Bi\u1ec3u \u0111\u1ed3 ch\u1ec9 ra s\u1ef1 b\u1ea5t th\u01b0\u1eddng "kh\u1ee7ng khi\u1ebfp" \u0111i\u1ec3m thi m\u00f4n To\u00e1n c\u1ee7a H\u00e0 Giang<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bieu-do-chi-ra-su-bat-thuong-khung-khiep-diem-thi-mon-toan-cua-ha-giang\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Bi\u1ec3u \u0111\u1ed3 ch\u1ec9 ra s\u1ef1 b\u1ea5t th\u01b0\u1eddng "kh\u1ee7ng khi\u1ebfp" \u0111i\u1ec3m thi m\u00f4n To\u00e1n c\u1ee7a H\u00e0 Giang\" \/>\n<meta property=\"og:description\" content=\"N\u1ebfu theo xu h\u01b0\u1edbng c\u1ee7a c\u1ea3 n\u01b0\u1edbc, H\u00e0 Giang ch\u1ec9 c\u00f3 7 th\u00ed sinh \u1edf ng\u01b0\u1ee1ng \u0111i\u1ec3m 8.6 \u0111\u1ebfn 9.6 m\u00f4n thi To\u00e1n THPT qu\u1ed1c gia, nh\u01b0ng trong th\u1ef1c t\u1ebf con s\u1ed1 th\u00ed sinh \u0111\u1ea1t \u0111i\u1ec3m n\u00e0y l\u00e0 72, t\u1ee9c cao g\u1ea5p 10 l\u1ea7n so v\u1edbi c\u1ea3 n\u01b0\u1edbc. \u0110i\u1ec3m s\u1ed1 cao \u1edf H\u00e0 Giang v\u01b0\u1ee3t […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/bieu-do-chi-ra-su-bat-thuong-khung-khiep-diem-thi-mon-toan-cua-ha-giang\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - 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Trao \u0111\u1ed5i v\u1edbi ph\u00f3ng vi\u00ean\u00a0D\u00e2n tr\u00ed,<\/i>\u00a0GS Nguy\u1ec5n V\u0103n Tu\u1ea5n Vi\u1ec7n Garvan (Australia) cho bi\u1ebft, \u00f4ng may m\u1eafn \u0111\u01b0\u1ee3c cung c\u1ea5p to\u00e0n b\u1ed9 s\u1ed1 li\u1ec7u \u0111i\u1ec3m thi c\u1ee7a m\u1ed7i th\u00ed sinh cho m\u1ed7i m\u00f4n thi tr\u00ean c\u1ea3 n\u01b0\u1edbc, trong \u0111\u00f3 c\u00f3 t\u1ec9nh H\u00e0 Giang. \u0110\u00e2y l\u00e0 d\u1eef li\u1ec7u c\u1ef1c k\u1ef3 qu\u00fd, v\u00ec d\u1ef1a v\u00e0o d\u1eef li\u1ec7u n\u00e0y, c\u00f3 th\u1ec3 tr\u1ea3 l\u1eddi c\u1ee5 th\u1ec3 c\u00e1c c\u00e2u h\u1ecfi.<\/p>\n

V\u1ec1 vi\u1ec7c d\u01b0 lu\u1eadn, c\u00f4ng ch\u00fang ng\u1ea1c nhi\u00ean v\u00e0 \u0111\u1eb7t c\u00e2u h\u1ecfi v\u1ec1 k\u1ef3 thi THPT qu\u1ed1c gia li\u00ean quan \u0111\u1ebfn \u0111i\u1ec3m thi \u1edf H\u00e0 Giang, theo \u00f4ng Tu\u1ea5n l\u00e0 h\u1ee3p l\u00fd. X\u00e9t tr\u00ean s\u1ed1 li\u1ec7u th\u1ef1c t\u1ebf th\u00ec k\u1ebft qu\u1ea3 r\u1ea5t \u0111\u00e1ng nghi ng\u1edd. Cho d\u00f9 kh\u00f4ng th\u1ec3 n\u00f3i c\u00f3 vi\u1ec7c s\u1eeda \u0111i\u1ec3m hay g\u00ec \u0111\u00f3 nh\u01b0ng \u0111i\u1ec3m s\u1ed1 m\u00f4n To\u00e1n c\u1ee7a H\u00e0 Giang r\u1ea5t kh\u00e1c bi\u1ec7t so v\u1edbi quy lu\u1eadt chung c\u1ee7a to\u00e0n qu\u1ed1c, s\u1ef1 kh\u00e1c bi\u1ec7t n\u00e0y kh\u00f4ng ph\u1ea3i l\u00e0 ng\u1eabu nhi\u00ean m\u00e0 \u0111\u00f3 l\u00e0 s\u1ef1 b\u1ea5t th\u01b0\u1eddng. R\u1ea5t c\u00f3 th\u1ec3 s\u1ef1 kh\u00e1c bi\u1ec7t n\u00e0y l\u00e0 do s\u1ef1 can thi\u1ec7p c\u1ee7a con ng\u01b0\u1eddi.<\/p>\n

Theo GS Nguy\u1ec5n V\u0103n Tu\u1ea5n, \u0111\u1ec3 x\u00e1c minh \u0111i\u1ec1u n\u00e0y kh\u00f4ng kh\u00f3, x\u00e1c minh c\u00e1c th\u00ed sinh c\u00f3 \u0111i\u1ec3m b\u1ea5t th\u01b0\u1eddng m\u00e0 bi\u1ec3u \u0111\u1ed3 th\u1ec3 hi\u1ec7n ra m\u1ed9t c\u00e1ch d\u1ec5 d\u00e0ng r\u1ed3i xem qua l\u1ef1c h\u1ecdc c\u1ee7a c\u00e1c em tr\u01b0\u1edbc \u0111\u00e2y ho\u1eb7c cho c\u00e1c em \u1ea5y thi l\u1ea1i. S\u1ed1 l\u01b0\u1ee3ng ch\u1ec9 v\u00e0i ch\u1ee5c em, vi\u1ec7c n\u00e0y ho\u00e0n to\u00e0n c\u00f3 th\u1ec3 th\u1ef1c hi\u1ec7n \u0111\u01b0\u1ee3c.<\/p>\n

Bi\u1ec3u \u0111\u1ed3 n\u00e0y cho th\u1ea5y ph\u00e2n b\u1ed1 \u0111i\u1ec3m c\u1ee7a H\u00e0 Giang (m\u00e0u h\u1ed3ng) v\u00e0 c\u1ee7a c\u1ea3 n\u01b0\u1edbc (m\u00e0u xanh). C\u00f3 hai \u0111i\u1ec3m ch\u00ednh c\u00f3 th\u1ec3 r\u00fat ra t\u1eeb h\u00ecnh n\u00e0y: (a) \u0110i\u1ec3m trung v\u1ecb c\u1ee7a H\u00e0 Giang l\u00e0 kho\u1ea3ng 3.2, th\u1ea5p h\u01a1n \u0111i\u1ec3m c\u1ee7a to\u00e0n qu\u1ed1c (trung v\u1ecb kho\u1ea3ng 5.0); (b) Ph\u00e2n b\u1ed1 \u0111i\u1ec3m c\u1ee7a H\u00e0 Giang c\u00f3 v\u1ebb b\u1ea5t th\u01b0\u1eddng \u1edf \u0111i\u1ec3m t\u1eeb 8 \u0111\u1ebfn 10. Ch\u00fa \u00fd \u0111\u01b0\u1eddng bi\u1ec3u di\u1ec5n c\u1ee7a H\u00e0 Giang “nh\u00f4 l\u00ean” trong khi \u0111\u00e1ng l\u00ed ra ph\u1ea3i smooth nh\u01b0 c\u1ea3 n\u01b0\u1edbc.<\/div>\n
<\/div>\n
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$\"\"$ <\/p>\n
\u0110\u1ec3 ki\u1ec3m tra k\u0129 h\u01a1n ch\u1ed7 “nh\u00f4 l\u00ean” \u0111\u00f3, c\u1ea7n ph\u1ea3i ph\u00e2n t\u00edch so s\u00e1nh gi\u1eefa ph\u00e2n b\u1ed1 \u0111i\u1ec3m th\u1ef1c t\u1ebf c\u1ee7a H\u00e0 Giang v\u00e0 \u0111i\u1ec3m c\u1ee7a c\u1ea3 n\u01b0\u1edbc.. V\u00ed d\u1ee5, ch\u00fa \u00fd c\u1ed9t s\u1ed1 4 (Ha Giang), \u1edf \u0111i\u1ec3m 9, n\u1ebfu theo ph\u00e2n b\u1ed1 qu\u1ed1c gia th\u00ec ch\u00fang ta k\u00ec v\u1ecdng H\u00e0 Giang c\u00f3 1 em \u0111\u1ea1t \u0111i\u1ec3m n\u00e0y. Th\u1ebf nh\u01b0ng trong th\u1ef1c t\u1ebf, H\u00e0 Giang c\u00f3 \u0111\u1ebfn 20 em \u0111\u1ea1t \u0111i\u1ec3m 9 (c\u1ed9t 3).<\/p>\n
N\u1ebfu ph\u00e2n b\u1ed1 \u0111i\u1ec3m thi c\u1ee7a H\u00e0 Giang t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi ph\u00e2n b\u1ed1 c\u1ee7a c\u1ea3 n\u01b0\u1edbc, th\u00ec c\u1ed9t th\u1ee9 5 s\u1ebd g\u1ea7n b\u1eb1ng 0. Nh\u01b0ng ch\u00fang ta th\u1ea5y trong th\u1ef1c t\u1ebf th\u00ec kh\u00f4ng ph\u1ea3i v\u1eady, v\u00e0 v\u00e0i ch\u1ed7 l\u1ec7ch th\u1ec3 hi\u1ec7n r\u1ea5t r\u00f5 sau \u0111\u00e2y:<\/p>\n
– \u1ede \u0111i\u1ec3m th\u1ea5p (t\u1eeb 1 \u0111\u1ebfn 3.6), s\u1ed1 th\u00ed sinh H\u00e0 Giang cao h\u01a1n so v\u1edbi gi\u00e1 tr\u1ecb k\u00ec v\u1ecdng<\/p>\n
– Nh\u01b0ng \u1edf \u0111i\u1ec3m cao h\u01a1n (t\u1eeb 4.0 \u0111\u1ebfn 7.8) th\u00ec s\u1ed1 th\u00ed sinh H\u00e0 Giang th\u1ea5p h\u01a1n gi\u00e1 tr\u1ecb k\u00ec v\u1ecdng c\u1ee7a c\u1ea3 n\u01b0\u1edbc<\/p>\n
– Nh\u01b0ng \u0111i\u1ec1u th\u00fa v\u1ecb nh\u1ea5t l\u00e0 \u1edf \u0111i\u1ec3m cao ‘top’ (t\u1eeb 8.6 \u0111\u1ebfn 9.6) s\u1ed1 th\u00ed sinh H\u00e0 Giang cao h\u01a1n so v\u1edbi ph\u00e2n b\u1ed1 c\u1ea3 n\u01b0\u1edbc. N\u1ebfu theo xu h\u01b0\u1edbng c\u1ee7a c\u1ea3 n\u01b0\u1edbc, H\u00e0 Giang ch\u1ec9 c\u00f3 7 th\u00ed sinh \u1edf ng\u01b0\u1ee1ng \u0111i\u1ec3m 8.6 \u0111\u1ebfn 9.6, nh\u01b0ng trong th\u1ef1c t\u1ebf con s\u1ed1 th\u00ed sinh \u0111\u1ea1t \u0111i\u1ec3m n\u00e0y l\u00e0 72, t\u1ee9c cao g\u1ea5p ~10 l\u1ea7n so v\u1edbi c\u1ea3 n\u01b0\u1edbc.<\/p>\n
$\"\"$ <\/p>\n
\n
Bi\u1ec3u \u0111\u1ed3 n\u00e0y c\u00f3 m\u1ee5c \u0111\u00edch nh\u1eadn d\u1ea1ng c\u1ee5 th\u1ec3 th\u00ed sinh n\u00e0o c\u00f3 \u0111i\u1ec3m cao b\u1ea5t th\u01b0\u1eddng. GS Tu\u1ea5n t\u00ecm m\u1ed1i li\u00ean h\u1ec7 gi\u1eefa m\u00f4n To\u00e1n v\u00e0 c\u00e1c m\u00f4n kh\u00e1c; sau \u0111\u00f3 d\u1ef1a v\u00e0o \u0111i\u1ec3m c\u1ee7a c\u00e1c m\u00f4n kh\u00e1c t\u00ednh gi\u00e1 tr\u1ecb k\u00ec v\u1ecdng \u0111i\u1ec3m m\u00f4n to\u00e1n cho m\u1ed7i em sau \u0111\u00f3 m\u00ecnh so s\u00e1nh \u0111i\u1ec3m k\u00ec v\u1ecdng v\u00e0 \u0111i\u1ec3m th\u1ef1c t\u1ebf. N\u1ebfu \u0111i\u1ec3m th\u1ef1c t\u1ebf cao g\u1ea5p 4 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n k\u00ec v\u1ecdng l\u00e0 b\u1ea5t th\u01b0\u1eddng. T\u1ea1i sao 4? V\u00ec 4 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n l\u00e0 99.99%, n\u00ean n\u1ebfu cao h\u01a1n con s\u1ed1 n\u00e0y th\u00ec xem nh\u01b0 l\u00e0 “qu\u00e1 c\u1ee1” (kh\u00f3 tin).<\/p>\n
\u0110\u01b0\u1eddng m\u00e0u \u0111\u1ecf l\u00e0 gi\u00e1 tr\u1ecb k\u1ef3 v\u1ecdng (\u0111\u00e1ng l\u00fd l\u00e0 ph\u1ea3i v\u1eady). Ch\u1ec9 c\u1ea7n 1 c\u00e1 nh\u00e2n l\u00e0 \u0111\u00e3 ph\u1ea3i nghi ng\u1edd, v\u00e0 \u1edf \u0111\u00e2y l\u00e0 kho\u1ea3ng 20 em tr\u00ean \u0111\u01b0\u1eddng m\u00e0u \u0111\u1ecf, v\u01b0\u1ee3t xa k\u1ef3 v\u1ecdng c\u00f3 th\u1ec3 xem l\u00e0 b\u1ea5t b\u00ecnh th\u01b0\u1eddng, \u0111\u1eb7c bi\u1ec7t c\u00f3 m\u1ed9t th\u00ed sinh “ng\u1ed3i” ri\u00eang \u1edf v\u1ecb tr\u00ed r\u1ea5t xa c\u00e1c b\u1ea1n kh\u00e1c. \u0110\u00e2y l\u00e0 nh\u1eefng con s\u1ed1 ph\u1ea3i nghi ng\u1edd ngay.<\/p>\n
\n
C\u00f3 tr\u00ean 950 th\u00ed sinh \u0111i\u1ec3m 0 m\u00f4n To\u00e1n l\u00e0 b\u1ea5t th\u01b0\u1eddng<\/strong><\/p>\n
GS Nguy\u1ec5n V\u0103n Tu\u1ea5n ph\u00e2n t\u00edch, m\u00f4n To\u00e1n c\u00f3 50 c\u00e2u, m\u1ed7i c\u00e2u c\u00f3 4 l\u1ef1a ch\u1ecdn. Do \u0111\u00f3, x\u00e1c su\u1ea5t sai cho m\u1ed7i c\u00e2u h\u1ecfi l\u00e0 3\/4. X\u00e1c su\u1ea5t m\u1ed9t th\u00ed sinh sai t\u1ea5t c\u1ea3 50 c\u00e2u ph\u1ea3i l\u00e0 p = (3\/4)^50 = 0.0000005663 (gi\u1ea3 \u0111\u1ecbnh \u0111\u1ed9c l\u1eadp). Nh\u01b0ng \u1edf \u0111\u00e2y, ch\u00fang ta c\u00f3 n=917484 th\u00ed sinh. G\u1ecdi x l\u00e0 s\u1ed1 th\u00ed sinh c\u00f3 \u0111i\u1ec3m 0, l\u00ed thuy\u1ebft ph\u00e2n b\u1ed1 nh\u1ecb ph\u00e2n cho bi\u1ebft gi\u00e1 tr\u1ecb trung b\u00ecnh c\u1ee7a x l\u00e0 mean(x) = np = 0.51 v\u00e0 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n sd = sqrt(n*p*(1-p)) = 0.72.<\/p>\n
D\u00f9ng hai tham s\u1ed1 n\u00e0y \u0111\u1ec3 m\u00f4 ph\u1ecfng th\u00ec ch\u00fang ta c\u00f3 th\u1ec3 t\u00ednh x\u00e1c su\u1ea5t c\u00f3 951 th\u00ed sinh c\u00f3 \u0111i\u1ec3m 0: 1-pnorm(951, mean=0.51, sd=0.72) k\u1ebft qu\u1ea3 l\u00e0 0. M\u1ed9t c\u00e1ch kh\u00e1c l\u00e0 gi\u00e1 tr\u1ecb k\u00ec v\u1ecdng trong s\u1ed1 1 tri\u1ec7u th\u00ed sinh thi, th\u00ec t\u1ed1i \u0111a ch\u1ec9 c\u00f3 3 th\u00ed sinh v\u1edbi \u0111i\u1ec3m 0 m\u00f4n to\u00e1n. Nh\u01b0ng trong th\u1ef1c t\u1ebf, k\u00ec thi n\u00e0y ghi nh\u1eadn c\u00f3 \u0111\u1ebfn 951 th\u00ed sinh c\u00f3 \u0111i\u1ec3m 0. V\u00e0, \u0111\u00f3 l\u00e0 \u0111i\u1ec1u b\u1ea5t th\u01b0\u1eddng.<\/p>\n
Theo Dantri<\/strong><\/p>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
N\u1ebfu theo xu h\u01b0\u1edbng c\u1ee7a c\u1ea3 n\u01b0\u1edbc, H\u00e0 Giang ch\u1ec9 c\u00f3 7 th\u00ed sinh \u1edf ng\u01b0\u1ee1ng \u0111i\u1ec3m 8.6 \u0111\u1ebfn 9.6 m\u00f4n thi To\u00e1n THPT qu\u1ed1c gia, nh\u01b0ng trong th\u1ef1c t\u1ebf con s\u1ed1 th\u00ed sinh \u0111\u1ea1t \u0111i\u1ec3m n\u00e0y l\u00e0 72, t\u1ee9c cao g\u1ea5p 10 l\u1ea7n so v\u1edbi c\u1ea3 n\u01b0\u1edbc. \u0110i\u1ec3m s\u1ed1 cao \u1edf H\u00e0 Giang v\u01b0\u1ee3t […]<\/p>\n","protected":false},"author":3,"featured_media":33291,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[19],"tags":[],"yoast_head":"\nBi\u1ec3u \u0111\u1ed3 ch\u1ec9 ra s\u1ef1 b\u1ea5t th\u01b0\u1eddng "kh\u1ee7ng khi\u1ebfp" \u0111i\u1ec3m thi m\u00f4n To\u00e1n c\u1ee7a H\u00e0 Giang<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bieu-do-chi-ra-su-bat-thuong-khung-khiep-diem-thi-mon-toan-cua-ha-giang\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Bi\u1ec3u \u0111\u1ed3 ch\u1ec9 ra s\u1ef1 b\u1ea5t th\u01b0\u1eddng "kh\u1ee7ng khi\u1ebfp" \u0111i\u1ec3m thi m\u00f4n To\u00e1n c\u1ee7a H\u00e0 Giang\" \/>\n<meta property=\"og:description\" content=\"N\u1ebfu theo xu h\u01b0\u1edbng c\u1ee7a c\u1ea3 n\u01b0\u1edbc, H\u00e0 Giang ch\u1ec9 c\u00f3 7 th\u00ed sinh \u1edf ng\u01b0\u1ee1ng \u0111i\u1ec3m 8.6 \u0111\u1ebfn 9.6 m\u00f4n thi To\u00e1n THPT qu\u1ed1c gia, nh\u01b0ng trong th\u1ef1c t\u1ebf con s\u1ed1 th\u00ed sinh \u0111\u1ea1t \u0111i\u1ec3m n\u00e0y l\u00e0 72, t\u1ee9c cao g\u1ea5p 10 l\u1ea7n so v\u1edbi c\u1ea3 n\u01b0\u1edbc. \u0110i\u1ec3m s\u1ed1 cao \u1edf H\u00e0 Giang v\u01b0\u1ee3t […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/bieu-do-chi-ra-su-bat-thuong-khung-khiep-diem-thi-mon-toan-cua-ha-giang\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - 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