2<\/sup> + 2x \u2013 1. <\/p>\n\n\n\n+ T\u1eadp x\u00e1c \u0111\u1ecbnh: R<\/p>\n\n\n\n
+ \u0110\u1ec9nh A(1\/3 ; \u20132\/3). <\/p>\n\n\n\n
+ Tr\u1ee5c \u0111\u1ed1i x\u1ee9ng x = 1\/3. <\/p>\n\n\n\n
+ \u0110\u1ed3 th\u1ecb kh\u00f4ng giao v\u1edbi tr\u1ee5c ho\u00e0nh.<\/p>\n\n\n\n
+ Giao \u0111i\u1ec3m v\u1edbi tr\u1ee5c tung l\u00e0 B(0; \u20131). <\/p>\n\n\n\n
\u0110i\u1ec3m \u0111\u1ed1i x\u1ee9ng v\u1edbi B(0 ; \u20131) qua \u0111\u01b0\u1eddng th\u1eb3ng x = 1\/3 l\u00e0 C(2\/3 ; \u20131). <\/p>\n\n\n\n
+ B\u1ea3ng bi\u1ebfn thi\u00ean:<\/p>\n\n\n\n