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{"id":44123,"date":"2019-10-13T13:24:35","date_gmt":"2019-10-13T06:24:35","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=44123"},"modified":"2019-10-13T13:24:36","modified_gmt":"2019-10-13T06:24:36","slug":"giai-vat-li-10-bai-12-luc-dan-hoi-cua-lo-xo-dinh-luat-huc","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-12-luc-dan-hoi-cua-lo-xo-dinh-luat-huc\/","title":{"rendered":"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 12: L\u1ef1c \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo. \u0110\u1ecbnh lu\u1eadt H\u00fac"},"content":{"rendered":"\n

C1.<\/strong> ( trang 71 sgk V\u1eadt L\u00fd 10) D\u00f9ng hai tay k\u00e9o d\u00e3n m\u1ed9t l\u00f2 xo (H\u00ecnh 12.1a):<\/p>\n\n\n\n

a.\tHai tay c\u00f3 ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a l\u00f2 xo kh\u00f4ng ? H\u00e3y n\u00eau r\u00f5 \u0111i\u1ec3m \u0111\u1eb7t, ph\u01b0\u01a1ng v\u00e0 chi\u1ec1u c\u1ee7a c\u00e1c l\u1ef1c n\u00e0y.<\/ins><\/p>\n\n\n\n

b.\tT\u1ea1i sao l\u00f2 xo ch\u1ec9 d\u00e3n \u0111\u1ebfn m\u1ed9t m\u1ee9c n\u00e0o \u0111\u00f3 th\u00ec d\u1eebng l\u1ea1i ?<\/p>\n\n\n\n

c.\tKhi th\u00f4i k\u00e9o, l\u1ef1c n\u00e0o \u0111\u00e3 l\u00e0m cho l\u00f2 xo l\u1ea5y l\u1ea1i chi\u1ec1u d\u00e0i ban \u0111\u1ea7u?<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n

a. C\u00f3. Hai l\u1ef1c n\u00e0y c\u00f3 \u0111i\u1ec3m \u0111\u1eb7t \u1edf hai tay, c\u00f9ng ph\u01b0\u01a1ng, ng\u01b0\u1ee3c chi\u1ec1u v\u1edbi l\u1ef1c k\u00e9o d\u00e3n.<\/p>\n\n\n\n

b. L\u00f2 xo c\u00e0ng d\u00e3n ra, l\u1ef1c \u0111\u00e0n h\u1ed3i c\u00e0ng t\u0103ng. Khi l\u1ef1c \u0111\u00e0n h\u1ed3i c\u00e2n b\u1eb1ng\n v\u1edbi l\u1ef1c k\u00e9o th\u00ec l\u00f2 xo ng\u1eebng d\u1ea7n. N\u1ebfu l\u1ef1c k\u00e9o qu\u00e1 l\u1edbn, l\u00f2 x\u00f2 d\u00e3n ra qu\u00e1 \ngi\u1edbi h\u1ea1n th\u00ec khi \u0111\u00f3, l\u00f2 xo kh\u00f4ng c\u00f2n t\u00ednh \u0111\u00e0n h\u1ed3i, l\u1ef1c \u0111\u00e0n h\u1ed3i m\u1ea5t \u0111i.<\/ins><\/p>\n\n\n\n

c. Khi th\u00f4i k\u00e9o, l\u1ef1c \u0111\u00e0n h\u1ed3i l\u00e0m cho c\u00e1c v\u00f2ng l\u00f2 xo co l\u1ea1i g\u1ea7n nhau nh\u01b0 l\u00fac ban \u0111\u1ea7u.<\/p>\n\n\n\n

C2.<\/strong>( trang 72 sgk V\u1eadt L\u00fd 10) L\u1ef1c c\u1ee7a l\u00f2 \nxo \u1edf H\u00ecnh 12.2b c\u00f3 \u0111\u1ed9 l\u1edbn b\u1eb1ng bao nhi\u00eau? T\u1ea1i sao? Mu\u1ed1n t\u0103ng l\u1ef1c c\u1ee7a l\u00f2 \nxo l\u00ean 2 ho\u1eb7c 3 l\u1ea7n ta l\u00e0m c\u00e1ch n\u00e0o?<\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

C3.<\/strong>( trang 72 sgk V\u1eadt L\u00fd 10) C\u00e1c k\u1ebft \nqu\u1ea3 trong B\u1ea3ng 12.1 c\u00f3 g\u1ee3i \u00fd cho ta m\u1ed9t m\u1ed1i li\u00ean h\u1ec7 n\u00e0o kh\u00f4ng ? N\u1ebfu c\u00f3 \nth\u00ec h\u00e3y ph\u00e1t bi\u1ec3u m\u1ed1i li\u00ean h\u1ec7 \u0111\u00f3.<\/p>\n\n\n\n

Tr\u1ea3 l\u1eddi:<\/strong><\/p>\n\n\n\n

C\u00f3 m\u1ed1i li\u00ean h\u1ec7 gi\u1eefa tr\u1ecdng l\u1ef1c v\u00e0 \u0111\u1ed9 d\u00e3n c\u1ee7a l\u00f2 xo do \u0111\u00f3 gi\u1eefa l\u1ef1c l\u00f2 xo v\u1edbi \u0111\u1ed9 d\u00e3n l\u00f2 xo:\n<\/p>\n\n\n\n

F\/\u0394l = h\u1eb1ng s\u1ed1. T\u1ee9c F t\u1ec9 l\u1ec7 v\u1edbi \u0111\u1ed9 d\u00e3n l\u00f2 xo. <\/p>\n\n\n\n

B\u00e0i 3 (trang 74 SGK V\u1eadt L\u00fd 10) :<\/strong> Ph\u1ea3i treo m\u1ed9t v\u1eadt c\u00f3 tr\u1ecdng l\u01b0\u1ee3ng b\u1eb1ng bao nhi\u00eau v\u00e0o m\u1ed9t l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 100 N\/ m \u0111\u1ec3 n\u00f3 d\u00e3n ra \u0111\u01b0\u1ee3c 10 cm ?<\/p>\n\n\n\n

A.\t1000 N ;         B. 100 N <\/ins><\/p>\n\n\n\n

C. 10 N ;            D. 1 N.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

Ch\u1ecdn C. \n<\/p>\n\n\n\n

Khi v\u1eadt n\u1eb1m c\u00e2n b\u1eb1ng tr\u1ecdng l\u1ef1c P c\u00e2n b\u1eb1ng v\u1edbi l\u1ef1c \u0111\u00e0n h\u1ed3i Fdh<\/sub>:\n<\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

V\u1ec1 \u0111\u1ed9 l\u1edbn: P = Fdh<\/sub> = k.\u0394l\n<\/p>\n\n\n\n

\u21d4 P = 100.0,1 = 10 N <\/p>\n\n\n\n

B\u00e0i 4 (trang 74 SGK V\u1eadt L\u00fd 10) :<\/strong> M\u1ed9t l\u00f2 \nxo c\u00f3 chi\u1ec1u d\u00e0i t\u1ef1 nhi\u00ean b\u1eb1ng 15 cm. L\u00f2 xo \u0111\u01b0\u1ee3c gi\u1eef c\u1ed1 \u0111\u1ecbnh t\u1ea1i m\u1ed9t \u0111\u1ea7u,\n c\u00f2n \u0111\u1ea7u kia ch\u1ecbu m\u1ed9t l\u1ef1c k\u00e9o b\u1eb1ng 4,5 N. Khi \u1ea5y l\u00f2 xo d\u00e0i 18 cm. \u0110\u1ed9 \nc\u1ee9ng c\u1ee7a l\u00f2 xo b\u1eb1ng bao nhi\u00eau ?<\/ins><\/p>\n\n\n\n

A.\t30 N\/m ;         B. 25 N\/m<\/p>\n\n\n\n

C. 1,5 N\/m ;         D. 150 N\/m.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

Ch\u1ecdn D.\n <\/p>\n\n\n\n

\u0110\u1ed9 bi\u1ebfn d\u1ea1ng c\u1ee7a l\u00f2 xo l\u00e0: \u0394l = l – l0<\/sub> = 18 – 15 = 3 cm = 0,03 m\n <\/p>\n\n\n\n

L\u1ef1c k\u00e9o c\u00e2n b\u1eb1ng v\u1edbi l\u1ef1c \u0111\u00e0n h\u1ed3i: Fk<\/sub> = F\u0111h<\/sub> = k.\u0394l\n <\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

B\u00e0i 5 (trang 74 SGK V\u1eadt L\u00fd 10) :<\/strong> M\u1ed9t l\u00f2 \nxo c\u00f3 chi\u1ec1u d\u00e0i t\u1ef1 nhi\u00ean 30 cm, khi b\u1ecb n\u00e9n l\u00f2 xo d\u00e0i 24 cm v\u00e0 l\u1ef1c \u0111\u00e0n \nh\u1ed3i c\u1ee7a n\u00f3 b\u1eb1ng 5 N. H\u1ecfi khi l\u1ef1c \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo b\u1ecb n\u00e9n b\u1eb1ng 10 N th\u00ec \nchi\u1ec1u d\u00e0i c\u1ee7a n\u00f3 b\u1eb1ng bao nhi\u00eau?<\/p>\n\n\n\n

A.\t18 cm ;         B.\t40 cm<\/p>\n\n\n\n

C.\t48 cm ;         D.\t22 cm.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/ins><\/p>\n\n\n\n

Ch\u1ecdn A. \n<\/p>\n\n\n\n

H\u00ecnh \u1ea3nh minh h\u1ecda: \n<\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

\u0110\u1ed9 bi\u1ebfn d\u1ea1ng c\u1ee7a l\u00f2 xo khi b\u1ecb n\u00e9n b\u1edfi l\u1ef1c c\u00f3 \u0111\u1ed9 l\u1edbn F1<\/sub> = 5N l\u00e0:\n<\/p>\n\n\n\n

|\u0394l| = |l1<\/sub> – l0<\/sub>| = |24 – 30| = 6cm\n<\/p>\n\n\n\n

\u0110\u1ed9 bi\u1ebfn d\u1ea1ng c\u1ee7a l\u00f2 xo khi b\u1ecb n\u00e9n b\u1edfi l\u1ef1c c\u00f3 \u0111\u1ed9 l\u1edbn F2<\/sub> = 10N = 2F1<\/sub> l\u00e0:\n<\/p>\n\n\n\n

|\u0394l2<\/sub>| = 2|\u0394l1<\/sub>| = 2. 6 = 12cm\n<\/p>\n\n\n\n

Chi\u1ec1u d\u00e0i d\u00f2 xo khi b\u1ecb n\u00e9n b\u1edfi l\u1ef1c 10N l\u00e0:\n<\/p>\n\n\n\n

l1<\/sub> = l0<\/sub> – \u0394l2<\/sub> = 30 – 12 = 18cm <\/p>\n\n\n\n

B\u00e0i 6 (trang 74 SGK V\u1eadt L\u00fd 10) :<\/strong> Treo m\u1ed9t\n v\u1eadt c\u00f3 tr\u1ecdng l\u01b0\u1ee3ng 2,0 N v\u00e0o m\u1ed9t l\u00f2 xo, l\u00f2 xo d\u00e3n ra 10 mm. Treo m\u1ed9t \nv\u1eadt kh\u00e1c c\u00f3 tr\u1ecdng l\u01b0\u1ee3ng ch\u01b0a bi\u1ebft v\u00e0o l\u00f2 xo, n\u00f3 d\u00e3n ra 80 mm.<\/ins><\/p>\n\n\n\n

a.\tT\u00ednh \u0111\u1ed9 c\u1ee9ng c\u1ee7a l\u00f2 xo.<\/p>\n\n\n\n

b.\tT\u00ednh tr\u1ecdng l\u01b0\u1ee3ng ch\u01b0a bi\u1ebft.<\/p>\n\n\n\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n\n\n\n

a)\tKhi treo v\u1eadt c\u00f3 tr\u1ecdng l\u01b0\u1ee3ng 2 N, \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng l\u00f2 xo d\u00e3n \u0394l1<\/sub> = 10 mm = 0,01 cm ta c\u00f3:\n<\/p>\n\n\n\n

\"Gi\u1ea3i<\/figure>\n\n\n\n

b) Khi treo v\u1eadt c\u00f3 tr\u1ecdng l\u01b0\u1ee3ng P2<\/sub>, t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, l\u00f2 xo d\u00e3n \u0394l2<\/sub> = 80 mm = 0,08 cm , ta c\u00f3:\n<\/p>\n\n\n\n

P2<\/sub> = F\u0111h<\/sub> = k.\u0394l2<\/sub> = 200.0,08 = 16(N)\n<\/ins><\/p>\n","protected":false},"excerpt":{"rendered":"

C1. ( trang 71 sgk V\u1eadt L\u00fd 10) D\u00f9ng hai tay k\u00e9o d\u00e3n m\u1ed9t l\u00f2 xo (H\u00ecnh 12.1a): a. Hai tay c\u00f3 ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a l\u00f2 xo kh\u00f4ng ? H\u00e3y n\u00eau r\u00f5 \u0111i\u1ec3m \u0111\u1eb7t, ph\u01b0\u01a1ng v\u00e0 chi\u1ec1u c\u1ee7a c\u00e1c l\u1ef1c n\u00e0y. b. T\u1ea1i sao l\u00f2 xo ch\u1ec9 d\u00e3n \u0111\u1ebfn m\u1ed9t m\u1ee9c n\u00e0o \u0111\u00f3 th\u00ec […]<\/p>\n","protected":false},"author":12,"featured_media":44124,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1640],"tags":[],"yoast_head":"\nGi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 12: L\u1ef1c \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo. \u0110\u1ecbnh lu\u1eadt H\u00fac<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/giai-vat-li-10-bai-12-luc-dan-hoi-cua-lo-xo-dinh-luat-huc\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gi\u1ea3i V\u1eadt L\u00ed 10 B\u00e0i 12: L\u1ef1c \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo. \u0110\u1ecbnh lu\u1eadt H\u00fac\" \/>\n<meta property=\"og:description\" content=\"C1. ( trang 71 sgk V\u1eadt L\u00fd 10) D\u00f9ng hai tay k\u00e9o d\u00e3n m\u1ed9t l\u00f2 xo (H\u00ecnh 12.1a): a. Hai tay c\u00f3 ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a l\u00f2 xo kh\u00f4ng ? H\u00e3y n\u00eau r\u00f5 \u0111i\u1ec3m \u0111\u1eb7t, ph\u01b0\u01a1ng v\u00e0 chi\u1ec1u c\u1ee7a c\u00e1c l\u1ef1c n\u00e0y. b. 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