\u0110\u1ec3 tr\u00e1nh m\u1ea5t \u0111i\u1ec3m khi l\u00e0m b\u00e0i thi THPT Qu\u1ed1c gia m\u00f4n Sinh, th\u00ed sinh c\u1ea7n ch\u00fa \u00fd nh\u1eefng l\u1ed7i th\u01b0\u1eddng g\u1eb7p sau:<\/p>\n

Theo chia s\u1ebb c\u1ee7a c\u00f4\u00a0Phan Th\u1ecb Ph\u00fa, trong b\u00e0i thi Sinh h\u1ecdc, th\u00ed sinh th\u01b0\u1eddng m\u1eafc nh\u1eefng l\u1ed7i kh\u00e1 “ng\u1edb ng\u1ea9n”, c\u00f3 th\u1ec3 g\u00e2y “m\u1ea5t \u0111i\u1ec3m oan”, trong\u00a0\u0111\u00f3 c\u00f3 c\u1ea3 l\u1ed7i do c\u00e1c em kh\u00f4ng\u00a0\u0111\u1ecdc k\u1ef9\u00a0\u0111\u1ec1 b\u00e0i. V\u00ec v\u1eady, ngay trong qu\u00e1\u00a0tr\u00ecnh\u00a0\u00f4n t\u1eadp, c\u00e1c em n\u00ean l\u01b0u t\u00e2m\u00a0\u0111\u1ebfn nh\u1eefng l\u1ed7i th\u00f4ng th\u01b0\u1eddng\u00a0\u0111\u1ec3 b\u00e0i thi ch\u00ednh th\u1ee9c \u0111\u1ea1t k\u1ebft qu\u1ea3 t\u1ed1t nh\u1ea5t.<\/p>\n

M\u1ed9t s\u1ed1 l\u1ed7i khi \u0111\u1ecdc \u0111\u1ea7u b\u00e0i kh\u00f4ng k\u1ef9<\/strong><\/p>\n

– C\u00e1c gen n\u1eb1m tr\u00ean c\u00e1c NST kh\u00e1c nhau kh\u00e1c v\u1edbi c\u00e1c gen c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t NST.<\/p>\n

– Gen n\u1eb1m \u1edf ti th\u1ec3, l\u1eadp th\u1ec3 hay h\u1ec7 gen v\u00f2ng th\u00ec c\u00e1c em ph\u1ea3i suy ra gen n\u1eb1m \u1edf t\u1ebf b\u00e0o ch\u1ea5t n\u00ean s\u1ebd tu\u00e2n theo quy lu\u1eadt di truy\u1ec1n qua t\u1ebf b\u00e0o ch\u1ea5t (ngo\u00e0i nh\u00e2n) ch\u1ee9 kh\u00f4ng ph\u1ea3i theo quy lu\u1eadt trong nh\u00e2n.<\/p>\n

– Gen n\u1eb1m tr\u00ean v\u00f9ng t\u01b0\u01a1ng \u0111\u1ed3ng c\u1ee7a NST X v\u00e0 Y hay \u0111\u1ecdc nh\u1ea7m v\u1edbi gen n\u1eb1m tr\u00ean v\u00f9ng kh\u00f4ng t\u01b0\u01a1ng \u0111\u1ed3ng c\u1ee7a X (kh\u00f4ng c\u00f3 alen tr\u00ean Y).<\/p>\n

– M\u1ed7i ki\u1ec3u gen quy \u0111\u1ecbnh m\u1ed9t ki\u1ec3u h\u00ecnh (t\u1ee9c l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng tr\u1ed9i kh\u00f4ng ho\u00e0n to\u00e0n) s\u1ebd kh\u00e1c v\u1edbi tr\u01b0\u1eddng h\u1ee3p tr\u1ed9i ho\u00e0n to\u00e0n trong vi\u1ec7c t\u00ednh s\u1ed1 ki\u1ec3u h\u00ecnh v\u00e0 t\u1ec9 l\u1ec7 ki\u1ec3u h\u00ecnh.<\/p>\n

– N\u1ebfu b\u00e0i h\u1ecfi t\u00ecm s\u1ed1 ki\u1ec3u gen t\u1ed1i \u0111a, t\u1ed1i thi\u1ec3u m\u00e0 kh\u00f4ng n\u00f3i gen n\u1eb1m \u1edf v\u1ecb tr\u00ed n\u00e0o trong t\u1ebf b\u00e0o th\u00ec em ph\u1ea3i x\u00e1c \u0111\u1ecbnh gen n\u1eb1m \u1edf v\u00f9ng t\u01b0\u01a1ng \u0111\u1ed3ng c\u1ee7a X v\u00e0 Y l\u00e0 s\u1ed1 ki\u1ec3u gen nhi\u1ec1u nh\u1ea5t. C\u00f2n gen n\u1eb1m ngo\u00e0i nh\u00e2n l\u00e0 s\u1ed1 ki\u1ec3u gen \u00edt nh\u1ea5t.<\/p>\n

– T\u1ea5t c\u1ea3 c\u00e1c t\u1ebf b\u00e0o kh\u00f4ng ph\u00e2n ly trong gi\u1ea3m ph\u00e2n 1(2) kh\u00e1c v\u1edbi tr\u01b0\u1eddng h\u1ee3p m\u1ed9t s\u1ed1 t\u1ebf b\u00e0o kh\u00f4ng ph\u00e2n ly trong gi\u1ea3m ph\u00e2n 1(2).<\/p>\n

– C\u1ea7n ch\u00fa \u00fd c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 (NST) gi\u1edbi t\u00ednh c\u1ee5 th\u1ec3 c\u1ee7a m\u1ed9t s\u1ed1 lo\u00e0i c\u00f3 kh\u00e1c nhau \u0111\u1ec3 \u00e1p d\u1ee5ng l\u00e0m b\u00e0i t\u1eadp. \u1ede g\u00e0, chim, t\u1eb1m, c\u00e1 … th\u00ec c\u1eb7p NST gi\u1edbi t\u00ednh c\u1ee7a gi\u1edbi \u0111\u1ef1c l\u00e0 XX, gi\u1edbi c\u00e1i l\u00e0 XY. C\u00f2n \u1edf ru\u1ed3i gi\u1ea5m, \u0111\u1ed9ng v\u1eadt thu\u1ed9c l\u1edbp th\u00fa th\u00ec ng\u01b0\u1ee3c l\u1ea1i c\u1eb7p NST gi\u1edbi t\u00ednh \u1edf gi\u1edbi c\u00e1i l\u1ea1i l\u00e0 XX, gi\u1edbi \u0111\u1ef1c l\u00e0 XY.<\/p>\n

C\u00f4\u00a0Phan Th\u1ecb Ph\u00fa hi v\u1ecdng r\u1eb1ng, c\u00e1c th\u00ed sinh s\u1ebd\u00a0\u00f4n t\u1eadp m\u1ed9t c\u00e1ch khoa\u00a0h\u1ecdc, gi\u1eef t\u00e2m l\u00fd b\u00ecnh t\u0129nh, t\u1ef1 tin\u00a0\u0111\u1ec3 tr\u00e1nh m\u1ea5t \u0111i\u1ec3m b\u1edfi nh\u1eefng l\u1ed7i kh\u00f4ng \u0111\u00e1ng c\u00f3\u00a0khi l\u00e0m b\u00e0i\u00a0v\u00e0 gi\u00e0nh\u00a0\u0111i\u1ec3m cao m\u00f4n Sinh h\u1ecdc trong k\u1ef3 thi THPT Qu\u1ed1c gia 2016.<\/p>\n

1. D\u1ea1ng b\u00e0i t\u1eadp Ph\u1ea7n AND, ARN, nh\u00e2n \u0111\u00f4i AND, phi\u00ean m\u00e3, d\u1ecbch m\u00e3<\/strong><\/p>\n

V\u00ed d\u1ee5:\u00a0<\/strong>M\u1ed9t plasmit c\u00f3 104 c\u1eb7p nucl\u00ea\u00f4tit ti\u1ebfn h\u00e0nh nh\u00e2n \u0111\u1ed9i 3 l\u1ea7n, s\u1ed1 li\u00ean k\u1ebft c\u1ed9ng ho\u00e1 tr\u1ecb \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh gi\u1eefa c\u00e1c nucl\u00ea\u00f4tit c\u1ee7a ADN l\u00e0.<\/p>\n

\u0110\u00e2y l\u00e0 m\u1ed9t plasmit (n\u1eb1m trong t\u1ebf b\u00e0o ch\u1ea5t c\u1ee7a nhi\u1ec1u lo\u00e0i vi khu\u1ea9n) n\u00ean ch\u00fang c\u00f3 h\u1ec7 gen d\u1ea1ng v\u00f2ng. V\u00ec v\u1eady t\u00ednh s\u1ed1 li\u00ean k\u1ebft h\u00f3a tr\u1ecb \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh trong qu\u00e1 tr\u00ecnh nh\u00e2n \u0111\u00f4i th\u00ec kh\u00f4ng th\u1ec3 \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c th\u00f4ng th\u01b0\u1eddng : HTht = HTgen ( 2n \u2013 1) = ( N- 2) (2n \u2013 1) m\u00e0 ph\u1ea3i t\u00ednh b\u1eb1ng c\u00f4ng th\u1ee9c: N (2n \u2013 1)<\/p>\n

a.160000. \u00a0 \u00a0 \u00a0 \u00a0b.159984. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 c.139986. \u00a0 \u00a0 \u00a0 \u00a0d.140000.<\/p>\n

\u0110\u00e1p \u00e1n: d<\/em><\/p>\n

2. D\u1ea1ng b\u00e0i t\u1eadp quy lu\u1eadt di truy\u1ec1n.<\/strong><\/p>\n

V\u00ed d\u1ee5 1<\/strong>. Cho bi\u1ebft A tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi a. L\u1ea5y h\u1ea1t ph\u1ea5n c\u1ee7a c\u00e2y tam b\u1ed9i Aaa th\u1ee5 ph\u1ea5n cho c\u00e2y t\u1ee9 b\u1ed9i Aaaa, n\u1ebfu h\u1ea1t ph\u1ea5n l\u01b0\u1ee1ng b\u1ed9i kh\u00f4ng c\u00f3 kh\u1ea3 n\u0103ng th\u1ee5 tinh th\u00ec t\u1ec9 l\u1ec7 ki\u1ec3u h\u00ecnh \u1edf \u0111\u1eddi con l\u00e0:<\/p>\n

a.3 : 1. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0b.8 : 1. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0c .11 : 1. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 d .9 : 1.<\/p>\n

C\u00e1c em s\u1ebd gi\u1ea3i b\u00e0i to\u00e1n v\u1edbi 2 s\u1ef1 ch\u00fa \u00fd sau:<\/p>\n

– H\u1ea1t ph\u1ea5n l\u01b0\u1ee1ng b\u1ed9i (2n) kh\u00f4ng c\u00f3 kh\u1ea3 n\u0103ng th\u1ee5 tinh th\u00ec sau khi em vi\u1ebft giao t\u1eed \u0111\u01b0\u1ee3c t\u1ea1o ra c\u1ee7a c\u01a1 th\u1ec3 tam b\u1ed9i g\u1ed3m n v\u00e0 2n th\u00ec em ph\u1ea3i cho giao t\u1eed 2n b\u1ecb ch\u1ebft, sau \u0111\u00f3 chia l\u1ea1i t\u1ec9 l\u1ec7 c\u1ee7a c\u00e1c giao t\u1eed c\u00f2n l\u1ea1i tham gia th\u1ee5 tinh 2\/3 a : 1\/3 A.<\/p>\n

– Khi \u0111\u1ecdc k\u1ebft qu\u1ea3 b\u00e0i to\u00e1n ph\u1ea3i ch\u00ednh x\u00e1c. V\u1edbi b\u00e0i n\u00e0y c\u00e1c em t\u00ecm t\u1ec9 l\u1ec7 ki\u1ec3u h\u00ecnh l\u1eb7n = 1\/9; k\u1ebft qu\u1ea3 l\u00e0 8 tr\u1ed9i: 1 l\u1eb7n ch\u1ee9 kh\u00f4ng ph\u1ea3i l\u00e0 9 tr\u1ed9i: 1 l\u1eb7n<\/p>\n

\u0110\u00e1p \u00e1n: b<\/em><\/p>\n

V\u00ed d\u1ee5 2<\/strong>. M\u1ed9t c\u1eb7p v\u1ee3 ch\u1ed3ng \u0111\u1ec1u c\u00f3 nh\u00f3m m\u00e1u A v\u00e0 \u0111\u1ec1u c\u00f3 ki\u1ec3u gen d\u1ecb h\u1ee3p v\u1ec1 t\u00ednh tr\u1ea1ng nh\u00f3m m\u00e1u. N\u1ebfu h\u1ecd sinh hai \u0111\u1ee9a con th\u00ec x\u00e1c xu\u1ea5t \u0111\u1ec3 1 \u0111\u1ee9a c\u00f3 nh\u00f3m m\u00e1u A v\u00e0 m\u1ed9t \u0111\u1ee9a c\u00f3 nh\u00f3m m\u00e0u O l\u00e0:<\/p>\n

a.3\/8 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0b.3\/16 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 c.1\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 d.1\/4<\/p>\n

V\u1edbi b\u00e0i n\u00e0y \u0111\u1ec1 y\u00eau c\u1ea7u ch\u1ec9 c\u1ea7n 1 \u0111\u1ee9a con nh\u00f3m m\u00e1u A v\u00e0 m\u1ed9t 1 \u0111\u1ee9a con nh\u00f3m m\u00e1u O, ch\u1ee9 kh\u00f4ng b\u1eaft bu\u1ed9c \u0111\u1ee9a con \u0111\u1ea7u ph\u1ea3i mang nh\u00f3m m\u00e1u A v\u00e0 \u0111\u1ee9a con sau ph\u1ea3i mang nh\u00f3m m\u00e1u O. V\u00ec v\u1eady s\u1ebd c\u00f3 2 tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra. V\u00e0 h\u1ecd \u0111\u1ec1u l\u00e0 con c\u1ee7a m\u1ed9t c\u1eb7p b\u1ed1 m\u1eb9 n\u00ean ch\u00fang ta ch\u1ec9 l\u1ea5y s\u1eafc xu\u1ea5t 1 l\u1ea7n c\u1ee7a b\u1ed1 v\u00e0 m\u1eb9 cho c\u00f9ng c\u1ea3 2 \u0111\u1ee9a tr\u1ebb.<\/p>\n

K\u1ebft qu\u1ea3 b\u00e0i to\u00e1n: (x\u00e1c su\u1ea5t c\u1ee7a b\u1ed1 ) x (x\u00e1c su\u1ea5t c\u1ee7a m\u1eb9 ) x (x\u00e1c su\u1ea5t c\u1ee7a 2 con).<\/p>\n

1.1 . [ ( 3\/4 .1\/4) .2] = 3\/8.<\/p>\n

\u0110\u00e1p \u00e1n: a<\/em><\/p>\n

V\u00ed d\u1ee5 3.<\/strong>\u00a0\u1ede t\u1eb1m, hai gen A v\u00e0 B c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t nh\u00f3m gen li\u00ean k\u1ebft c\u00e1ch nhau 20cM. \u1ede ph\u00e9p lai \u2640ABab \u00d7 \u2642 AbaB , ki\u1ec3u gen abab c\u1ee7a \u0111\u1eddi con c\u00f3 t\u1ec9 l\u1ec7<\/p>\n

a.0,05. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 b.0,01. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 c.0,04. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0d.0,00.<\/p>\n

C\u00e1c em v\u1eabn quen l\u00e0m b\u00e0i t\u1eadp s\u1ef1 ho\u00e1n v\u1ecb gen x\u1ea3y ra \u1edf con ru\u1ed3i gi\u1ea5m c\u00e1i. Tuy nhi\u00ean trong SGK \u0111\u01a1n c\u1eed v\u00ed d\u1ee5 v\u1ec1 con t\u1eb1m trong b\u00e0i 12 th\u00ec c\u00e1c em ph\u1ea3i ch\u00fa \u00fd s\u1ef1 ho\u00e1n v\u1ecb gen l\u1ea1i x\u1ea3y ra \u1edf con t\u1eb1m \u0111\u1ef1c (c\u00f3 c\u1eb7p NST g\u1edbi t\u00ednh l\u00e0 XX) .<\/p>\n

\u0110\u00e1p \u00e1n: a<\/em><\/p>\n

V\u00ed d\u1ee5 4.<\/strong>\u00a0Gen A v\u00e0 B c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t c\u1eb7p NST th\u01b0\u1eddng, trong \u0111\u00f3 gen A c\u00f3 5 alen, gen B c\u00f3 3 alen. S\u1ed1 ki\u1ec3u gen d\u1ecb h\u1ee3p v\u1ec1 c\u1ea3 hai gen l\u00e0.<\/p>\n

a.30. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0b.105. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 c.45. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 d.60.<\/p>\n

\u0110\u00e2y l\u00e0 m\u1ed9t b\u00e0i m\u1eafc b\u1eaby h\u1ecdc sinh v\u00ec c\u00e1c gen c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t NST n\u00ean s\u1ed1 ki\u1ec3u gen d\u1ecb h\u1ee3p c\u1ee7a c\u1ea3 2 c\u1eb7p ( ngo\u00e0i tr\u01b0\u1eddng h\u1ee3p li\u00ean k\u1ebft \u0111\u1ed3ng AB\/ab c\u00f2n c\u00f3 tr\u01b0\u1eddng h\u1ee3p li\u00ean k\u1ebft \u0111\u1ed1i Ab\/aB do ho\u00e1n v\u1ecb gen).<\/p>\n

K\u1ebft qu\u1ea3 b\u00e0i to\u00e1n tr\u00ean l\u00e0: (C25 . C23.).2 = 60<\/p>\n

3. D\u1ea1ng b\u00e0i t\u1eadp di truy\u1ec1n qu\u1ea7n th\u1ec3<\/strong><\/p>\n

V\u00ed d\u1ee5<\/strong>. \u1ede ng\u01b0\u1eddi, t\u00ednh tr\u1ea1ng nh\u00f3m m\u00e1u ABO do m\u1ed9t gen c\u1ecf alen IA, IB, IO quy \u0111\u1ecbnh. Trong m\u1ed9t qu\u1ea7n th\u1ec3 \u0111an c\u00e2n b\u1eb1ng v\u1ec1 di truy\u1ec1n c\u00f3 25% s\u1ed1 ng\u01b0\u1eddi mang nh\u00f3m m\u00e1u O; 39% s\u1ed1 ng\u01b0\u1eddi mang nh\u00f3m m\u00e1u B. M\u1ed9t v\u1eb7p v\u1ee3 ch\u1ed3ng \u0111\u1ec1u mang nh\u00f3m m\u00e1u A sinh ng\u01b0\u1eddi con, x\u00e1c su\u1ea5t \u0111\u1ec3 \u0111\u1ee9a con n\u00e0y mang nh\u00f3m m\u00e1u gi\u1ed1ng b\u1ed1 m\u1eb9.<\/p>\n

a.25144 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 b.119144 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0c.1924 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 d.34<\/p>\n

V\u1edbi b\u00e0i n\u00e0y c\u00e1c em d\u1ec5 d\u00e0ng t\u00ednh \u0111\u01b0\u1ee3c p(IA) = 0,2 ; q(IB) = 0,3 ; r(IO) = 0,5.<\/p>\n

\u0110\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c x\u00e1c su\u1ea5t \u0111\u1ee9a con n\u00e0y mang nh\u00f3m m\u00e1u gi\u1ed1ng b\u1ed1 m\u1eb9, ta c\u00f3 100% – (x\u00e1c su\u1ea5t \u0111\u1ee9a con n\u00e0y mang nh\u00f3m m\u00e1u kh\u00e1c b\u1ed1 m\u1eb9 b\u1ed1 m\u1eb9).<\/p>\n

Mu\u1ed1n v\u1eady ph\u1ea3i t\u00ecm \u0111\u01b0\u1ee3c x\u00e1c su\u1ea5t ng\u01b0\u1eddi cha m\u00e0 ng\u01b0\u1eddi m\u1eb9 \u0111\u1ec1u c\u00f3 ki\u1ec3u gen IAIO trong t\u1ed5ng s\u1ed1 ng\u01b0\u1eddi mang nh\u00f3m m\u00e1u A ch\u1ee9 kh\u00f4ng ph\u1ea3i t\u00ecm trong t\u1ed5ng qu\u1ea7n th\u1ec3. V\u00ec ng\u01b0\u1eddi cha v\u00e0 m\u1eb9 \u0111\u00e3 sinh ra \u0111\u1eddi v\u00e0 \u0111\u1ea7u b\u00e0i \u0111\u00e3 kh\u1eb3ng \u0111\u1ecbnh l\u00e0 nh\u00f3m m\u00e1u A.<\/p>\n

– K\u1ebft qu\u1ea3 b\u00e0i to\u00e1n: 100% – ( 5\/6 b\u1ed1 . 5\/6 m\u1eb9 . 1\/4 con) = 119\/144<\/p>\n

\u0110\u00e1p \u00e1n: b<\/em><\/p>\n

Theo Kim Thoa<\/strong><\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

\u0110\u1ec3 tr\u00e1nh m\u1ea5t \u0111i\u1ec3m khi l\u00e0m b\u00e0i thi THPT Qu\u1ed1c gia m\u00f4n Sinh, th\u00ed sinh c\u1ea7n ch\u00fa \u00fd nh\u1eefng l\u1ed7i th\u01b0\u1eddng g\u1eb7p sau: Theo chia s\u1ebb c\u1ee7a c\u00f4\u00a0Phan Th\u1ecb Ph\u00fa, trong b\u00e0i thi Sinh h\u1ecdc, th\u00ed sinh th\u01b0\u1eddng m\u1eafc nh\u1eefng l\u1ed7i kh\u00e1 “ng\u1edb ng\u1ea9n”, c\u00f3 th\u1ec3 g\u00e2y “m\u1ea5t \u0111i\u1ec3m oan”, trong\u00a0\u0111\u00f3 c\u00f3 c\u1ea3 l\u1ed7i do […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[160],"tags":[],"yoast_head":"\n