\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n 2016 \u2013 THPT Phong Ch\u00e2u em tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n
B\u00e0i 4 (2 \u0111i\u1ec3m)<\/strong><\/p>\n Cho h\u00e0m s\u1ed1 y= – 1\/3 \u00a0x3<\/sup> \u00a0– x + 2\/3<\/p>\n a)\u00a0\u00a0\u00a0\u00a0 Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 ( C) t\u1ea1i \u0111i\u1ec3m A(0;2\/3)<\/p>\n b)\u00a0\u00a0\u00a0\u00a0 Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (C) bi\u1ebft ti\u1ebfp tuy\u1ebfn vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng (d): y = (-1\/3)x + 2\/3<\/p>\n <\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n 2016 \u2013 THPT Phong Ch\u00e2u em tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y: \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n 2016 \u2013 THPT Phong Ch\u00e2u B\u00e0i 4 (2 \u0111i\u1ec3m) Cho h\u00e0m s\u1ed1 y= – 1\/3 \u00a0x3 \u00a0– x + 2\/3 a)\u00a0\u00a0\u00a0\u00a0 Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[171],"tags":[],"yoast_head":"\n