<\/p>\n
\n \n C\u00e2u 1<\/strong>. H\u00e0m s\u1ed1 y = x3<\/sup> \u2013 3x + 1 \u0111\u1eb7t c\u1ef1c \u0111\u1ea1i t\u1ea1i:<\/p>\n<\/div>\n A. x = – 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. x = 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. x = 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. x = 2<\/p>\n<\/div>\n C\u00e2u 2<\/strong>. Ph\u01b0\u01a1ng tr\u00ecnh \u00a0 c\u00f3 hai nghi\u1ec7m l\u00e0 a v\u00e0 b. Gi\u00e1 tr\u1ecb c\u1ee7a a + b + ab l\u00e0:<\/p>\n<\/div>\n A. 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. 3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 1<\/p>\n <\/p>\n \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia 2017 m\u00f4n To\u00e1n tr\u1eafc nghi\u1ec7m – \u0110\u1ec1 s\u1ed1 2<\/strong><\/p>\n \u00a0Ngu\u1ed3n \u0111\u1ec1 thi v\u00e0 \u0111\u00e1p \u00e1n: Gi\u00e1o vi\u00ean \u0110\u00e0o Tr\u1ecdng Anh<\/strong><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n <\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n theo h\u00ecnh th\u1ee9c tr\u1eafc nghi\u1ec7m c\u1ee7a th\u1ea7y\u00a0\u0110\u00e0o Tr\u1ecdng Anh n\u0103m 2017 c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft C\u00e2u 1. H\u00e0m s\u1ed1 y = x3 \u2013 3x + 1 \u0111\u1eb7t c\u1ef1c \u0111\u1ea1i t\u1ea1i: A. x = – 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. x = 0 \u00a0 \u00a0 […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[],"yoast_head":"\n |