(cho b\u1edfi th\u00ed nghi\u1ec7m) b\u1eb1ng c\u00e1ch v\u1eadn d\u1ee5ng qui t\u1eafc momen l\u1ef1c \u0111\u1ed1i v\u1edbi tr\u1ee5c quay O.<\/p>\n\n\n\n
Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\nL\u1ef1c k\u1ebf ch\u1ec9 F b\u1eb1ng t\u1ed5ng \u0111\u1ed9 l\u1edbn P1<\/sub> v\u00e0 P2<\/sub>, t\u1ee9c: F = P1<\/sub> + P2<\/sub>.\n<\/p>\n\n\n\nG\u1ecdi tr\u1ee5c quay l\u00e0 O, \u00e1p d\u1ee5ng quy t\u1eafc momen l\u1ef1c cho tr\u1ee5c quay O , ta c\u00f3:\n<\/p>\n\n\n\n
P1<\/sub>.d1<\/sub> = P2<\/sub>. d2<\/sub> (d1<\/sub> = OO1<\/sub> v\u00e0 d2<\/sub> = OO2<\/sub>) \n<\/p>\n\n\n\n<\/ins><\/p>\n\n\n\nC2<\/strong> (trang 104 sgk V\u1eadt L\u00fd 10): Coi th\u01b0\u1edbc l\u00e0 m\u1ed9t \u0111o\u1ea1n th\u1eb3ng n\u1eb1m ngang. H\u00e3y bi\u1ec3u di\u1ec5n c\u00e1c vecto l\u1ef1c P1<\/sub>, P2<\/sub> v\u00e0 h\u1ee3p l\u1ef1c P c\u1ee7a ch\u00fang.<\/p>\n\n\n\nTr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\nKhi treo chung hai ch\u00f9m qu\u1ea3 c\u00e2n v\u00e0o t\u00e2m O, ta c\u00f3 h\u1ee3p l\u1ef1c:\n<\/p>\n\n\n\nC3<\/strong> (trang 105 sgk V\u1eadt L\u00fd 10): <\/p>\n\n\n\na) T\u1ea1i sao tr\u1ecdng t\u00e2m c\u1ee7a chi\u1ebfc nh\u1eabn l\u1ea1i n\u1eb1m ngo\u00e0i ph\u1ea7n v\u1eadt ch\u1ea5t c\u1ee7a v\u1eadt (H\u00ecnh 19.5)?<\/p>\n\n\n\n
b) N\u00eau m\u1ed9t s\u1ed1 v\u1eadt kh\u00e1c c\u00f3 tr\u1ecdng t\u00e2m n\u1eb1m ngo\u00e0i ph\u1ea7n v\u1eadt ch\u1ea5t c\u1ee7a v\u1eadt.<\/p>\n\n\n\n
Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\na) X\u00e9t m\u1ed9t ph\u1ea7n nh\u1ecf c\u1ee7a nh\u1eabn c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng \u0394m, ta lu\u00f4n t\u00ecm \u0111\u01b0\u1ee3c ph\u1ea7n \nkh\u1ed1i l\u01b0\u1ee3ng \u0394m’ = \u0394m v\u00e0 \u0111\u1ed1i x\u1ee9ng v\u1edbi nhau qua t\u00e2m O c\u1ee7a nh\u1eabn.<\/p>\n\n\n\n
\u0394m’ v\u00e0 \u0394m ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a tr\u1ecdng l\u1ef1c t\u01b0\u01a1ng \u1ee9ng l\u00e0 <\/p>\n\n\n\n\u0110\u00e2y l\u00e0 hai l\u1ef1c song song, c\u00f9ng chi\u1ec1u, \u0111\u1ed1i x\u1ee9ng qua O n\u00ean h\u1ee3p l\u1ef1c c\u1ee7a ch\u00fang n\u1eb1m \u1edf t\u00e2m O v\u00e0 Phl<\/sub> = P + P’.<\/p>\n\n\n\nX\u00e9t cho v\u00f4 s\u1ed1 c\u1eb7p kh\u1ed1i l\u01b0\u1ee3ng \u0111\u1ed1i x\u1ee9ng qua O , ta \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 t\u01b0\u01a1ng \nt\u1ef1. K\u1ebft qu\u1ea3 t\u1ed5ng h\u1ee3p c\u1ee7a v\u00f4 s\u1ed1 l\u1ef1c song song, \u0111\u1ed1i x\u1ee9ng nhau t\u1eebng c\u1eb7p s\u1ebd \nl\u00e0 tr\u1ecdng l\u1ef1c P c\u1ee7a c\u1ea3 v\u00f2ng nh\u1eabn v\u00e0 \u0111\u1eb7t t\u1ea1i t\u00e2m O.<\/ins><\/p>\n\n\n\nb) C\u00e1c thanh g\u1ed7, kim lo\u1ea1i,\u2026 gh\u00e9p th\u00e0nh h\u00ecnh tam gi\u00e1c, h\u00ecnh vu\u00f4ng, h\u00ecnh ch\u1eef nh\u1eadt\u2026<\/p>\n\n\n\n
C4<\/strong> (trang 106 sgk V\u1eadt L\u00fd 10): V\u1eadn d\u1ee5ng \nquy t\u1eafc h\u1ee3p l\u1ef1c song song c\u00f9ng chi\u1ec1u, h\u00e3y n\u00eau nh\u1eefng \u0111\u1eb7c \u0111i\u1ec3m c\u1ee7a h\u1ec7 ba \nl\u1ef1c song song c\u00e2n b\u1eb1ng (H\u00ecnh 19.6).<\/p>\n\n\n\nTr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n+ Ba l\u1ef1c ph\u1ea3i c\u00f3 gi\u00e1 \u0111\u1ed3ng ph\u1eb3ng.<\/p>\n\n\n\n
+ Hai l\u1ef1c song song v\u00e0 c\u00f9ng chi\u1ec1u ph\u1ea3i \u1edf ngo\u00e0i, l\u1ef1c c\u00f2n l\u1ea1i ph\u1ea3i ng\u01b0\u1ee3c chi\u1ec1u v\u1edbi hai l\u1ef1c v\u00e0 \u1edf trong.<\/p>\n\n\n\n
+ H\u1ee3p l\u1ef1c c\u1ee7a hai l\u1ef1c \u1edf ngo\u00e0i ph\u1ea3i c\u00e2n b\u1eb1ng v\u1edbi l\u1ef1c \u1edf trong.<\/p>\n\n\n\n
B\u00e0i 2 (trang 106 SGK V\u1eadt L\u00fd 10) :<\/strong> M\u1ed9t \nng\u01b0\u1eddi g\u00e1nh m\u1ed9t th\u00f9ng g\u1ea1o n\u1eb7ng 300 N v\u00e0 m\u1ed9t th\u00f9ng ng\u00f4 n\u1eb7ng 200 N. \u0110\u00f2n \ng\u00e1nh d\u00e0i 1 m. H\u1ecfi vai ng\u01b0\u1eddi \u0111\u00f3 ph\u1ea3i \u0111\u1eb7t \u1edf \u0111i\u1ec3m n\u00e0o, ch\u1ecbu m\u1ed9t l\u1ef1c b\u1eb1ng \nbao nhi\u00eau? B\u1ecf qua tr\u1ecdng l\u1ef1c c\u1ee7a \u0111\u00f2n g\u00e1nh.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\nH\u00ecnh bi\u1ec3u di\u1ec5n l\u1ef1c:<\/p>\n\n\n\n\u00c1p d\u1ee5ng quy t\u1eafc h\u1ee3p l\u1ef1c hai l\u1ef1c song song c\u00f9ng chi\u1ec1u:<\/p>\n\n\n\n<\/ins><\/p>\n\n\n\nM\u1eb7t kh\u00e1c ta c\u00f3:<\/p>\n\n\n\n
d1<\/sub> + d2<\/sub> = AB = 1 m (2)<\/p>\n\n\n\nT\u1eeb (1), (2) ta c\u00f3 h\u1ec7 ph\u01b0\u01a1ng tr\u00ecnh sau:\n\n<\/p>\n\n\n\n
Vai ng\u01b0\u1eddi g\u00e1nh ch\u1ecbu m\u1ed9t l\u1ef1c l\u00e0:<\/p>\n\n\n\n
\u00a0\u00a0\u00a0P = Pg\u1ea1o<\/sub> + Png\u00f4<\/sub> = 300 + 200 = 500<\/strong> (N).<\/p>\n\n\n\nB\u00e0i 3 (trang 106 SGK V\u1eadt L\u00fd 10) :<\/strong> Hai \nng\u01b0\u1eddi d\u00f9ng m\u1ed9t chi\u1ebfc g\u1eady \u0111\u1ec3 khi\u00eang m\u1ed9t c\u1ed7 m\u00e1y n\u1eb7ng 1000 N. \u0110i\u1ec3m treo c\u1ed7 \nm\u00e1y c\u00e1ch vai ng\u01b0\u1eddi \u0111i tr\u01b0\u1edbc 60 cm v\u00e0 c\u00e1ch vai ng\u01b0\u1eddi \u0111i sau 40 cm. B\u1ecf qua\n tr\u1ecdng l\u01b0\u1ee3ng c\u1ee7a g\u1eady, h\u1ecfi m\u1ed7i ng\u01b0\u1eddi ch\u1ecbu m\u1ed9t l\u1ef1c b\u1eb1ng bao nhi\u00eau?<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\nG\u1ecdi P1<\/sub> l\u00e0 l\u1ef1c t\u00e1c d\u1ee5ng l\u00ean vai ng\u01b0\u1eddi \u0111i tr\u01b0\u1edbc, P2<\/sub> l\u00e0 l\u1ef1c t\u00e1c d\u1ee5ng l\u00ean vai ng\u01b0\u1eddi \u0111i sau, ta \u0111\u00e3 c\u00f3: d1<\/sub> = OO1<\/sub> = 60 cm; d2<\/sub> = OO2<\/sub> = 40 cm.\n<\/p>\n\n\n\n\u00c1p d\u1ee5ng quy t\u1eafc h\u1ee3p l\u1ef1c hai l\u1ef1c song song c\u00f9ng chi\u1ec1u ta \u0111\u01b0\u1ee3c:\n<\/p>\n\n\n\nGi\u1ea3i h\u1ec7 (1) v\u00e0 (2) ta \u0111\u01b0\u1ee3c: P1<\/sub> = 400 N, P2<\/sub> = 600 N <\/p>\n\n\n\nB\u00e0i 4 (trang 106 SGK V\u1eadt L\u00fd 10) :<\/strong> M\u1ed9t t\u1ea5m\n v\u00e1n n\u1eb7ng 240 N \u0111\u01b0\u1ee3c b\u1eafc qua m\u1ed9t con m\u01b0\u01a1ng. Tr\u1ecdng t\u00e2m c\u1ee7a t\u1ea5m v\u00e1n c\u00e1ch \n\u0111i\u1ec3m t\u1ef1a A 2,4 m v\u00e0 c\u00e1ch \u0111i\u1ec3m t\u1ef1a B 1,2 m. H\u1ecfi l\u1ef1c m\u00e0 t\u1ea5m v\u00e1n t\u00e1c d\u1ee5ng \nl\u00ean \u0111i\u1ec3m t\u1ef1a A b\u1eb1ng bao nhi\u00eau?<\/p>\n\n\n\nA.\t160 N <\/ins><\/p>\n\n\n\nB. 80 N <\/p>\n\n\n\n
C. 120 N <\/p>\n\n\n\n
D. 60 N<\/p>\n\n\n\n
L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\nCh\u1ecdn B.\n<\/p>\n\n\n\n
Bi\u1ec3u di\u1ec5n l\u1ef1c nh\u01b0 h\u00ecnh v\u1ebd sau:\n<\/p>\n\n\n\nGi\u1ea3i h\u1ec7 (1) v\u00e0 (2) ta \u0111\u01b0\u1ee3c: P1<\/sub> = 80 N; P2<\/sub> = 160 N. <\/p>\n\n\n\nB\u00e0i 5 (trang 106 SGK V\u1eadt L\u00fd 10) :<\/strong> H\u00e3y x\u00e1c\n \u0111\u1ecbnh tr\u1ecdng t\u00e2m c\u1ee7a m\u1ed9t b\u1ea3n ph\u1eb3ng m\u1ecfng, \u0111\u1ed3ng ch\u1ea5t, h\u00ecnh ch\u1eef nh\u1eadt, d\u00e0i 12\n cm, r\u1ed9ng 6 cm, b\u1ecb c\u1eaft m\u1ea5t m\u1ed9t ph\u1ea7n h\u00ecnh vu\u00f4ng c\u00f3 c\u1ea1nh 3 cm \u1edf m\u1ed9t g\u00f3c \n(H\u00ecnh 19.7).<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\nB\u1ea3n ph\u1eb3ng coi nh\u01b0 g\u1ed3m hai b\u1ea3n AHEF v\u00e0 HBCD gh\u00e9p l\u1ea1i. \n<\/p>\n\n\n\n
Bi\u1ec3u di\u1ec5n tr\u1ecdng t\u00e2m c\u00e1c b\u1ea3n nh\u01b0 h\u00ecnh v\u1ebd sau:\n<\/p>\n\n\n\nV\u00ec c\u00e1c b\u1ea3n \u0111\u1ed3ng ch\u1ea5t, ph\u1eb3ng m\u1ecfng \u0111\u1ec1u n\u00ean t\u1ec9 l\u1ec7 di\u1ec7n t\u00edch b\u1eb1ng t\u1ec9 l\u1ec7 v\u1ec1 tr\u1ecdng l\u01b0\u1ee3ng:\n<\/p>\n\n\n\n<\/ins><\/p>\n\n\n\nG\u1ecdi G l\u00e0 tr\u1ecdng t\u00e2m c\u1ee7a c\u1ea3 b\u1ea3n ph\u1eb3ng \u21d2 G ph\u1ea3i n\u1eb1m tr\u1ec1n \u0111o\u1ea1n th\u1eb3ng O1<\/sub>O2<\/sub>, trong \u0111\u00f3 O1<\/sub> l\u00e0 tr\u1ecdng t\u00e2m c\u1ee7a b\u1ea3n AHEF, O2<\/sub> l\u00e0 tr\u1ecdng t\u00e2m c\u1ee7a b\u1ea3n HBCD.\n<\/p>\n\n\n\nTa c\u00f3:\n<\/p>\n\n\n\nX\u00e9t tam gi\u00e1c vu\u00f4ng O1<\/sub>O2<\/sub>K ta c\u00f3:\n<\/p>\n\n\n\nGi\u1ea3i h\u1ec7 (1) v\u00e0 (2) ta \u0111\u01b0\u1ee3c: GG1<\/sub> \u2248 0,88 cm\n<\/p>\n\n\n\nV\u1eady tr\u1ecdng t\u00e2m G c\u1ee7a b\u1ea3n ph\u1eb3ng n\u1eb1m tr\u00ean \u0111o\u1ea1n O1<\/sub>O2<\/sub> c\u00e1ch O1<\/sub> m\u1ed9t \u0111o\u1ea1n 0,88 cm.\n<\/p>\n","protected":false},"excerpt":{"rendered":"B\u00e0i 19 : Quy t\u1eafc h\u1ee3p l\u1ef1c song song c\u00f9ng chi\u1ec1u C1 (trang 104 sgk V\u1eadt L\u00fd 10): a) L\u1ef1c k\u1ebf ch\u1ec9 gi\u00e1 tr\u1ecb F b\u1eb1ng bao nhi\u00eau? b) Ch\u1ee9ng minh r\u1eb1ng, c\u00f3 th\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c t\u1ec9 s\u1ed1 (cho b\u1edfi th\u00ed nghi\u1ec7m) b\u1eb1ng c\u00e1ch v\u1eadn d\u1ee5ng qui t\u1eafc momen l\u1ef1c \u0111\u1ed1i v\u1edbi tr\u1ee5c quay O. […]<\/p>\n","protected":false},"author":12,"featured_media":44145,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1640],"tags":[],"yoast_head":"\n
Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 19 : Quy t\u1eafc h\u1ee3p l\u1ef1c song song c\u00f9ng chi\u1ec1u<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-19-quy-tac-hop-luc-song-song-cung-chieu\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 19 : Quy t\u1eafc h\u1ee3p l\u1ef1c song song c\u00f9ng chi\u1ec1u\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 19 : Quy t\u1eafc h\u1ee3p l\u1ef1c song song c\u00f9ng chi\u1ec1u C1 (trang 104 sgk V\u1eadt L\u00fd 10): a) L\u1ef1c k\u1ebf ch\u1ec9 gi\u00e1 tr\u1ecb F b\u1eb1ng bao nhi\u00eau? b) Ch\u1ee9ng minh r\u1eb1ng, c\u00f3 th\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c t\u1ec9 s\u1ed1 (cho b\u1edfi th\u00ed nghi\u1ec7m) b\u1eb1ng c\u00e1ch v\u1eadn d\u1ee5ng qui t\u1eafc momen l\u1ef1c \u0111\u1ed1i v\u1edbi tr\u1ee5c quay O. 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![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-19-c-1-trang-104-sgk-vat-ly-10.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-19-c-1-trang-104-sgk-vat-ly-10-1.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-19-c-2-trang-104-sgk-ly-10.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-19-c-3-trang-105-sgk-ly-10.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-2-trang-106-sgk-vat-ly-10.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-2-trang-106-sgk-vat-ly-10-1.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-2-trang-106-sgk-vat-ly-10-2.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-3-trang-106-sgk-vat-ly-10.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-3-trang-106-sgk-vat-ly-10-1.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-4-trang-106-sgk-ly-10.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-4-trang-106-sgk-ly-10-1.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-5-trang-106-sgk-vat-ly-10.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-5-trang-106-sgk-vat-ly-10-1.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-5-trang-106-sgk-vat-ly-10-2.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-5-trang-106-sgk-vat-ly-10-3.PNG\")
<\/figure>\n\n\n\n