\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n 2016 tr\u01b0\u1eddng THPT L\u01b0\u01a1ng Ng\u1ecdc Quy\u1ebfn th\u00e0nh ph\u1ed1 Th\u00e1i Nguy\u00ean c\u00e1c em tham kh\u1ea3o chi ti\u1ebft b\u00ean d\u01b0\u1edbi<\/p>\n
C\u00e2u 3 ( 2 \u0111i\u1ec3m)<\/strong><\/p>\n Cho h\u00e0m s\u1ed1 y = f(x) = x3<\/sup> \u2013 2x2<\/sup> + mx \u2013 3<\/p>\n a)\u00a0\u00a0\u00a0\u00a0 V\u1edbi m =1 vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 t\u1ea1i \u0111i\u1ec3m A(0;-3)<\/p>\n b)\u00a0\u00a0\u00a0 T\u00ecm m \u0111\u1ec3 f\u2019(x)\u00a00 v\u1edbi m\u1ecdi x thu\u1ed9c R<\/p>\n C\u00e2u 4 (3 \u0111i\u1ec3m)<\/strong><\/p>\n Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh vu\u00f4ng c\u1ea1nh a, hai m\u1eb7t ph\u1eb3ng (SAB) v\u00e0 (SAC) c\u00f9ng vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (ABCD) , SA=2a<\/p>\n a)\u00a0\u00a0\u00a0\u00a0 Ch\u1ee9ng minh\u00a0 SA vu\u00f4ng g\u00f3c v\u1edbi (ABCD)<\/p>\n b)\u00a0\u00a0\u00a0 Ch\u1ee9ng minh (SAC) vu\u00f4ng g\u00f3c v\u1edbi (SBD)<\/p>\n c)\u00a0\u00a0\u00a0\u00a0 T\u00ednh g\u00f3c gi\u1eefa \u0111\u01b0\u1eddng th\u1eb3ng SB v\u00e0 m\u1eb7t ph\u1eb3ng (SAD)<\/p>\n <\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n 2016 tr\u01b0\u1eddng THPT L\u01b0\u01a1ng Ng\u1ecdc Quy\u1ebfn th\u00e0nh ph\u1ed1 Th\u00e1i Nguy\u00ean c\u00e1c em tham kh\u1ea3o chi ti\u1ebft b\u00ean d\u01b0\u1edbi C\u00e2u 3 ( 2 \u0111i\u1ec3m) Cho h\u00e0m s\u1ed1 y = f(x) = x3 \u2013 2×2 + mx \u2013 3 a)\u00a0\u00a0\u00a0\u00a0 V\u1edbi m =1 vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[171],"tags":[],"yoast_head":"\n