Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 \u0110\u1ea1i s\u1ed1 B\u00e0i 5 trang 19<\/strong>: Khi \u0111\u1ecdc c\u00e1c th\u00f4ng tin sau em hi\u1ec3u \u0111\u00f3 l\u00e0 c\u00e1c s\u1ed1 \u0111\u00fang hay g\u1ea7n \u0111\u00fang ?<\/ins><\/p>\n\n\n\n B\u00e1n k\u00ednh \u0111\u01b0\u1eddng X\u00edch \u0110\u1ea1o c\u1ee7a Tr\u00e1i \u0110\u1ea5t l\u00e0 6378 km.<\/p>\n\n\n\n Kho\u1ea3ng c\u00e1ch t\u1eeb M\u1eb7t Tr\u0103ng \u0111\u1ebfn Tr\u00e1i \u0110\u1ea5t l\u00e0 384 400 km.<\/p>\n\n\n\n Kho\u1ea3ng c\u00e1ch t\u1eeb M\u1eb7t Tr\u1eddi \u0111\u1ebfn Tr\u00e1i \u0110\u1ea5t l\u00e0 148 600 000 km<\/p>\n\n\n\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n C\u00e1c th\u00f4ng \u0111\u00f3 \u0111\u01b0\u1ee3c hi\u1ec3u l\u00e0 c\u00e1c s\u1ed1 g\u1ea7n \u0111\u00fang.<\/p>\n\n\n\n Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 \u0110\u1ea1i s\u1ed1 B\u00e0i 5 trang 20<\/strong>: T\u00ednh \u0111\u01b0\u1eddng ch\u00e9o c\u1ee7a m\u1ed9t h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh b\u1eb1ng 3cm v\u00e0 x\u00e1c \u0111\u1ecbnh \u0111\u1ed9 ch\u00ednh x\u00e1c c\u1ee7a k\u1ebft qu\u1ea3 t\u00ecm \u0111\u01b0\u1ee3c. Cho bi\u1ebft \u221a2 = 1,4142135\u2026<\/ins><\/p>\n\n\n\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n \u0110\u01b0\u1eddng ch\u00e9o c\u1ee7a h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh b\u1eb1ng 3 cm l\u00e0 3\u221a2 cm.<\/p>\n\n\n\n Ta c\u00f3: a—<\/sup> = 3\u221a2, a = 3.1,41<\/p>\n\n\n\n \u221a\u0394a<\/sub> =|a—<\/sup> – a|= 0,0126 \u2264 0,0127<\/p>\n\n\n\n V\u1eady \u0111\u1ed9 ch\u00ednh x\u00e1c l\u00e0 d = 0,0127<\/p>\n\n\n\n Tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi To\u00e1n 10 \u0110\u1ea1i s\u1ed1 B\u00e0i 5 trang 22<\/strong>: H\u00e3y vi\u1ebft s\u1ed1 quy tr\u00f2n c\u1ee7a s\u1ed1 g\u1ea7n \u0111\u00fang trong nh\u1eefng tr\u01b0\u1eddng h\u1ee3p sau<\/ins><\/p>\n\n\n\n a) 374 529 \u00b1 200\t<\/p>\n\n\n\n b) 4,1356 \u00b1 0,001<\/p>\n\n\n\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n\n\n\n a) S\u1ed1 quy tr\u00f2n c\u1ee7a 374 529 \u00b1 200 l\u00e0 375000<\/p>\n\n\n\n b) S\u1ed1 quy tr\u00f2n c\u1ee7a 4,1356 \u00b1 0,001 l\u00e0 4,14<\/p>\n\n\n\n B\u00e0i 1 (trang 23 SGK \u0110\u1ea1i s\u1ed1 10):<\/strong> Bi\u1ebft \u221b5 = 1,709975947….. <\/p>\n\n\n\n Vi\u1ebft g\u1ea7n \u0111\u00fang \u221b5 theo nguy\u00ean t\u1eafc l\u00e0m tr\u00f2n v\u1edbi hai, ba, b\u1ed1n ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n v\u00e0 \u01b0\u1edbc l\u01b0\u1ee3ng sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i.<\/p>\n\n\n\n L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n \u2013 L\u00e0m tr\u00f2n v\u1edbi hai ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n: \u221b5 = 1,71.<\/p>\n\n\n\n Sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i: |1,71 \u2013 \u221b5| < |1,71 \u2013 1,7099| = 0,0001. <\/p>\n\n\n\n V\u1eady sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i kh\u00f4ng v\u01b0\u1ee3t qu\u00e1 0,0001.<\/p>\n\n\n\n \u2013 L\u00e0m tr\u00f2n v\u1edbi ba ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n: \u221b5 = 1,710<\/p>\n\n\n\n Sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i: |1,71 \u2013 \u221b5| < |1,71 \u2013 1,7099| = 0,0001.<\/p>\n\n\n\n V\u1eady sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i kh\u00f4ng v\u01b0\u1ee3t qu\u00e1 0,0001. <\/p>\n\n\n\n \u2013 L\u00e0m tr\u00f2n v\u1edbi b\u1ed1n ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n: \u221b5 = 1,7100<\/p>\n\n\n\n |1,71 \u2013 \u221b5| < |1,71 \u2013 1,7099| = 0,0001. <\/p>\n\n\n\n V\u1eady sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i kh\u00f4ng v\u01b0\u1ee3t qu\u00e1 0,0001.<\/p>\n\n\n\n Ki\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n + Quy t\u1eafc l\u00e0m tr\u00f2n s\u1ed1: <\/p>\n\n\n\n N\u1ebfu ch\u1eef s\u1ed1 h\u00e0ng quy tr\u00f2n nh\u1ecf h\u01a1n 5 th\u00ec ta thay n\u00f3 v\u00e0 c\u00e1c ch\u1eef s\u1ed1 b\u00ean ph\u1ea3i n\u00f3 b\u1edfi ch\u1eef s\u1ed1 0. <\/p>\n\n\n\n N\u1ebfu ch\u1eef s\u1ed1 sau h\u00e0ng quy tr\u00f2n l\u1edbn h\u01a1n ho\u1eb7c b\u1eb1ng 5 th\u00ec ta c\u0169ng l\u00e0m nh\u01b0 \ntr\u00ean nh\u01b0ng c\u1ed9ng th\u00eam m\u1ed9t \u0111\u01a1n v\u1ecb v\u00e0o ch\u1eef s\u1ed1 c\u1ee7a h\u00e0ng quy tr\u00f2n.<\/p>\n\n\n\n + V\u1edbi s\u1ed1 \u0111\u00fang a\u2212, sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i c\u1ee7a s\u1ed1 g\u1ea7n \u0111\u00fang a l\u00e0 \u0394a<\/sub> = |a – a\u2212| <\/p>\n\n\n\n + V\u00ec ta kh\u00f4ng th\u1ec3 x\u00e1c \u0111\u1ecbnh ch\u00ednh x\u00e1c s\u1ed1 \u0111\u00fang a\u2212 n\u00ean ta kh\u00f4ng th\u1ec3 t\u00ednh \u0111\u01b0\u1ee3c c\u00e1c sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i m\u00e0 ph\u1ea3i \u01b0\u1edbc l\u01b0\u1ee3ng ch\u00fang.<\/p>\n\n\n\n B\u00e0i 2 (trang 23 SGK \u0110\u1ea1i s\u1ed1 10):<\/strong> Chi\u1ec1u d\u00e0i m\u1ed9t c\u00e1i c\u1ea7u \u0111o \u0111\u01b0\u1ee3c l\u00e0: l = 1745,25m \u00b1 0,01m. <\/p>\n\n\n\n H\u00e3y vi\u1ebft s\u1ed1 quy tr\u00f2n c\u1ee7a s\u1ed1 g\u1ea7n \u0111\u00fang 1745,25.<\/p>\n\n\n\n L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n Ta c\u00f3: l = 1745,25m \u00b1 0,01m c\u00f3 \u0111\u1ed9 ch\u00ednh x\u00e1c \u0111\u1ebfn h\u00e0ng ph\u1ea7n tr\u0103m (\u0111\u1ed9 ch\u00ednh x\u00e1c l\u00e0 0,01) n\u00ean ta quy tr\u00f2n s\u1ed1 \u0111\u1ebfn h\u00e0ng ph\u1ea7n ch\u1ee5c. <\/p>\n\n\n\n V\u1eady s\u1ed1 quy tr\u00f2n c\u1ee7a 1745,25m l\u00e0 1745,3 m.<\/p>\n\n\n\n Ki\u1ebfn th\u1ee9c \u00e1p d\u1ee5ng<\/strong><\/p>\n\n\n\n + N\u1ebfu \u0111\u1ed9 ch\u00ednh x\u00e1c c\u1ee7a ph\u00e9p \u0111o \u0111\u1ebfn h\u00e0ng ch\u1ee5c th\u00ec ta ph\u1ea3i quy tr\u00f2n \u0111\u1ebfn\n h\u00e0ng tr\u0103m; \u0111\u1ed9 ch\u00ednh x\u00e1c \u0111\u1ebfn h\u00e0ng tr\u0103m th\u00ec ta ph\u1ea3i quy tr\u00f2n s\u1ed1 \u0111\u1ebfn h\u00e0ng \nngh\u00ecn; \u0111\u1ed9 ch\u00ednh x\u00e1c \u0111\u1ebfn h\u00e0ng ngh\u00ecn th\u00ec ta ph\u1ea3i quy tr\u00f2n \u0111\u1ebfn h\u00e0ng ch\u1ee5c \nngh\u00ecn; \u2026<\/p>\n\n\n\n + N\u1ebfu \u0111\u1ed9 ch\u00ednh x\u00e1c c\u1ee7a ph\u00e9p \u0111o \u0111\u1ebfn h\u00e0ng ph\u1ea7n ngh\u00ecn th\u00ec ta ph\u1ea3i quy tr\u00f2n \u0111\u1ebfn h\u00e0ng ph\u1ea7n tr\u0103m; \u0111\u1ed9 ch\u00ednh x\u00e1c \u0111\u1ebfn h\u00e0ng ph\u1ea7n tr\u0103m th\u00ec ta ph\u1ea3i quy tr\u00f2n \u0111\u1ebfn h\u00e0ng ph\u1ea7n ch\u1ee5c; \u2026<\/p>\n\n\n\n B\u00e0i 3 (trang 23 SGK \u0110\u1ea1i s\u1ed1 10):<\/strong> a) Cho s\u1ed1 g\u1ea7n \u0111\u00fang c\u1ee7a \u03c0 l\u00e0 a = 3,141592653589 v\u1edbi \u0111\u1ed9 ch\u00ednh x\u00e1c l\u00e0 10-10<\/sup>. H\u00e3y vi\u1ebft s\u1ed1 quy tr\u00f2n c\u1ee7a a.<\/ins><\/p>\n\n\n\n b) Cho b = 3,14 v\u00e0 c = 3,1416 l\u00e0 nh\u1eefng gi\u00e1 tr\u1ecb g\u1ea7n \u0111\u00fang c\u1ee7a \u03c0. H\u00e3y \u01b0\u1edbc l\u01b0\u1ee3ng sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i c\u1ee7a b v\u00e0 c. <\/p>\n\n\n\n L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n a) V\u00ec \u0111\u1ed9 ch\u00ednh x\u00e1c \u0111\u1ebfn 10\u201310 (10 ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n sau d\u1ea5u ,) n\u00ean ta quy tr\u00f2n \u0111\u1ebfn 10\u20139 (9 ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n sau d\u1ea5u ph\u1ea9y) <\/p>\n\n\n\n V\u1eady s\u1ed1 quy tr\u00f2n c\u1ee7a a l\u00e0 3,141592654. <\/p>\n\n\n\n b) \u03c0 = 3,14159265358\u2026 <\/p>\n\n\n\n + Vi\u1ebft b = 3,14 : <\/p>\n\n\n\n Sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i : |b \u2013 \u03c0| < |3,14 \u2013 3,14159265358| < 0,0016 <\/p>\n\n\n\n V\u1eady sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i c\u1ee7a b kh\u00f4ng qu\u00e1 0,0016. <\/p>\n\n\n\n + Vi\u1ebft c = 3,1416 : <\/p>\n\n\n\n Sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i : |c \u2013 \u03c0| < |3,1416 \u2013 3,14159265358| = 0,00001. <\/p>\n\n\n\n V\u1eady sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i c\u1ee7a c kh\u00f4ng v\u01b0\u1ee3t qu\u00e1 0,00001. <\/p>\n\n\n\n B\u00e0i 4 (trang 23 SGK \u0110\u1ea1i s\u1ed1 10):<\/strong> Th\u1ef1c hi\u1ec7n c\u00e1c ph\u00e9p sau tr\u00ean m\u00e1y t\u00ednh b\u1ecf t\u00fai (trong k\u1ebft qu\u1ea3 l\u1ea5y 4 ch\u1eef s\u1ed1 \u1edf ph\u1ea7n th\u1eadp ph\u00e2n).<\/p>\n\n\n\n a) 37<\/sup>.\u221a14 v\u1edbi 4 ch\u1eef s\u1ed1 \u1edf ph\u1ea7n th\u1eadp ph\u00e2n.<\/p>\n\n\n\n b) \u221b15.124<\/sup> v\u1edbi 4 ch\u1eef s\u1ed1 \u1edf ph\u1ea7n th\u1eadp ph\u00e2n.<\/ins><\/p>\n\n\n\n H\u01b0\u1edbng d\u1eabn c\u00e1ch gi\u1ea3i c\u00e2u a)<\/em>: N\u1ebfu d\u00f9ng m\u00e1y t\u00ednh CASIO fx-500 MS ta l\u00e0m nh\u01b0 sau.<\/p>\n\n\n\n