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{"id":6569,"date":"2016-11-22T02:45:03","date_gmt":"2016-11-22T02:45:03","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=6569"},"modified":"2016-11-22T02:45:03","modified_gmt":"2016-11-22T02:45:03","slug":"de-thi-cuoi-hoc-ki-1-mon-van-lop-11-nam-2015-truong-thpt-da-phuc","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/de-thi-cuoi-hoc-ki-1-mon-van-lop-11-nam-2015-truong-thpt-da-phuc\/","title":{"rendered":"\u0110\u1ec1 thi cu\u1ed1i h\u1ecdc k\u00ec 1 m\u00f4n V\u0103n l\u1edbp 11 n\u0103m 2015 tr\u01b0\u1eddng THPT \u0110a Ph\u00fac"},"content":{"rendered":"

\u0110\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n V\u0103n – THPT \u0110a Ph\u00fac n\u0103m 2015 – 2016, c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, c\u00e1c em tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n\n\n\n
\n

TH\u01af\u1edcNG THPT \u0110A PH\u00daC<\/strong><\/p>\n

N\u0103m h\u1ecdc: 2015 – 2016<\/strong><\/p>\n<\/td>\n

\n

\u0110\u1ec0 THI H\u1eccC K\u00cc I – KH\u1ed0I 11<\/strong><\/p>\n

M\u00f4n: Ng\u1eef v\u0103n<\/strong><\/p>\n

Th\u1eddi gian: 90 ph\u00fat<\/strong><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

I. PH\u1ea6N \u0110\u1eccC HI\u1ec2U.\u00a0<\/strong>(4,0 \u0111i\u1ec3m)<\/em><\/p>\n

\u0110\u1ecdc \u0111o\u1ea1n th\u01a1 sau v\u00e0 th\u1ef1c hi\u1ec7n y\u00eau c\u1ea7u t\u1eeb c\u00e2u 1 \u0111\u1ebfn c\u00e2u 5:<\/strong><\/p>\n

\u0110\u1ea5t t\u1ed5 qu\u1ed1c khi ch\u1eadp ch\u1eddn b\u00f3ng gi\u1eb7c<\/em><\/p>\n

C\u00e1c con n\u1eb1m thao th\u1ee9c ph\u00eda Tr\u01b0\u1eddng S\u01a1n<\/em><\/p>\n

Bi\u1ec3n T\u1ed5 qu\u1ed1c ch\u01b0a m\u1ed9t ng\u00e0y y\u00ean \u1ea3<\/em><\/p>\n

Bi\u1ec3n c\u1ea7n lao nh\u01b0\u00a0 \u00e1o m\u1eb9 b\u1ea1c s\u1eddn.<\/em><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Th\u00e1ng 4\/2009<\/em><\/strong><\/p>\n

(Tr\u00edch:\u00a0T\u1ed5 Qu\u1ed1c nh\u00ecn t\u1eeb Bi\u1ec3n<\/em><\/strong>\u00a0– Nguy\u1ec5n Vi\u1ec7t Chi\u1ebfn)<\/p>\n

C\u00e2u 1<\/strong>: Ch\u1ec9 ra ph\u01b0\u01a1ng th\u1ee9c bi\u1ec3u \u0111\u1ea1t ch\u00ednh \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng trong \u0111o\u1ea1n th\u01a1.<\/p>\n

C\u00e2u 2<\/strong>: N\u00eau n\u1ed9i dung ch\u00ednh c\u1ee7a \u0111o\u1ea1n th\u01a1.<\/p>\n

C\u00e2u 3<\/strong>: X\u00e1c \u0111\u1ecbnh hai bi\u1ec7n ph\u00e1p tu t\u1eeb \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng trong \u0111o\u1ea1n th\u01a1? N\u00eau t\u00e1c d\u1ee5ng?<\/p>\n

C\u00e2u 4<\/strong>: Anh\/ch\u1ecb hi\u1ec3u nh\u01b0 th\u1ebf n\u00e0o v\u1ec1 c\u00e2u th\u01a1: “C\u00e1c con n\u1eb1m thao th\u1ee9c ph\u00eda Tr\u01b0\u1eddng S\u01a1n\u201d?<\/p>\n

C\u00e2u 5<\/strong>: T\u1eeb n\u1ed9i dung c\u1ee7a \u0111o\u1ea1n th\u01a1, anh\/ch\u1ecb h\u00e3y vi\u1ebft m\u1ed9t \u0111o\u1ea1n v\u0103n ng\u1eafn kho\u1ea3ng 10 d\u00f2ng tr\u00ecnh b\u00e0y suy ngh\u0129 v\u1ec1 tr\u00e1ch nhi\u1ec7m c\u1ee7a thanh ni\u00ean v\u1edbi bi\u1ec3n \u0111\u1ea3o qu\u00ea h\u01b0\u01a1ng.<\/p>\n

II. PH\u1ea6N L\u00c0M V\u0102N.\u00a0<\/strong>(6,0 \u0111i\u1ec3m)<\/em><\/u><\/p>\n

C\u1ea3m nh\u1eadn c\u1ee7a anh\/ch\u1ecb v\u1ec1 qu\u00e1 tr\u00ecnh h\u1ed3i sinh c\u1ee7a Ch\u00ed Ph\u00e8o trong truy\u1ec7n ng\u1eafn c\u00f9ng t\u00ean c\u1ee7a nh\u00e0 v\u0103n Nam Cao \u0111\u1ec3 th\u1ea5y \u0111\u01b0\u1ee3c gi\u00e1 tr\u1ecb nh\u00e2n \u0111\u1ea1o m\u1edbi m\u1ebb trong truy\u1ec7n ng\u1eafn n\u00e0y.<\/p>\n

\u0110\u00e1p \u00e1n \u0111\u1ec1 thi h\u1ecdc k\u00ec 1 l\u1edbp 11 m\u00f4n V\u0103n – THPT \u0110a Ph\u00fac n\u0103m 2015<\/h3>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
\n

Ph\u1ea7n<\/strong><\/p>\n<\/td>\n

\n

C\u00e2u<\/strong><\/p>\n<\/td>\n

\n

N\u1ed9i dung c\u1ea7n \u0111\u1ea1t<\/strong><\/p>\n<\/td>\n

\n

\u0110i\u1ec3m<\/strong><\/p>\n<\/td>\n<\/tr>\n

\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

\u0110\u1ecdc hi\u1ec3u<\/em><\/strong><\/p>\n

(4\u0111)<\/em><\/strong><\/p>\n<\/td>\n

\n

C\u00e2u 1<\/p>\n

0,5\u0111<\/p>\n<\/td>\n

Ph\u01b0\u01a1ng th\u1ee9c bi\u1ec3u \u0111\u1ea1t:<\/strong>\u00a0H\u1ecdc sinh c\u00f3 th\u1ec3 tr\u1ea3 l\u1eddi: ph\u01b0\u01a1ng th\u1ee9c bi\u1ec3u c\u1ea3m ho\u1eb7c bi\u1ec3u c\u1ea3m.<\/td>\n\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

\n

C\u00e2u 2<\/p>\n

1\u0111<\/p>\n<\/td>\n

N\u1ed9i dung ch\u00ednh:<\/strong>\u00a0S\u1ef1 tr\u0103n tr\u1edf, lo l\u1eafng v\u1ec1 t\u00ecnh h\u00ecnh bi\u1ec3n \u0111\u1ea3o \u0111ang b\u1ecb \u0111e d\u1ecda b\u1edfi c\u00e1c th\u1ebf l\u1ef1c x\u00e2m l\u0103ng v\u00e0 s\u1ef1 bi\u1ebft \u01a1n v\u1edbi bi\u1ec3n \u0111\u1ea3o qu\u00ea h\u01b0\u01a1ng.<\/td>\n\n

1\u0111<\/p>\n<\/td>\n<\/tr>\n

HS ch\u1ec9 tr\u1ea3 l\u1eddi:<\/strong>\u00a0 S\u1ef1 tr\u0103n tr\u1edf, lo l\u1eafng v\u1ec1 t\u00ecnh h\u00ecnh bi\u1ec3n \u0111\u1ea3o \u0111ang b\u1ecb \u0111e d\u1ecda b\u1edfi c\u00e1c th\u1ebf l\u1ef1c x\u00e2m l\u0103ng.<\/td>\n\n

0,75\u0111<\/p>\n<\/td>\n<\/tr>\n

C\u00e2u tr\u1ea3 l\u1eddi ch\u01b0a th\u1eadt \u0111\u1ea7y \u0111\u1ee7 v\u00e0 r\u00f5 \u00fd<\/td>\n\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

\n

C\u00e2u 3<\/p>\n

1\u0111<\/p>\n<\/td>\n

– Hai bi\u1ec7n ph\u00e1p tu t\u1eeb: \u0110i\u1ec7p t\u1eeb, so s\u00e1nh…..<\/td>\n\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

– T\u00e1c d\u1ee5ng:<\/p>\n

+ \u0110i\u1ec7p t\u1eeb: s\u1ef1 tr\u0103n tr\u1edf, lo \u00e2u v\u1ec1 t\u00ecnh h\u00ecnh bi\u1ec3n \u0111\u1ea3o<\/p>\n

+ So s\u00e1nh: S\u1ef1 bi\u1ebft \u01a1n v\u1edbi bi\u1ec3n \u0111\u1ea3o<\/td>\n

\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

\n

C\u00e2u 4<\/p>\n

0,5\u0111<\/p>\n<\/td>\n

* HS c\u00f3 th\u1ec3 tr\u1ea3 l\u1eddi m\u1ed9t trong nh\u1eefng c\u00e1ch sau:<\/strong><\/p>\n

– Con d\u00e2n Vi\u1ec7tNamng\u00e0n \u0111\u1eddi \u1edf m\u1ecdi mi\u1ec1n t\u1ed5 qu\u1ed1c \u0111\u1ec1u h\u01b0\u1edbng v\u1ec1 (thao th\u1ee9c, lo l\u1eafng) bi\u1ec3n \u0111\u1ea3o qu\u00ea h\u01b0\u01a1ng – ch\u1ee7 quy\u1ec1n d\u00e2n t\u1ed9c….<\/p>\n

– Ho\u1eb7c<\/strong>: Tr\u01b0\u1eddng S\u01a1n h\u01b0\u1edbng v\u1ec1 bi\u1ec3n \u0111\u1ea3o, thao th\u1ee9c lo l\u1eafng v\u1ec1 ch\u1ee7 quy\u1ec1n d\u00e2n t\u1ed9c…..<\/p>\n

………<\/td>\n

\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

\n

C\u00e2u 5<\/p>\n

1\u0111<\/p>\n<\/td>\n

* HS vi\u1ebft \u0111o\u1ea1n theo nhi\u1ec1u c\u00e1ch kh\u00e1c nhau nh\u01b0ng ph\u1ea3i \u0111\u1ea3m b\u1ea3o \u0111\u01b0\u1ee3c c\u00e1c \u00fd sau:<\/strong><\/p>\n

– Kh\u1eb3ng \u0111\u1ecbnh vai tr\u00f2 bi\u1ec3n \u0111\u1ea3o.<\/p>\n

– Hi\u1ec7n nay t\u00ecnh h\u00ecnh bi\u1ec3n \u0111\u00f4ng \u0111ang di\u1ec5n bi\u1ebfn ph\u1ee9c t\u1ea1p.<\/p>\n

– Suy ngh\u0129 v\u1ec1 tr\u00e1ch nhi\u1ec7m c\u00f4ng d\u00e2n c\u1ee7a m\u1ed7i ng\u01b0\u1eddi.<\/p>\n

– K\u1ec3 ra nh\u1eefng h\u00e0nh \u0111\u1ed9ng c\u1ee5 th\u1ec3, thi\u1ebft th\u1ef1c<\/p>\n

…….<\/td>\n

\n

1\u0111<\/p>\n<\/td>\n<\/tr>\n

C\u00e2u tr\u1ea3 l\u1eddi chung chung, di\u1ec5n \u0111\u1ea1t ch\u01b0a th\u1eadt r\u00f5 \u00fd.<\/td>\n\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

\u00a0<\/em><\/strong><\/p>\n

L\u00e0m V\u0103n<\/em><\/strong><\/p>\n

(7\u0111 )<\/em><\/strong><\/p>\n<\/td>\n

\n

H\u00ecnh th\u1ee9c (0,5\u0111)<\/strong><\/p>\n<\/td>\n

HS bi\u1ebft tri\u1ec3n khai m\u1ed9t b\u00e0i l\u00e0m v\u0103n ngh\u1ecb lu\u1eadn c\u00f3 b\u1ed1 c\u1ee5c \u0111\u1ee7 3 ph\u1ea7n. Di\u1ec5n \u0111\u1ea1t r\u00f5 r\u00e0ng, \u00edt ho\u1eb7c kh\u00f4ng m\u1eafc l\u1ed7i ch\u00ednh t\u1ea3. C\u00f3 k\u0129 n\u0103ng ph\u00e2n t\u00edch, c\u1ea3m th\u1ee5 th\u01a1 (\u0111i t\u1eeb \u0111\u1eb7c s\u1eafc ngh\u1ec7 thu\u1eadt \u0111\u1ec3 kh\u00e1i qu\u00e1t n\u1ed9i dung t\u01b0 t\u01b0\u1edfng).<\/em><\/strong><\/p>\n

* M\u1edf b\u00e0i: gi\u1edbi thi\u1ec7u v\u1ea5n \u0111\u1ec1 ngh\u1ecb lu\u1eadn.<\/p>\n

 <\/p>\n

* Th\u00e2n b\u00e0i:<\/p>\n

– Tri\u1ec3n khai \u0111\u01b0\u1ee3c v\u1ea5n \u0111\u1ec1 ngh\u1ecb lu\u1eadn<\/p>\n

– C\u00f3 nh\u1eefng c\u1ea3m nh\u1eadn( nh\u1eadn x\u00e9t) x\u00e1c \u0111\u00e1ng<\/p>\n

– C\u00f3 nh\u1eefng l\u00ed gi\u1ea3i h\u1ee3p l\u00ed<\/p>\n

– Th\u00e2n b\u00e0i \u0111\u01b0\u1ee3c chia th\u00e0nh nhi\u1ec1u \u0111o\u1ea1n v\u0103n.<\/p>\n

* K\u1ebft b\u00e0i: Th\u00e2u t\u00f3m, \u0111\u00e1nh gi\u00e1 \u0111\u01b0\u1ee3c v\u1ea5n \u0111\u1ec1 ngh\u1ecb lu\u1eadn.<\/td>\n

\n

\n

\n

\n

\n

\n

\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

N\u1ed9i dung (5\u0111)<\/strong><\/td>\n\u00a0HS c\u00f3 th\u1ec3 tr\u00ecnh b\u00e0y theo nhi\u1ec1u c\u00e1ch kh\u00e1c nhau song c\u1ea7n \u0111\u1ea1t \u0111\u01b0\u1ee3c c\u00e1c n\u1ed9i dung c\u01a1 b\u1ea3n sau:<\/em><\/strong><\/td>\n\u00a0<\/strong><\/p>\n

 <\/td>\n<\/tr>\n

1. Tr\u00ecnh b\u00e0y ng\u1eafn g\u1ecdn qu\u00e1 tr\u00ecnh tha h\u00f3a c\u1ee7a Ch\u00ed Ph\u00e8o<\/td>\n\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

2. Qu\u00e1 tr\u00ecnh h\u1ed3i sinh c\u1ee7a Ch\u00ed Ph\u00e8o (sau cu\u1ed9c g\u1eb7p g\u1ee1 th\u1ecb N\u1edf<\/td>\n\n

\n<\/td>\n<\/tr>\n

– Gi\u1edbi thi\u1ec7u ng\u1eafn g\u1ecdn v\u1ec1 th\u1ecb N\u1edf.<\/td>\n\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

– S\u1ef1 h\u1ed3i sinh c\u1ee7a Ch\u00ed Ph\u00e8o.<\/td>\n\n

\n<\/td>\n<\/tr>\n

+ S\u1ef1 tr\u1edf v\u1ec1 c\u1ee7a \u00fd th\u1ee9c: Nh\u1eadn th\u1ee9c \u0111\u01b0\u1ee3c kh\u00f4ng gian, th\u1eddi gian (qu\u00e1 kh\u1ee9, hi\u1ec7n tai, t\u01b0\u01a1ng lai)<\/td>\n\n

0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

+ S\u1ef1 xu\u1ea5t hi\u1ec7n nh\u1eefng cung b\u1eadc c\u1ea3m x\u00fac th\u00f4ng th\u01b0\u1eddng c\u1ee7a con ng\u01b0\u1eddi.<\/td>\n\n

1\u0111<\/p>\n<\/td>\n<\/tr>\n

+ Ch\u00ed Ph\u00e8o c\u00f3 nh\u1eefng suy ngh\u0129 h\u01b0\u1edbng thi\u1ec7n (th\u00e8m l\u01b0\u01a1ng thi\u1ec7n, l\u00e0m h\u00f2a v\u1edbi m\u1ecdi ng\u01b0\u1eddi…..)<\/td>\n\n

1\u0111<\/p>\n<\/td>\n<\/tr>\n

+ T\u00ecnh ng\u01b0\u1eddi tr\u1edf v\u1ec1 v\u1edbi Ch\u00ed Ph\u00e8o (h\u00e0nh \u0111\u1ed9ng v\u00e0 l\u1eddi n\u00f3i)<\/td>\n\n

1\u0111<\/p>\n<\/td>\n<\/tr>\n

3. \u0110\u00e1nh gi\u00e1 chung:<\/p>\n

– Gi\u00e1 tr\u1ecb nh\u00e2n \u0111\u1ea1o m\u1edbi m\u1ebb trong: Ph\u00e1t hi\u1ec7n v\u00e0 kh\u1eb3ng \u0111i\u1ecbnh nh\u00e2n ph\u1ea9m, b\u1ea3n ch\u1ea5t l\u01b0\u01a1ng thi\u1ec7n c\u1ee7a con ng\u01b0\u1eddi ngay c\u1ea3 khi h\u1ecd m\u1ea5t \u0111i c\u1ea3 nh\u00e2n h\u00ecnh v\u00e0 nh\u00e2n t\u00ednh; kh\u1eb3ng \u0111\u1ecbnh s\u1ee9c m\u1ea1nh c\u1ee7a t\u00ecnh y\u00eau th\u01b0\u01a1ng: d\u00f9ng t\u00ecnh ng\u01b0\u1eddi \u0111\u1ec3 l\u00e0m s\u1ed1ng l\u1ea1i t\u00ecnh ng\u01b0\u1eddi.<\/p>\n

– Ngh\u1ec7 thu\u1eadt ph\u00e2n t\u00edch t\u00e2m l\u00fd nh\u00e2n v\u1eadt s\u00e2u s\u1eafc v\u00e0 tinh t\u1ebf.<\/td>\n

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0,5\u0111<\/p>\n<\/td>\n<\/tr>\n

L\u01b0u \u00fd<\/u><\/strong><\/td>\nSa\u0301ng ta\u0323o:\u00a0 C\u00f3 c\u00e1ch di\u1ec5n \u0111\u1ea1t s\u00e1ng t\u1ea1o, th\u1ec3 hi\u1ec7n suy ngh\u0129 s\u00e2u s\u1eafc, m\u1edbi m\u1ebb v\u1ec1 v\u1ea5n \u0111\u1ec1 ngh\u1ecb lu\u1eadn<\/td>\n\n

0,25\u0111<\/p>\n<\/td>\n<\/tr>\n

Ch\u00ednh t\u1ea3, d\u00f9ng t\u1eeb, \u0111\u1eb7t c\u00e2u: \u0110\u1ea3m b\u1ea3o quy t\u1eafc ch\u00ednh t\u1ea3, d\u00f9ng t\u1eeb, \u0111\u1eb7t c\u00e2u.<\/td>\n\n

0,25\u0111<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

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