Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\nTr\u1ecdng t\u00e2m c\u1ee7a th\u01b0\u1edbc \u1edf ch\u1ed7 m\u00e0 khi \u0111\u1eb7t ng\u00f3n tay \u1edf \u0111\u00f3 th\u00ec th\u01b0\u1edbc n\u1eb1m c\u00e2n \nb\u1eb1ng. V\u00ec khi \u0111\u00f3 tr\u1ecdng l\u1ef1c n\u1eb1m c\u00e2n b\u1eb1ng v\u1edbi ph\u1ea3n l\u1ef1c gi\u00e1 \u0111\u1ee1 (tay \u0111\u1ee1).<\/p>\n\n\n\n
C3.<\/strong> ( trang 98 sgk V\u1eadt L\u00fd 10): C\u00f3 nh\u1eadn x\u00e9t g\u00ec v\u1ec1 gi\u00e1 c\u1ee7a ba l\u1ef1c?<\/p>\n\n\n\nTr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\nGi\u00e1 c\u1ee7a ba l\u1ef1c c\u00f9ng n\u1eb1m trong m\u1ed9t m\u1eb7t ph\u1eb3ng c\u1ee7a v\u1eadt ph\u1eb3ng m\u1ecfng.<\/p>\n\n\n\n
B\u00e0i 6 (trang 100 SGK V\u1eadt L\u00fd 10) :<\/strong> M\u1ed9t \nv\u1eadt c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m = 2 kg \u0111\u01b0\u1ee3c gi\u1eef y\u00ean tr\u00ean m\u1ed9t m\u1eb7t ph\u1eb3ng nghi\u00eang b\u1edfi \nm\u1ed9t s\u1ee3i d\u00e2y song song v\u1edbi \u0111\u01b0\u1eddng d\u1ed1c ch\u00ednh (H\u00ecnh 17.9). Bi\u1ebft g\u00f3c nghi\u00eang \u03b1\n = 30o<\/sup>, g = 9,8 m\/s2<\/sup> v\u00e0 ma s\u00e1t l\u00e0 kh\u00f4ng \u0111\u00e1ng k\u1ec3. H\u00e3y x\u00e1c \u0111\u1ecbnh:<\/ins><\/p>\n\n\n\n\n\na)\tl\u1ef1c c\u0103ng c\u1ee7a d\u00e2y. \n\nb)\tph\u1ea3n l\u1ef1c c\u1ee7a m\u1eb7t ph\u1eb3ng nghi\u00eang l\u00ean v\u1eadt.\n\n\n<\/p>\n\n\n\n
L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\nH\u00ecnh bi\u1ec3u di\u1ec5n l\u1ef1c:<\/p>\n\n\n\n<\/ins><\/p>\n\n\n\na)\tV\u00ec v\u1eadt n\u1eb1m c\u00e2n b\u1eb1ng n\u00ean ta c\u00f3:\n<\/p>\n\n\n\nHay \n<\/p>\n\n\n\n(\u1edf \u0111\u00e2y ta ph\u00e2n t\u00edch tr\u1ecdng l\u1ef1c P th\u00e0nh 2 l\u1ef1c th\u00e0nh ph\u1ea7n Px<\/sub> v\u00e0 Py<\/sub>)\n<\/p>\n\n\n\nChi\u1ebfu (\u2217) l\u00ean tr\u1ee5c Ox ta c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh v\u1ec1 \u0111\u1ed9 l\u1edbn sau:\n<\/p>\n\n\n\n
T = Px<\/sub> = P.sin30o<\/sup> = m.g.sin30o<\/sup> = 2. 9,8. 0,5 = 9,8 N.\n<\/p>\n\n\n\nb)\tPh\u1ea3n l\u1ef1c c\u1ee7a m\u1eb7t ph\u1eb3ng nghi\u00eang l\u00ean v\u1eadt: \n<\/p>\n\n\n\n
Chi\u1ebfu (\u2217) l\u00ean tr\u1ee5c Oy ta \u0111\u01b0\u1ee3c:\n<\/p>\n\n\n\n
Q \u2013 Py = 0 \u2194 Q \u2013 Pcos30o<\/sup> = 0\n<\/p>\n\n\n\n\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u2192 Q = Py = Pcos30o<\/sup> = 17 (N) <\/p>\n\n\n\nB\u00e0i 7 (trang 100 SGK V\u1eadt L\u00fd 10) :<\/strong> Hai m\u1eb7t ph\u1eb3ng \u0111\u1ee1 t\u1ea1o v\u1edbi m\u1eb7t ph\u1eb3ng n\u1eb1m ngang c\u00e1c g\u00f3c \u03b1 = 45o<\/sup> . Tr\u00ean hai m\u1eb7t ph\u1eb3ng \u0111\u00f3 ng\u01b0\u1eddi ta \u0111\u1eb7t m\u1ed9t qu\u1ea3 c\u1ea7u \u0111\u1ed3ng ch\u1ea5t c\u00f3 kh\u1ed5i l\u01b0\u1ee3ng 2 kg (H\u00ecnh 17.10). B\u1ecf qua ma s\u00e1t v\u00e0 l\u1ea5y g = 10 m\/s2<\/sup> . H\u1ecfi \u00e1p l\u1ef1c c\u1ee7a qu\u1ea3 c\u1ea7u l\u00ean m\u1ed7i m\u1eb7t ph\u1eb3ng \u0111\u1ee1 b\u1eb1ng bao nhi\u00eau?<\/ins><\/p>\n\n\n\nA.\t20 N ; B. 28 N <\/p>\n\n\n\n
C. 14 N ; D. 1,4 N.<\/p>\n\n\n\nH\u00ecnh 17.10<\/em><\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\nCh\u1ecdn C\n<\/p>\n\n\n\n
L\u1ef1c t\u00e1c d\u1ee5ng l\u00ean qu\u1ea3 c\u1ea7u \u0111\u01b0\u1ee3c bi\u1ec3u di\u1ec5n nh\u01b0 h\u00ecnh v\u1ebd sau:\n<\/p>\n\n\n\n
Khi qu\u1ea3 c\u1ea7u n\u1eb1m c\u00e2n b\u1eb1ng ta c\u00f3:\n<\/p>\n\n\n\n<\/ins><\/p>\n\n\n\nCh\u1ecdn h\u1ec7 tr\u1ee5c t\u00f2a \u0111\u1ed9 Oxy nh\u01b0 h\u00ecnh v\u1ebd.\n<\/p>\n\n\n\n
Chi\u1ebfu ph\u01b0\u01a1ng tr\u00ecnh (1) l\u00ean Ox v\u00e0 Oy ta \u0111\u01b0\u1ee3c:\n<\/p>\n\n\n\n
Ox: N1<\/sub>cos\u03b1 – N2<\/sub>cos\u03b1 = 0 (2) \n<\/p>\n\n\n\nOy: -P + N1<\/sub>sin\u03b1 + N2<\/sub>sin\u03b1 = 0 (3) \n<\/p>\n\n\n\nT\u1eeb (2) \u21d2 N1<\/sub> = N2<\/sub>. Thay v\u00e0o (3) ta \u0111\u01b0\u1ee3c: \n<\/p>\n\n\n\n\u21d2 N1<\/sub> = N2<\/sub> = 14N\n<\/p>\n\n\n\nTheo \u0111\u1ecbnh lu\u1eadt III Newton, ta x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c \u00e1p l\u1ef1c m\u00e0 qu\u1ea3 c\u1ea7u \u0111\u00e8 l\u00ean m\u1ed7i m\u1eb7t ph\u1eb3ng \u0111\u1ee1 l\u00e0: N\u20191<\/sub> = N\u20192<\/sub> = 14 N. <\/p>\n\n\n\nB\u00e0i 8 (trang 100 SGK V\u1eadt L\u00fd 10) :<\/strong> \tM\u1ed9t qu\u1ea3 c\u1ea7u \u0111\u1ed3ng ch\u1ea5t c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 3 kg \u0111\u01b0\u1ee3c treo v\u00e0o t\u01b0\u1eddng nh\u1edd m\u1ed9t s\u1ee3i d\u00e2y. D\u00e2y h\u1ee3p v\u1edbi t\u01b0\u1eddng m\u1ed9t g\u00f3c \u03b1 = 20o<\/sup> (H\u00ecnh 17.11). B\u1ecf qua ma s\u00e1t \u1edf ch\u1ed7 ti\u1ebfp x\u00fac c\u1ee7a qu\u1ea3 c\u1ea7u v\u1edbi t\u01b0\u1eddng, l\u1ea5y g = 9,8 m\/s2<\/sup>. L\u1ef1c c\u0103ng T c\u1ee7a s\u1ee3i d\u00e2y l\u00e0 bao nhi\u00eau?<\/ins><\/p>\n\n\n\nA. 88 N ; B. 10 N<\/p>\n\n\n\n
C. 28 N ; D. 32 N.<\/p>\n\n\n\nL\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\nCh\u1ecdn D. Khi qu\u1ea3 c\u1ea7u n\u1eb1m c\u00e2n b\u1eb1ng,kh\u00f4ng c\u00f3 ma s\u00e1t, th\u00ec ph\u01b0\u01a1ng c\u1ee7a d\u00e2y treo \u0111i qua t\u00e2m O c\u1ee7a qu\u1ea3 c\u1ea7u\n<\/p>\n\n\n\nX\u00e9t tam gi\u00e1c vu\u00f4ng N\u2019OT ta c\u00f3: \n<\/p>\n\n\n\n<\/ins><\/p>\n","protected":false},"excerpt":{"rendered":"B\u00e0i 17 : C\u00e2n b\u1eb1ng c\u1ee7a m\u1ed9t v\u1eadt ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a hai l\u1ef1c v\u00e0 c\u1ee7a ba l\u1ef1c kh\u00f4ng song song C1. ( trang 96 sgk V\u1eadt L\u00fd 10): C\u00f3 nh\u1eadn x\u00e9t g\u00ec v\u1ec1 ph\u01b0\u01a1ng c\u1ee7a hai d\u00e2y khi v\u1eadt \u0111\u1ee9ng y\u00ean? Tr\u1ea3 l\u1eddi: Ph\u01b0\u01a1ng c\u1ee7a hai d\u00e2y c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng. C2. […]<\/p>\n","protected":false},"author":12,"featured_media":44139,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1640],"tags":[],"yoast_head":"\n
Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 17 : C\u00e2n b\u1eb1ng c\u1ee7a m\u1ed9t v\u1eadt ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a hai l\u1ef1c v\u00e0 c\u1ee7a ba l\u1ef1c kh\u00f4ng song song<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-17-can-bang-cua-mot-vat-chiu-tac-dung-cua-hai-luc-va-cua-ba-luc-khong-song-song\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 17 : C\u00e2n b\u1eb1ng c\u1ee7a m\u1ed9t v\u1eadt ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a hai l\u1ef1c v\u00e0 c\u1ee7a ba l\u1ef1c kh\u00f4ng song song\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 17 : C\u00e2n b\u1eb1ng c\u1ee7a m\u1ed9t v\u1eadt ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a hai l\u1ef1c v\u00e0 c\u1ee7a ba l\u1ef1c kh\u00f4ng song song C1. 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( trang 96 sgk V\u1eadt L\u00fd 10): C\u00f3 nh\u1eadn x\u00e9t g\u00ec v\u1ec1 ph\u01b0\u01a1ng c\u1ee7a hai d\u00e2y khi v\u1eadt \u0111\u1ee9ng y\u00ean? Tr\u1ea3 l\u1eddi: Ph\u01b0\u01a1ng c\u1ee7a hai d\u00e2y c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng. C2. 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<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-6-trang-100-sgk-vat-ly-10-1.PNG\")
<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-6-trang-100-sgk-vat-ly-10-2.PNG\")
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<\/figure>\n\n\n\n![\"Gi\u1ea3i](\"https:\/\/vietjack.com\/giai-bai-tap-vat-ly-10\/images\/bai-7-trang-100-sgk-vat-ly-10.PNG\")
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<\/figure>\n\n\n\n