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{"id":67,"date":"2016-02-10T02:44:56","date_gmt":"2016-02-10T02:44:56","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=67"},"modified":"2016-02-11T06:07:44","modified_gmt":"2016-02-11T06:07:44","slug":"de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/","title":{"rendered":"\u0110\u1ec1 thi minh h\u1ecda (k\u00e8m \u0111\u00e1p \u00e1n) M\u00f4n V\u1eadt l\u00fd k\u1ef3 thi THPT Qu\u1ed1c gia n\u0103m 2015"},"content":{"rendered":"

D\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0111\u1ec1 thi minh h\u1ecda K\u1ef3 thi th\u1eed THPT qu\u1ed1c gia M\u00f4n V\u1eadt l\u00fd ch\u00ednh th\u1ee9c n\u0103m 2015 c\u1ee7a B\u1ed9 gi\u00e1o d\u1ee5c. Ch\u00fac c\u00e1c b\u1ea1n h\u1ecdc sinh \u00f4n t\u1eadp th\u1eadt t\u1ed1t \u0111\u1ec3 chu\u1ea9n b\u1ecb cho k\u1ef3 thi quan tr\u1ecdng n\u00e0y!<\/em><\/strong><\/p>\n

Cho bi\u1ebft h\u1eb1ng s\u1ed1 Pl\u0103ng h = 6,625.10\u2212<\/sup>34 <\/sup>J.s; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng trong ch\u00e2n kh\u00f4ng c = 3.108 <\/sup>m\/s.<\/p>\n

C\u00e2u 1: <\/strong>M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng tr\u00ecnh x = 4cos\u03c9t (x t\u00ednh b\u1eb1ng cm). Ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9<\/p>\n

A. <\/strong> 8 cm. B. <\/strong>4 cm. C. <\/strong>2 cm. D. <\/strong>1 cm.<\/p>\n

C\u00e2u 2:<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m l\u00f2 xo nh\u1eb9 c\u00f3 \u0111\u1ed9 c\u1ee9ng k v\u00e0 v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng m. Cho con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng ngang. Chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00e0:
\n\"Vat<\/a><\/p>\n

C\u00e2u 3: <\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng t\u1eaft d\u1ea7n c\u00f3 c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng gi\u1ea3m li\u00ean t\u1ee5c theo th\u1eddi gian l\u00e0<\/p>\n

A.<\/strong> bi\u00ean \u0111\u1ed9 v\u00e0 n\u0103ng l\u01b0\u1ee3ng. B. <\/strong>li \u0111\u1ed9 v\u00e0 t\u1ed1c \u0111\u1ed9.<\/p>\n

C.<\/strong> bi\u00ean \u0111\u1ed9 v\u00e0 t\u1ed1c \u0111\u1ed9. D. <\/strong>bi\u00ean \u0111\u1ed9 v\u00e0 gia t\u1ed1c.<\/p>\n

C\u00e2u 4: <\/strong>Dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc \u0111\u1ed3ng h\u1ed3 l\u00e0<\/p>\n

A.<\/strong>dao \u0111\u1ed9ng \u0111i\u1ec7n t\u1eeb. B. <\/strong>dao \u0111\u1ed9ng t\u1eaft d\u1ea7n.<\/p>\n

C.<\/strong> dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c. D. <\/strong>dao \u0111\u1ed9ng duy tr\u00ec.<\/p>\n

C\u00e2u 5: <\/strong>M\u1ed9t v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng 100 g dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng tr\u00ecnh x = 10cos6t (x t\u00ednh b\u1eb1ng cm, t t\u00ednh b\u1eb1ng s). C\u01a1 n\u0103ng dao \u0111\u1ed9ng c\u1ee7a v\u1eadt n\u00e0y b\u1eb1ng<\/p>\n

A. <\/strong>36 mJ. B.<\/strong>18 mJ. C. <\/strong>18 J. D. <\/strong>36 J.<\/p>\n

C\u00e2u 6: <\/strong>Hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1, l\u1ec7ch pha nhau 0,5\u03c0, c\u00f3 bi\u00ean \u0111\u1ed9 l\u1ea7n l\u01b0\u1ee3t l\u00e0 8 cm v\u00e0 15 cm. Dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a hai dao \u0111\u1ed9ng n\u00e0y c\u00f3 bi\u00ean \u0111\u1ed9 b\u1eb1ng<\/p>\n

A. <\/strong>23 cm. B. <\/strong>7 cm. C.<\/strong>11 cm. D. <\/strong>17 cm.<\/p>\n

C\u00e2u 7:<\/strong> M\u1ed9t con l\u1eafc \u0111\u01a1n \u0111ang dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 v\u1edbi bi\u00ean \u0111\u1ed9 g\u00f3c \u03b10<\/sub>. Bi\u1ebft l\u1ef1c c\u0103ng d\u00e2y c\u00f3 gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t b\u1eb1ng 1,02 l\u1ea7n gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t. Gi\u00e1 tr\u1ecb c\u1ee7a \u03b10 <\/sub>l\u00e0<\/p>\n

A. <\/strong>6,6o<\/sup>. B.<\/strong> 3,3o<\/sup>. C.<\/strong> 9,6o<\/sup>. D.<\/strong> 5,6o<\/sup>.<\/p>\n

C\u00e2u 8:<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng v\u1edbi chu k\u00ec v\u00e0 bi\u00ean \u0111\u1ed9 l\u1ea7n l\u01b0\u1ee3t l\u00e0 0,4 s v\u00e0 8 cm. Ch\u1ecdn tr\u1ee5c x\u2019x th\u1eb3ng \u0111\u1ee9ng, chi\u1ec1u d\u01b0\u01a1ng h\u01b0\u1edbng xu\u1ed1ng, g\u1ed1c t\u1ecda \u0111\u1ed9 t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, g\u1ed1c th\u1eddi gian (t = 0) khi v\u1eadt qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng theo chi\u1ec1u d\u01b0\u01a1ng. L\u1ea5y gia t\u1ed1c r\u01a1i t\u1ef1 do g = 10 m\/s2<\/sup> v\u00e0 \u03c02<\/sup> = 10. Th\u1eddi gian ng\u1eafn nh\u1ea5t k\u1ec3 t\u1eeb khi t = 0 \u0111\u1ebfn khi l\u1ef1c \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c ti\u1ec3u l\u00e0<\/p>\n

\"Vat<\/a><\/p>\n

C\u00e2u 9:<\/strong> Hai con l\u1eafc \u0111\u01a1n c\u00f3 chi\u1ec1u d\u00e0i l\u1ea7n l\u01b0\u1ee3t l\u00e0 81 cm v\u00e0 64 cm \u0111\u01b0\u1ee3c treo \u1edf tr\u1ea7n m\u1ed9t c\u0103n ph\u00f2ng, t\u1ea1i n\u01a1i c\u00f3 g = 10 m\/s2<\/sup>. Khi c\u00e1c v\u1eadt nh\u1ecf c\u1ee7a hai con l\u1eafc \u0111ang \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, \u0111\u1ed3ng th\u1eddi truy\u1ec1n cho ch\u00fang c\u00e1c v\u1eadn t\u1ed1c c\u00f9ng h\u01b0\u1edbng sao cho hai con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi c\u00f9ng bi\u00ean \u0111\u1ed9 g\u00f3c, trong hai m\u1eb7t ph\u1eb3ng song song v\u1edbi nhau. G\u1ecdi \u2206t l\u00e0 kho\u1ea3ng th\u1eddi gian ng\u1eafn nh\u1ea5t k\u1ec3 t\u1eeb l\u00fac truy\u1ec1n v\u1eadn t\u1ed1c \u0111\u1ebfn l\u00fac hai d\u00e2y treo song song nhau. Gi\u00e1 tr\u1ecb \u2206t g<\/strong>\u1ea7n gi\u00e1 tr<\/strong>\u1ecb n\u00e0o nh<\/strong>\u1ea5t <\/strong>sau \u0111\u00e2y?<\/p>\n

A.<\/strong> 8,12 s. B. <\/strong>2,36 s. C. <\/strong>7,20 s. D. <\/strong>0,45 s.<\/p>\n

C\u00e2u 10:<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng 0,02 kg v\u00e0 l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng 1 N\/m. V\u1eadt nh\u1ecf \u0111\u01b0\u1ee3c \u0111\u1eb7t tr\u00ean gi\u00e1 \u0111\u1ee1 c\u1ed1 \u0111\u1ecbnh n\u1eb1m ngang d\u1ecdc theo tr\u1ee5c l\u00f2 xo. H\u1ec7 s\u1ed1 ma s\u00e1t tr\u01b0\u1ee3t gi\u1eefa gi\u00e1 \u0111\u1ee1 v\u00e0 v\u1eadt nh\u1ecf l\u00e0 0,1. Ban \u0111\u1ea7u gi\u1eef v\u1eadt \u1edf v\u1ecb tr\u00ed l\u00f2 xo b\u1ecb n\u00e9n 10 cm r\u1ed3i bu\u00f4ng nh\u1eb9 \u0111\u1ec3 con l\u1eafc dao \u0111\u1ed9ng t\u1eaft d\u1ea7n. L\u1ea5y g = 10 m\/s2<\/sup>. T\u1ed1c \u0111\u1ed9 l\u1edbn nh\u1ea5t v\u1eadt nh\u1ecf \u0111\u1ea1t \u0111\u01b0\u1ee3c trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng l\u00e0<\/p>\n

A.<\/strong> 40 3 cm\/s. B. <\/strong>20 6 cm\/s. C. <\/strong>10 30cm\/s. D.<\/strong>40 2 cm\/s.<\/p>\n

C\u00e2u 11: <\/strong>Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang khi n\u00f3i v\u1ec1 s\u00f3ng c\u01a1?<\/p>\n

    \n
  1. B\u01b0\u1edbc s\u00f3ng l\u00e0 kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111i\u1ec3m g\u1ea7n nhau nh\u1ea5t tr\u00ean c\u00f9ng m\u1ed9t ph\u01b0\u01a1ng truy\u1ec1n s\u00f3ng m\u00e0 dao \u0111\u1ed9ng t\u1ea1i hai \u0111i\u1ec3m \u0111\u00f3 c\u00f9ng pha.<\/li>\n
  2. S\u00f3ng c\u01a1 truy\u1ec1n trong ch\u1ea5t l\u1ecfng lu\u00f4n l\u00e0 s\u00f3ng ngang.<\/li>\n
  3. S\u00f3ng c\u01a1 truy\u1ec1n trong ch\u1ea5t r\u1eafn lu\u00f4n l\u00e0 s\u00f3ng d\u1ecd<\/li>\n
  4. B\u01b0\u1edbc s\u00f3ng l\u00e0 kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111i\u1ec3m tr\u00ean c\u00f9ng m\u1ed9t ph\u01b0\u01a1ng truy\u1ec1n s\u00f3ng m\u00e0 dao \u0111\u1ed9ng t\u1ea1i hai \u0111i\u1ec3m \u0111\u00f3 c\u00f9ng pha.<\/li>\n<\/ol>\n

    C\u00e2u 12:<\/strong> Hai \u00e2m c\u00f9ng \u0111\u1ed9 cao l\u00e0 hai \u00e2m c\u00f3 c\u00f9ng<\/p>\n

    A.<\/strong> c\u01b0\u1eddng \u0111\u1ed9 \u00e2m. B. <\/strong>m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m. C. <\/strong>bi\u00ean \u0111\u1ed9. D. <\/strong>t\u1ea7n s\u1ed1.<\/p>\n

    C\u00e2u 13:<\/strong> M\u1ed9t thi\u1ebft b\u1ecb t\u1ea1o ra s\u00f3ng h\u00ecnh sin truy\u1ec1n trong m\u1ed9t m\u00f4i tr\u01b0\u1eddng, theo ph\u01b0\u01a1ng Ox t\u1eeb ngu\u1ed3n O v\u1edbi t\u1ea7n s\u1ed1 20 Hz v\u00e0 t\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng n\u1eb1m trong kho\u1ea3ng t\u1eeb 0,7 m\/s \u0111\u1ebfn 1 m\/s. G\u1ecdi A v\u00e0 B l\u00e0 hai \u0111i\u1ec3m thu\u1ed9c Ox, \u1edf c\u00f9ng m\u1ed9t ph\u00eda so v\u1edbi O v\u00e0 c\u00e1ch nhau 10 cm. Hai ph\u1ea7n t\u1eed m\u00f4i tr\u01b0\u1eddng t\u1ea1i A v\u00e0 B lu\u00f4n dao \u0111\u1ed9ng ng\u01b0\u1ee3c pha v\u1edbi nhau. T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng l\u00e0<\/p>\n

    A<\/strong>.90 cm\/s. B. <\/strong>80 cm\/s. C. <\/strong>85 cm\/s. D. <\/strong>100 cm\/s.<\/p>\n

    C\u00e2u 14:<\/strong> M\u1ed9t ngu\u1ed3n \u0111i\u1ec3m O ph\u00e1t s\u00f3ng \u00e2m c\u00f3 c\u00f4ng su\u1ea5t kh\u00f4ng \u0111\u1ed5i trong m\u1ed9t m\u00f4i tr\u01b0\u1eddng truy\u1ec1n \u00e2m xem nh\u01b0 \u0111\u1eb3ng h\u01b0\u1edbng v\u00e0 kh\u00f4ng h\u1ea5p th\u1ee5 \u00e2m. Hai \u0111i\u1ec3m A, B c\u00e1ch ngu\u1ed3n \u00e2m l\u1ea7n l\u01b0\u1ee3t l\u00e0 r1<\/sub> v\u00e0 r2<\/sub>. Bi\u1ebft c\u01b0\u1eddng \u0111\u1ed9 r2<\/sup><\/u> b\u1eb1ng \u00e2m t\u1ea1i A g\u1ea5p 4 l\u1ea7n c\u01b0\u1eddng \u0111\u1ed9 \u00e2m t\u1ea1i B. T\u1ec9 s\u1ed1<\/p>\n

    \"Vat<\/a><\/p>\n

    C\u00e2u 15:<\/strong> M\u1ed9t h\u1ecdc sinh l\u00e0m th\u1ef1c h\u00e0nh t\u1ea1o ra \u1edf m\u1eb7t ch\u1ea5t l\u1ecfng hai ngu\u1ed3n s\u00f3ng A, B c\u00e1ch nhau 18 cm, dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 uA <\/sub>= uB<\/sub> = acos50\u03c0t (t t\u00ednh b\u1eb1ng s). T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng \u1edf m\u1eb7t ch\u1ea5t l\u1ecfng l\u00e0 50 cm\/s. G\u1ecdi O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB, \u0111i\u1ec3m M \u1edf m\u1eb7t ch\u1ea5t l\u1ecfng n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng trung tr\u1ef1c c\u1ee7a AB v\u00e0 g\u1ea7n O nh\u1ea5t sao cho ph\u1ea7n t\u1eed ch\u1ea5t l\u1ecfng t\u1ea1i M dao \u0111\u1ed9ng c\u00f9ng pha v\u1edbi ph\u1ea7n t\u1eed ch\u1ea5t l\u1ecfng t\u1ea1i O.<\/p>\n

    Kho\u1ea3ng c\u00e1ch MO l\u00e0<\/p>\n

    A.<\/strong> 10 cm. B. <\/strong>2 cm. C. <\/strong>2 2 cm. D. <\/strong>2 10 cm.<\/p>\n

    C\u00e2u 16:<\/strong> Trong m\u1ed9t th\u00ed nghi\u1ec7m v\u1ec1 giao thoa s\u00f3ng n\u01b0\u1edbc, hai ngu\u1ed3n s\u00f3ng k\u1ebft h\u1ee3p O1<\/sub>v\u00e0 O2<\/sub> dao \u0111\u1ed9ng c\u00f9ng pha, c\u00f9ng bi\u00ean \u0111\u1ed9. Ch\u1ecdn h\u1ec7 t\u1ecda \u0111\u1ed9 vu\u00f4ng g\u00f3c xOy (thu\u1ed9c m\u1eb7t n\u01b0\u1edbc) v\u1edbi g\u1ed1c t\u1ecda \u0111\u1ed9 l\u00e0 v\u1ecb tr\u00ed \u0111\u1eb7t ngu\u1ed3n O1<\/sub> c\u00f2n ngu\u1ed3n O2<\/sub> n\u1eb1m tr\u00ean tr\u1ee5c Oy. Hai \u0111i\u1ec3m P v\u00e0 Q n\u1eb1m tr\u00ean Ox c\u00f3 OP = 4,5 cm v\u00e0 OQ = 8 cm. D\u1ecbch chuy\u1ec3n ngu\u1ed3n O2<\/sub> tr\u00ean tr\u1ee5c Oy \u0111\u1ebfn v\u1ecb tr\u00ed sao cho g\u00f3c c\u00f3 gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t th\u00ec ph\u1ea7n t\u1eed n\u01b0\u1edbc t\u1ea1i P kh\u00f4ng dao \u0111\u1ed9ng c\u00f2n ph\u1ea7n t\u1eed n\u01b0\u1edbc t\u1ea1i Q dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i. Bi\u1ebft gi\u1eefa P v\u00e0 Q kh\u00f4ng c\u00f2n c\u1ef1c \u0111\u1ea1i n\u00e0o kh\u00e1c. Tr\u00ean \u0111o\u1ea1n OP, \u0111i\u1ec3m g\u1ea7n P nh\u1ea5t m\u00e0 c\u00e1c ph\u1ea7n t\u1eed n\u01b0\u1edbc dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i c\u00e1ch P m\u1ed9t \u0111o\u1ea1n l\u00e0<\/p>\n

    A<\/strong>. 3,4 cm. B. <\/strong>2,0 cm. C. <\/strong>2,5 cm. D. <\/strong>1,1 cm.<\/p>\n

    C\u00e2u 17:<\/strong> C\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u trong m\u1ed9t \u0111o\u1ea1n m\u1ea1ch l\u00e0 i = 2 2cos(100\u03c0t+)(A) (t t\u00ednh b\u1eb1ng s).<\/p>\n

    Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y \u0111\u00fang?<\/p>\n

      \n
    1. T\u1ea7n s\u1ed1 d\u00f2ng \u0111i\u1ec7n l\u00e0 100 Hz.<\/li>\n
    2. C\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n s\u1edbm pha so v\u1edbi \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1<\/li>\n
    3. C\u01b0\u1eddng \u0111\u1ed9 hi\u1ec7u d\u1ee5ng c\u1ee7a d\u00f2ng \u0111i\u1ec7n l\u00e0 2 A.<\/li>\n
    4. C\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n \u0111\u1ed5i chi\u1ec1u 50 l\u1ea7n trong m\u1ed9t gi\u00e2y.<\/li>\n<\/ol>\n

      C\u00e2u 18:<\/strong> \u0110\u1eb7t m\u1ed9t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u c\u00f3 gi\u00e1 tr\u1ecb hi\u1ec7u d\u1ee5ng U v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch RLC n\u1ed1i ti\u1ebfp, c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n trong \u0111o\u1ea1n m\u1ea1ch c\u00f3 gi\u00e1 tr\u1ecb hi\u1ec7u d\u1ee5ng l\u00e0 I v\u00e0 l\u1ec7ch pha so v\u1edbi \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch m\u1ed9t g\u00f3c \u03d5. C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 \u0111i\u1ec7n c\u1ee7a \u0111o\u1ea1n m\u1ea1ch l\u00e0<\/p>\n

      A.<\/strong> UI. B.<\/strong> UIsin\u03c6. C.<\/strong> UIcos\u03c6. D.<\/strong> UItan\u03c6.<\/p>\n

      C\u00e2u 19:<\/strong> M\u1ed9t tr\u1ea1m th\u1ee7y \u0111i\u1ec7n nh\u1ecf \u1edf x\u00e3 N\u00e0n Ma, huy\u1ec7n X\u00edn M\u1ea7n, t\u1ec9nh H\u00e0 Giang c\u00f3 m\u1ed9t m\u00e1y ph\u00e1t \u0111i\u1ec7n xoay chi\u1ec1u m\u1ed9t pha v\u1edbi r\u00f4to l\u00e0 nam ch\u00e2m c\u00f3 p c\u1eb7p c\u1ef1c. Khi r\u00f4to quay \u0111\u1ec1u v\u1edbi t\u1ed1c \u0111\u1ed9 n v\u00f2ng\/gi\u00e2y th\u00ec t\u1eeb th\u00f4ng qua m\u1ed7i cu\u1ed9n d\u00e2y c\u1ee7a stato bi\u1ebfn thi\u00ean tu\u1ea7n ho\u00e0n v\u1edbi t\u1ea7n s\u1ed1 bao nhi\u00eau Hz? \"Vat<\/a><\/p>\n

      C\u00e2u 20: <\/strong>\u0110o\u1ea1n m\u1ea1ch xoay chi\u1ec1u RLC n\u1ed1i ti\u1ebfp \u0111ang c\u00f3 dung kh\u00e1ng l\u1edbn h\u01a1n c\u1ea3m kh\u00e1ng. \u0110\u1ec3 c\u00f3 c\u1ed9ng h\u01b0\u1edfng \u0111i\u1ec7n th\u00ec c\u00f3 th\u1ec3<\/p>\n

      A.<\/strong> gi\u1ea3m \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 \u0111i\u1ec7n. B.<\/strong> gi\u1ea3m \u0111\u1ed9 t\u1ef1 c\u1ea3m c\u1ee7a cu\u1ed9n d\u00e2y.<\/p>\n

      C.<\/strong> t\u0103ng \u0111i\u1ec7n tr\u1edf \u0111o\u1ea1n m\u1ea1ch. D.<\/strong> t\u0103ng t\u1ea7n s\u1ed1 d\u00f2ng \u0111i\u1ec7n.<\/p>\n

      C\u00e2u 21:<\/strong> Cho \u0111o\u1ea1n m\u1ea1ch xoay chi\u1ec1u g\u1ed3m cu\u1ed9n d\u00e2y c\u00f3 \u0111i\u1ec7n tr\u1edf thu\u1ea7n R, m\u1eafc n\u1ed1i ti\u1ebfp v\u1edbi t\u1ee5 \u0111i\u1ec7n. Bi\u1ebft \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u cu\u1ed9n d\u00e2y l\u1ec7ch pha 0,5\u03c0 so v\u1edbi \u0111i\u1ec7n \u00e1p \u1edf hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch. M\u1ed1i li\u00ean h\u1ec7 gi\u1eefa \u0111i\u1ec7n tr\u1edf thu\u1ea7n R v\u1edbi c\u1ea3m kh\u00e1ng ZL<\/sub> c\u1ee7a cu\u1ed9n d\u00e2y v\u00e0 dung kh\u00e1ng ZC<\/sub> c\u1ee7a t\u1ee5 \u0111i\u1ec7n l\u00e0<\/p>\n

      A.<\/strong> R2<\/sup> = (ZL<\/sub> \u2013 ZC<\/sub>)ZL<\/sub>. B. <\/strong>R2<\/sup> = (ZL<\/sub> \u2013 ZC<\/sub>)ZC<\/sub>.<\/p>\n

      C.<\/strong> R2<\/sup> = (ZC<\/sub> \u2013 ZL<\/sub>)ZL<\/sub>. D. <\/strong>R2<\/sup> = (ZL<\/sub> + ZC<\/sub>)ZC<\/sub>.<\/p>\n

      C\u00e2u 22: <\/strong>\u0110\u1eb7t \u0111i\u1ec7n \u00e1p \"VL6\"<\/a>v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch ch\u1ec9 c\u00f3 t\u1ee5 \u0111i\u1ec7n th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n trong m\u1ea1ch l\u00e0 i = I0<\/sub>cos(100\u03c0t + \u03c6) (A). Gi\u00e1 tr\u1ecb c\u1ee7a \u03c6 b\u1eb1ng:<\/p>\n

      \"Vat<\/a><\/p>\n

      C\u00e2u 23:<\/strong> \u0110i\u1ec7n n\u0103ng \u0111\u01b0\u1ee3c truy\u1ec1n t\u1eeb n\u01a1i ph\u00e1t \u0111\u1ebfn m\u1ed9t khu d\u00e2n c\u01b0 b\u1eb1ng \u0111\u01b0\u1eddng d\u00e2y m\u1ed9t pha v\u1edbi hi\u1ec7u su\u1ea5t truy\u1ec1n t\u1ea3i l\u00e0 90%. Coi hao ph\u00ed \u0111i\u1ec7n n\u0103ng ch\u1ec9 do t\u1ecfa nhi\u1ec7t tr\u00ean \u0111\u01b0\u1eddng d\u00e2y v\u00e0 kh\u00f4ng v\u01b0\u1ee3t qu\u00e1 20%. N\u1ebfu c\u00f4ng su\u1ea5t s\u1eed d\u1ee5ng \u0111i\u1ec7n c\u1ee7a khu d\u00e2n c\u01b0 n\u00e0y t\u0103ng 20% v\u00e0 gi\u1eef nguy\u00ean \u0111i\u1ec7n \u00e1p \u1edf n\u01a1i ph\u00e1t th\u00ec hi\u1ec7u su\u1ea5t truy\u1ec1n t\u1ea3i \u0111i\u1ec7n n\u0103ng tr\u00ean ch\u00ednh \u0111\u01b0\u1eddng d\u00e2y \u0111\u00f3 l\u00e0<\/p>\n

      A.<\/strong> 85,8%. B. <\/strong>89,2%. C. <\/strong>87,7%. D. <\/strong>92,8%.<\/p>\n

      C\u00e2u 24: <\/strong>M\u1ed9t \u0111o\u1ea1n m\u1ea1ch AB g\u1ed3m cu\u1ed9n c\u1ea3m thu\u1ea7nc\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m L, \u0111i\u1ec7n tr\u1edf thu\u1ea7n R1<\/sub> = 100 \u2126, t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C v\u00e0 \u0111i\u1ec7n tr\u1edf thu\u1ea7n R2<\/sub> =100 \u2126 m\u1eafc n\u1ed1i ti\u1ebfp theo \u0111\u00fang th\u1ee9 t\u1ef1 tr\u00ean. G\u1ecdi M l\u00e0 \u0111i\u1ec3m n\u1ed1i gi\u1eefa R1<\/sub> v\u00e0 t\u1ee5 \u0111i\u1ec7n C. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch AB \u0111i\u1ec7n \u00e1p u = 200 cos\u03c9t (V). Khi m\u1eafc ampe k\u1ebf c\u00f3 \u0111i\u1ec7n tr\u1edf r\u1ea5t nh\u1ecf v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch MB th\u00ec ampe k\u1ebf ch\u1ec9 1A. Khi thay ampe k\u1ebf b\u1eb1ng m\u1ed9t v\u00f4n k\u1ebf c\u00f3 \u0111i\u1ec7n tr\u1edf r\u1ea5t l\u1edbn th\u00ec h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a \u0111o\u1ea1n m\u1ea1ch AB c\u1ef1c \u0111\u1ea1i. S\u1ed1 ch\u1ec9 c\u1ee7a v\u00f4n k\u1ebf khi \u0111\u00f3 l\u00e0:<\/p>\n

      \"vl<\/a><\/p>\n

      C\u00e2u 25: <\/strong>Trong gi\u1edd th\u1ef1c h\u00e0nh, m\u1ed9t h\u1ecdc sinh m\u1eafc \u0111o\u1ea1n m\u1ea1ch AB g\u1ed3m \u0111i\u1ec7n tr\u1edf thu\u1ea7n 40 \u2126, t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C thay \u0111\u1ed5i \u0111\u01b0\u1ee3c v\u00e0 cu\u1ed9n d\u00e2y c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m L n\u1ed1i ti\u1ebfp nhau theo \u0111\u00fang th\u1ee9 t\u1ef1 tr\u00ean. G\u1ecdi M l\u00e0 \u0111i\u1ec3m n\u1ed1i gi\u1eefa \u0111i\u1ec7n tr\u1edf thu\u1ea7n v\u00e0 t\u1ee5 \u0111i\u1ec7n. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch AB m\u1ed9t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u c\u00f3 gi\u00e1 tr\u1ecb hi\u1ec7u d\u1ee5ng 200V v\u00e0 t\u1ea7n s\u1ed1 50 Hz. Khi \u0111i\u1ec1u ch\u1ec9nh \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 \u0111i\u1ec7n \u0111\u1ebfn gi\u00e1 tr\u1ecb Cm<\/sub> th\u00ec \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch MB \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c ti\u1ec3u b\u1eb1ng 75 V. \u0110i\u1ec7n tr\u1edf thu\u1ea7n c\u1ee7a cu\u1ed9n d\u00e2y l\u00e0<\/p>\n

      A<\/strong> .24 \u2126. B.<\/strong> 16 \u2126. C.<\/strong> 30 \u2126. D.<\/strong> 40 \u2126.<\/p>\n

      C\u00e2u 26: <\/strong>\u0110\u1eb7t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u \u1ed5n \u0111\u1ecbnh v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch AB m\u1eafc n\u1ed1i ti\u1ebfp (h\u00ecnh v\u1ebd). Bi\u1ebft t\u1ee5 \u0111i\u1ec7n c\u00f3 dung kh\u00e1ng ZC<\/sub>, cu\u1ed9n c\u1ea3m thu\u1ea7n c\u00f3 c\u1ea3m kh\u00e1ng ZL <\/sub>v\u00e0 3ZL <\/sub>= 2ZC<\/sub>. \u0110\u1ed3 th\u1ecb bi\u1ec3u di\u1ec5n s\u1ef1 ph\u1ee5 thu\u1ed9c v\u00e0o th\u1eddi gian c\u1ee7a \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch AN v\u00e0 \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch MB nh\u01b0 h\u00ecnh v\u1ebd. \u0110i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111i\u1ec3mM v\u00e0 N l\u00e0:<\/p>\n

      \"VL7\"<\/a><\/strong><\/p>\n

      A.<\/strong> 173 V. B. <\/strong>122 V. C. <\/strong>86 V. D. <\/strong>102 V.
      \n      \"VL8\"<\/a><\/strong><\/p>\n

      A.<\/strong> 85 V. B.<\/strong> 145 V. C.<\/strong> 57 V. D.<\/strong> 173 V.<\/p>\n

      C\u00e2u 28: <\/strong>Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 sai<\/strong> khi n\u00f3i v\u1ec1 s\u00f3ng \u0111i\u1ec7n t\u1eeb?<\/p>\n

      A. Trong s\u00f3ng \u0111i\u1ec7n t\u1eeb, dao \u0111\u1ed9ng c\u1ee7a \u0111i\u1ec7n tr\u01b0\u1eddng v\u00e0 c\u1ee7a t\u1eeb tr\u01b0\u1eddng t\u1ea1i m\u1ed9t \u0111i\u1ec3m lu\u00f4n \u0111\u1ed3ng pha v\u1edbi nhau.<\/p>\n

      B. S\u00f3ng \u0111i\u1ec7n t\u1eeb l\u00e0 s\u00f3ng ngang n\u00ean n\u00f3 ch\u1ec9 truy\u1ec1n \u0111\u01b0\u1ee3c trong ch\u1ea5t r\u1eafn<\/p>\n

      C. Khi s\u00f3ng \u0111i\u1ec7n t\u1eeb g\u1eb7p m\u1eb7t ph\u00e2n c\u00e1ch gi\u1eefa hai m\u00f4i tr\u01b0\u1eddng th\u00ec n\u00f3 c\u00f3 th\u1ec3 b\u1ecb ph\u1ea3n x\u1ea1 v\u00e0 kh\u00fac x\u1ea1.<\/p>\n

      D. S\u00f3ng \u0111i\u1ec7n t\u1eeb truy\u1ec1n \u0111\u01b0\u1ee3c trong ch\u00e2n kh\u00f4ng.<\/p>\n

      C\u00e2u 29:<\/strong> \u1ede tr\u1ee5 s\u1edf Ban ch\u1ec9 huy qu\u00e2n s\u1ef1 huy\u1ec7n \u0111\u1ea3o Tr\u01b0\u1eddng Sa c\u00f3 m\u1ed9t m\u00e1y \u0111ang ph\u00e1t s\u00f3ng \u0111i\u1ec7n t\u1eeb. V\u00e0o th\u1eddi \u0111i\u1ec3m t, t\u1ea1i \u0111i\u1ec3m M tr\u00ean ph\u01b0\u01a1ng truy\u1ec1n theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng h\u01b0\u1edbng l\u00ean, vect\u01a1 c\u1ea3m \u1ee9ng t\u1eeb \u0111ang c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i v\u00e0 h\u01b0\u1edbng v\u1ec1 ph\u00eda Nam. Khi \u0111\u00f3, vect\u01a1 c\u01b0\u1eddng \u0111\u1ed9 \u0111i\u1ec7n tr\u01b0\u1eddng c\u00f3 \u0111\u1ed9 l\u1edbn<\/p>\n

      A.<\/strong> c\u1ef1c \u0111\u1ea1i v\u00e0 h\u01b0\u1edbng v\u1ec1 ph\u00eda T\u00e2y. B.<\/strong> c\u1ef1c \u0111\u1ea1i v\u00e0 h\u01b0\u1edbng v\u1ec1 ph\u00eda \u0110\u00f4ng.<\/p>\n

      C.<\/strong> c\u1ef1c \u0111\u1ea1i v\u00e0 h\u01b0\u1edbng v\u1ec1 ph\u00eda B\u1eafc. D.<\/strong> b\u1eb1ng kh\u00f4ng.<\/p>\n

      C\u00e2u 30: <\/strong>M\u1ed9t m\u1ea1ch dao \u0111\u1ed9ng LC l\u00ed t\u01b0\u1edfng g\u1ed3m t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung 18 nF v\u00e0 cu\u1ed9n c\u1ea3m thu\u1ea7n c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m 6 \u00b5H. Trong m\u1ea1ch \u0111ang c\u00f3 dao \u0111\u1ed9ng \u0111i\u1ec7n t\u1eeb v\u1edbi hi\u1ec7u \u0111i\u1ec7n th\u1ebf c\u1ef1c \u0111\u1ea1i gi\u1eefa hai b\u1ea3n t\u1ee5 \u0111i\u1ec7n l\u00e0 2,4 V. C\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n c\u1ef1c \u0111\u1ea1i trong m\u1ea1ch c\u00f3 gi\u00e1 tr\u1ecb l\u00e0<\/p>\n

      A<\/strong>.212,54 mA. B<\/strong>.65,73 mA. C. <\/strong>92,95 mA. D. <\/strong>131,45 mA.<\/p>\n

      C\u00e2u 31:<\/strong> Gi\u1ea3 s\u1eed m\u1ed9t v\u1ec7 tinh d\u00f9ng trong truy\u1ec1n th\u00f4ng \u0111ang \u0111\u1ee9ng y\u00ean so v\u1edbi m\u1eb7t \u0111\u1ea5t \u1edf m\u1ed9t \u0111\u1ed9 cao x\u00e1c \u0111\u1ecbnh trong m\u1eb7t ph\u1eb3ng X\u00edch \u0110\u1ea1o Tr\u00e1i \u0110\u1ea5t; \u0111\u01b0\u1eddng th\u1eb3ng n\u1ed1i v\u1ec7 tinh v\u1edbi t\u00e2m Tr\u00e1i \u0110\u1ea5t \u0111i qua kinh \u0111\u1ed9 s\u1ed1 0. Coi Tr\u00e1i \u0110\u1ea5t nh\u01b0 m\u1ed9t qu\u1ea3 c\u1ea7u, b\u00e1n k\u00ednh l\u00e0 6370 km, kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 6.1024<\/sup> kg v\u00e0 chu k\u1ef3 quay quanh tr\u1ee5c c\u1ee7a n\u00f3 l\u00e0 24 gi\u1edd; h\u1eb1ng s\u1ed1 h\u1ea5p d\u1eabn G = 6,67.10\u201311<\/sup> N.m2<\/sup>\/kg2<\/sup>. S\u00f3ng c\u1ef1c ng\u1eafn (f > 30 MHz) ph\u00e1t t\u1eeb v\u1ec7 tinh truy\u1ec1n th\u1eb3ng \u0111\u1ebfn c\u00e1c \u0111i\u1ec3m n\u1eb1m tr\u00ean X\u00edch \u0110\u1ea1o Tr\u00e1i \u0110\u1ea5t trong kho\u1ea3ng kinh \u0111\u1ed9 n\u00e0o n\u00eau d\u01b0\u1edbi \u0111\u00e2y?<\/p>\n

      A.<\/strong> T\u1eeb kinh \u0111\u1ed9 81o<\/sup>20\u2019\u0110 theo h\u01b0\u1edbng T\u00e2y \u0111\u1ebfn kinh \u0111\u1ed9 81o<\/sup>20\u2019T.<\/p>\n

      B.<\/strong> T\u1eeb kinh \u0111\u1ed9 81o<\/sup>20\u2019\u0110 theo h\u01b0\u1edbng \u0110\u00f4ng \u0111\u1ebfn kinh \u0111\u1ed9 81o<\/sup>20\u2019T.<\/p>\n

      C.<\/strong> T\u1eeb kinh \u0111\u1ed9 81o<\/sup>20\u2019T theo h\u01b0\u1edbng T\u00e2y \u0111\u1ebfn kinh \u0111\u1ed9 81o<\/sup>20\u2019\u0110.<\/p>\n

      D.<\/strong> T\u1eeb kinh \u0111\u1ed9 8o<\/sup>40\u2019 \u0110 theo h\u01b0\u1edbng T\u00e2y \u0111\u1ebfn kinh \u0111\u1ed9 8o<\/sup>40\u2019T.<\/p>\n

      C\u00e2u 32: <\/strong>Tia t\u1eed ngo\u1ea1i<\/p>\n

      A. <\/strong> c\u00f3 c\u00f9ng b\u1ea3n ch\u1ea5t v\u1edbi tia X. B.<\/strong> c\u00f3 t\u1ea7n s\u1ed1 nh\u1ecf h\u01a1n t\u1ea7n s\u1ed1 c\u1ee7a tia h\u1ed3ng ngo\u1ea1i.<\/p>\n

      C<\/strong> . mang \u0111i\u1ec7n t\u00edch \u00e2m. D.<\/strong> c\u00f3 c\u00f9ng b\u1ea3n ch\u1ea5t v\u1edbi s\u00f3ng \u00e2m.<\/p>\n

      C\u00e2u 33:<\/strong> Khi n\u00f3i v\u1ec1 tia h\u1ed3ng ngo\u1ea1i v\u00e0 tia t\u1eed ngo\u1ea1i, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y \u0111\u00fang?<\/p>\n

      A<\/strong>. Tia h\u1ed3ng ngo\u1ea1i v\u00e0 tia t\u1eed ngo\u1ea1i g\u00e2y ra hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n \u0111\u1ed1i v\u1edbi m\u1ecdi kim lo\u1ea1<\/p>\n

      B.<\/strong> T\u1ea7n s\u1ed1 c\u1ee7a tia h\u1ed3ng ngo\u1ea1i nh\u1ecf h\u01a1n t\u1ea7n s\u1ed1 c\u1ee7a tia t\u1eed ngo\u1ea1\\<\/p>\n

      C.<\/strong> Tia h\u1ed3ng ngo\u1ea1i v\u00e0 tia t\u1eed ngo\u1ea1i \u0111\u1ec1u l\u00e0m ion h\u00f3a m\u1ea1nh c\u00e1c ch\u1ea5t kh\u00ed.<\/p>\n

      D.<\/strong> M\u1ed9t v\u1eadt b\u1ecb nung n\u00f3ng ph\u00e1t ra tia t\u1eed ngo\u1ea1i, khi \u0111\u00f3 v\u1eadt kh\u00f4ng ph\u00e1t ra tia h\u1ed3ng ngo\u1ea1<\/p>\n

      C\u00e2u 34:<\/strong> Trong ch\u00e2n kh\u00f4ng, c\u00e1c b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng t\u0103ng d\u1ea7n theo th\u1ee9 t\u1ef1 \u0111\u00fang l\u00e0<\/p>\n

      A. <\/strong>tia gamma; tia X; tia t\u1eed ngo\u1ea1i; \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y; tia h\u1ed3ng ngo\u1ea1i v\u00e0 s\u00f3ng v\u00f4 tuy\u1ebfn.<\/p>\n

      B<\/strong>. \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y; tia t\u1eed ngo\u1ea1i; tia X; tia gamma; s\u00f3ng v\u00f4 tuy\u1ebfn v\u00e0 tia h\u1ed3ng ngo\u1ea1<\/p>\n

      C.<\/strong> tia h\u1ed3ng ngo\u1ea1i; \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y; tia t\u1eed ngo\u1ea1i; tia X; tia gamma v\u00e0 s\u00f3ng v\u00f4 tuy\u1ebf<\/p>\n

      D<\/strong>. s\u00f3ng v\u00f4 tuy\u1ebfn; tia h\u1ed3ng ngo\u1ea1i; \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y; tia t\u1eed ngo\u1ea1i; tia X v\u00e0 tia gamma.<\/p>\n

      C\u00e2u 35:<\/strong> Chi\u1ebfu t\u1eeb n\u01b0\u1edbc ra kh\u00f4ng kh\u00ed m\u1ed9t ch\u00f9m tia s\u00e1ng song song r\u1ea5t h\u1eb9p (coi nh\u01b0 m\u1ed9t tia s\u00e1ng) g\u1ed3m 5 th\u00e0nh ph\u1ea7n \u0111\u01a1n s\u1eafc: t\u00edm, lam, \u0111\u1ecf, l\u1ee5c, v\u00e0ng. Tia l\u00f3 \u0111\u01a1n s\u1eafc m\u00e0u l\u1ee5c \u0111i l\u00e0 l\u00e0 m\u1eb7t n\u01b0\u1edbc (s\u00e1t v\u1edbi m\u1eb7t ph\u00e2n c\u00e1ch gi\u1eefa hai m\u00f4i tr\u01b0\u1eddng). Kh\u00f4ng k\u1ec3 tia \u0111\u01a1n s\u1eafc m\u00e0u l\u1ee5c, l\u00f3 ra ngo\u00e0i kh\u00f4ng kh\u00ed l\u00e0 c\u00e1c tia \u0111\u01a1n s\u1eafc:<\/p>\n

      A.<\/strong> t\u00edm, lam, \u0111\u1ecf. B.<\/strong> \u0111\u1ecf, v\u00e0ng, lam. C.<\/strong> \u0111\u1ecf, v\u00e0ng. D.<\/strong> lam, t\u00edm.<\/p>\n

      C\u00e2u 36:<\/strong> Trong gi\u1edd h\u1ecdc th\u1ef1c h\u00e0nh, m\u1ed9t h\u1ecdc sinh l\u00e0m th\u00ed nghi\u1ec7m Y-\u00e2ng v\u1ec1 giao thoa \u00e1nh s\u00e1ng v\u1edbi kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe l\u00e0 0,5 mm v\u00e0 kho\u1ea3ng c\u00e1ch t\u1eeb m\u1eb7t ph\u1eb3ng ch\u1ee9a hai khe \u0111\u1ebfn m\u00e0n l\u00e0 2 m. \u00c1nh s\u00e1ng \u0111\u01a1n s\u1eafc d\u00f9ng trong th\u00ed nghi\u1ec7m c\u00f3 b\u01b0\u1edbc s\u00f3ng 0,5 \u00b5m. V\u00f9ng giao thoa tr\u00ean m\u00e0n r\u1ed9ng 26 mm (v\u00e2n trung t\u00e2m \u1edf ch\u00ednh gi\u1eefa). S\u1ed1 v\u00e2n s\u00e1ng quan s\u00e1t \u0111\u01b0\u1ee3c tr\u00ean m\u00e0n l\u00e0<\/p>\n

      A<\/strong>.15. B.<\/strong> 17. C.<\/strong> 13. D.<\/strong> 11.<\/p>\n

      C\u00e2u 37:<\/strong> Trong m\u1ed9t th\u00ed nghi\u1ec7m Y-\u00e2ng v\u1ec1 giao thoa \u00e1nh s\u00e1ng, ngu\u1ed3n s\u00e1ng ph\u00e1t \u0111\u1ed3ng th\u1eddi hai b\u1ee9c x\u1ea1 \u0111\u01a1n s\u1eafc, trong \u0111\u00f3 b\u1ee9c x\u1ea1 m\u00e0u \u0111\u1ecf c\u00f3 b\u01b0\u1edbc s\u00f3ng 720 nm v\u00e0 b\u1ee9c x\u1ea1 m\u00e0u l\u1ee5c c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb (c\u00f3 gi\u00e1 tr\u1ecb trong kho\u1ea3ng t\u1eeb 500 nm \u0111\u1ebfn 575 nm). Tr\u00ean m\u00e0n quan s\u00e1t, gi\u1eefa hai v\u00e2n s\u00e1ng g\u1ea7n nhau nh\u1ea5t v\u00e0 c\u00f9ng m\u00e0u v\u1edbi v\u00e2n s\u00e1ng trung t\u00e2m, c\u00f3 8 v\u00e2n s\u00e1ng m\u00e0u l\u1ee5c. Gi\u00e1 tr\u1ecb c\u1ee7a \u03bb l\u00e0<\/p>\n

      A<\/strong>.500 nm. B.<\/strong>520 nm. C.<\/strong> 540 nm. D.<\/strong> 560 nm.<\/p>\n

      C\u00e2u 38<\/strong>: Khi n\u00f3i v\u1ec1 ph\u00f4t\u00f4n, ph\u00e1t bi\u1ec3u n\u00e0o d\u01b0\u1edbi \u0111\u00e2y \u0111\u00fang?<\/p>\n

      A. <\/strong>Ph\u00f4t\u00f4n c\u00f3 th\u1ec3 t\u1ed3n t\u1ea1i trong tr\u1ea1ng th\u00e1i \u0111\u1ee9ng y\u00ean.<\/p>\n

      B<\/strong>. V\u1edbi m\u1ed7i \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc c\u00f3 t\u1ea7n s\u1ed1 f x\u00e1c \u0111\u1ecbnh, c\u00e1c ph\u00f4t\u00f4n \u0111\u1ec1u mang n\u0103ng l\u01b0\u1ee3ng nh\u01b0<\/p>\n

      C.<\/strong> N\u0103ng l\u01b0\u1ee3ng c\u1ee7a ph\u00f4t\u00f4n c\u00e0ng l\u1edbn khi b\u01b0\u1edbc s\u00f3ng \u00e1nh s\u00e1ng \u1ee9ng v\u1edbi ph\u00f4t\u00f4n \u0111\u00f3 c\u00e0ng l\u1edb<\/p>\n

      D.<\/strong> N\u0103ng l\u01b0\u1ee3ng c\u1ee7a ph\u00f4t\u00f4n \u00e1nh s\u00e1ng t\u00edm nh\u1ecf h\u01a1n n\u0103ng l\u01b0\u1ee3ng c\u1ee7a ph\u00f4t\u00f4n \u00e1nh s\u00e1ng \u0111\u1ecf.<\/p>\n

      C\u00e2u 39: <\/strong>Pin quang \u0111i\u1ec7n l\u00e0 ngu\u1ed3n \u0111i\u1ec7n, trong \u0111\u00f3<\/p>\n

      A.<\/strong> h\u00f3a n\u0103ng \u0111\u01b0\u1ee3c bi\u1ebfn \u0111\u1ed5i tr\u1ef1c ti\u1ebfp th\u00e0nh \u0111i\u1ec7n n\u0103ng<\/p>\n

      B.<\/strong> quang n\u0103ng \u0111\u01b0\u1ee3c bi\u1ebfn \u0111\u1ed5i tr\u1ef1c ti\u1ebfp th\u00e0nh \u0111i\u1ec7n n\u0103ng<\/p>\n

      C.<\/strong> c\u01a1 n\u0103ng \u0111\u01b0\u1ee3c bi\u1ebfn \u0111\u1ed5i tr\u1ef1c ti\u1ebfp th\u00e0nh \u0111i\u1ec7n n\u0103ng<\/p>\n

      D.<\/strong> nhi\u1ec7t n\u0103ng \u0111\u01b0\u1ee3c bi\u1ebfn \u0111\u1ed5i tr\u1ef1c ti\u1ebfp th\u00e0nh \u0111i\u1ec7n n\u0103ng<\/p>\n

      C\u00e2u 40:<\/strong> Hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n ngo\u00e0i l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng \u00ealectron b\u1ecb b\u1ee9t ra kh\u1ecfi t\u1ea5m kim lo\u1ea1i khi<\/p>\n

      A.<\/strong> chi\u1ebfu v\u00e0o t\u1ea5m kim lo\u1ea1i n\u00e0y m\u1ed9t ch\u00f9m h\u1ea1t nh\u00e2n heli.<\/p>\n

      B.<\/strong> chi\u1ebfu v\u00e0o t\u1ea5m kim lo\u1ea1i n\u00e0y m\u1ed9t b\u1ee9c x\u1ea1 \u0111i\u1ec7n t\u1eeb c\u00f3 b\u01b0\u1edbc s\u00f3ng th\u00edch h\u1ee3p<\/p>\n

      C.<\/strong> cho d\u00f2ng \u0111i\u1ec7n ch\u1ea1y qua t\u1ea5m kim lo\u1ea1i n\u00e0y.<\/p>\n

      D.<\/strong> t\u1ea5m kim lo\u1ea1i n\u00e0y b\u1ecb nung n\u00f3ng b\u1edfi m\u1ed9t ngu\u1ed3n nhi\u1ec7t<\/p>\n

      C\u00e2u 41:<\/strong> Theo m\u1eabu nguy\u00ean t\u1eed Bo, b\u00e1n k\u00ednh qu\u1ef9 \u0111\u1ea1o K c\u1ee7a \u00ealectron trong nguy\u00ean t\u1eed hi\u0111r\u00f4 l\u00e0 r0<\/sub>. Khi \u00ealectron chuy\u1ec3n t\u1eeb qu\u1ef9 \u0111\u1ea1o N v\u1ec1 qu\u1ef9 \u0111\u1ea1o L th\u00ec b\u00e1n k\u00ednh qu\u1ef9 \u0111\u1ea1o gi\u1ea3m b\u1edbt<\/p>\n

      A. <\/strong> 12r0<\/sub>. B.<\/strong> 4r0<\/sub>. C.<\/strong> 9r0<\/sub>. D.<\/strong> 16r0<\/sub>.<\/p>\n

      C\u00e2u 42:<\/strong> M\u1ed9t h\u1ecdc sinh l\u00e0m th\u1ef1c h\u00e0nh v\u1ec1 hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n b\u1eb1ng c\u00e1ch chi\u1ebfu b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng b\u1eb1ng \u03bb0<\/sub>\/3 v\u00e0o m\u1ed9t b\u1ea3n kim lo\u1ea1i c\u00f3 gi\u1edbi h\u1ea1n quang \u0111i\u1ec7n l\u00e0 \u03bb0<\/sub>. Cho r\u1eb1ng n\u0103ng l\u01b0\u1ee3ng m\u00e0 \u00ealectron quang \u0111i\u1ec7n h\u1ea5p th\u1ee5 t\u1eeb ph\u00f4t\u00f4n c\u1ee7a b\u1ee9c x\u1ea1 tr\u00ean, m\u1ed9t ph\u1ea7n d\u00f9ng \u0111\u1ec3 gi\u1ea3i ph\u00f3ng n\u00f3, ph\u1ea7n c\u00f2n l\u1ea1i bi\u1ebfn ho\u00e0n to\u00e0n th\u00e0nh \u0111\u1ed9ng n\u0103ng c\u1ee7a n\u00f3. Gi\u00e1 tr\u1ecb \u0111\u1ed9ng n\u0103ng n\u00e0y l\u00e0<\/p>\n

       <\/p>\n

      C\u00e2u 43:<\/strong> Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch<\/p>\n

      A.<\/strong> ch\u1ec9 x\u1ea3y ra \u1edf nhi\u1ec7t \u0111\u1ed9 r\u1ea5t cao c\u1ee1 h\u00e0ng ch\u1ee5c tri\u1ec7u \u0111\u1ed9.<\/p>\n

      B.<\/strong> l\u00e0 s\u1ef1 v\u1ee1 c\u1ee7a m\u1ed9t h\u1ea1t nh\u00e2n n\u1eb7ng th\u00e0nh hai h\u1ea1t nh\u00e2n nh\u1eb9 h\u01a1n<\/p>\n

      C.<\/strong> l\u00e0 ph\u1ea3n \u1ee9ng h\u1ea1t nh\u00e2n thu n\u0103ng l\u01b0\u1ee3ng<\/p>\n

      D.<\/strong> l\u00e0 ph\u1ea3n \u1ee9ng trong \u0111\u00f3 hai h\u1ea1t nh\u00e2n nh\u1eb9 t\u1ed5ng h\u1ee3p l\u1ea1i th\u00e0nh h\u1ea1t nh\u00e2n n\u1eb7ng h\u01a1<\/p>\n

      C\u00e2u 44:<\/strong> Ph\u00f3ng x\u1ea1 \u03b2\u2013<\/sup> l\u00e0<\/p>\n

      A.<\/strong> ph\u1ea3n \u1ee9ng h\u1ea1t nh\u00e2n thu n\u0103ng l\u01b0\u1ee3<\/p>\n

      B.<\/strong> ph\u1ea3n \u1ee9ng h\u1ea1t nh\u00e2n kh\u00f4ng thu v\u00e0 kh\u00f4ng to\u1ea3 n\u0103ng l\u01b0\u1ee3ng<\/p>\n

      C.<\/strong> s\u1ef1 gi\u1ea3i ph\u00f3ng \u00ealectron t\u1eeb l\u1edbp \u00ealectron ngo\u00e0i c\u00f9ng c\u1ee7a nguy\u00ean t\u1eed.<\/p>\n

      D.<\/strong> ph\u1ea3n \u1ee9ng h\u1ea1t nh\u00e2n to\u1ea3 n\u0103ng l\u01b0\u1ee3ng<\/p>\n

      C\u00e2u 45:<\/strong> M\u1ed9t m\u1eabu c\u00f3 N0<\/sub> h\u1ea1t nh\u00e2n c\u1ee7a ch\u1ea5t ph\u00f3ng x\u1ea1 X. Sau 1 chu k\u00ec b\u00e1n r\u00e3, s\u1ed1 h\u1ea1t nh\u00e2n X c\u00f2n l\u1ea1i l\u00e0<\/p>\n

      A. <\/strong>0,25 N0<\/sub>. B.<\/strong> 0,5 N0<\/sub>. C.<\/strong> 0,75 N0<\/sub>. D.<\/strong>N0<\/sub>.<\/p>\n

      C\u00e2u 46:<\/strong>Cho ph\u1ea3n \u1ee9ng h\u1ea1t nh\u00e2n 0<\/sub>1<\/sup>n + 235<\/sup>92<\/sub>U \u2192 94<\/sup>38<\/sub>Sr + +X 20<\/sub>1<\/sup>n.H\u1ea1t nh\u00e2n X c\u00f3 c\u1ea5u t\u1ea1o g\u1ed3m<\/p>\n

      A.<\/strong> 54 pr\u00f4t\u00f4n v\u00e0 86 n\u01a1tron. B. <\/strong>86 pr\u00f4t\u00f4n v\u00e0 54 n\u01a1tron.<\/p>\n

      C.<\/strong> 54 pr\u00f4t\u00f4n v\u00e0 140 n\u01a1tron. D. <\/strong>86 pr\u00f4t\u00f4n v\u00e0 140 n\u01a1tron.<\/p>\n

      C\u00e2u 47:<\/strong> M\u1ed9t l\u00f2 ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch c\u1ee7a nh\u00e0 m\u00e1y \u0111i\u1ec7n h\u1ea1t nh\u00e2n Ninh Thu\u1eadn c\u00f3 c\u00f4ng su\u1ea5t 200 MW. Cho r\u1eb1ng to\u00e0n b\u1ed9 n\u0103ng l\u01b0\u1ee3ng m\u00e0 l\u00f2 ph\u1ea3n \u1ee9ng n\u00e0y sinh ra \u0111\u1ec1u do s\u1ef1 ph\u00e2n h\u1ea1ch c\u1ee7a 235<\/sup>U v\u00e0 \u0111\u1ed3ng v\u1ecb n\u00e0y ch\u1ec9 b\u1ecb ti\u00eau hao b\u1edfi qu\u00e1 tr\u00ecnh ph\u00e2n h\u1ea1ch. Coi m\u1ed7i n\u0103m c\u00f3 365 ng\u00e0y; m\u1ed7i ph\u00e2n h\u1ea1ch sinh ra 200 MeV; s\u1ed1 A-v\u00f4ga-\u0111r\u00f4 NA<\/sub> = 6,02.1023<\/sup> mol\u20131<\/sup>. Kh\u1ed1i l\u01b0\u1ee3ng 235<\/sup>U m\u00e0 l\u00f2 ph\u1ea3n \u1ee9ng ti\u00eau th\u1ee5 trong 3 n\u0103m l\u00e0<\/p>\n

      A<\/strong>.461,6 kg. B. <\/strong>230,8 kg. C. <\/strong>230,8 g. D. <\/strong>461,6 g.<\/p>\n

      C\u00e2u 48: <\/strong>B\u1eafn h\u1ea1t pr\u00f4t\u00f4n v\u1edbi \u0111\u1ed9ng n\u0103ng KP<\/sub> = 1,46MeV v\u00e0o h\u1ea1t nh\u00e2n Li \u0111\u1ee9ng y\u00ean, t\u1ea1o ra hai h\u1ea1t nh\u00e2n gi\u1ed1ng nhau c\u00f3 c\u00f9ng kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 mX<\/sub> v\u00e0 c\u00f9ng \u0111\u1ed9ng n\u0103ng. Cho mLi<\/sub> = 7,0142u, mp<\/sub> = 1,0073u, mX<\/sub> = 4,0015u, 1u=931,5MeV\/c2<\/sup>. Hai h\u1ea1t sau ph\u1ea3n \u1ee9ng c\u00f3 vect\u01a1 v\u1eadn t\u1ed1c h\u1ee3p nhau m\u1ed9t g\u00f3c l\u00e0<\/p>\n

      A<\/strong>. 168o<\/sup>36\u2019. B.<\/strong> 48o<\/sup>18\u2019. C.<\/strong> 60o<\/sup>. D.<\/strong> 70o<\/sup>.<\/p>\n

      C\u00e2u 49: <\/strong>D\u00f9ng m\u1ed9t th\u01b0\u1edbc chia \u0111\u1ed9 \u0111\u1ebfn milimet \u0111o kho\u1ea3ng c\u00e1ch d gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 B, c\u1ea3 5 l\u1ea7n \u0111o \u0111\u1ec1u cho c\u00f9ng gi\u00e1 tr\u1ecb l\u00e0 1,345 m. L\u1ea5y sai s\u1ed1 d\u1ee5ng c\u1ee5 l\u00e0 m\u1ed9t \u0111\u1ed9 chia nh\u1ecf nh\u1ea5t. K\u1ebft qu\u1ea3 \u0111o \u0111\u01b0\u1ee3c vi\u1ebft l\u00e0<\/p>\n

      A.<\/strong> d = (1345 \u00b1 2) mm. B. <\/strong>d = (1,345 \u00b1 0,001) m.<\/p>\n

      C.<\/strong> d = (1345 \u00b1 3) mm. D. <\/strong>d = (1,3450 \u00b1 0,0005) m.<\/p>\n

      \"VL9\"<\/a><\/p>\n

       <\/p>\n

      \u0110\u00e1p \u00e1n \u0110\u1ec1 thi minh h\u1ecda THPT Qu\u1ed1c gia M\u00f4n V\u1eadt L\u00fd n\u0103m 2015 \u2013 B\u1ed9 gi\u00e1o d\u1ee5c<\/strong><\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
      C\u00e2u s<\/strong>\u1ed1<\/td>\n\u0110\u00e1p \u00e1n <\/strong><\/td>\nC\u00e2u s<\/strong>\u1ed1<\/td>\n\u0110\u00e1p \u00e1n <\/strong><\/td>\nC\u00e2u s<\/strong>\u1ed1<\/td>\n\u0110\u00e1p \u00e1n <\/strong><\/td>\n<\/tr>\n
      1<\/td>\nB<\/td>\n18<\/td>\nC<\/td>\n35<\/td>\nC<\/td>\n<\/tr>\n
      2<\/td>\nB<\/td>\n19<\/td>\nB<\/td>\n36<\/td>\nC<\/td>\n<\/tr>\n
      3<\/td>\nA<\/td>\n20<\/td>\nD<\/td>\n37<\/td>\nD<\/td>\n<\/tr>\n
      4<\/td>\nD<\/td>\n21<\/td>\nC<\/td>\n38<\/td>\nB<\/td>\n<\/tr>\n
      5<\/td>\nB<\/td>\n22<\/td>\nC<\/td>\n39<\/td>\nB<\/td>\n<\/tr>\n
      6<\/td>\nD<\/td>\n23<\/td>\nC<\/td>\n40<\/td>\nB<\/td>\n<\/tr>\n
      7<\/td>\nA<\/td>\n24<\/td>\nC<\/td>\n41<\/td>\nA<\/td>\n<\/tr>\n
      8<\/td>\nB<\/td>\n25<\/td>\nA<\/td>\n42<\/td>\nD<\/td>\n<\/tr>\n
      9<\/td>\nD<\/td>\n26<\/td>\nC<\/td>\n43<\/td>\nB<\/td>\n<\/tr>\n
      10<\/td>\nD<\/td>\n27<\/td>\nB<\/td>\n44<\/td>\nD<\/td>\n<\/tr>\n
      11<\/td>\nA<\/td>\n28<\/td>\nB<\/td>\n45<\/td>\nB<\/td>\n<\/tr>\n
      12<\/td>\nD<\/td>\n29<\/td>\nA<\/td>\n46<\/td>\nA<\/td>\n<\/tr>\n
      13<\/td>\nB<\/td>\n30<\/td>\nD<\/td>\n47<\/td>\nB<\/td>\n<\/tr>\n
      14<\/td>\nA<\/td>\n31<\/td>\nA<\/td>\n48<\/td>\nA<\/td>\n<\/tr>\n
      15<\/td>\nD<\/td>\n32<\/td>\nA<\/td>\n49<\/td>\nB<\/td>\n<\/tr>\n
      16<\/td>\nB<\/td>\n33<\/td>\nB<\/td>\n50<\/td>\nC<\/td>\n<\/tr>\n
      17<\/td>\nC<\/td>\n34<\/td>\nA<\/td>\n<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"

      D\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0111\u1ec1 thi minh h\u1ecda K\u1ef3 thi th\u1eed THPT qu\u1ed1c gia M\u00f4n V\u1eadt l\u00fd ch\u00ednh th\u1ee9c n\u0103m 2015 c\u1ee7a B\u1ed9 gi\u00e1o d\u1ee5c. Ch\u00fac c\u00e1c b\u1ea1n h\u1ecdc sinh \u00f4n t\u1eadp th\u1eadt t\u1ed1t \u0111\u1ec3 chu\u1ea9n b\u1ecb cho k\u1ef3 thi quan tr\u1ecdng n\u00e0y! Cho bi\u1ebft h\u1eb1ng s\u1ed1 Pl\u0103ng h = 6,625.10\u221234 J.s; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng […]<\/p>\n","protected":false},"author":1,"featured_media":6905,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[14,25],"tags":[],"yoast_head":"\n\u0110\u1ec1 thi minh h\u1ecda (k\u00e8m \u0111\u00e1p \u00e1n) M\u00f4n V\u1eadt l\u00fd k\u1ef3 thi THPT Qu\u1ed1c gia n\u0103m 2015<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 thi minh h\u1ecda (k\u00e8m \u0111\u00e1p \u00e1n) M\u00f4n V\u1eadt l\u00fd k\u1ef3 thi THPT Qu\u1ed1c gia n\u0103m 2015\" \/>\n<meta property=\"og:description\" content=\"D\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0111\u1ec1 thi minh h\u1ecda K\u1ef3 thi th\u1eed THPT qu\u1ed1c gia M\u00f4n V\u1eadt l\u00fd ch\u00ednh th\u1ee9c n\u0103m 2015 c\u1ee7a B\u1ed9 gi\u00e1o d\u1ee5c. Ch\u00fac c\u00e1c b\u1ea1n h\u1ecdc sinh \u00f4n t\u1eadp th\u1eadt t\u1ed1t \u0111\u1ec3 chu\u1ea9n b\u1ecb cho k\u1ef3 thi quan tr\u1ecdng n\u00e0y! Cho bi\u1ebft h\u1eb1ng s\u1ed1 Pl\u0103ng h = 6,625.10\u221234 J.s; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam\" \/>\n<meta property=\"article:author\" content=\"www.facebook.com\/lop12.edu.vn\/\" \/>\n<meta property=\"article:published_time\" content=\"2016-02-10T02:44:56+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2016-02-11T06:07:44+00:00\" \/>\n<meta name=\"author\" content=\"Lop12\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Lop12\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"25 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/\",\"url\":\"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/\",\"name\":\"\u0110\u1ec1 thi minh h\u1ecda (k\u00e8m \u0111\u00e1p \u00e1n) M\u00f4n V\u1eadt l\u00fd k\u1ef3 thi THPT Qu\u1ed1c gia n\u0103m 2015\",\"isPartOf\":{\"@id\":\"https:\/\/lop12.edu.vn\/#website\"},\"datePublished\":\"2016-02-10T02:44:56+00:00\",\"dateModified\":\"2016-02-11T06:07:44+00:00\",\"author\":{\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/8219caa3d91a087a4ce81b8b5ac734b5\"},\"breadcrumb\":{\"@id\":\"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/lop12.edu.vn\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"\u0110\u1ec1 thi minh h\u1ecda (k\u00e8m \u0111\u00e1p \u00e1n) M\u00f4n V\u1eadt l\u00fd k\u1ef3 thi THPT Qu\u1ed1c gia n\u0103m 2015\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/lop12.edu.vn\/#website\",\"url\":\"https:\/\/lop12.edu.vn\/\",\"name\":\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/lop12.edu.vn\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/8219caa3d91a087a4ce81b8b5ac734b5\",\"name\":\"Lop12\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/65b2897b6a31b932be1276ba7fc18d41?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/65b2897b6a31b932be1276ba7fc18d41?s=96&d=mm&r=g\",\"caption\":\"Lop12\"},\"sameAs\":[\"http:\/\/www.lop12.edu.vn\",\"www.facebook.com\/lop12.edu.vn\/\"],\"url\":\"https:\/\/lop12.edu.vn\/author\/hungld\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"\u0110\u1ec1 thi minh h\u1ecda (k\u00e8m \u0111\u00e1p \u00e1n) M\u00f4n V\u1eadt l\u00fd k\u1ef3 thi THPT Qu\u1ed1c gia n\u0103m 2015","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/lop12.edu.vn\/de-thi-minh-hoa-kem-dap-an-mon-vat-ly-ky-thi-thpt-quoc-gia-nam-2015\/","og_locale":"en_US","og_type":"article","og_title":"\u0110\u1ec1 thi minh h\u1ecda (k\u00e8m \u0111\u00e1p \u00e1n) M\u00f4n V\u1eadt l\u00fd k\u1ef3 thi THPT Qu\u1ed1c gia n\u0103m 2015","og_description":"D\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0111\u1ec1 thi minh h\u1ecda K\u1ef3 thi th\u1eed THPT qu\u1ed1c gia M\u00f4n V\u1eadt l\u00fd ch\u00ednh th\u1ee9c n\u0103m 2015 c\u1ee7a B\u1ed9 gi\u00e1o d\u1ee5c. 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