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{"id":44442,"date":"2019-10-21T17:31:55","date_gmt":"2019-10-21T10:31:55","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=44442"},"modified":"2021-03-21T23:28:07","modified_gmt":"2021-03-21T16:28:07","slug":"giai-toan-10-chuong-3-phuong-phap-toa-do-trong-mat-phang-bai-2-phuong-trinh-duong-tron","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/giai-toan-10-chuong-3-phuong-phap-toa-do-trong-mat-phang-bai-2-phuong-trinh-duong-tron\/","title":{"rendered":"[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 3: Ph\u01b0\u01a1ng ph\u00e1p t\u1ecda \u0111\u1ed9 trong m\u1eb7t ph\u1eb3ng\/ B\u00e0i 2: Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n"},"content":{"rendered":"\n

Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: Cho hai \u0111i\u1ec3m A(3; -4) v\u00e0 B(-3; 4).<\/ins><\/p>\n\n\n\n

Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n

G\u1ecdi I l\u00e0 \u0111\u01b0\u1eddng tr\u00f2n nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh<\/p>\n\n\n\n

\u21d2 I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB \u21d2 I (0; 0)<\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

\u21d2 R = AB\/2 = 5<\/p>\n\n\n\n

Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh l\u00e0:<\/p>\n\n\n\n

x2<\/sup> + y2<\/sup> = 25<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: H\u00e3y cho bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n:<\/ins><\/p>\n\n\n\n

2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0;<\/p>\n\n\n\n

x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\n

x2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\n

x2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n

+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n

+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n