B\u00e0i 6 (trang 210 SGK H\u00f3a 11):<\/b>\u00a0<\/span>Trung h\u00f2a 16,60gam h\u1ed7n h\u1ee3p g\u1ed3m axit axetic v\u00e0 axit fomic b\u1eb1ng dung d\u1ecbch natri hi\u0111roxit thu \u0111\u01b0\u1ee3c 23,20 gam h\u1ed7n h\u1ee3p hai mu\u1ed1i.<\/p>\na. Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c ph\u1ea3n \u1ee9ng \u1edf d\u1ea1ng ph\u00e2n t\u1eed v\u00e0 ion r\u00fat g\u1ecdn.<\/p>\n
b. X\u00e1c \u0111\u1ecbnh th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a m\u1ed7i ch\u1ea5t trong h\u1ed7n h\u1ee3p tr\u01b0\u1edbc v\u00e0 sau ph\u1ea3n \u1ee9ng.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) G\u1ecdi s\u1ed1 mol c\u1ee7a axit axetic v\u00e0 axit fomic l\u1ea7n l\u01b0\u1ee3t l\u00e0 x v\u00e0 y (mol)<\/p>\n
Ph\u01b0\u01a1ng tr\u00ecnh ho\u00e1 h\u1ecdc \u1edf d\u1ea1ng ph\u00e2n t\u1eed:<\/p>\n
![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-6-trang-210-sgk-hoa-11.PNG\")
Ph\u01b0\u01a1ng tr\u00ecnh ho\u00e1 h\u1ecdc \u1edf d\u1ea1ng ion:<\/p>\n
CH3<\/sub>COOH + OH–<\/sup>\u00a0\u2192 CH3<\/sub>COO–<\/sup>\u00a0+ H2<\/sub>O<\/p>\nHCOOH + OH–<\/sup>\u00a0\u2192 HCOO–<\/sup>\u00a0+ H2<\/sub>O<\/p>\nb) Theo \u0111\u1ec1 b\u00e0i ta c\u00f3 h\u1ec7 ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n
![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-6-trang-210-sgk-hoa-11-1.PNG\")
<\/div>\n
\n
B\u00e0i 7 (trang 210 SGK H\u00f3a 11):<\/b><\/span>\u00a0\u0110un 12,0 gam axit axetic v\u1edbi m\u1ed9t l\u01b0\u1ee3ng d\u01b0 ancol etylic ( c\u00f3 axit H2<\/sub>SO4<\/sub>\u00a0\u0111\u1eb7c l\u00e0m x\u00fac t\u00e1c ). \u0110\u1ebfn khi d\u1eebng th\u00ed nghi\u1ec7m thu \u0111\u01b0\u1ee3c 12,3 gam este.<\/p>\na. Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a ph\u1ea3n \u1ee9ng.<\/p>\n
b. T\u00ednh ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a axit \u0111\u00e3 tham gia ph\u1ea3n \u1ee9ng este h\u00f3a.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc:<\/p>\n
CH3<\/sub>COOH + C2<\/sub>H5<\/sub>OH —H2<\/sub>SO4<\/sub><\/sup>\u2192 CH3<\/sub>COOC2<\/sub>H5<\/sub>\u00a0+ H2<\/sub>O<\/p>\nb)<\/p>\n
![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-7-trang-210-sgk-hoa-11.PNG\")
<\/p>\n
<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
B\u00e0i 1 (trang 210 SGK H\u00f3a 11):\u00a0Th\u1ebf n\u00e0o l\u00e0 axit cacbonxylic? Vi\u1ebft c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o, g\u1ecdi t\u00ean c\u00e1c axit c\u00f3 c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C4H2O2. L\u1eddi gi\u1ea3i: – \u0110\u1ecbnh ngh\u0129a axit cacboxylic : l\u00e0 nh\u1eefng h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1 m\u00e0 ph\u00e2n t\u1eed c\u00f3 nh\u00f3m cacboxyl (-COOH) li\u00ean k\u1ebft tr\u1ef1c ti\u1ebfp v\u1edbi nguy\u00ean t\u1eed cacbon(1)\u00a0ho\u1eb7c […]<\/p>\n","protected":false},"author":3,"featured_media":32143,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1322],"tags":[1513,1512],"yoast_head":"\n
Ch\u01b0\u01a1ng 9: B\u00e0i 45 : Axit cacboxylic<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-9-bai-45-axit-cacboxylic\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 9: B\u00e0i 45 : Axit cacboxylic\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 210 SGK H\u00f3a 11):\u00a0Th\u1ebf n\u00e0o l\u00e0 axit cacbonxylic? Vi\u1ebft c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o, g\u1ecdi t\u00ean c\u00e1c axit c\u00f3 c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C4H2O2. 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![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-1-trang-210-sgk-hoa-11.PNG\")
<\/p>\n![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-2-trang-210-sgk-hoa-11.PNG\")
<\/p>\n![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-3-trang-210-sgk-hoa-11.PNG\")
B\u00e0i 4 (trang 210 SGK H\u00f3a 11):<\/b><\/span>\u00a0Ch\u1ea5t Y c\u00f3 c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C4<\/sub>H8<\/sub>O2<\/sub>\u00a0t\u00e1c d\u1ee5ng v\u1edbi NaOH t\u1ea1o th\u00e0nh ch\u1ea5t Z (C4<\/sub>H7<\/sub>O2<\/sub>Na). V\u1eady Y thu\u1ed9c lo\u1ea1i h\u1ee3p ch\u1ea5t n\u00e0o sau \u0111\u00e2y?<\/p>\n![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-5-trang-210-sgk-hoa-11.PNG\")
\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0mNaOH<\/sub>\u00a0= 0,1.1,5 = 0,15(mol)<\/p>\n![\"Gi\u1ea3i](\"http:\/\/vietjack.com\/giai-hoa-lop-11\/images\/bai-5-trang-210-sgk-hoa-11-1.PNG\")
<\/div>\n