Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9<\/strong>: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8.<\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nV\u1ec1 \u0111\u1ed9 d\u00e0i: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 c\u00f9ng \u0111\u1ed9 d\u00e0i<\/p>\n\n\n\nV\u1ec1 h\u01b0\u1edbng: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 h\u01b0\u1edbng ng\u01b0\u1ee3c nhau.<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: Cho AB\u2192<\/em> + BC\u2192<\/em> = 0\u2192<\/em>. H\u00e3y ch\u1ee9ng t\u1ecf BC\u2192<\/em> l\u00e0 vect\u01a1 \u0111\u1ed1i c\u1ee7a AB\u2192<\/em>.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nV\u1ec1 \u0111\u1ed9 d\u00e0i: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 c\u00f9ng \u0111\u1ed9 d\u00e0i<\/p>\n\n\n\nV\u1ec1 h\u01b0\u1edbng: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 h\u01b0\u1edbng ng\u01b0\u1ee3c nhau.<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: Cho AB\u2192<\/em> + BC\u2192<\/em> = 0\u2192<\/em>. H\u00e3y ch\u1ee9ng t\u1ecf BC\u2192<\/em> l\u00e0 vect\u01a1 \u0111\u1ed1i c\u1ee7a AB\u2192<\/em>.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nV\u1ec1 \u0111\u1ed9 d\u00e0i: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 c\u00f9ng \u0111\u1ed9 d\u00e0i<\/p>\n\n\n\nV\u1ec1 h\u01b0\u1edbng: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 h\u01b0\u1edbng ng\u01b0\u1ee3c nhau.<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: Cho AB\u2192<\/em> + BC\u2192<\/em> = 0\u2192<\/em>. H\u00e3y ch\u1ee9ng t\u1ecf BC\u2192<\/em> l\u00e0 vect\u01a1 \u0111\u1ed1i c\u1ee7a AB\u2192<\/em>.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nV\u1ec1 \u0111\u1ed9 d\u00e0i: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 c\u00f9ng \u0111\u1ed9 d\u00e0i<\/p>\n\n\n\nV\u1ec1 h\u01b0\u1edbng: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 h\u01b0\u1edbng ng\u01b0\u1ee3c nhau.<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: Cho AB\u2192<\/em> + BC\u2192<\/em> = 0\u2192<\/em>. H\u00e3y ch\u1ee9ng t\u1ecf BC\u2192<\/em> l\u00e0 vect\u01a1 \u0111\u1ed1i c\u1ee7a AB\u2192<\/em>.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
V\u1ec1 \u0111\u1ed9 d\u00e0i: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 c\u00f9ng \u0111\u1ed9 d\u00e0i<\/p>\n\n\n\nV\u1ec1 h\u01b0\u1edbng: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 h\u01b0\u1edbng ng\u01b0\u1ee3c nhau.<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: Cho AB\u2192<\/em> + BC\u2192<\/em> = 0\u2192<\/em>. H\u00e3y ch\u1ee9ng t\u1ecf BC\u2192<\/em> l\u00e0 vect\u01a1 \u0111\u1ed1i c\u1ee7a AB\u2192<\/em>.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
V\u1ec1 h\u01b0\u1edbng: hai vect\u01a1 AB\u2192<\/em> v\u00e0 CD\u2192<\/em> c\u00f3 h\u01b0\u1edbng ng\u01b0\u1ee3c nhau.<\/p>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: Cho AB\u2192<\/em> + BC\u2192<\/em> = 0\u2192<\/em>. H\u00e3y ch\u1ee9ng t\u1ecf BC\u2192<\/em> l\u00e0 vect\u01a1 \u0111\u1ed1i c\u1ee7a AB\u2192<\/em>.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10<\/strong>: Cho AB\u2192<\/em> + BC\u2192<\/em> = 0\u2192<\/em>. H\u00e3y ch\u1ee9ng t\u1ecf BC\u2192<\/em> l\u00e0 vect\u01a1 \u0111\u1ed1i c\u1ee7a AB\u2192<\/em>.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\nTr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 11<\/strong>: H\u00e3y gi\u1ea3i th\u00edch v\u00ec sao hi\u1ec7u c\u1ee7a hai vect\u01a1 OB\u2192<\/em> v\u00e0 OA\u2192<\/em> l\u00e0 vect\u01a1 AB\u2192<\/em>.<\/ins><\/p>\n\n\n\nL\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
B\u00e0i 1 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho \u0111o\u1ea1n th\u1eb3ng AB v\u00e0 \u0111i\u1ec3m M n\u1eb1m gi\u1eefa A v\u00e0 B sao cho AM > MB. V\u1ebd c\u00e1c vector\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\n\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
\u2013 Tr\u00ean \u0111o\u1ea1n MA, l\u1ea5y \u0111i\u1ec3m C sao cho MC = MB <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nNh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\nKhi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Nh\u1eadn th\u1ea5y \n v\u00e0 \n c\u00f9ng h\u01b0\u1edbng n\u00ean \n = \n <\/p>\n\n\n\n
Khi \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Ki\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi ba \u0111i\u1ec3m A, B, C b\u1ea5t k\u00ec ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
B\u00e0i 2 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho h\u00ecnh b\u00ecnh h\u00e0nh ABCD v\u00e0 \u0111i\u1ec3m M t\u00f9y \u00fd. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Ta c\u00f3: ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean\n\n<\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Ki\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n<\/figure>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\nB\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
+ Quy t\u1eafc ba \u0111i\u1ec3m: \n v\u1edbi m\u1ecdi \u0111i\u1ec3m A, B, C. <\/p>\n\n\n\n
+ a\u2192 + 0\u2192 = a\u2192 <\/p>\n\n\n\n
B\u00e0i 3 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Ch\u1ee9ng minh r\u1eb1ng \u0111\u1ed1i v\u1edbi t\u1ee9 gi\u00e1c ABCD b\u1ea5t k\u1ef3 ta lu\u00f4n c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\na) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
a) Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\nb) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
b) \u00c1p d\u1ee5ng quy t\u1eafc tr\u1eeb hai vec t\u01a1 ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
<\/ins><\/p>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Ki\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
+ Quy t\u1eafc ba \u0111i\u1ec3m : V\u1edbi A, B, C b\u1ea5t k\u00ec ta c\u00f3 : <\/p>\n\n\n\n<\/figure>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
B\u00e0i 4 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c ABC. B\u00ean ngo\u00e0i c\u1ee7a tam gi\u00e1c v\u1ebd c\u00e1c h\u00ecnh b\u00ecnh h\u00e0nh: ABIJ, BCPQ, CARS. Ch\u1ee9ng minh r\u1eb1ng \n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Ta c\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nAJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
AJIB l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/p>\n\n\n\n<\/figure>\n\n\n\nT\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
T\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady: <\/p>\n\n\n\n<\/figure>\n\n\n\nBCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
BCPQ l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n <\/p>\n\n\n\n<\/figure>\n\n\n\nCARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
CARS l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh n\u00ean \n<\/ins><\/p>\n\n\n\nDo \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Do \u0111\u00f3: <\/p>\n\n\n\n<\/figure>\n\n\n\nKi\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Ki\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\nQuy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Quy t\u1eafc ba \u0111i\u1ec3m c\u1ed9ng hai vec t\u01a1<\/p>\n\n\n\n<\/figure>\n\n\n\nB\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
B\u00e0i 5 (trang 12 SGK H\u00ecnh h\u1ecdc 10):<\/strong> Cho tam gi\u00e1c \u0111\u1ec1u ABC c\u1ea1nh b\u1eb1ng a. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u00e1c vect\u01a1\n<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n<\/figure>\n\n\n\nTa c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Ta c\u00f3:<\/p>\n\n\n\n<\/figure>\n\n\n\n(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
(Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh) <\/ins><\/p>\n\n\n\n(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
(Trong \u0111\u00f3 D l\u00e0 \u0111\u1ec9nh c\u00f2n l\u1ea1i c\u1ee7a h\u00ecnh b\u00ecnh h\u00e0nh ABCD)<\/p>\n\n\n\n<\/figure>\n\n\n\n+ T\u00ednh BD: <\/p>\n\n\n\nH\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
+ T\u00ednh BD: <\/p>\n\n\n\n
H\u00ecnh b\u00ecnh h\u00e0nh ABCD c\u00f3 AB = BC = a n\u00ean ABCD l\u00e0 h\u00ecnh thoi. <\/p>\n\n\n\n
\u21d2 AC \u22a5 BD t\u1ea1i O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AC v\u00e0 BD. <\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n[Gi\u1ea3i To\u00e1n 10] Ch\u01b0\u01a1ng 1: Vect\u01a1\/ B\u00e0i 2: T\u1ed5ng v\u00e0 hi\u1ec7u c\u1ee7a hai vect\u01a1<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n
Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 9: H\u00e3y ki\u1ec3m tra c\u00e1c t\u00ednh ch\u1ea5t c\u1ee7a ph\u00e9p c\u1ed9ng tr\u00ean h\u00ecnh 1.8. L\u1eddi gi\u1ea3i Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 H\u00ecnh h\u1ecdc B\u00e0i 2 trang 10: V\u1ebd h\u00ecnh b\u00ecnh h\u00e0nh ABCD. H\u00e3y nh\u1eadn x\u00e9t v\u1ec1 \u0111\u1ed9 d\u00e0i v\u00e0 h\u01b0\u1edbng c\u1ee7a hai vect\u01a1 AB\u2192 […]<\/p>\n","protected":false},"author":12,"featured_media":44376,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1633],"tags":[],"yoast_head":"\n