C1<\/strong> (trang 143 sgk V\u1eadt L\u00fd 10): Con l\u1eafc \u0111\u01a1n\n t\u1ea1o b\u1edfi m\u1ed9t v\u1eadt n\u1eb7ng nh\u1ecf g\u1eafn v\u00e0o \u0111\u1ea7u m\u1ed9t s\u1ee3i d\u00e2y m\u1ea3nh kh\u00f4ng co d\u00e3n, \u0111\u1ea7u\n kia c\u1ee7a d\u00e2y g\u1eafn c\u1ed1 \u0111\u1ecbnh t\u1ea1i C (H\u00ecnh 27.2). \u0110\u01b0a v\u1eadt l\u00ean v\u1ecb tr\u00ed A r\u1ed3i th\u1ea3\n nh\u1eb9 nh\u00e0ng, v\u1eadt s\u1ebd \u0111i xu\u1ed1ng \u0111\u1ebfn O (v\u1ecb tr\u00ed th\u1ea5p nh\u1ea5t ) r\u1ed3i \u0111i l\u00ean \u0111\u1ebfn B, \nsau \u0111\u00f3 quay l\u1ea1i v\u00e0 dao \u0111\u1ed9ng c\u1ee9 th\u1ebf ti\u1ebfp di\u1ec5n. N\u1ebfu kh\u00f4ng c\u00f3 t\u00e1c d\u1ee5ng c\u1ee7a \nc\u00e1c l\u1ef1c c\u1ea3n, l\u1ef1c ma s\u00e1t :<\/ins><\/p>\n\n\n\n a) Ch\u1ee9ng minh r\u1eb1ng A v\u00e0 B \u0111\u1ed1i x\u1ee9ng v\u1edbi nhau qua CO.<\/p>\n\n\n\n b) V\u1ecb tr\u00ed n\u00e0o \u0111\u1ed9ng n\u0103ng c\u1ef1c \u0111\u1ea1i? C\u1ef1c ti\u1ec3u?<\/p>\n\n\n\n c) Trong qu\u00e1 tr\u00ecnh n\u00e0o \u0111\u1ed9ng n\u0103ng chuy\u1ec3n h\u00f3a th\u00e0nh th\u1ebf n\u0103ng v\u00e0 ng\u01b0\u1ee3c l\u1ea1i?<\/p>\n\n\n\n Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n a) \u00c1p d\u1ee5ng \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n c\u01a1 n\u0103ng:\n<\/p>\n\n\n\n WA<\/sub> = WB<\/sub> \u21d4 mgzA<\/sub> + 0 = mgzB<\/sub> + 0 \u21d4 zA<\/sub> = zB<\/sub>\n <\/p>\n\n\n\n \u21d2 A v\u00e0 B \u0111\u1ed1i x\u1ee9ng nhau qua CO.\n<\/p>\n\n\n\n (t\u1ea1i A v\u00e0 B v\u1eadt d\u1eebng l\u1ea1i n\u00ean \u0111\u1ed9ng n\u0103ng b\u1eb1ng 0)\n<\/p>\n\n\n\n b) Ch\u1ecdn g\u1ed1c th\u1ebf n\u0103ng t\u1ea1i O (l\u00e0 v\u1ecb tr\u00ed th\u1ea5p nh\u1ea5t)\n<\/p>\n\n\n\n \u2217 T\u1ea1i A v\u00e0 B c\u00f3 \u0111\u1ed9 cao l\u1edbn nh\u1ea5t, v\u1eadt d\u1eebng l\u1ea1i n\u00ean:\n<\/p>\n\n\n\n W\u0111<\/sub>(A) = W\u0111<\/sub>(B) = 0\n<\/p>\n\n\n\n Wt<\/sub>(A) = Wt<\/sub>(B) = mgzmax<\/sub> = Wtmax<\/sub>\n<\/p>\n\n\n\n T\u1ea1i O: V\u1eadt c\u00f3 v\u1eadn t\u1ed1c l\u1edbn nh\u1ea5t khi chuy\u1ec3n \u0111\u1ed9ng qua O n\u00ean:\n<\/p>\n\n\n\n Wt<\/sub>(O) = 0, W\u0111<\/sub>(O) = (1\/2). mvo max<\/sub>2<\/sup> = W\u0111(max)zA\n<\/sub><\/p>\n\n\n\n c) Qu\u00e1 tr\u00ecnh qu\u1ea3 c\u1ea7u nh\u1ecf c\u1ee7a con l\u1eafc chuy\u1ec3n \u0111\u1ed9ng t\u1eeb bi\u00ean A v\u1ec1 O th\u1ebf \nn\u0103ng gi\u1ea3m d\u1ea7n, chuy\u1ec3n h\u00f3a th\u00e0nh \u0111\u1ed9ng n\u0103ng. Ng\u01b0\u1ee3c l\u1ea1i khi con l\u1eafc chuy\u1ec3n \n\u0111\u1ed9ng t\u1eeb O v\u1ec1 A th\u00ec \u0111\u1ed9ng n\u0103ng gi\u1ea3m d\u1ea7n, chuy\u1ec3n h\u00f3a d\u1ea7n th\u00e0nh th\u1ebf n\u0103ng.\n<\/ins><\/p>\n\n\n\n c) Qu\u00e1 tr\u00ecnh qu\u1ea3 c\u1ea7u nh\u1ecf c\u1ee7a con l\u1eafc chuy\u1ec3n \u0111\u1ed9ng t\u1eeb bi\u00ean A v\u1ec1 O th\u1ebf n\u0103ng gi\u1ea3m d\u1ea7n, chuy\u1ec3n h\u00f3a th\u00e0nh \u0111\u1ed9ng n\u0103ng.<\/p>\n\n\n\n C2<\/strong> (trang 144 sgk V\u1eadt L\u00fd 10): M\u1ed9t v\u1eadt nh\u1ecf\n tr\u01b0\u1ee3t kh\u00f4ng v\u1eadn t\u1ed1c \u0111\u1ea7u t\u1eeb m\u1ed9t \u0111\u1ec9nh d\u1ed1c cao h = 5 (H\u00ecnh 27.3); khi \nxu\u1ed1ng t\u1edbi ch\u00e2n d\u1ed1c B, v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt l\u00e0 v = 6 m\/s. C\u01a1 n\u0103ng c\u1ee7a v\u1eadt c\u00f3 \nb\u1ea3o to\u00e0n kh\u00f4ng ? Gi\u1ea3i th\u00edch?<\/p>\n\n\n\n Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n Ch\u1ecdn m\u1ed1c th\u1ebf n\u0103ng t\u1ea1i ch\u00e2n d\u1ed1c B. \n<\/p>\n\n\n\n \u2217 C\u01a1 n\u0103ng c\u1ee7a v\u1eadt t\u1ea1i \u0111\u1ec9nh d\u1ed1c A l\u00e0:\n<\/p>\n\n\n\n WA<\/sub> = mgzA<\/sub> + 0 = 50m (t\u1ea1i A: v = 0 \u21d2 W\u0111<\/sub> = 0)\n<\/p>\n\n\n\n \u2217 C\u01a1 n\u0103ng t\u1ea1i ch\u00e2n d\u1ed1c B l\u00e0 :\n<\/p>\n\n\n\n