\u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n tr\u01b0\u1eddng THPT Ng\u00f4 Quy\u1ec1n 2015 c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, c\u00e1c em tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n
II. PH\u1ea6N RI\u00caNG (3,0 \u0111i\u1ec3m<\/em>)\u00a0 <\/strong>H\u1ecdc sinh ch\u1ec9 \u0111\u01b0\u1ee3c l\u00e0m m\u1ed9t trong hai ph\u1ea7n sau <\/em>(ph\u1ea7n 1 ho\u1eb7c ph\u1ea7n 2<\/em>)<\/p>\n Ph\u1ea7n 1<\/u><\/strong> : Theo ch\u01b0\u01a1ng tr\u00ecnh Chu\u1ea9n<\/em><\/strong><\/p>\n C\u00e2u 6a<\/strong> (1,0 \u0111i\u1ec3m<\/em>): \u00a0Cho h\u00e0m s\u1ed1 f(x)= x3<\/sup> + 2x2<\/sup> -1 c\u00f3 \u0111\u1ed3 th\u1ecb (C<\/em>). Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a (C<\/em>) t\u1ea1i \u0111i\u1ec3m M <\/em>c\u00f3 ho\u00e0nh \u0111\u1ed9 .<\/p>\n C\u00e2u 7a<\/strong> (1,0 \u0111i\u1ec3m<\/em>): \u00a0Ch\u1ee9ng minh r\u1eb1ng ph\u01b0\u01a1ng tr\u00ecnh 4x4<\/sup> + 2x2<\/sup> \u2013x -3 = c\u00f3 \u00edt nh\u1ea5t hai nghi\u1ec7m ph\u00e2n bi\u1ec7t tr\u00ean kho\u1ea3ng .<\/p>\n C\u00e2u 8a<\/strong> (1,0 \u0111i\u1ec3m<\/em>): \u00a0Cho h\u00ecnh ch\u00f3p S.ABC<\/em> c\u00f3 ABC<\/em> l\u00e0 tam gi\u00e1c vu\u00f4ng c\u00e2n t\u1ea1i A<\/em>, AB<\/em> = a<\/em>, SA<\/em> vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (ABC<\/em>) v\u00e0 SA<\/em> = . G\u1ecdi M<\/em> l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC<\/em>. D\u1ef1ng v\u00e0 t\u00ednh \u0111\u1ed9 d\u00e0i \u0111o\u1ea1n vu\u00f4ng g\u00f3c chung c\u1ee7a hai \u0111\u01b0\u1eddng th\u1eb3ng SM<\/em> v\u00e0 AC<\/em> theo a<\/em>.<\/p>\n <\/p>\n <\/p>\n <\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n tr\u01b0\u1eddng THPT Ng\u00f4 Quy\u1ec1n 2015 c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, c\u00e1c em tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y: \u0110\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n \u2013 THPT Ng\u00f4 Quy\u1ec1n 2015 II. PH\u1ea6N RI\u00caNG (3,0 \u0111i\u1ec3m)\u00a0 H\u1ecdc sinh ch\u1ec9 \u0111\u01b0\u1ee3c l\u00e0m m\u1ed9t trong hai ph\u1ea7n sau (ph\u1ea7n […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[171],"tags":[],"yoast_head":"\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi h\u1ecdc k\u00ec 2 l\u1edbp 11 m\u00f4n To\u00e1n \u2013 THPT Ng\u00f4 Quy\u1ec1n 2015<\/strong><\/h4>\n