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{"id":44168,"date":"2019-10-13T14:05:21","date_gmt":"2019-10-13T07:05:21","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=44168"},"modified":"2019-10-13T14:05:22","modified_gmt":"2019-10-13T07:05:22","slug":"giai-vat-li-10-bai-27-co-nang","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-27-co-nang\/","title":{"rendered":"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 27 : C\u01a1 n\u0103ng"},"content":{"rendered":"\n

B\u00e0i 27 : C\u01a1 n\u0103ng<\/h2>\n\n\n\n

C1<\/strong> (trang 143 sgk V\u1eadt L\u00fd 10): Con l\u1eafc \u0111\u01a1n\n t\u1ea1o b\u1edfi m\u1ed9t v\u1eadt n\u1eb7ng nh\u1ecf g\u1eafn v\u00e0o \u0111\u1ea7u m\u1ed9t s\u1ee3i d\u00e2y m\u1ea3nh kh\u00f4ng co d\u00e3n, \u0111\u1ea7u\n kia c\u1ee7a d\u00e2y g\u1eafn c\u1ed1 \u0111\u1ecbnh t\u1ea1i C (H\u00ecnh 27.2). \u0110\u01b0a v\u1eadt l\u00ean v\u1ecb tr\u00ed A r\u1ed3i th\u1ea3\n nh\u1eb9 nh\u00e0ng, v\u1eadt s\u1ebd \u0111i xu\u1ed1ng \u0111\u1ebfn O (v\u1ecb tr\u00ed th\u1ea5p nh\u1ea5t ) r\u1ed3i \u0111i l\u00ean \u0111\u1ebfn B, \nsau \u0111\u00f3 quay l\u1ea1i v\u00e0 dao \u0111\u1ed9ng c\u1ee9 th\u1ebf ti\u1ebfp di\u1ec5n. N\u1ebfu kh\u00f4ng c\u00f3 t\u00e1c d\u1ee5ng c\u1ee7a \nc\u00e1c l\u1ef1c c\u1ea3n, l\u1ef1c ma s\u00e1t :<\/ins><\/p>\n\n\n\n

a) Ch\u1ee9ng minh r\u1eb1ng A v\u00e0 B \u0111\u1ed1i x\u1ee9ng v\u1edbi nhau qua CO.<\/p>\n\n\n\n

b) V\u1ecb tr\u00ed n\u00e0o \u0111\u1ed9ng n\u0103ng c\u1ef1c \u0111\u1ea1i? C\u1ef1c ti\u1ec3u?<\/p>\n\n\n\n

c) Trong qu\u00e1 tr\u00ecnh n\u00e0o \u0111\u1ed9ng n\u0103ng chuy\u1ec3n h\u00f3a th\u00e0nh th\u1ebf n\u0103ng v\u00e0 ng\u01b0\u1ee3c l\u1ea1i?<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n

a) \u00c1p d\u1ee5ng \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n c\u01a1 n\u0103ng:\n<\/p>\n\n\n\n

WA<\/sub> = WB<\/sub> \u21d4 mgzA<\/sub> + 0 = mgzB<\/sub> + 0 \u21d4 zA<\/sub> = zB<\/sub>\n <\/p>\n\n\n\n

\u21d2 A v\u00e0 B \u0111\u1ed1i x\u1ee9ng nhau qua CO.\n<\/p>\n\n\n\n

(t\u1ea1i A v\u00e0 B v\u1eadt d\u1eebng l\u1ea1i n\u00ean \u0111\u1ed9ng n\u0103ng b\u1eb1ng 0)\n<\/p>\n\n\n\n

b) Ch\u1ecdn g\u1ed1c th\u1ebf n\u0103ng t\u1ea1i O (l\u00e0 v\u1ecb tr\u00ed th\u1ea5p nh\u1ea5t)\n<\/p>\n\n\n\n

\u2217 T\u1ea1i A v\u00e0 B c\u00f3 \u0111\u1ed9 cao l\u1edbn nh\u1ea5t, v\u1eadt d\u1eebng l\u1ea1i n\u00ean:\n<\/p>\n\n\n\n

W\u0111<\/sub>(A) = W\u0111<\/sub>(B) = 0\n<\/p>\n\n\n\n

Wt<\/sub>(A) = Wt<\/sub>(B) = mgzmax<\/sub> = Wtmax<\/sub>\n<\/p>\n\n\n\n

T\u1ea1i O: V\u1eadt c\u00f3 v\u1eadn t\u1ed1c l\u1edbn nh\u1ea5t khi chuy\u1ec3n \u0111\u1ed9ng qua O n\u00ean:\n<\/p>\n\n\n\n

Wt<\/sub>(O) = 0, W\u0111<\/sub>(O) = (1\/2). mvo max<\/sub>2<\/sup> = W\u0111(max)zA\n<\/sub><\/p>\n\n\n\n

c) Qu\u00e1 tr\u00ecnh qu\u1ea3 c\u1ea7u nh\u1ecf c\u1ee7a con l\u1eafc chuy\u1ec3n \u0111\u1ed9ng t\u1eeb bi\u00ean A v\u1ec1 O th\u1ebf \nn\u0103ng gi\u1ea3m d\u1ea7n, chuy\u1ec3n h\u00f3a th\u00e0nh \u0111\u1ed9ng n\u0103ng. Ng\u01b0\u1ee3c l\u1ea1i khi con l\u1eafc chuy\u1ec3n \n\u0111\u1ed9ng t\u1eeb O v\u1ec1 A th\u00ec \u0111\u1ed9ng n\u0103ng gi\u1ea3m d\u1ea7n, chuy\u1ec3n h\u00f3a d\u1ea7n th\u00e0nh th\u1ebf n\u0103ng.\n<\/ins><\/p>\n\n\n\n

c) Qu\u00e1 tr\u00ecnh qu\u1ea3 c\u1ea7u nh\u1ecf c\u1ee7a con l\u1eafc chuy\u1ec3n \u0111\u1ed9ng t\u1eeb bi\u00ean A v\u1ec1 O th\u1ebf n\u0103ng gi\u1ea3m d\u1ea7n, chuy\u1ec3n h\u00f3a th\u00e0nh \u0111\u1ed9ng n\u0103ng.<\/p>\n\n\n\n

C2<\/strong> (trang 144 sgk V\u1eadt L\u00fd 10): M\u1ed9t v\u1eadt nh\u1ecf\n tr\u01b0\u1ee3t kh\u00f4ng v\u1eadn t\u1ed1c \u0111\u1ea7u t\u1eeb m\u1ed9t \u0111\u1ec9nh d\u1ed1c cao h = 5 (H\u00ecnh 27.3); khi \nxu\u1ed1ng t\u1edbi ch\u00e2n d\u1ed1c B, v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt l\u00e0 v = 6 m\/s. C\u01a1 n\u0103ng c\u1ee7a v\u1eadt c\u00f3 \nb\u1ea3o to\u00e0n kh\u00f4ng ? Gi\u1ea3i th\u00edch?<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n

Ch\u1ecdn m\u1ed1c th\u1ebf n\u0103ng t\u1ea1i ch\u00e2n d\u1ed1c B. \n<\/p>\n\n\n\n

\u2217 C\u01a1 n\u0103ng c\u1ee7a v\u1eadt t\u1ea1i \u0111\u1ec9nh d\u1ed1c A l\u00e0:\n<\/p>\n\n\n\n

WA<\/sub> = mgzA<\/sub> + 0 = 50m (t\u1ea1i A: v = 0 \u21d2 W\u0111<\/sub> = 0)\n<\/p>\n\n\n\n

\u2217 C\u01a1 n\u0103ng t\u1ea1i ch\u00e2n d\u1ed1c B l\u00e0 :\n<\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

\u2217 Nh\u01b0 v\u1eady c\u01a1 n\u0103ng kh\u00f4ng \u0111\u01b0\u1ee3c b\u1ea3o to\u00e0n (WA<\/sub> \u2260 WB<\/sub>).\n<\/p>\n\n\n\n

\u2217 Nguy\u00ean nh\u00e2n: Do c\u00f3 ma s\u00e1t tr\u00ean m\u1eb7t ph\u1eb3ng nghi\u00eang v\u1edbi v\u1eadt khi tr\u01b0\u1ee3t.\n<\/p>\n\n\n\n

\u2217 C\u00f4ng c\u1ee7a l\u1ef1c ma s\u00e1t \u0111\u01b0\u1ee3c t\u00ednh l\u00e0: Ams<\/sub> = WB<\/sub> \u2013 WA<\/sub> = 18 – 50 = -32 (J) (d\u1ea5u \u2013 ch\u1ee9ng t\u1ecf c\u00f4ng l\u1ef1c ma s\u00e1t l\u00e0 c\u00f4ng c\u1ea3n). <\/p>\n\n\n\n

B\u00e0i 6 (trang 144 SGK V\u1eadt L\u00fd 10):<\/strong> Khi c\u00f3 t\u00e1c d\u1ee5ng c\u1ee7a c\u1ea3 tr\u1ecdng l\u1ef1c v\u00e0 l\u1ef1c \u0111\u00e0n h\u1ed3i th\u00ec c\u01a1 n\u0103ng c\u1ee7a v\u1eadt \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 th\u1ebf n\u00e0o?<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n

Khi c\u00f3 t\u00e1c d\u1ee5ng c\u1ee7a c\u1ea3 tr\u1ecdng l\u1ef1c v\u00e0 l\u1ef1c \u0111\u00e0n h\u1ed3i (v\u00ed d\u1ee5 chuy\u1ec3n \u0111\u1ed9ng \nc\u1ee7a v\u1eadt n\u1eb7ng g\u1eafn v\u00e0o \u0111\u1ea7u l\u00f2 xo treo th\u1eb3ng \u0111\u1ee9ng) th\u00ec c\u01a1 n\u0103ng c\u1ee7a v\u1eadt \u0111\u01b0\u1ee3c\n t\u00ednh :<\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

B\u00e0i 7 (trang 145 SGK V\u1eadt L\u00fd 10) :<\/strong> M\u1ed9t v\u1eadt\n nh\u1ecf \u0111\u01b0\u1ee3c n\u00e9m l\u00ean t\u1eeb m\u1ed9t \u0111i\u1ec3m M ph\u00eda tr\u00ean m\u1eb7t \u0111\u1ea5t; v\u1eadt l\u00ean t\u1edbi \u0111i\u1ec3m N \nth\u00ec d\u1eebng v\u00e0 r\u01a1i xu\u1ed1ng . B\u1ecf qua s\u1ee9c c\u1ea3n c\u1ee7a kh\u00f4ng kh\u00ed. Trong qu\u00e1 tr\u00ecnh MN<\/p>\n\n\n\n

A. \u0111\u1ed9ng n\u0103ng t\u0103ng<\/ins><\/p>\n\n\n\n

B. th\u1ebf n\u0103ng gi\u1ea3m<\/p>\n\n\n\n

C. c\u01a1 n\u0103ng c\u1ef1c \u0111\u1ea1i t\u1ea1i N <\/p>\n\n\n\n

D. c\u01a1 n\u0103ng kh\u00f4ng \u0111\u1ed5i <\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

Ch\u1ecdn D. \n<\/p>\n\n\n\n

V\u00ec b\u1ecf qua s\u1ee9c c\u1ea3n c\u1ee7a kh\u00f4ng kh\u00ed n\u00ean trong qu\u00e1 tr\u00ecnh MN c\u01a1 n\u0103ng kh\u00f4ng \u0111\u1ed5i. <\/p>\n\n\n\n

B\u00e0i 8 (trang 145 SGK V\u1eadt L\u00fd 10) :<\/strong>T\u1eeb \u0111i\u1ec3m M\n (c\u00f3 \u0111\u1ed9 cao so v\u1edbi m\u1eb7t \u0111\u1ea5t b\u1eb1ng 0,8 m) n\u00e9m l\u00ean m\u1ed9t v\u1eadt v\u1edbi v\u1eadn t\u1ed1c \u0111\u1ea7u 2\n m\/s. Bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a v\u1eadt b\u1eb1ng 0,5 kg, l\u1ea5y g = 10 m\/s2<\/sup>. C\u01a1 n\u0103ng c\u1ee7a v\u1eadt b\u1eb1ng bao nhi\u00eau? <\/ins><\/p>\n\n\n\n

A. 4 J <\/p>\n\n\n\n

B. 1 J <\/p>\n\n\n\n

C. 5 J <\/p>\n\n\n\n

D. 8 J<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

<\/ins><\/p>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 27 : C\u01a1 n\u0103ng C1 (trang 143 sgk V\u1eadt L\u00fd 10): Con l\u1eafc \u0111\u01a1n t\u1ea1o b\u1edfi m\u1ed9t v\u1eadt n\u1eb7ng nh\u1ecf g\u1eafn v\u00e0o \u0111\u1ea7u m\u1ed9t s\u1ee3i d\u00e2y m\u1ea3nh kh\u00f4ng co d\u00e3n, \u0111\u1ea7u kia c\u1ee7a d\u00e2y g\u1eafn c\u1ed1 \u0111\u1ecbnh t\u1ea1i C (H\u00ecnh 27.2). \u0110\u01b0a v\u1eadt l\u00ean v\u1ecb tr\u00ed A r\u1ed3i th\u1ea3 nh\u1eb9 nh\u00e0ng, v\u1eadt s\u1ebd \u0111i […]<\/p>\n","protected":false},"author":12,"featured_media":44169,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1640],"tags":[],"yoast_head":"\nGi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 27 : C\u01a1 n\u0103ng<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-27-co-nang\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 27 : C\u01a1 n\u0103ng\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 27 : C\u01a1 n\u0103ng C1 (trang 143 sgk V\u1eadt L\u00fd 10): Con l\u1eafc \u0111\u01a1n t\u1ea1o b\u1edfi m\u1ed9t v\u1eadt n\u1eb7ng nh\u1ecf g\u1eafn v\u00e0o \u0111\u1ea7u m\u1ed9t s\u1ee3i d\u00e2y m\u1ea3nh kh\u00f4ng co d\u00e3n, \u0111\u1ea7u kia c\u1ee7a d\u00e2y g\u1eafn c\u1ed1 \u0111\u1ecbnh t\u1ea1i C (H\u00ecnh 27.2). \u0110\u01b0a v\u1eadt l\u00ean v\u1ecb tr\u00ed A r\u1ed3i th\u1ea3 nh\u1eb9 nh\u00e0ng, v\u1eadt s\u1ebd \u0111i […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-27-co-nang\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - 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