\u0110\u1ec1 thi h\u1ecdc k\u00ec 1 m\u00f4n Sinh h\u1ecdc l\u1edbp 11 tr\u01b0\u1eddng THPT Long M\u1ef9 n\u0103m 2014<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-thi-hoc-ki-1-mon-sinh-hoc-lop-11-truong-thpt-long-nam-2014\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 thi h\u1ecdc k\u00ec 1 m\u00f4n Sinh h\u1ecdc l\u1edbp 11 tr\u01b0\u1eddng THPT Long M\u1ef9 n\u0103m 2014\" \/>\n<meta property=\"og:description\" content=\"\u0110\u00e1p \u00e1n v\u1ec1 \u0111\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n Sinh h\u1ecdc Tr\u01b0\u1eddng THPT Long M\u1ef9 n\u0103m 2013 – 2014, c\u00e1c b\u1ea1n tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y: \u0110\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n Sinh h\u1ecdc n\u0103m 2014 Tr\u01b0\u1eddng THPT Long M\u1ef9 A.\u00a0\u00a0\u00a0\u00a0PH\u1ea6N CHUNG C\u00e2u 1: (1 \u0111i\u1ec3m) a. 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{"id":6585,"date":"2016-11-22T03:03:28","date_gmt":"2016-11-22T03:03:28","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=6585"},"modified":"2016-11-22T03:03:28","modified_gmt":"2016-11-22T03:03:28","slug":"de-thi-hoc-ki-1-mon-sinh-hoc-lop-11-truong-thpt-long-nam-2014","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/de-thi-hoc-ki-1-mon-sinh-hoc-lop-11-truong-thpt-long-nam-2014\/","title":{"rendered":"\u0110\u1ec1 thi h\u1ecdc k\u00ec 1 m\u00f4n Sinh h\u1ecdc l\u1edbp 11 tr\u01b0\u1eddng THPT Long M\u1ef9 n\u0103m 2014"},"content":{"rendered":"

\u0110\u00e1p \u00e1n v\u1ec1 \u0111\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n Sinh h\u1ecdc Tr\u01b0\u1eddng THPT Long M\u1ef9 n\u0103m 2013 – 2014, c\u00e1c b\u1ea1n tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n

\u0110\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n Sinh h\u1ecdc n\u0103m 2014 Tr\u01b0\u1eddng THPT Long M\u1ef9<\/strong><\/h3>\n
A.\u00a0\u00a0\u00a0\u00a0<\/strong>PH\u1ea6N CHUNG<\/strong><\/p>\n
C\u00e2u 1: (1 \u0111i\u1ec3m)<\/strong><\/p>\n
a. H\u00e3y tr\u00ecnh b\u00e0y qu\u00e1 tr\u00ecnh chuy\u1ec3n h\u00f3a nit\u01a1 h\u1eefu c\u01a1 trong \u0111\u1ea5t nh\u1edd c\u00e1c vi khu\u1ea9n d\u01b0\u1edbi d\u1ea1ng s\u01a1 \u0111\u1ed3. (0,5 \u0111i\u1ec3m)<\/p>\n
b. Tr\u00ecnh b\u00e0y \u00fd ngh\u0129a c\u1ee7a s\u1ef1 h\u00ecnh th\u00e0nh amit \u1edf th\u1ef1c v\u1eadt. (0,5 \u0111i\u1ec3m)<\/p>\n
C\u00e2u 2: (2 \u0111i\u1ec3m)\u00a0<\/strong>Ph\u00e2n bi\u1ec7t pha t\u1ed1i trong quang h\u1ee3p gi\u1eefa hai nh\u00f3m th\u1ef1c v\u1eadt C_{3\u00a0<\/sub>v\u00e0 C_{4<\/sub>\u00a0v\u1edbi c\u00e1c ti\u00eau ch\u00ed sau:<\/p>\n}}
– Ch\u1ea5t nh\u1eadn CO_{2<\/sub>\u00a0\u0111\u1ea7u ti\u00ean.<\/p>\n}
– Enzim c\u1ed1 \u0111\u1ecbnh CO_{2<\/sub>.<\/p>\n}
– S\u1ea3n ph\u1ea9m c\u1ed1 \u0111\u1ecbnh CO_{2<\/sub>\u00a0\u0111\u1ea7u ti\u00ean.<\/p>\n}
– Kh\u00f4ng gian th\u1ef1c hi\u1ec7n.<\/p>\n
C\u00e2u 3: (2,5 \u0111i\u1ec3m)<\/strong><\/p>\n
a. N\u00eau \u0111\u1eb7c \u0111i\u1ec3m c\u00e1c con \u0111\u01b0\u1eddng tho\u00e1t h\u01a1i n\u01b0\u1edbc \u1edf l\u00e1. (1 \u0111i\u1ec3m)<\/p>\n
b. N\u00eau \u00fd ngh\u0129a c\u1ee7a qu\u00e1 tr\u00ecnh tho\u00e1t h\u01a1i n\u01b0\u1edbc \u1edf th\u1ef1c v\u1eadt? (1,5 \u0111i\u1ec3m)<\/p>\n
C\u00e2u 4: (1,5 \u0111i\u1ec3m)<\/strong><\/p>\n
a. So s\u00e1nh v\u1ec1 hi\u1ec7u qu\u1ea3 n\u0103ng l\u01b0\u1ee3ng (ATP) gi\u1eefa h\u00f4 h\u1ea5p hi\u1ebfu kh\u00ed v\u00e0 l\u00ean men \u1edf th\u1ef1c v\u1eadt? (0,75 \u0111i\u1ec3m)<\/p>\n
b. Trong \u0111i\u1ec1u ki\u1ec7n n\u00e0o c\u00e2y th\u1ef1c hi\u1ec7n qu\u00e1 tr\u00ecnh l\u00ean men? Qu\u00e1 tr\u00ecnh l\u00ean men \u0111\u01b0\u1ee3c th\u1ef1c hi\u1ec7n \u1edf c\u01a1 quan n\u00e0o c\u1ee7a th\u1ef1c v\u1eadt v\u00e0 g\u00e2y ra h\u1eadu qu\u1ea3 g\u00ec cho c\u00e2y? (0,75 \u0111i\u1ec3m)<\/p>\n
C\u00e2u 5: (1 \u0111i\u1ec3m)<\/strong><\/p>\n
a. N\u00eau kh\u00e1i ni\u1ec7m n\u0103ng su\u1ea5t sinh h\u1ecdc v\u00e0 n\u0103ng su\u1ea5t kinh t\u1ebf. (0,5 \u0111i\u1ec3m)<\/p>\n
b. Cho bi\u1ebft: nhu c\u1ea7u dinh d\u01b0\u1ee1ng \u0111\u1ed1i v\u1edbi nit\u01a1 c\u1ee7a l\u00faa l\u00e0 14g\/1kg ch\u1ea5t kh\u00f4 thu ho\u1ea1ch, kh\u1ea3 n\u0103ng cung c\u1ea5p ch\u1ea5t dinh d\u01b0\u1ee1ng c\u1ee7a \u0111\u1ea5t b\u1eb1ng 0, h\u1ec7 s\u1ed1 s\u1eed d\u1ee5ng ph\u00e2n b\u00f3n c\u1ee7a l\u00faa l\u00e0 65%. H\u00e3y t\u00ednh l\u01b0\u1ee3ng ph\u00e2n b\u00f3n c\u1ea7n cung c\u1ea5p \u0111\u1ec3 c\u00f3 m\u1ed9t thu ho\u1ea1ch l\u00e0 15 t\u1ea5n.\u00a0 (0,5 \u0111i\u1ec3m)<\/p>\n
B. PH\u1ea6N RI\u00caNG<\/strong><\/p>\n
H\u1ecdc sinh ch\u1ec9 \u0111\u01b0\u1ee3c ch\u1ecdn m\u1ed9t trong hai ph\u1ea7n sau \u0111\u1ec3 l\u00e0m b\u00e0i.<\/p>\n
A. Ch\u01b0\u01a1ng tr\u00ecnh c\u01a1 b\u1ea3n.<\/strong><\/p>\n
C\u00e2u 6: (1 \u0111i\u1ec3m)<\/strong><\/p>\n
Tr\u00ecnh b\u00e0y c\u00e1c b\u01b0\u1edbc ti\u1ebfn h\u00e0nh v\u00e0 k\u1ebft qu\u1ea3 c\u1ee7a th\u00ed nghi\u1ec7m ch\u1ee9ng minh h\u00f4 h\u1ea5p h\u00fat O_{2<\/sub>.<\/p>\n}
C\u00e2u 7: (1 \u0111i\u1ec3m)<\/strong><\/p>\n
Gi\u1ea3i th\u00edch t\u1ea1i sao th\u1ef1c v\u1eadtCAMth\u1ef1c hi\u1ec7n pha t\u1ed1i c\u1ee7a quang h\u1ee3p v\u00e0o hai th\u1eddi \u0111i\u1ec3m (ban \u0111\u00eam v\u00e0 ban ng\u00e0y)?<\/p>\n
B. Ch\u01b0\u01a1ng tr\u00ecnh n\u00e2ng cao<\/strong><\/p>\n
C\u00e2u 8: (1 \u0111i\u1ec3m)<\/strong><\/p>\n
Tr\u00ecnh b\u00e0y c\u00e1c b\u01b0\u1edbc ti\u1ebfn h\u00e0nh v\u00e0 k\u1ebft qu\u1ea3 c\u1ee7a th\u00ed nghi\u1ec7m t\u00e1ch s\u1eafc t\u1ed1 \u1edf l\u00e1 c\u00e2y b\u1eb1ng hai h\u1ee3p ch\u1ea5t n\u01b0\u1edbc r\u1eeda m\u00f3ng tay (ax\u00eat\u00f4n) v\u00e0 d\u1ea7u l\u1eeda tr\u1eafng.<\/p>\n
C\u00e2u 9: (1 \u0111i\u1ec3m)<\/strong><\/p>\n
\u0110i\u1ec1u ki\u1ec7n x\u1ea3y ra h\u00f4 h\u1ea5p s\u00e1ng? Gi\u1ea3i th\u00edch v\u00ec sao th\u1ef1c v\u1eadt C_{4\u00a0<\/sub>th\u01b0\u1eddng kh\u00f4ng c\u00f3 h\u00f4 h\u1ea5p s\u00e1ng?<\/p>\n}
——————-H\u1ebeT——————-<\/strong><\/p>\n
<\/p>\n
\u0110\u00e1p \u00e1n \u0111\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n Sinh h\u1ecdc n\u0103m 2014 Tr\u01b0\u1eddng THPT Long M\u1ef9:<\/h3>\n
$\"De$ <\/p>\n
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\u0110\u00e1p \u00e1n v\u1ec1 \u0111\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n Sinh h\u1ecdc Tr\u01b0\u1eddng THPT Long M\u1ef9 n\u0103m 2013 – 2014, c\u00e1c b\u1ea1n tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y: \u0110\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n Sinh h\u1ecdc n\u0103m 2014 Tr\u01b0\u1eddng THPT Long M\u1ef9 A.\u00a0\u00a0\u00a0\u00a0PH\u1ea6N CHUNG C\u00e2u 1: (1 \u0111i\u1ec3m) a. 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