Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: Cho hai \u0111i\u1ec3m A(3; -4) v\u00e0 B(-3; 4).<\/ins><\/p>\n\n\n\nVi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\nG\u1ecdi I l\u00e0 \u0111\u01b0\u1eddng tr\u00f2n nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh<\/p>\n\n\n\n\u21d2 I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB \u21d2 I (0; 0)<\/p>\n\n\n\n<\/figure>\n\n\n\n\u21d2 R = AB\/2 = 5<\/p>\n\n\n\nPh\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh l\u00e0:<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> = 25<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: H\u00e3y cho bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n:<\/ins><\/p>\n\n\n\n2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh.<\/p>\n\n\n\n
L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\nG\u1ecdi I l\u00e0 \u0111\u01b0\u1eddng tr\u00f2n nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh<\/p>\n\n\n\n\u21d2 I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB \u21d2 I (0; 0)<\/p>\n\n\n\n<\/figure>\n\n\n\n\u21d2 R = AB\/2 = 5<\/p>\n\n\n\nPh\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh l\u00e0:<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> = 25<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: H\u00e3y cho bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n:<\/ins><\/p>\n\n\n\n2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
G\u1ecdi I l\u00e0 \u0111\u01b0\u1eddng tr\u00f2n nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh<\/p>\n\n\n\n
\u21d2 I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB \u21d2 I (0; 0)<\/p>\n\n\n\n<\/figure>\n\n\n\n\u21d2 R = AB\/2 = 5<\/p>\n\n\n\nPh\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh l\u00e0:<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> = 25<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: H\u00e3y cho bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n:<\/ins><\/p>\n\n\n\n2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
\u21d2 R = AB\/2 = 5<\/p>\n\n\n\n
Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n (C) nh\u1eadn AB l\u00e0 \u0111\u01b0\u1eddng k\u00ednh l\u00e0:<\/p>\n\n\n\n
x2<\/sup> + y2<\/sup> = 25<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: H\u00e3y cho bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n:<\/ins><\/p>\n\n\n\n2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 82<\/strong>: H\u00e3y cho bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n:<\/ins><\/p>\n\n\n\n2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
x2<\/sup> + y2<\/sup> \u2013 2x \u2013 6y + 20 = 0;<\/p>\n\n\n\nx2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
x2<\/sup> + y2<\/sup> + 6x + 2y + 10 = 0.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
+ 2x2<\/sup> + y2<\/sup> \u2013 8x + 2y \u2013 1 = 0 kh\u00f4ng ph\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n v\u00ec h\u1ec7 s\u1ed1 c\u1ee7a x2<\/sup> kh\u00e1c h\u1ec7 s\u1ed1 c\u1ee7a y2<\/sup>. <\/p>\n\n\n\n+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n
+ Ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup> + y2<\/sup> + 2x \u2013 4y \u2013 4 = 0 c\u00f3 : <\/p>\n\n\n\n