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{"id":44186,"date":"2019-10-13T14:22:49","date_gmt":"2019-10-13T07:22:49","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=44186"},"modified":"2019-10-13T14:22:50","modified_gmt":"2019-10-13T07:22:50","slug":"giai-vat-li-10-bai-33-cac-nguyen-li-cua-nhiet-dong-luc-hoc","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-33-cac-nguyen-li-cua-nhiet-dong-luc-hoc\/","title":{"rendered":"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 33 : C\u00e1c nguy\u00ean l\u00ed c\u1ee7a nhi\u1ec7t \u0111\u1ed9ng l\u1ef1c h\u1ecdc"},"content":{"rendered":"\n

B\u00e0i 33 : C\u00e1c nguy\u00ean l\u00ed c\u1ee7a nhi\u1ec7t \u0111\u1ed9ng l\u1ef1c h\u1ecdc<\/h2>\n\n\n\n

C1.<\/strong> ( trang 176 sgk V\u1eadt L\u00fd 10): X\u00e1c \u0111\u1ecbnh \nd\u1ea5u c\u1ee7a c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng trong h\u1ec7 th\u1ee9c c\u1ee7a nguy\u00ean l\u00ed I N\u0110LH cho c\u00e1c qu\u00e1 \ntr\u00ecnh h\u1ec7 thu nhi\u1ec7t l\u01b0\u1ee3ng \u0111\u1ec3 t\u0103ng n\u1ed9i n\u0103ng \u0111\u1ed3ng th\u1eddi th\u1ef1c hi\u1ec7n c\u00f4ng.<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/ins><\/p>\n\n\n\n

H\u1ec7 th\u1ee9c c\u1ee7a nguy\u00ean l\u00ed I: \u0394U = A + Q<\/p>\n\n\n\n

V\u1edbi: Q > 0 v\u00ec h\u1ec7 thu nhi\u1ec7t l\u01b0\u1ee3ng; <\/p>\n\n\n\n

     A < 0 v\u00ec h\u1ec7 th\u1ef1c hi\u1ec7n c\u00f4ng; <\/p>\n\n\n\n

     \u0394U > 0 v\u00ec n\u1ed9i n\u0103ng c\u1ee7a h\u1ec7 t\u0103ng.<\/p>\n\n\n\n

C2.<\/strong> ( trang 176 sgk V\u1eadt L\u00fd 10): C\u00e1c h\u1ec7 th\u1ee9c sau \u0111\u00e2y di\u1ec5n t\u1ea3 nh\u1eefng qu\u00e1 tr\u00ecnh n\u00e0o?<\/p>\n\n\n\n

a) \u0394U = Q khi Q > 0: v\u1eadt nh\u1eadn nhi\u1ec7t \u0111\u1ec3 l\u00e0m t\u0103ng n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

     \u0394U = Q khi Q < 0: v\u1eadt t\u1ecfa nhi\u1ec7t v\u00e0 l\u00e0m gi\u1ea3m n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

b) \u0394U = A khi A > 0: v\u1eadt nh\u1eadn c\u00f4ng \u0111\u1ec3 l\u00e0m t\u0103ng n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

     \u0394U = A khi A < 0: v\u1eadt th\u1ef1c hi\u1ec7n c\u00f4ng l\u00e0m gi\u1ea3m n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

c) \u0394U = Q + A khi Q > 0 v\u00e0 A < 0: V\u1eadt nh\u1eadn nhi\u1ec7t l\u01b0\u1ee3ng v\u00e0 th\u1ef1c hi\u1ec7n c\u00f4ng, n\u1ed9i n\u0103ng c\u1ee7a v\u1eadt c\u00f3 th\u1ec3 t\u0103ng ho\u1eb7c gi\u1ea3m.\n<\/p>\n\n\n\n

d) \u0394U = Q + A khi Q > 0 v\u00e0 A > 0: V\u1eadt nh\u1eadn nhi\u1ec7t l\u01b0\u1ee3ng v\u00e0 nh\u1eadn c\u00f4ng, n\u1ed9i n\u0103ng c\u1ee7a v\u1eadt t\u0103ng.\n<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/ins><\/p>\n\n\n\n

a)\t\u0394U = Q khi Q > 0: v\u1eadt nh\u1eadn nhi\u1ec7t \u0111\u1ec3 l\u00e0m t\u0103ng n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

Q < 0: v\u1eadt t\u1ecfa nhi\u1ec7t l\u00e0m gi\u1ea3m n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

b)\t\u0394U = A khi A > 0: v\u1eadt nh\u1eadn c\u00f4ng \u0111\u1ec3 l\u00e0m t\u0103ng n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

A < 0: v\u1eadt th\u1ef1c hi\u1ec7n c\u00f4ng l\u00e0m gi\u1ea3m n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

c) \u0394U = Q + A khi Q > 0 v\u00e0 A < 0: qu\u00e1 tr\u00ecnh truy\u1ec1n nhi\u1ec7t v\u00e0 th\u1ef1c hi\u1ec7n c\u00f4ng : thu nhi\u1ec7t v\u00e0 sinh c\u00f4ng.<\/p>\n\n\n\n

d) \u0394U = Q + A khi Q > 0 v\u00e0 A > 0: qu\u00e1 tr\u00ecnh truy\u1ec1n nhi\u1ec7t v\u00e0 th\u1ef1c hi\u1ec7n c\u00f4ng : thu nhi\u1ec7t v\u00e0 nh\u1eadn c\u00f4ng.<\/p>\n\n\n\n

C3.<\/strong> ( trang 178 sgk V\u1eadt L\u00fd 10): V\u1ec1 m\u00f9a \nh\u00e8, ng\u01b0\u1eddi ta c\u00f3 th\u1ec3 d\u00f9ng m\u00e1y \u0111i\u1ec1u h\u00f2a nhi\u1ec7t \u0111\u1ed9 \u0111\u1ec3 truy\u1ec1n nhi\u1ec7t t\u1eeb trong \nph\u00f2ng ra ngo\u00e0i tr\u1eddi, m\u1eb7c d\u00f9 nhi\u1ec7t \u0111\u1ed9 ngo\u00e0i tr\u1eddi cao h\u01a1n trong ph\u00f2ng. H\u1ecfi\n \u0111i\u1ec1u n\u00e0y c\u00f3 vi ph\u1ea1m nguy\u00ean l\u00ed II N\u0110LH kh\u00f4ng? T\u1ea1i sao?<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n

Kh\u00f4ng, v\u00ec nhi\u1ec7t kh\u00f4ng t\u1ef1 truy\u1ec1n t\u1eeb trong ph\u00f2ng ra ngo\u00e0i tr\u1eddi n\u00f3ng h\u01a1n m\u00e0 ph\u1ea3i nh\u1edd m\u00e1y.<\/p>\n\n\n\n

C4.<\/strong> ( trang 178 sgk V\u1eadt L\u00fd 10): \u0110\u1ed9ng c\u01a1 \nnhi\u1ec7t kh\u00f4ng th\u1ec3 chuy\u1ec3n h\u00f3a t\u1ea5t c\u1ea3 nhi\u1ec7t l\u01b0\u1ee3ng nh\u1eadn \u0111\u01b0\u1ee3c th\u00e0nh c\u00f4ng c\u01a1 \nh\u1ecdc. H\u00e3y ch\u1ee9ng minh r\u1eb1ng, c\u00e1ch ph\u00e1t bi\u1ec3u tr\u00ean kh\u00f4ng vi ph\u1ea1m \u0111\u1ecbnh lu\u1eadt \nb\u1ea3o to\u00e0n v\u00e0 chuy\u1ec3n h\u00f3a n\u0103ng l\u01b0\u1ee3ng.<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n

M\u1ed9t ph\u1ea7n nhi\u1ec7t l\u01b0\u1ee3ng \u0111\u1ed9ng c\u01a1 nhi\u1ec7t nh\u1eadn \u0111\u01b0\u1ee3c chuy\u1ec3n h\u00f3a th\u00e0nh c\u00f4ng c\u01a1 h\u1ecdc, ph\u1ea7n con l\u1ea1i \u0111\u01b0\u1ee3c truy\u1ec1n cho ngu\u1ed3n l\u1ea1nh. V\u00ec v\u1eady n\u0103ng l\u01b0\u1ee3ng v\u1eabn \u0111\u01b0\u1ee3c b\u1ea3o to\u00e0n, kh\u00f4ng vi ph\u1ea1m \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n v\u00e0 chuy\u1ec3n h\u00f3a n\u0103ng l\u01b0\u1ee3ng.<\/p>\n\n\n\n

B\u00e0i 3 (trang 179 SGK V\u1eadt L\u00fd 10) :<\/strong> Trong c\u00e1c h\u1ec7 th\u1ee9c sau, h\u1ec7 th\u1ee9c n\u00e0o di\u1ec5n t\u1ea3 qu\u00e1 tr\u00ecnh nung n\u00f3ng khi trong m\u1ed9t b\u00ecnh k\u00edn khi b\u1ecf qua s\u1ef1 n\u1edf v\u00ec nhi\u1ec7t c\u1ee7a b\u00ecnh?<\/ins><\/p>\n\n\n\n

A. \u0394U = A ;         B. \u0394U = Q + A<\/p>\n\n\n\n

C. \u0394U = 0 ;         D. \u0394U = Q.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

– Ch\u1ecdn D<\/strong>. <\/p>\n\n\n\n

– Qu\u00e1 tr\u00ecnh nung n\u00f3ng kh\u00ed trong b\u00ecnh k\u00edn l\u00e0 qu\u00e1 tr\u00ecnh \u0111\u1eb3ng t\u00edch => A = 0<\/p>\n\n\n\n

=> \u0394U = Q. Hay nhi\u1ec7t l\u01b0\u1ee3ng m\u00e0 ch\u1ea5t kh\u00ed nh\u1eadn \u0111\u01b0\u1ee3c ch\u1ec9 d\u00f9ng l\u00e0m t\u0103ng n\u1ed9i n\u0103ng.<\/p>\n\n\n\n

B\u00e0i 4 (trang 180 SGK V\u1eadt L\u00fd 10) :<\/strong> Trong qu\u00e1 tr\u00ecnh ch\u1ea5t kh\u00ed nh\u1eadn nhi\u1ec7t v\u00e0 sinh c\u00f4ng th\u00ec Q v\u00e0 A trong h\u1ec7 th\u1ee9c \u03b4U = A + Q ph\u1ea3i c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o sau \u0111\u00e2y?<\/p>\n\n\n\n

A. Q < 0 v\u00e0 A > 0<\/ins><\/p>\n\n\n\n

B. Q > 0 v\u00e0 A > 0<\/p>\n\n\n\n

C. Q > 0 v\u00e0 A < 0<\/p>\n\n\n\n

D. Q < 0 v\u00e0 A < 0<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

– Ch\u1ecdn C<\/strong>.<\/p>\n\n\n\n

– V\u00ec v\u1eadt nh\u1eadn nhi\u1ec7t th\u00ec Q > 0, v\u1eadt sinh c\u00f4ng th\u00ec A < 0.<\/p>\n\n\n\n

B\u00e0i 5 (trang 180 SGK V\u1eadt L\u00fd 10) :<\/strong> Tr\u01b0\u1eddng h\u1ee3p n\u00e0o sau \u0111\u00e2y \u1ee9ng v\u1edbi qu\u00e1 tr\u00ecnh \u0111\u1eb3ng t\u00edch khi nhi\u1ec7t \u0111\u1ed9 t\u0103ng?<\/p>\n\n\n\n

A. \u0394U = Q v\u1edbi A > 0<\/ins><\/p>\n\n\n\n

B. \u0394U = Q + A v\u1edbi A > 0<\/p>\n\n\n\n

C. \u0394U = Q + A v\u1edbi A < 0 <\/p>\n\n\n\n

D. \u0394U = Q v\u1edbi Q < 0<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

– Ch\u1ecdn A<\/strong>.<\/p>\n\n\n\n

– V\u00ec trong qu\u00e1 tr\u00ecnh \u0111\u1eb3ng t\u00ednh nhi\u1ec7t l\u01b0\u1ee3ng m\u00e0 kh\u00ed nh\u1eadn \u0111\u01b0\u1ee3c ch\u1ec9 \u0111\u1ec3 l\u00e0m t\u0103ng n\u1ed9i n\u0103ng c\u1ee7a kh\u00ed.<\/p>\n\n\n\n

B\u00e0i 6 (trang 180 SGK V\u1eadt L\u00fd 10) :<\/strong> Ng\u01b0\u1eddi \nta th\u1ef1c hi\u1ec7n c\u00f4ng 100 J \u0111\u1ec3 n\u00e9n kh\u00ed trong m\u1ed9t xilanh. T\u00ednh \u0111\u1ed9 bi\u1ebfn thi\u00ean \nn\u1ed9i n\u0103ng c\u1ee7a kh\u00ed, bi\u1ebft kh\u00ed truy\u1ec1n ra m\u00f4i tr\u01b0\u1eddng xung quanh nhi\u1ec7t l\u01b0\u1ee3ng \n20 J.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n

\u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c nguy\u00ean l\u00ed I N\u0110LH: \u0394U = A + Q<\/p>\n\n\n\n

V\u00ec ch\u1ea5t kh\u00ed nh\u1eadn c\u00f4ng (kh\u00ed b\u1ecb n\u00e9n) v\u00e0 truy\u1ec1n nhi\u1ec7t n\u00ean A > 0, Q < 0<\/p>\n\n\n\n

Do \u0111\u00f3 : \u0394U = A + Q = 100 \u2013 20 = 80 J.<\/p>\n\n\n\n

B\u00e0i 7 (trang 180 SGK V\u1eadt L\u00fd 10) :<\/strong> Ng\u01b0\u1eddi \nta truy\u1ec1n cho kh\u00ed trong xilanh nhi\u1ec7t l\u01b0\u1ee3ng 100 J. Kh\u00ed n\u1edf ra th\u1ef1c hi\u1ec7n \nc\u00f4ng 70 J \u0111\u1ea9y pit-t\u00f4ng l\u00ean. T\u00ednh \u0111\u1ed9 bi\u1ebfn thi\u00ean n\u1ed9i n\u0103ng c\u1ee7a kh\u00ed.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n

Kh\u00ed trong xilanh nh\u1eadn \u0111\u01b0\u1ee3c nhi\u1ec7t l\u01b0\u1ee3ng => Q > 0.<\/p>\n\n\n\n

Kh\u00ed th\u1ef1c hi\u1ec7n c\u00f4ng => A < 0<\/p>\n\n\n\n

\u0110\u1ed9 bi\u1ebfn thi\u00ean n\u1ed9i n\u0103ng c\u1ee7a kh\u00ed trong xilanh l\u00e0:<\/p>\n\n\n\n

\u0394U = A + Q = 100 – 70 = 30J.<\/p>\n\n\n\n

B\u00e0i 8 (trang 180 SGK V\u1eadt L\u00fd 10) :<\/strong> Khi truy\u1ec1n nhi\u1ec7t l\u01b0\u1ee3ng 6.106<\/sup> J cho kh\u00ed trong m\u1ed9t xilanh h\u00ecnh tr\u1ee5 th\u00ec kh\u00ed n\u1edf ra \u0111\u1ea9y pit-t\u00f4ng l\u00ean l\u00e0m th\u1ec3 t\u00edch c\u1ee7a kh\u00ed t\u0103ng th\u00eam 0,50 m3<\/sup>. T\u00ednh \u0111\u1ed9 bi\u1ebfn thi\u00ean n\u1ed9i n\u0103ng c\u1ee7a kh\u00ed. Bi\u1ebft \u00e1p su\u1ea5t c\u1ee7a kh\u00ed l\u00e0 8.106<\/sup> N\/m2<\/sup> v\u00e0 coi \u00e1p su\u1ea5t n\u00e0y kh\u00f4ng \u0111\u1ed5i trong qu\u00e1 tr\u00ecnh kh\u00ed th\u1ef1c hi\u1ec7n c\u00f4ng.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n

G\u1ecdi S l\u00e0 di\u1ec7n t\u00edch ti\u1ebft di\u1ec7n th\u1eb3ng c\u1ee7a xilanh, h l\u00e0 qu\u00e3ng \u0111\u01b0\u1eddng pitt\u00f4ng d\u1ecbch chuy\u1ec3n, p l\u00e0 \u00e1p su\u1ea5t kh\u00ed trong xilanh, ta c\u00f3:<\/p>\n\n\n\n

V\u00ec \u00e1p su\u1ea5t kh\u00ed kh\u00f4ng \u0111\u1ed5i trong qu\u00e1 tr\u00ecnh kh\u00ed th\u1ef1c hi\u00ean c\u00f4ng n\u00ean \u00e1p l\u1ef1c F l\u00ean pit-t\u00f4ng kh\u00f4ng \u0111\u1ed5i.<\/p>\n\n\n\n

\u2192 C\u00f4ng m\u00e0 ch\u1ea5t kh\u00ed th\u1ef1c hi\u1ec7n c\u00f3 \u0111\u1ed9 l\u1edbn l\u00e0:<\/p>\n\n\n\n

A = F.h = p.S.h = p.\u0394V = 8.106<\/sup>.0,5 = 4.106<\/sup> J.<\/p>\n\n\n\n

V\u00ec ch\u1ea5t kh\u00ed th\u1ef1c hi\u1ec7n c\u00f4ng v\u00e0 nh\u1eadn nhi\u1ec7t n\u00ean theo quy d\u1ea5u ta c\u00f3: Q > 0, A < 0<\/p>\n\n\n\n

Ta c\u00f3: \u0394U = A + Q = – 4.106<\/sup> + 6.106<\/sup> = 2.106<\/sup> (J)<\/p>\n\n\n\n

V\u1eady \u0111\u1ed9 bi\u1ebfn thi\u00ean n\u1ed9i n\u0103ng c\u1ee7a kh\u00ed l\u00e0 \u0394U = 2.106<\/sup> (J)<\/p>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 33 : C\u00e1c nguy\u00ean l\u00ed c\u1ee7a nhi\u1ec7t \u0111\u1ed9ng l\u1ef1c h\u1ecdc C1. ( trang 176 sgk V\u1eadt L\u00fd 10): X\u00e1c \u0111\u1ecbnh d\u1ea5u c\u1ee7a c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng trong h\u1ec7 th\u1ee9c c\u1ee7a nguy\u00ean l\u00ed I N\u0110LH cho c\u00e1c qu\u00e1 tr\u00ecnh h\u1ec7 thu nhi\u1ec7t l\u01b0\u1ee3ng \u0111\u1ec3 t\u0103ng n\u1ed9i n\u0103ng \u0111\u1ed3ng th\u1eddi th\u1ef1c hi\u1ec7n c\u00f4ng. Tr\u1ea3 l\u1eddi: H\u1ec7 th\u1ee9c […]<\/p>\n","protected":false},"author":12,"featured_media":44188,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1640],"tags":[],"yoast_head":"\nGi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 33 : C\u00e1c nguy\u00ean l\u00ed c\u1ee7a nhi\u1ec7t \u0111\u1ed9ng l\u1ef1c h\u1ecdc<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-33-cac-nguyen-li-cua-nhiet-dong-luc-hoc\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 33 : C\u00e1c nguy\u00ean l\u00ed c\u1ee7a nhi\u1ec7t \u0111\u1ed9ng l\u1ef1c h\u1ecdc\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 33 : C\u00e1c nguy\u00ean l\u00ed c\u1ee7a nhi\u1ec7t \u0111\u1ed9ng l\u1ef1c h\u1ecdc C1. ( trang 176 sgk V\u1eadt L\u00fd 10): X\u00e1c \u0111\u1ecbnh d\u1ea5u c\u1ee7a c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng trong h\u1ec7 th\u1ee9c c\u1ee7a nguy\u00ean l\u00ed I N\u0110LH cho c\u00e1c qu\u00e1 tr\u00ecnh h\u1ec7 thu nhi\u1ec7t l\u01b0\u1ee3ng \u0111\u1ec3 t\u0103ng n\u1ed9i n\u0103ng \u0111\u1ed3ng th\u1eddi th\u1ef1c hi\u1ec7n c\u00f4ng. 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