\u1ee7a alen A, a l\u1ea7n l\u01b0\u1ee3t l\u00e0:<\/p>\n

\u00a0A. 0,3 ; 0,7 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 0,8 ; 0,2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. 0,7 ; 0,3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0D. 0,2 ; 0,8<\/u><\/p>\n

\n

HD:<\/strong> T\u1ea7n s\u1ed1 alen A = 0.04 + 0.32\/2 = 0.2<\/p>\n

T\u1ea7n s\u1ed1 alen A = 0.64 + 0.32\/2 = 0.8<\/p>\n

C\u00e2u 21<\/strong>: <\/strong>C\u1ea5u tr\u00fac di truy\u1ec1n c\u1ee7a qu\u1ea7n th\u1ec3 ban \u0111\u1ea7u : 0,2 AA + 0,6 Aa + 0,2 aa = 1. Sau 2 th\u1ebf h\u1ec7 t\u1ef1 ph\u1ed1i th\u00ec c\u1ea5u tr\u00fac di truy\u1ec1n c\u1ee7a qu\u1ea7n th\u1ec3 s\u1ebd l\u00e0:<\/p>\n

\u00a0A. 0,35 AA + 0,30 Aa + 0,35 aa = 1.<\/p>\n

B. 0,425 AA + 0,15 Aa + 0,425 aa = 1.<\/u><\/p>\n

C. 0,25 AA + 0,50Aa + 0,25 aa = 1.<\/p>\n

D. 0,4625 AA + 0,075 Aa + 0,4625 aa = 1.<\/p>\n

HD: <\/strong>T\u1ea7n s\u1ed1 Aa = 0.6x(1\/2)^{2<\/sup> = 0.15<\/p>\n}

T\u1ea7n s\u1ed1 AA = 0.2 + 0.6x (1- (1\/2)^{2<\/sup> )\/2 = 0.425<\/p>\n}

T\u1ea7n s\u1ed1 aa = 0.2 + 0.6x (1- (1\/2)^{2<\/sup> )\/2 = 0.425<\/p>\n}

\u00a0<\/strong>C\u00e2u 22<\/strong>: <\/strong>M\u1ed9t qu\u1ea7n th\u1ec3 c\u00e2n b\u1eb1ng Hac\u0111i-Vanbec c\u00f3 300 c\u00e1 th\u1ec3, bi\u1ebft t\u1ea7n s\u1ed1 t\u01b0\u01a1ng \u0111\u1ed1i c\u1ee7a alen A = 0,3; a = 0,7. S\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 c\u00f3 ki\u1ec3u gen Aa l\u00e0:<\/p>\n

A. 63 c\u00e1 th\u1ec3. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. <\/u>126 c\u00e1 th\u1ec3.<\/u>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. 147 c\u00e1 th\u1ec3. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 90 c\u00e1 th\u1ec3.<\/p>\n

HD:<\/strong> T\u1ea7n s\u1ed1 Aa \u00a0=\u00a0 2 x 0.3 x 0.7 = 0.42<\/p>\n

S\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 c\u00f3 ki\u1ec3u gen Aa l\u00e0: 0.42 x 300 = \u00a0126 c\u00e1 th\u1ec3.<\/u><\/p>\n

C\u00e2u <\/strong>23<\/strong>:<\/strong> Qu\u1ea7n th\u1ec3 ng\u1eabu ph\u1ed1i n\u00e0o sau \u0111\u00e2y \u0111\u00e3 \u0111\u1ea1t tr\u1ea1ng th\u00e1i c\u00e2n b\u1eb1ng di truy\u1ec1n?<\/p>\n

A. 0,25AA : 0,5Aa : 0,25aa.\u00a0 <\/u>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,3AA : 0,6Aa : 0,1aa.<\/p>\n

\n

C. 0,3AA : 0,5Aa : 0,2aa.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0,1AA : 0,5Aa : 0,4aa.<\/p>\n

C\u00e2u 24<\/strong>: <\/strong>B\u1ec7nh m\u00f9 m\u00e0u (do gen l\u1eb7n g\u00e2y n\u00ean) th\u01b0\u1eddng th\u1ea5y \u1edf nam \u00edt th\u1ea5y \u1edf n\u1eef v\u00ec nam gi\u1edbi<\/p>\n

A. ch\u1ec9 c\u1ea7n mang 1 gen g\u00e2y b\u1ec7nh \u0111\u00e3 bi\u1ec3u hi\u1ec7n, n\u1eef c\u1ea7n mang 2 gen l\u1eb7n m\u1edbi bi\u1ec3u hi\u1ec7n.<\/u><\/p>\n

B. c\u1ea7n mang 2 gen g\u00e2y b\u1ec7nh \u0111\u00e3 bi\u1ec3u hi\u1ec7n, n\u1eef c\u1ea7n mang 2 gen l\u1eb7n m\u1edbi bi\u1ec3u hi\u1ec7n.<\/p>\n

C. ch\u1ec9 c\u1ea7n mang 1 gen \u0111\u00e3 bi\u1ec3u hi\u1ec7n, n\u1eef c\u1ea7n mang 1 gen l\u1eb7n m\u1edbi bi\u1ec3u hi\u1ec7n.<\/p>\n

D. c\u1ea7n mang gen tr\u1ed9i \u0111\u00e3 bi\u1ec3u hi\u1ec7n, n\u1eef c\u1ea7n mang 2 gen l\u1eb7n m\u1edbi bi\u1ec3u hi\u1ec7n.<\/p>\n

C\u00e2u 25:<\/strong> Cho s\u01a1 \u0111\u00f4\u0300 pha\u0309 h\u00ea\u0323 sau:<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n

\u00a0\u00a0\u00a0 S\u01a1 \u0111\u1ed3 ph\u1ea3 h\u1ec7 tr\u00ean m\u00f4 t\u1ea3 s\u1ef1 di truy\u1ec1n c\u1ee7a m\u1ed9t b\u1ec7nh \u1edf ng\u01b0\u1eddi do m\u1ed9t trong hai alen c\u1ee7a m\u1ed9t gen quy \u0111\u1ecbnh. Bi\u1ebft r\u1eb1ng kh\u00f4ng x\u1ea3y ra \u0111\u1ed9t bi\u1ebfn \u1edf t\u1ea5t c\u1ea3 c\u00e1c c\u00e1 th\u1ec3 trong ph\u1ea3 h\u1ec7. Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang?<\/p>\n

A. C\u00f3 5 c\u00e1 th\u1ec3 \u1edf th\u1ebf h\u1ec7 th\u1ee9 II bi\u1ebft ch\u00ednh x\u00e1c ki\u1ec3u gen.<\/u><\/p>\n

B. X\u00e1c xu\u1ea5t c\u1eb7p v\u1ee3 ch\u1ed3ng \u1edf th\u1ebf h\u1ec7 th\u1ee9 III sinh \u0111\u01b0\u1ee3c ng\u01b0\u1eddi con th\u1ee9 2 l\u00e0 con g\u00e1i b\u1ecb b\u1ec7nh l\u00e0 50%<\/p>\n

C. C\u00f3 \u00edt nh\u1ea5t 4 c\u00e1 th\u1ebf ch\u01b0a bi\u1ebft ch\u00ednh x\u00e1c ki\u1ec3u gen<\/p>\n

D. Gen g\u00e2y b\u1ec7nh l\u00e0 gen l\u1eb7n, n\u1eb1m tr\u00ean NST gi\u1edbi t\u00ednh X.<\/p>\n

HD: <\/strong>B\u1ec7nh do gen l\u1eb7n n\u1eb1m tr\u00ean NST th\u01b0\u1eddng quy \u0111\u1ecbnh. Lo\u1ea1i ph\u01b0\u01a1ng \u00e1n D.<\/p>\n

\n

B. X\u00e1c xu\u1ea5t c\u1eb7p v\u1ee3 ch\u1ed3ng \u1edf th\u1ebf h\u1ec7 th\u1ee9 III sinh \u0111\u01b0\u1ee3c ng\u01b0\u1eddi con th\u1ee9 2 l\u00e0 con g\u00e1i b\u1ecb b\u1ec7nh l\u00e0 1\/2×1\/4 = 1\/8= 12.5%. Lo\u1ea1i ph\u01b0\u01a1ng \u00e1n B<\/p>\n

C. C\u00f3 \u00edt nh\u1ea5t 5 c\u00e1 th\u1ebf ch\u01b0a bi\u1ebft ch\u00ednh x\u00e1c ki\u1ec3u gen. Lo\u1ea1i ph\u01b0\u01a1ng \u00e1n C.<\/p>\n

C\u00e2u 26<\/strong>: <\/strong>\u00a0C\u01a1 quan t\u01b0\u01a1ng \u0111\u1ed3ng (c\u01a1 quan c\u00f9ng ngu\u1ed3n) l\u00e0<\/p>\n

A. nh\u1eefng c\u01a1 quan n\u1eb1m \u1edf v\u1ecb tr\u00ed t\u01b0\u01a1ng \u1ee9ng tr\u00ean c\u01a1 th\u1ec3, c\u00f3 ki\u1ec3u c\u1ea5u t\u1ea1o gi\u1ed1ng nhau.<\/p>\n

B. nh\u1eefng c\u01a1 quan \u0111\u01b0\u1ee3c b\u1eaft ngu\u1ed3n t\u1eeb m\u1ed9t c\u01a1 quan \u1edf c\u00f9ng lo\u00e0i t\u1ed5 ti\u00ean m\u1eb7c d\u1ea7u hi\u1ec7n t\u1ea1i c\u00e1c c\u01a1 quan n\u00e0y c\u00f3 th\u1ec3 th\u1ef1c hi\u1ec7n ch\u1ee9c n\u0103ng r\u1ea5t kh\u00e1c nhau.<\/u><\/p>\n

C. nh\u1eefng c\u01a1 quan n\u1eb1m \u1edf nh\u1eefng v\u1ecb tr\u00ed t\u01b0\u01a1ng \u1ee9ng tr\u00ean c\u01a1 th\u1ec3, c\u00f3 ngu\u1ed3n g\u1ed1c kh\u00e1c nhau trong qu\u00e1 tr\u00ecnh ph\u00e1t tri\u1ec3n ph\u00f4i cho n\u00ean c\u00f3 ki\u1ec3u c\u1ea5u t\u1ea1o gi\u1ed1ng nhau.<\/p>\n

D. nh\u1eefng c\u01a1 quan n\u1eb1m \u1edf nh\u1eefng v\u1ecb tr\u00ed kh\u00e1c nhau tr\u00ean c\u01a1 th\u1ec3, c\u00f3 c\u00f9ng ngu\u1ed3n g\u1ed1c trong qu\u00e1 tr\u00ecnh ph\u00e1t tri\u1ec3n ph\u00f4i.<\/p>\n

C\u00e2u 27<\/strong>: <\/strong>C\u00e1c c\u01a1 quan tho\u00e1i ho\u00e1 l\u00e0 c\u01a1 quan<\/p>\n

A. ph\u00e1t tri\u1ec3n kh\u00f4ng \u0111\u1ea7y \u0111\u1ee7 \u1edf c\u01a1 th\u1ec3 tr\u01b0\u1edfng th\u00e0nh.<\/u><\/p>\n

B. thay \u0111\u1ed5i c\u1ea5u t\u1ea1o ph\u00f9 h\u1ee3p v\u1edbi ch\u1ee9c n\u0103ng m\u1edbi<\/p>\n

C. thay \u0111\u1ed5i c\u1ea5u t\u1ea1o<\/p>\n

D. bi\u1ebfn m\u1ea5t ho\u00e0n to\u00e0n<\/p>\n

C\u00e2u 28<\/strong>: <\/strong>Theo \u0110acuyn, c\u01a1 ch\u1ebf ch\u1ee7 y\u1ebfu c\u1ee7a qu\u00e1 tr\u00ecnh ti\u1ebfn ho\u00e1 l\u00e0<\/p>\n

A c\u00e1c \u0111\u1eb7c t\u00ednh thu \u0111\u01b0\u1ee3c trong \u0111\u1eddi c\u00e1 th\u1ec3 d\u01b0\u1edbi t\u00e1c d\u1ee5ng c\u1ee7a ngo\u1ea1i c\u1ea3nh hay t\u1eadp qu\u00e1n ho\u1ea1t \u0111\u1ed9ng c\u1ee7a sinh v\u1eadt \u0111\u1ec1u di truy\u1ec1n.<\/p>\n

B. c\u00e1c bi\u1ebfn d\u1ecb nh\u1ecf, ri\u00eang r\u1ebd t\u00edch lu\u1ef9 th\u00e0nh nh\u1eefng sai kh\u00e1c l\u1edbn v\u00e0 ph\u1ed5 bi\u1ebfn d\u01b0\u1edbi t\u00e1c d\u1ee5ng c\u1ee7a CLTN<\/u><\/p>\n

C. sinh v\u1eadt bi\u1ebfn \u0111\u1ed5i d\u01b0\u1edbi t\u00e1c d\u1ee5ng tr\u1ef1c ti\u1ebfp ho\u1eb7c gi\u00e1n ti\u1ebfp c\u1ee7a \u0111i\u1ec1u ki\u1ec7n ngo\u1ea1i c\u1ea3nh.<\/p>\n

D. s\u1ef1 c\u1ee7ng c\u1ed1 ng\u1eabu nhi\u00ean c\u00e1c \u0111\u1ed9t bi\u1ebfn trung t\u00ednh kh\u00f4ng li\u00ean quan \u0111\u1ebfn ch\u1ecdn l\u1ecdc t\u1ef1 nhi\u00ean.<\/p>\n

C\u00e2u 29:<\/strong> Ph\u00e1t bi\u1ec3u n\u00e0o d\u01b0\u1edbi \u0111\u00e2y kh\u00f4ng thu\u1ed9c n\u1ed9i dung c\u1ee7a thuy\u1ebft \u0110acuyn?<\/p>\n

A. To\u00e0n b\u1ed9 sinh gi\u1edbi ng\u00e0y nay l\u00e0 k\u1ebft qu\u1ea3 c\u1ee7a qu\u00e1 tr\u00ecnh ti\u1ebfn ho\u00e1 t\u1eeb m\u1ed9t ngu\u1ed3n g\u1ed1c chung.<\/p>\n

B. Lo\u00e0i m\u1edbi \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh d\u1ea7n d\u1ea7n qua nhi\u1ec1u d\u1ea1ng trung gian d\u01b0\u1edbi t\u00e1c d\u1ee5ng c\u1ee7a ch\u1ecdn l\u1ecdc t\u1ef1 nhi\u00ean theo con \u0111\u01b0\u1eddng ph\u00e2n li t\u00ednh tr\u1ea1ng.<\/p>\n

C. Ch\u1ecdn l\u1ecdc t\u1ef1 nhi\u00ean t\u00e1c \u0111\u1ed9ng th\u00f4ng qua \u0111\u1eb7c t\u00ednh bi\u1ebfn d\u1ecb v\u00e0 di truy\u1ec1n l\u00e0 nh\u00e2n t\u1ed1 ch\u00ednh trong qu\u00e1 tr\u00ecnh h\u00ecnh th\u00e0nh \u0111\u1eb7c \u0111i\u1ec3m th\u00edch nghi tr\u00ean c\u01a1 th\u1ec3 sinh v\u1eadt.<\/p>\n

D. Ngo\u1ea1i c\u1ea3nh thay \u0111\u1ed5i ch\u1eadm ch\u1ea1p n\u00ean sinh v\u1eadt c\u00f3 kh\u1ea3 n\u0103ng ph\u1ea3n \u1ee9ng ph\u00f9 h\u1ee3p v\u00e0 kh\u00f4ng b\u1ecb \u0111\u00e0o th\u1ea3i.<\/u><\/p>\n

C\u00e2u 30<\/strong>: \u0110\u1eb7c \u0111i\u1ec3m n\u00e0o sau \u0111\u00e2y kh\u00f4ng c\u00f3 \u1edf k\u1ec9 \u0110\u1ec7 Tam?<\/p>\n

A. C\u00e2y h\u1ea1t k\u00edn ph\u00e1t tri\u1ec3n m\u1ea1nh.<\/p>\n

B. Chim v\u00e0 th\u00fa ph\u00e1t tri\u1ec3n m\u1ea1nh.<\/p>\n

C. Ph\u00e1t sinh c\u00e1c nh\u00f3m linh tr\u01b0\u1edfng.<\/p>\n

D. Xu\u1ea5t hi\u1ec7n lo\u00e0i ng\u01b0\u1eddi.<\/u><\/p>\n

C\u00e2u 31<\/strong>: Trong m\u1ed9t h\u1ec7 sinh th\u00e1i, chu\u1ed7i th\u1ee9c \u0103n n\u00e0o trong s\u1ed1 c\u00e1c chu\u1ed7i th\u1ee9c \u0103n sau cung c\u1ea5p sinh kh\u1ed1i c\u00f3 l\u01b0\u1ee3ng n\u0103ng l\u01b0\u1ee3ng cao nh\u1ea5t cho con ng\u01b0\u1eddi (sinh kh\u1ed1i c\u1ee7a th\u1ef1c v\u1eadt \u1edf c\u00e1c chu\u1ed7i l\u00e0 b\u1eb1ng nhau)?<\/p>\n

\u00a0A. Th\u1ef1c v\u1eadt\u00a0–>\u00a0d\u00ea\u00a0–>\u00a0ng\u01b0\u1eddi.<\/p>\n

B. Th\u1ef1c v\u1eadt\u00a0–>\u00a0ng\u01b0\u1eddi.<\/p>\n

\u00a0C. Th\u1ef1c v\u1eadt\u00a0–>\u00a0\u0111\u1ed9ng v\u1eadt ph\u00f9 du\u00a0–>\u00a0c\u00e1\u00a0–>ng\u01b0\u1eddi.<\/p>\n

D. Th\u1ef1c v\u1eadt\u00a0–>\u00a0c\u00e1\u00a0–>chim\u00a0–>\u00a0tr\u1ee9ng chim\u00a0–>\u00a0ng\u01b0\u1eddi.<\/u><\/p>\n

C\u00e2u 32<\/strong>: Nh\u1eefng \u0111\u1eb7c \u0111i\u1ec3m n\u00e0o c\u00f3 th\u1ec3 c\u00f3 \u1edf m\u1ed9t qu\u1ea7n th\u1ec3 sinh v\u1eadt?<\/p>\n

1. Qu\u1ea7n th\u1ec3 bao g\u1ed3m nhi\u1ec1u c\u00e1 th\u1ec3 sinh v\u1eadt.\u00a0\u00a0\u00a0 2. Qu\u1ea7n th\u1ec3 l\u00e0 t\u1eadp h\u1ee3p c\u1ee7a c\u00e1c c\u00e1 th\u1ec3 c\u00f9ng lo\u00e0i.\u00a0\u00a0 3. C\u00e1c c\u00e1 th\u1ec3 trong qu\u1ea7n th\u1ec3 c\u00f3 kh\u1ea3 n\u0103ng giao ph\u1ed1i v\u1edbi nhau.\u00a0 4. Qu\u1ea7n th\u1ec3 g\u1ed3m nhi\u1ec1u c\u00e1 th\u1ec3 c\u00f9ng lo\u00e0i ph\u00e2n b\u1ed1 \u1edf c\u00e1c n\u01a1i xa nhau. 5. C\u00e1c c\u00e1 th\u1ec3 trong qu\u1ea7n th\u1ec3 c\u00f3 ki\u1ec3u gen ho\u00e0n to\u00e0n gi\u1ed1ng nhau. 6. Qu\u1ea7n th\u1ec3 c\u00f3 th\u1ec3 c\u00f3 khu v\u1ef1c ph\u00e2n b\u1ed1 r\u1ed9ng, gi\u1edbi h\u1ea1n b\u1edfi c\u00e1c ch\u01b0\u1edbng ng\u1ea1i c\u1ee7a thi\u00ean nhi\u00ean nh\u01b0 s\u00f4ng, n\u00fai, eo bi\u1ec3n\u2026<\/p>\n

T\u1ed5 h\u1ee3p c\u00e2u \u0111\u00fang l\u00e0<\/p>\n

A. 1, 2, 3.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 2, 3, 6.<\/u> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 3, 4, 5. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 4, 5, 6.<\/p>\n

C\u00e2u 33:<\/strong> Ph\u00e2n b\u1ed1 theo nh\u00f3m (hay \u0111i\u1ec3m) l\u00e0<\/p>\n

A. d\u1ea1ng ph\u00e2n b\u1ed1 \u00edt ph\u1ed5 bi\u1ebfn, g\u1eb7p trong \u0111i\u1ec1u ki\u1ec7n m\u00f4i tr\u01b0\u1eddng kh\u00f4ng \u0111\u1ed3ng nh\u1ea5t, c\u00e1c c\u00e1 th\u1ec3 th\u00edch s\u1ed1ng t\u1ee5 h\u1ecdp v\u1edbi nhau.<\/p>\n

B. d\u1ea1ng ph\u00e2n b\u1ed1 r\u1ea5t ph\u1ed5 bi\u1ebfn, g\u1eb7p trong \u0111i\u1ec1u ki\u1ec7n m\u00f4i tr\u01b0\u1eddng kh\u00f4ng \u0111\u1ed3ng nh\u1ea5t, c\u00e1c c\u00e1 th\u1ec3 s\u1ed1ng t\u1ee5 h\u1ecdp v\u1edbi nhau \u1edf nh\u1eefng n\u01a1i c\u00f3 \u0111i\u1ec1u ki\u1ec7n t\u1ed1t nh\u1ea5t.<\/u><\/p>\n

C. d\u1ea1ng ph\u00e2n b\u1ed1 r\u1ea5t ph\u1ed5 bi\u1ebfn, g\u1eb7p trong \u0111i\u1ec1u ki\u1ec7n m\u00f4i tr\u01b0\u1eddng \u0111\u1ed3ng nh\u1ea5t, c\u00e1c c\u00e1 th\u1ec3 th\u00edch s\u1ed1ng t\u1ee5 h\u1ecdp v\u1edbi nhau.<\/p>\n

D. d\u1ea1ng ph\u00e2n b\u1ed1 r\u1ea5t ph\u1ed5 bi\u1ebfn, g\u1eb7p trong \u0111i\u1ec1u ki\u1ec7n m\u00f4i tr\u01b0\u1eddng kh\u00f4ng \u0111\u1ed3ng nh\u1ea5t, c\u00e1c c\u00e1 th\u1ec3 kh\u00f4ng th\u00edch s\u1ed1ng t\u1ee5 h\u1ecdp v\u1edbi nhau.<\/p>\n

C\u00e2u 34<\/strong>: \u0110i\u1ec1u n\u00e0o kh\u00f4ng ph\u1ea3i l\u00e0 nguy\u00ean nh\u00e2n khi k\u00edch th\u01b0\u1edbc xu\u1ed1ng d\u01b0\u1edbi m\u1ee9c t\u1ed1i thi\u1ec3u, qu\u1ea7n th\u1ec3 d\u1ec5 r\u01a1i v\u00e0o tr\u1ea1ng th\u00e1i suy gi\u1ea3m d\u1eabn t\u1edbi di\u1ec7t vong?<\/p>\n

A. S\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 c\u1ee7a qu\u1ea7n th\u1ec3 qu\u00e1 \u00edt, s\u1ef1 h\u1ed7 tr\u1ee3 gi\u1eefa c\u00e1c c\u00e1 th\u1ec3 b\u1ecb gi\u1ea3m, qu\u1ea7n th\u1ec3 kh\u00f4ng c\u00f3 kh\u1ea3 n\u0103ng ch\u1ed1ng ch\u1ecdi v\u1edbi nh\u1eefng thay \u0111\u1ed5i c\u1ee7a m\u00f4i tr\u01b0\u1eddng.<\/p>\n

B. Kh\u1ea3 n\u0103ng sinh s\u1ea3n suy gi\u1ea3m do c\u01a1 h\u1ed9i t\u00ecm g\u1eb7p c\u1ee7a c\u00e1c c\u00e1 th\u1ec3 \u0111\u1ef1c v\u1edbi c\u00e1c c\u00e1 th\u1ec3 c\u00e1i \u00edt.<\/p>\n

C. S\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 qu\u00e1 \u00edt n\u00ean s\u1ef1 giao ph\u1ed1i c\u1eadn huy\u1ebft th\u01b0\u1eddng x\u1ea3y ra, s\u1ebd d\u1eabn \u0111\u1ebfn suy tho\u00e1i qu\u1ea7n th\u1ec3.<\/p>\n

D. M\u1eadt \u0111\u1ed9 c\u00e1 th\u1ec3 b\u1ecb thay \u0111\u1ed5i, l\u00e0m gi\u1ea3m nhi\u1ec1u kh\u1ea3 n\u0103ng h\u1ed7 tr\u1ee3 v\u1ec1 m\u1eb7t dinh d\u01b0\u1ee1ng gi\u1eefa c\u00e1c c\u00e1 th\u1ec3 trong qu\u1ea7n th\u1ec3.<\/u><\/p>\n

C\u00e2u 35<\/strong>: Hi\u1ec7n t\u01b0\u1ee3ng kh\u1ed1ng ch\u1ebf sinh h\u1ecdc trong qu\u1ea7n x\u00e3 bi\u1ec3u hi\u1ec7n \u1edf<\/p>\n

A. s\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 trong qu\u1ea7n x\u00e3 lu\u00f4n \u0111\u01b0\u1ee3c kh\u1ed1ng ch\u1ebf \u1edf m\u1ee9c \u0111\u1ed9 cao ph\u00f9 h\u1ee3p v\u1edbi kh\u1ea3 n\u0103ng cung c\u1ea5p ngu\u1ed3n s\u1ed1ng c\u1ee7a m\u00f4i tr\u01b0\u1eddng.<\/p>\n

B. s\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 trong qu\u1ea7n x\u00e3 lu\u00f4n \u0111\u01b0\u1ee3c kh\u1ed1ng ch\u1ebf \u1edf m\u1ee9c \u0111\u1ed9 t\u1ed1i thi\u1ec3u ph\u00f9 h\u1ee3p v\u1edbi kh\u1ea3 n\u0103ng cung c\u1ea5p ngu\u1ed3n s\u1ed1ng c\u1ee7a m\u00f4i tr\u01b0\u1eddng.<\/p>\n

C. s\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 trong qu\u1ea7n x\u00e3 lu\u00f4n \u0111\u01b0\u1ee3c kh\u1ed1ng ch\u1ebf \u1edf m\u1ee9c \u0111\u1ed9 nh\u1ea5t \u0111\u1ecbnh (dao \u0111\u1ed9ng quanh v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng) do s\u1ef1 t\u00e1c \u0111\u1ed9ng c\u1ee7a c\u00e1c m\u1ed1i quan h\u1ec7 ho\u1eb7c h\u1ed7 tr\u1ee3 ho\u1eb7c \u0111\u1ed1i kh\u00e1ng gi\u1eefa c\u00e1c lo\u00e0i trong qu\u1ea7n x\u00e3.<\/u><\/p>\n

D. s\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 trong qu\u1ea7n x\u00e3 lu\u00f4n \u0111\u01b0\u1ee3c kh\u1ed1ng ch\u1ebf \u1edf m\u1ee9c \u0111\u1ed9 nh\u1ea5t \u0111\u1ecbnh g\u1ea7n ph\u00f9 h\u1ee3p v\u1edbi kh\u1ea3 n\u0103ng cung c\u1ea5p ngu\u1ed3n s\u1ed1ng c\u1ee7a m\u00f4i tr\u01b0\u1eddng.<\/p>\n

C\u00e2u <\/strong>36<\/strong>: Qu\u00e1 tr\u00ecnh di\u1ec5n th\u1ebf th\u1ee9 sinh t\u1ea1i r\u1eebng lim H\u1eefu L\u0169ng, t\u0129nh L\u1ea1ng S\u01a1n nh\u01b0 th\u1ebf n\u00e0o?<\/p>\n

\u00a0\u00a0A. R\u1eebng lim nguy\u00ean sinh b\u1ecb ch\u1eb7t h\u1ebft\u00a0–>\u00a0c\u00e2y g\u1ed7 nh\u1ecf v\u00e0 c\u00e2y b\u1ee5i\u00a0–>\u00a0r\u1eebng th\u01b0a c\u00e2y g\u1ed7 nh\u1ecf\u00a0–>\u00a0c\u00e2y b\u1ee5i v\u00e0 c\u1ecf chi\u1ebfm \u01b0u th\u1ebf\u00a0–>\u00a0Tr\u1ea3ng c\u1ecf.<\/p>\n

\u00a0 B. R\u1eebng lim nguy\u00ean sinh b\u1ecb ch\u1eb7t h\u1ebft\u00a0–>\u00a0r\u1eebng th\u01b0a c\u00e2y g\u1ed7 nh\u1ecf\u00a0–>c\u00e2y b\u1ee5i v\u00e0 c\u1ecf chi\u1ebfm \u01b0u th\u1ebf\u00a0–>c\u00e2y g\u1ed7 nh\u1ecf v\u00e0 c\u00e2y b\u1ee5i\u00a0–>Tr\u1ea3ng c\u1ecf.<\/p>\n

\u00a0C. R\u1eebng lim nguy\u00ean sinh b\u1ecb ch\u1eb7t h\u1ebft\u00a0–>c\u00e2y b\u1ee5i v\u00e0 c\u1ecf chi\u1ebfm \u01b0u th\u1ebf\u00a0–>r\u1eebng th\u01b0a c\u00e2y g\u1ed7 nh\u1ecf\u00a0–>c\u00e2y g\u1ed7 nh\u1ecf v\u00e0 c\u00e2y b\u1ee5i–>\u00a0Tr\u1ea3ng c\u1ecf.<\/p>\n

\u00a0\u00a0D. R\u1eebng lim nguy\u00ean sinh b\u1ecb ch\u1eb7t h\u1ebft\u00a0–>r\u1eebng th\u01b0a c\u00e2y g\u1ed7 nh\u1ecf\u00a0–>c\u00e2y g\u1ed7 nh\u1ecf v\u00e0 c\u00e2y b\u1ee5i\u00a0–>c\u00e2y b\u1ee5i v\u00e0 c\u1ecf chi\u1ebfm \u01b0u th\u1ebf\u00a0–>Tr\u1ea3ng c\u1ecf<\/u>.<\/p>\n

C\u00e2u 37<\/strong>: Trong m\u1ed9t h\u1ec7 sinh th\u00e1i, sinh kh\u1ed1i c\u1ee7a m\u1ed7i b\u1eadc dinh d\u01b0\u1ee1ng \u0111\u01b0\u1ee3c k\u00ed hi\u1ec7u b\u1eb1ng c\u00e1c ch\u1eef t\u1eeb A \u0111\u1ebfn E. Trong \u0111\u00f3:<\/p>\n

A = 500 kcal; C = 5000 kcal; D = 50 kcal; E = 5 kcal. X\u00e1c \u0111\u1ecbnh hi\u1ec7u su\u1ea5t n\u0103ng l\u01b0\u1ee3ng \u1edf\u00a0 b\u1eb7c cu\u1ed1i c\u00f9ng so v\u1edbi b\u1eadc n\u0103ng l\u01b0\u1ee3ng tr\u01b0\u1edbc \u0111\u00f3 l\u00e0 bao nhi\u00eau.<\/p>\n

A. 1\/100\u00a0\u00a0\u00a0\u00a0 B. 1\/10<\/u>\u00a0\u00a0 \u00a0\u00a0\u00a0C. 1\/1000\u00a0\u00a0 D. 5\/100<\/p>\n

C\u00e2u <\/strong>\u00a038<\/strong>: Chu tr\u00ecnh sinh \u0111\u1ecba ho\u00e1 l\u00e0<\/p>\n

A. chu tr\u00ecnh chuy\u1ec3n ho\u00e1 c\u00e1c ch\u1ea5t v\u00f4 c\u01a1 v\u00e0 h\u1eefu c\u01a1 trong t\u1ef1 nhi\u00ean, theo \u0111\u01b0\u1eddng t\u1eeb m\u00f4i tr\u01b0\u1eddng ngo\u00e0i truy\u1ec1n qua c\u00e1c b\u1eadc dinh d\u01b0\u1ee1ng, r\u1ed3i t\u1eeb \u0111\u00f3 truy\u1ec1n tr\u1edf l\u1ea1i m\u00f4i tr\u01b0\u1eddng.<\/p>\n

B. chu tr\u00ecnh chuy\u1ec3n ho\u00e1 c\u00e1c ch\u1ea5t v\u00f4 c\u01a1 v\u00e0 h\u1eefu c\u01a1 trong t\u1ef1 nhi\u00ean, theo \u0111\u01b0\u1eddng t\u1eeb m\u00f4i tr\u01b0\u1eddng ngo\u00e0i truy\u1ec1n v\u00e0o c\u01a1 th\u1ec3 sinh v\u1eadt, qua c\u00e1c b\u1eadc dinh d\u01b0\u1ee1ng, r\u1ed3i t\u1eeb c\u01a1 th\u1ec3 sinh v\u1eadt truy\u1ec1n tr\u1edf l\u1ea1i m\u00f4i tr\u01b0\u1eddng.<\/p>\n

C. chu tr\u00ecnh chuy\u1ec3n ho\u00e1 c\u00e1c ch\u1ea5t v\u00f4 c\u01a1 trong t\u1ef1 nhi\u00ean, theo \u0111\u01b0\u1eddng t\u1eeb m\u00f4i tr\u01b0\u1eddng ngo\u00e0i truy\u1ec1n v\u00e0o c\u01a1 th\u1ec3 sinh v\u1eadt, r\u1ed3i truy\u1ec1n tr\u1edf l\u1ea1i m\u00f4i tr\u01b0\u1eddng.<\/p>\n

D. chu tr\u00ecnh chuy\u1ec3n ho\u00e1 c\u00e1c ch\u1ea5t v\u00f4 c\u01a1 trong t\u1ef1 nhi\u00ean, theo \u0111\u01b0\u1eddng t\u1eeb m\u00f4i tr\u01b0\u1eddng ngo\u00e0i truy\u1ec1n v\u00e0o c\u01a1 th\u1ec3 sinh v\u1eadt, qua c\u00e1c b\u1eadc dinh d\u01b0\u1ee1ng, r\u1ed3i t\u1eeb c\u01a1 th\u1ec3 sinh v\u1eadt truy\u1ec1n tr\u1edf l\u1ea1i m\u00f4i tr\u01b0\u1eddng.<\/u><\/p>\n

C\u00e2u 39<\/strong>: \u0110\u1eb7c \u0111i\u1ec3m n\u00e0o sau \u0111\u00e2y kh\u00f4ng ph\u1ea3i c\u1ee7a qu\u1ea7n x\u00e3?<\/p>\n

A. Qu\u1ea7n x\u00e3 l\u00e0 m\u1ed9t t\u1eadp h\u1ee3p c\u00e1c qu\u1ea7n th\u1ec3 sinh v\u1eadt thu\u1ed9c nhi\u1ec1u lo\u00e0i kh\u00e1c nhau, c\u00f9ng s\u1ed1ng trong m\u1ed9t kho\u1ea3ng kh\u00f4ng gian nh\u1ea5t \u0111\u1ecbnh (g\u1ecdi l\u00e0 sinh c\u1ea3nh).<\/p>\n

B. Qu\u1ea7n x\u00e3 l\u00e0 m\u1ed9t t\u1eadp h\u1ee3p c\u00e1c qu\u1ea7n th\u1ec3 sinh v\u1eadt thu\u1ed9c c\u00f9ng m\u1ed9t lo\u00e0i, c\u00f9ng s\u1ed1ng trong m\u1ed9t kho\u1ea3ng kh\u00f4ng gian nh\u1ea5t \u0111\u1ecbnh (g\u1ecdi l\u00e0 sinh c\u1ea3nh).<\/u><\/p>\n

C. C\u00e1c sinh v\u1eadt trong qu\u1ea7n x\u00e3 th\u00edch nghi v\u1edbi m\u00f4i tr\u01b0\u1eddng s\u1ed1ng c\u1ee7a ch\u00fang.<\/p>\n

D. C\u00e1c sinh v\u1eadt trong qu\u1ea7n x\u00e3 c\u00f3 m\u1ed1i quan h\u1ec7 g\u1eafn b\u00f3 v\u1edbi nhau nh\u01b0 m\u1ed9t th\u1ec3 th\u1ed1ng nh\u1ea5t v\u00e0 do v\u1eady qu\u1ea7n x\u00e3 c\u00f3 c\u1ea5u tr\u00fac t\u01b0\u01a1ng \u0111\u1ed1i \u1ed5n \u0111\u1ecbnh.<\/p>\n

C\u00e2u 40<\/strong>: \u0110i\u1ec1u n\u00e0o kh\u00f4ng \u0111\u00fang \u0111\u1ed1i v\u1edbi s\u1ef1 bi\u1ebfn \u0111\u1ed9ng s\u1ed1 l\u01b0\u1ee3ng c\u00f3 t\u00ednh chu k\u00ec c\u1ee7a c\u00e1c lo\u00e0i \u1edf Vi\u1ec7t Nam?<\/p>\n

A. S\u00e2u h\u1ea1i xu\u1ea5t hi\u1ec7n nhi\u1ec1u v\u00e0o c\u00e1c m\u00f9a xu\u00e2n, h\u00e8.<\/p>\n

B. Chim cu g\u00e1y th\u01b0\u1eddng xu\u1ea5t hi\u1ec7n nhi\u1ec1u v\u00e0o th\u1eddi gian thu ho\u1ea1ch l\u00faa, ng\u00f4 h\u00e0ng n\u0103m.<\/p>\n

C. Mu\u1ed7i th\u01b0\u1eddng c\u00f3 nhi\u1ec1u khi th\u1eddi ti\u1ebft \u1ea5m \u00e1p v\u00e0 \u0111\u1ed9 \u1ea9m cao.<\/p>\n

D. \u1ebech nh\u00e1i c\u00f3 nhi\u1ec1u v\u00e0o m\u00f9a kh\u00f4.<\/u><\/p>\n

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Tr\u01b0\u01a1\u0300ng THPT Nguy\u00ea\u0303n Tr\u01b0\u01a1\u0300ng T\u00f4\u0323 t\u00f4\u0309 ch\u01b0\u0301c ky\u0300 thi th\u01b0\u0309 m\u00f4n Sinh n\u0103m 2017 cho ca\u0301c em ho\u0323c sinh l\u01a1\u0301p 12, ca\u0301c em theo do\u0303i \u0111\u00ea\u0300 thi va\u0300 \u0111a\u0301p a\u0301n b\u00ean d\u01b0\u01a1\u0301i \u0111\u00e2y: S\u1ede GI\u00c1O D\u1ee4C V\u00c0 \u0110\u00c0O T\u1ea0O B\u00ccNH \u0110\u1ecaNH\u00a0\u00a0 \u00a0 \u00a0 \u00a0 TR\u01af\u1edcNG THPT NGUY\u1ec4N TR\u01af\u1edcNG T\u1ed8\u00a0 \u0110\u1ec0 THI TH\u1eec THPT QU\u1ed0C GIA […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[129],"tags":[],"yoast_head":"\n