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{"id":6694,"date":"2016-11-22T07:05:20","date_gmt":"2016-11-22T07:05:20","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=6694"},"modified":"2016-11-22T07:05:20","modified_gmt":"2016-11-22T07:05:20","slug":"de-thi-hoc-ki-2-lop-11-nam-2015-mon-toan-thpt-luc-nam","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/de-thi-hoc-ki-2-lop-11-nam-2015-mon-toan-thpt-luc-nam\/","title":{"rendered":"\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam"},"content":{"rendered":"

\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam t\u1ec9nh B\u1eafc Giang gi\u00fap c\u00e1c em c\u1ee7ng c\u1ed1 ki\u1ebfn th\u1ee9c chu\u1ea9n b\u1ecb th\u1eadt t\u1ed1t cho k\u00ec thi s\u1eafp t\u1edbi:<\/p>\n

\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam<\/strong><\/h4>\n

C\u00e2u 1.<\/strong>\u00a0(3 \u0111i\u1ec3m)<\/em><\/p>\n

Cho h\u00e0m s\u1ed1\u00a0\u00a0f<\/em>(x<\/em>) = \u00a0x<\/em>4<\/sup>\u00a0– 2(m<\/em>\u00a0– 1)x2<\/sup><\/em>\u00a0+\u00a0m<\/em>\u00a0-1 c\u00f3 \u0111\u1ed3 th\u1ecb (Cm<\/sub>)<\/p>\n

1) V\u1edbi m = 2, h\u00e3y vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb (C2<\/sub>)<\/p>\n

    \n
  1. T\u1ea1i \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 b\u1eb1ng\u00a0\u00a0 -2.<\/li>\n
  2. Bi\u1ebft ti\u1ebfp tuy\u1ebfn \u0111\u00f3 song song v\u1edbi tr\u1ee5c ho\u00e0nh.<\/li>\n<\/ol>\n

    2) T\u00ecm m \u0111\u1ec3 ph\u01b0\u01a1ng tr\u00ecnh\u00a0f<\/em>(x<\/em>) =\u00a0 0 c\u00f3 4 nghi\u1ec7m ph\u00e2n bi\u1ec7t l\u1eadp th\u00e0nh c\u1ea5p s\u1ed1 c\u1ed9ng.<\/p>\n

    C\u00e2u 4.<\/strong>\u00a0(2,5\u0111i\u1ec3m):\u00a0<\/em>Cho t\u1ee9 di\u1ec7n ABCD c\u00f3 AB = AC = a, BC = 6\/5a, AD = 4\/5 a \u00a0v\u00e0 DA vu\u00f4ng g\u00f3c mp (ABC). G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC, H l\u00e0 h\u00ecnh chi\u1ebfu c\u1ee7a A tr\u00ean DM.<\/p>\n

    1) Ch\u1ee9ng minh AH\u00a0vu\u00f4ng g\u00f3c\u00a0<\/em>mp(BCD)<\/em>.<\/p>\n

    2)\u00a0 T\u00ednh cosin g\u00f3c gi\u1eefa AC v\u00e0 DM<\/p>\n

    3) G\u1ecdi \u00a0l\u00e0 tr\u1ecdng t\u00e2m c\u1ee7a \u00a0BCD. T\u00ednh kho\u1ea3ng c\u00e1ch t\u1eeb \u00a0\u0111\u1ebfn mp(ABC)<\/p>\n

    \"\"<\/p>\n

    \u0110\u00e1p \u00e1n \u0111\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam<\/strong><\/h4>\n

    \"\"<\/p>\n

     <\/p>\n","protected":false},"excerpt":{"rendered":"

    \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam t\u1ec9nh B\u1eafc Giang gi\u00fap c\u00e1c em c\u1ee7ng c\u1ed1 ki\u1ebfn th\u1ee9c chu\u1ea9n b\u1ecb th\u1eadt t\u1ed1t cho k\u00ec thi s\u1eafp t\u1edbi: \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam C\u00e2u 1.\u00a0(3 \u0111i\u1ec3m) Cho h\u00e0m s\u1ed1\u00a0\u00a0f(x) = \u00a0x4\u00a0– […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[171],"tags":[],"yoast_head":"\n\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-thi-hoc-ki-2-lop-11-nam-2015-mon-toan-thpt-luc-nam\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam\" \/>\n<meta property=\"og:description\" content=\"\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam t\u1ec9nh B\u1eafc Giang gi\u00fap c\u00e1c em c\u1ee7ng c\u1ed1 ki\u1ebfn th\u1ee9c chu\u1ea9n b\u1ecb th\u1eadt t\u1ed1t cho k\u00ec thi s\u1eafp t\u1edbi: \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 n\u0103m 2015 m\u00f4n To\u00e1n \u2013THPT L\u1ee5c Nam C\u00e2u 1.\u00a0(3 \u0111i\u1ec3m) Cho h\u00e0m s\u1ed1\u00a0\u00a0f(x) = \u00a0x4\u00a0– […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/de-thi-hoc-ki-2-lop-11-nam-2015-mon-toan-thpt-luc-nam\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - 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