0<\/sup>C hay h\u1ed9p x\u1ed1p\n<\/p>\n\n\n\n– Sau 6 -8 gi\u1edd s\u1eefa \u0111\u00f4ng t\u1ee5 l\u1ea1i l\u00e0 s\u1eefa chua \u0111\u00e3 \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh.\n<\/p>\n\n\n\n
– B\u1ea3o qu\u1ea3n s\u1eefa chua trong t\u1ee7 l\u1ea1nh\n<\/p>\n\n\n\n
*Quan s\u00e1t hi\u1ec7n t\u01b0\u1ee3ng:\n<\/p>\n\n\n\n
– M\u00e0u s\u1eafc s\u1eefa chuy\u1ec3n t\u1eeb m\u00e0u tr\u1eafng sang tr\u1eafng ng\u00e0.\n<\/p>\n\n\n\n
– Tr\u1ea1ng th\u00e1i t\u1eeb l\u1ecfng sang \u0111\u00f4ng t\u1ee5 (\u0111\u1eb7c s\u1ec7t l\u1ea1i)\n<\/p>\n\n\n\n
– H\u01b0\u01a1ng th\u01a1m nh\u1eb9\n<\/p>\n\n\n\n
– V\u1ecb ng\u1ecdt gi\u1ea3m, t\u0103ng v\u1ecb chua\n<\/p>\n\n\n\n
*K\u1ebft lu\u1eadn:\n<\/p>\n\n\n\n
Vi khu\u1ea9n lactic \u0111\u00e3 bi\u1ebfn \u0111\u01b0\u1eddng th\u00e0nh axit lactic\n<\/p>\n\n\n\n
Lact\u00f4z\u01a1 ====> Galact\u00f4z\u01a1 + Gluc\u00f4z\u01a1 (x\u00fac t\u00e1c l\u00e0 vi khu\u1ea9n lactic)\n<\/p>\n\n\n\n
Gluc\u00f4z\u01a1 ====> axit lactic (x\u00fac t\u00e1c l\u00e0 vi khu\u1ea9n lactic)\n<\/p>\n\n\n\n
b, Mu\u1ed1i rau c\u1ee7 qu\u1ea3\n<\/p>\n\n\n\n
* Ti\u1ebfn h\u00e0nh\n<\/p>\n\n\n\n
– Rau c\u1ea3i c\u1eaft nh\u1ecf 3- 4 cm, ph\u01a1i se m\u1eb7t.\n<\/p>\n\n\n\n
– \u0110\u1ed5 rau v\u00e0o b\u00ecnh tr\u1ee5\n<\/p>\n\n\n\n
– Pha n\u01b0\u1edbc mu\u1ed1i \u1ea5m 6% r\u1ed3i \u0111\u1ed5 ng\u1eadp rau \n<\/p>\n\n\n\n
– N\u00e9n ch\u1eb7t \u0111\u1eady k\u00edn \u0111\u1ec3 n\u01a1i \u1ea5m\n<\/p>\n\n\n\n
– C\u00f3 th\u1ec3 cho th\u00eam n\u01b0\u1edbc \u0111\u01b0\u1eddng\n<\/p>\n\n\n\n
* Quan s\u00e1t hi\u1ec7n t\u01b0\u1ee3ng\n<\/p>\n\n\n\n
– M\u00e0u xanh c\u1ee7a rau chuy\u1ec3n sang m\u00e0u v\u00e0ng\n<\/p>\n\n\n\n
– C\u00f3 v\u1ecb chua nh\u1eb9 th\u01a1m\n<\/p>\n\n\n\n
* Gi\u1ea3i th\u00edch hi\u1ec7n t\u01b0\u1ee3ng\n<\/p>\n\n\n\n
– Vi khu\u1ea9n lactic \u0111\u00e3 ph\u00e2n gi\u1ea3i m\u1ed9t s\u1ed1 \u0111\u01b0\u1eddng c\u00f3 trong rau th\u00e0nh axit lactic theo ph\u01b0\u01a1ng tr\u00ecnh:\n<\/p>\n\n\n\n
Gluc\u00f4z\u01a1 ==(vi khu\u1ea9n lactic)==>axit lactic\n<\/p>\n\n\n\n
– Do s\u1ef1 ch\u00eanh l\u1ec7ch v\u1ec1 n\u1ed3ng \u0111\u1ed9 gi\u1eefa trong v\u00e0 ngo\u00e0i t\u1ebf b\u00e0o, n\u00ean n\u01b0\u1edbc \u0111\u00e3\n \u0111i t\u1eeb m\u00f4i tr\u01b0\u1eddng nh\u01b0\u1ee3c tr\u01b0\u01a1ng sang m\u00f4i tr\u01b0\u1eddng \u01b0u tr\u01b0\u01a1ng l\u00e0m c\u00e2n b\u1eb1ng s\u1ef1\n ch\u00eanh l\u1ec7ch n\u1ed3ng \u0111\u1ed9 \u0111\u00f3, gi\u00fap cho qu\u00e1 tr\u00ecnh l\u00ean men lactic x\u1ea3y ra.\n<\/p>\n\n\n\n
K\u1ebft lu\u1eadn rau \u0111\u00e3 bi\u1ebfn th\u00e0nh d\u01b0a chua.\n <\/p>\n","protected":false},"excerpt":{"rendered":"
L\u00fd thuy\u1ebft Sinh h\u1ecdc 10 B\u00e0i 24: Th\u1ef1c h\u00e0nh: L\u00ean men \u00eatilic v\u00e0 lactic I. L\u00ean men \u00catilic 1. Chu\u1ea9n b\u1ecb – 3 \u1ed1ng nghi\u1ec7m – B\u00e1nh men m\u1edbi ch\u1ebf t\u1ea1o \u0111\u01b0\u1ee3c gi\u00e3 nh\u1ecf v\u00e0 r\u00e2y l\u1ea5y b\u1ed9t m\u1ecbn ho\u1eb7c n\u1ea5m men thu\u1ea7n khi\u1ebft. – 20 ml dung d\u1ecbch \u0111\u01b0\u1eddng k\u00ednh 10% – 20 ml […]<\/p>\n","protected":false},"author":12,"featured_media":44060,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1644],"tags":[],"yoast_head":"\n
L\u00fd thuy\u1ebft Sinh h\u1ecdc 10 B\u00e0i 24: Th\u1ef1c h\u00e0nh: L\u00ean men \u00eatilic v\u00e0 lactic<\/title>\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n