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{"id":3095,"date":"2016-05-04T10:47:49","date_gmt":"2016-05-04T10:47:49","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=3095"},"modified":"2016-05-04T10:47:49","modified_gmt":"2016-05-04T10:47:49","slug":"de-thi-thu-thpt-quoc-gia-mon-ly-nam-2016_thpt-chuyen-le-hong-phong-nam-dinh-2","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/de-thi-thu-thpt-quoc-gia-mon-ly-nam-2016_thpt-chuyen-le-hong-phong-nam-dinh-2\/","title":{"rendered":"\u0110\u1ec1 thi Th\u1eed THPT qu\u1ed1c gia m\u00f4n L\u00fd n\u0103m 2016_THPT Chuy\u00ean L\u00ea H\u1ed3ng Phong (Nam \u0110\u1ecbnh)"},"content":{"rendered":"

D\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0110\u1ec1 thi Th\u1eed THPT qu\u1ed1c gia m\u00f4n L\u00fd n\u0103m 2016_THPT Chuy\u00ean L\u00ea H\u1ed3ng Phong (Nam \u0110\u1ecbnh). Ch\u00fac c\u00e1c b\u1ea1n h\u1ecdc sinh \u00f4n t\u1eadp th\u1eadt t\u1ed1t \u0111\u1ec3 chu\u1ea9n b\u1ecb cho k\u1ef3 thi quan tr\u1ecdng n\u00e0y!<\/p>\n\n\n\n\n
TR\u01af\u1edcNG THPT CHUY\u00caN<\/u><\/strong><\/p>\n

L\u00ca H\u1ed2NG PHONG<\/u><\/strong><\/p>\n

 <\/p>\n

\u0110\u1ec0 CH\u00cdNH TH\u1ee8C<\/strong><\/p>\n

(\u0110\u1ec1 thi g\u1ed3m c\u00f3 5 trang)<\/td>\n

K\u1ef2 THI TH\u1eec THPT QG L\u1ea6N 1 N\u0102M 2016<\/strong><\/p>\n

M\u00d4N: V\u1eacT L\u00dd<\/strong><\/p>\n

Th\u1eddi gian l\u00e0m b\u00e0i: 90 ph\u00fat <\/em><\/p>\n

(50 c\u00e2u tr\u1eafc nghi\u1ec7m)<\/em><\/p>\n

 <\/td>\n<\/tr>\n

<\/td>\nM\u00e3 \u0111\u1ec1 thi 132<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\"De<\/a><\/p>\n

\"De<\/a><\/p>\n

C\u00e2u 17:<\/strong> Trong th\u00ed nghi\u1ec7m Y-\u00e2ng, ngu\u1ed3n S ph\u00e1t b\u1ee9c x\u1ea1 \u0111\u01a1n s\u1eafc , m\u00e0n quan s\u00e1t c\u00e1ch m\u1eb7t ph\u1eb3ng hai khe m\u1ed9t kho\u1ea3ng kh\u00f4ng \u0111\u1ed5i D, kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe S1<\/sub>S2<\/sub>=a c\u00f3 th\u1ec3 thay \u0111\u1ed5i (nh\u01b0ng S1<\/sub> v\u00e0 S2<\/sub> lu\u00f4n c\u00e1ch \u0111\u1ec1u S). X\u00e9t \u0111i\u1ec3m M tr\u00ean m\u00e0n, l\u00fac \u0111\u1ea7u l\u00e0 v\u00e2n s\u00e1ng b\u1eadc 4, n\u1ebfu l\u1ea7n l\u01b0\u1ee3t gi\u1ea3m ho\u1eb7c t\u0103ng kho\u1ea3ng c\u00e1ch S1<\/sub>S2<\/sub> m\u1ed9t l\u01b0\u1ee3ng th\u00ec t\u1ea1i \u0111\u00f3 l\u00e0 v\u00e2n s\u00e1ng b\u1eadc k v\u00e0 b\u1eadc 3k. N\u1ebfu t\u0103ng kho\u1ea3ng c\u00e1ch S1<\/sub>S2<\/sub> th\u00eam th\u00ec t\u1ea1i M l\u00e0<\/p>\n

A.<\/strong> v\u00e2n s\u00e1ng b\u1eadc 9. B.<\/strong> v\u00e2n s\u00e1ng b\u1eadc 8.<\/p>\n

C.<\/strong> v\u00e2n t\u1ed1i th\u1ee9 9 . D.<\/strong> v\u00e2n s\u00e1ng b\u1eadc 7.<\/p>\n

C\u00e2u 18:<\/strong> M\u1ed9t \u0111\u00e8n ph\u00e1t ra b\u1ee9c x\u1ea1 c\u00f3 t\u1ea7n s\u1ed1 f = 1014 <\/sup>Hz. b\u1ee9c x\u1ea1 n\u00e0y thu\u1ed9c v\u00f9ng n\u00e0o c\u1ee7a thang s\u00f3ng \u0111i\u1ec7n t\u1eeb?<\/p>\n

A.<\/strong> V\u00f9ng t\u1eed ngo\u1ea1i. B.<\/strong> V\u00f9ng h\u1ed3ng ngo\u1ea1i.<\/p>\n

C.<\/strong> V\u00f9ng \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y. D.<\/strong> Tia R\u01a1nghen.<\/p>\n

C\u00e2u 19:<\/strong> Trong thang m\u00e1y c\u00f3 treo m\u1ed9t con l\u1eafc \u0111\u01a1n. L\u00fac \u0111\u1ea7u thang m\u00e1y \u0111\u1ee9ng y\u00ean, chu k\u1ef3 con l\u1eafc l\u00e0 T0<\/sub>. H\u1ecfi thang m\u00e1y chuy\u1ec3n \u0111\u1ed9ng theo chi\u1ec1u n\u00e0o, gia t\u1ed1c b\u1eb1ng bao nhi\u00eau \u0111\u1ec3 chu k\u00ec t\u0103ng 10%? L\u1ea5y g = 10 m\/s2<\/sup>.<\/p>\n

A.<\/strong> \u0110i l\u00ean, a = 1,74 m\/s2<\/sup>. B<\/strong>. \u0110i xu\u1ed1ng, a = 1,74 m\/s2<\/sup> .<\/p>\n

C.<\/strong> \u0110i xu\u1ed1ng, a = 1,13 m\/s2<\/sup>. D<\/strong>. \u0110i l\u00ean, a = 1,13 m\/s2<\/sup>.<\/p>\n

C\u00e2u 20:<\/strong> C\u00f4ban ph\u00f3ng x\u1ea1 Co c\u00f3 chu k\u00ec b\u00e1n r\u00e3 5,7 n\u0103m. \u0110\u1ec3 kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t ph\u00f3ng x\u1ea1 gi\u1ea3m \u0111i e l\u1ea7n so v\u1edbi kh\u1ed1i l\u01b0\u1ee3ng ban \u0111\u1ea7u th\u00ec c\u1ea7n kho\u1ea3ng th\u1eddi gian:<\/p>\n

A.<\/strong> 8 n\u0103m. B. <\/strong>8,23 n\u0103m. C. <\/strong>9 n\u0103m. D. <\/strong>8,55 n\u0103m.<\/p>\n

C\u00e2u 21:<\/strong> M v\u00e0 N l\u00e0 hai \u0111i\u1ec3m tr\u00ean m\u1ed9t m\u1eb7t n\u01b0\u1edbc ph\u1eb3ng l\u1eb7ng c\u00e1ch nhau m\u1ed9t kho\u1ea3ng 20cm. T\u1ea1i \u0111i\u1ec3m O tr\u00ean \u0111\u01b0\u1eddng th\u1eb3ng MN v\u00e0 n\u1eb1m ngo\u00e0i \u0111o\u1ea1n MN, ng\u01b0\u1eddi ta \u0111\u1eb7t ngu\u1ed3n dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t n\u01b0\u1edbc v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh , t\u1ea1o ra s\u00f3ng tr\u00ean m\u1eb7t n\u01b0\u1edbc v\u1edbi b\u01b0\u1edbc s\u00f3ng . Kho\u1ea3ng c\u00e1ch xa nh\u1ea5t gi\u1eefa hai ph\u1ea7n t\u1eed m\u00f4i tr\u01b0\u1eddng t\u1ea1i M v\u00e0 N khi c\u00f3 s\u00f3ng truy\u1ec1n qua l\u00e0 bao nhi\u00eau?<\/p>\n

A<\/strong>. 25cm. B. <\/strong>20,52cm. C. <\/strong>23cm. D. <\/strong>21, 79cm.<\/p>\n

C\u00e2u 22:<\/strong> B\u1eafn m\u1ed9t h\u1ea1t \u03b1 c\u00f3 \u0111\u1ed9ng n\u0103ng 4 MeV v\u00e0o h\u1eadt nh\u00e2n \u0111\u1ee9ng y\u00ean t\u1ea1o th\u00e0nh h\u1ea1t proton v\u00e0 . Ph\u1ea3n \u1ee9ng thu n\u0103ng l\u01b0\u1ee3ng l\u00e0 1,21 MeV. Bi\u1ebft hai h\u1ea1t sinh ra c\u00f3 c\u00f9ng \u0111\u1ed9ng n\u0103ng. G\u00f3c bay gi\u1eefa h\u1ea1t \u03b1 v\u00e0 h\u1ea1t nh\u00e2n l\u00e0<\/p>\n

A.<\/strong> 8,280<\/sup>. B. <\/strong>20,180<\/sup>. C. <\/strong>15,380<\/sup>. D. <\/strong>10,380<\/sup>.<\/p>\n

C\u00e2u 23:<\/strong> M\u1ed9t s\u00f3ng c\u01a1 h\u1ecdc truy\u1ec1n d\u1ecdc theo tr\u1ee5c 0x<\/em> v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh , trong \u0111\u00f3 x<\/em> t\u00ednh b\u1eb1ng cm, t t\u00ednh b\u1eb1ng s. T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng b\u1eafng:<\/p>\n

A<\/strong>. 100m\/s. B. <\/strong>20m\/s.<\/p>\n

C. <\/strong>50cm\/s. D. <\/strong>50m\/s.<\/p>\n

C\u00e2u 24:<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo treo v\u00e0o m\u1ed9t \u0111i\u1ec3m c\u1ed1 \u0111\u1ecbnh, dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng v\u1edbi chu k\u00ec 1,8 s. Trong m\u1ed9t chu k\u00ec, n\u1ebfu t\u1ec9 s\u1ed1 c\u1ee7a th\u1eddi gian l\u00f2 xo gi\u00e3n v\u1edbi th\u1eddi gian l\u00f2 xo n\u00e9n b\u1eb1ng 2 th\u00ec th\u1eddi gian m\u00e0 l\u1ef1c \u0111\u00e0n h\u1ed3i ng\u01b0\u1ee3c chi\u1ec1u l\u1ef1c k\u00e9o v\u1ec1 l\u00e0<\/p>\n

A<\/strong>. 0,1 s. B. <\/strong>0,2 s. C . <\/strong>0,3 s. D. <\/strong>0,4 s.<\/p>\n

C\u00e2u 25:<\/strong> Trong \u0111i\u1ec1u tr\u1ecb b\u1eb1ng ph\u00f3ng x\u1ea1, m\u1ed9t ngu\u1ed3n ph\u00f3ng x\u1ea1 c\u00f3 chu k\u1ef3 b\u00e1n r\u00e3 T = 6 n\u0103m. Khi \u0111i\u1ec1u tr\u1ecb l\u1ea7n \u0111\u1ea7u th\u00ec th\u1eddi gian cho m\u1ed9t li\u1ec1u chi\u1ebfu x\u1ea1 l\u00e0 5 ph\u00fat. Sau 1 n\u0103m th\u00ec th\u1eddi gian chi\u1ebfu x\u1ea1 cho m\u1ed9t li\u1ec1u t\u0103ng g\u1ea5p \u0111\u00f4i l\u00e0 (xem T r\u1ea5t l\u1edbn so v\u1edbi th\u1eddi gian chi\u1ebfu x\u1ea1)<\/p>\n

A<\/strong>. 11,22 ph\u00fat. B. <\/strong>17,23 ph\u00fat. C. <\/strong>9,12 ph\u00fat. D. <\/strong>18,38 ph\u00fat.<\/p>\n

C\u00e2u 26:<\/strong> M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i b\u1eb1ng 6 cm\/s v\u00e0 gia t\u1ed1c c\u1ef1c \u0111\u1ea1i b\u1eb1ng 18 cm\/s. T\u1ea7n s\u1ed1 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0:<\/p>\n

A<\/strong>. 0,95 Hz. B. <\/strong>2,86 Hz. C. <\/strong>1,43 Hz. D. <\/strong>0,48 Hz.<\/p>\n

C\u00e2u 27:<\/strong> Trong th\u00ed nghi\u1ec7m Young: Hai khe song song c\u00e1ch nhau a = 2 mm v\u00e0 c\u00e1ch \u0111\u1ec1u m\u00e0n E m\u1ed9t kho\u1ea3ng D = 3 m. Quan s\u00e1t v\u00e2n giao thoa tr\u00ean m\u00e0n ng\u01b0\u1eddi ta th\u1ea5y kho\u1ea3ng c\u00e1ch t\u1eeb v\u00e2n s\u00e1ng th\u1ee9 n\u0103m \u0111\u1ebfn v\u00e2n s\u00e1ng trung t\u00e2m l\u00e0 4,5 mm. B\u01b0\u1edbc s\u00f3ng c\u1ee7a ngu\u1ed3n s\u00e1ng \u0111\u00f3 l\u00e0:<\/p>\n

A.<\/strong> 0,7 mm. B. <\/strong>0,75 mm. C. <\/strong>0,6 mm. D. <\/strong>0,65 mm.<\/p>\n

C\u00e2u 28:<\/strong> C\u00f4ng tho\u00e1t electorn kh\u1ecfi m\u1eb7t kim lo\u1ea1i canxi (Ca) l\u00e0 2,76eV. Gi\u1edbi h\u1ea1n quang \u0111i\u1ec7n c\u1ee7a kim lo\u1ea1i l\u00e0:<\/p>\n

A<\/strong>. 0,36. B. <\/strong>0,66. C. <\/strong>0,72. D. <\/strong>0,45.<\/p>\n

C\u00e2u 29:<\/strong> M\u1ea1ch thu s\u00f3ng c\u00f3 l\u1ed1i v\u00e0o l\u00e0 m\u1ea1ch dao \u0111\u1ed9ng LC, t\u1ee5 \u0111i\u1ec7n C l\u00e0 t\u1ee5 ph\u1eb3ng kh\u00f4ng kh\u00ed th\u00ec khi \u0111\u00f3 b\u01b0\u1edbc s\u00f3ng m\u00e0 m\u1ea1ch thu \u0111\u01b0\u1ee3c l\u00e0 40 m. N\u1ebfu nh\u00fang 2\/3 di\u1ec7n t\u00edch c\u00e1c b\u1ea3n t\u1ee5 v\u00e0o trong \u0111i\u1ec7n m\u00f4i c\u00f3 h\u1eb1ng s\u1ed1 \u0111i\u1ec7n m\u00f4i \u03b5 = 2,5 th\u00ec b\u01b0\u1edbc s\u00f3ng m\u00e0 m\u1ea1ch thu \u0111\u01b0\u1ee3c khi \u0111\u00f3 b\u1eb1ng<\/p>\n

A<\/strong>. 66 m. B. <\/strong>69 m. C. <\/strong>57 m. D. <\/strong>62 m.<\/p>\n

C\u00e2u 30:<\/strong> M\u1ed9t v\u1eadt nh\u1ecf dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo m\u1ed9t qu\u1ef9 \u0111\u1ea1o th\u1eb3ng d\u00e0i 14 cm v\u1edbi chu k\u00ec 1 s. T\u1eeb th\u1eddi \u0111i\u1ec3m v\u1eadt qua v\u1ecb tr\u00ed c\u00f3 li \u0111\u1ed9 3,5 cm theo chi\u1ec1u d\u01b0\u01a1ng \u0111\u1ebfn khi gia t\u1ed1c c\u1ee7a v\u1eadt \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c ti\u1ec3u l\u1ea7n th\u1ee9 hai, v\u1eadt c\u00f3 t\u1ed1c \u0111\u1ed9 trung b\u00ecnh l\u00e0<\/p>\n

A<\/strong>. 28,0 cm\/s. B. <\/strong>26,7 cm\/s.<\/p>\n

C. <\/strong>27,0 cm\/s. D. <\/strong>27,3 cm\/s.<\/p>\n

C\u00e2u 31:<\/strong> M\u1ed9t \u0111\u1eb7c t\u00ednh v\u1eadt l\u00ed c\u1ee7a \u00e2m l\u00e0:<\/p>\n

A<\/strong>. \u0111\u1ed3 th\u1ecb dao \u0111\u1ed9ng \u00e2m. B. <\/strong>\u0111\u1ed9 cao.<\/p>\n

C. <\/strong>\u00e2m s\u1eafc. D. <\/strong>\u0111\u1ed9 to.<\/p>\n

C\u00e2u 32:<\/strong> Th\u1ef1c hi\u00ean giao thoa \u00e1nh s\u00e1ng v\u1edbi ngu\u1ed3n g\u1ed3m hai th\u00e0nh ph\u1ea7n \u0111\u01a1n s\u1eafc nh\u00ecn th\u1ea5y c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb1<\/sub> = 0,64\u03bcm v\u00e0 \u03bb2<\/sub>. Tr\u00ean m\u00e0n h\u1ee9ng c\u00e1c v\u00e2n giao thoa, gi\u1eefa hai v\u00e2n g\u1ea7n nh\u1ea5t c\u00f9ng m\u00e0u v\u1edbi v\u00e2n s\u00e1ng trung t\u00e2m \u0111\u1ebfm \u0111\u01b0\u1ee3c 11 v\u00e2n s\u00e1ng. Trong \u0111\u00f3, s\u1ed1 v\u00e2n c\u1ee7a b\u1ee9c x\u1ea1 \u03bb1<\/sub> v\u00e0 c\u1ee7a b\u1ee9c x\u1ea1 \u03bb2<\/sub> l\u1ec7ch nhau 3 v\u00e2n, b\u01b0\u1edbc s\u00f3ng c\u1ee7a \u03bb2<\/sub> l\u00e0:<\/p>\n

A.<\/strong> 0,42 \u03bcm. B. <\/strong>0,72 \u03bcm.<\/p>\n

C. <\/strong>0,4 \u03bcm. D. <\/strong>0,54 \u03bcm.<\/p>\n

\"De<\/a><\/p>\n

\"De<\/a><\/p>\n

C\u00e2u 43:<\/strong> Electron b\u1eadt ra kh\u1ecfi kim lo\u1ea1i khi c\u00f3 m\u1ed9t b\u1ee9c x\u1ea1 \u0111\u01a1n s\u1eafc chi\u1ebfu v\u00e0o, l\u00e0 v\u00ec:<\/p>\n

A.<\/strong> t\u1ea7n s\u1ed1 b\u1ee9c x\u1ea1 \u0111\u00f3 c\u00f3 gi\u00e1 tr\u1ecb l\u1edbn h\u01a1n m\u1ed9t gi\u00e1 tr\u1ecb x\u00e1c \u0111\u1ecbnh.<\/p>\n

B.<\/strong> v\u1eadn t\u1ed1c c\u1ee7a b\u1ee9c x\u1ea1 \u0111\u00f3 l\u1edbn h\u01a1n v\u1eadn t\u1ed1c x\u00e1c \u0111\u1ecbnh.<\/p>\n

C.<\/strong> b\u1ee9c x\u1ea1 \u0111\u00f3 c\u00f3 c\u01b0\u1eddng \u0111\u1ed9 r\u1ea5t l\u1edbn.<\/p>\n

D<\/strong>. b\u1ee9c x\u1ea1 \u0111\u00f3 c\u00f3 b\u01b0\u1edbc s\u00f3ng x\u00e1c \u0111\u1ecbnh.<\/p>\n

C\u00e2u 44:<\/strong> \u0110o\u1ea1n m\u1ea1ch xoay chi\u1ec1u AB g\u1ed3m \u0111o\u1ea1n m\u1ea1ch AN n\u1ed1i ti\u1ebfp v\u1edbi \u0111o\u1ea1n m\u1ea1ch NB. \u0110o\u1ea1n AN g\u1ed3m cu\u1ed9n c\u1ea3m thu\u1ea7n n\u1ed1i ti\u1ebfp v\u1edbi \u0111i\u1ec7n tr\u1edf thu\u1ea7n R, \u0111o\u1ea1n m\u1ea1ch NB ch\u1ec9 c\u00f3 t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C thay \u0111\u1ed5i \u0111\u01b0\u1ee3c. Hai \u0111\u1ea7u AB duy tr\u00ec m\u1ed9t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u c\u00f3 gi\u00e1 tr\u1ecb hi\u1ec7u d\u1ee5ng U v\u00e0 t\u1ea7n s\u1ed1 f kh\u00f4ng \u0111\u1ed5i. C\u1ea3m kh\u00e1ng b\u1eb1ng R. Khi C = C1<\/sub> th\u00ec h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a m\u1ea1ch b\u1eb1ng 1 v\u00e0 c\u00f4ng su\u1ea5t b\u1eb1ng 100W. Khi C = C2<\/sub> th\u00ec \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111i\u1ec3m AN c\u00f3 gi\u00e1 tr\u1ecb b\u1eb1ng U. C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 c\u1ee7a m\u1ea1ch khi \u0111\u00f3 b\u1eb1ng<\/p>\n

A<\/strong>. 50W. B. <\/strong>25W. C. <\/strong>25W. D. <\/strong>50W.<\/p>\n

C\u00e2u 45:<\/strong> \u0110\u1eb7t m\u1ed9t \u0111i\u1ec7n \u00e1p u = U0<\/sub>cos\u03c9t (V) (c\u00f3 t\u1ea7n s\u1ed1 g\u00f3c thay \u0111\u1ed5i \u0111\u01b0\u1ee3c) v\u00e0o hai \u0111\u1ea7u m\u1ea1ch m\u1eafc n\u1ed1i ti\u1ebfp g\u1ed3m cu\u1ed9n c\u1ea3m thu\u1ea7n L, \u0111i\u1ec7n tr\u1edf R v\u00e0 t\u1ee5 \u0111i\u1ec7n C v\u1edbi . CR2<\/sup> < 2L. Khi \u03c9 = \u03c91<\/sub> th\u00ec \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u t\u1ee5 \u0111i\u1ec7n c\u1ef1c \u0111\u1ea1i. Khi \u03c92<\/sub> = 4\/3 \u03c91<\/sub>th\u00ec \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u cu\u1ed9n c\u1ea3m \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i v\u00e0 b\u1eb1ng 332,61V. Gi\u1eef nguy\u00ean \u03c9 = \u03c92<\/sub> v\u00e0 b\u00e2y gi\u1edd cho C thay \u0111\u1ed5i \u0111\u1ebfn khi \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u t\u1ee5 \u0111i\u1ec7n \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i m\u1edbi. Gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i m\u1edbi n\u00e0y x\u1ea5p x\u1ec9 b\u1eb1ng<\/p>\n

A.<\/strong> 220,21V. B. <\/strong>381,05V. C. <\/strong>421,27V. D. <\/strong>311,13V.<\/p>\n

C\u00e2u 46:<\/strong> Cho m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u RLC n\u1ed1i ti\u1ebfp. Bi\u1ebft L = CR2<\/sup>\/4. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u m\u1ea1ch m\u1ed9t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u c\u00f3 t\u1ea7n s\u1ed1 g\u00f3c thay \u0111\u1ed5i \u0111\u01b0\u1ee3c. \u0110o\u1ea1n m\u1ea1ch c\u00f3 c\u00f9ng h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t v\u1edbi hai gi\u00e1 tr\u1ecb c\u1ee7a t\u1ea7n s\u1ed1 g\u00f3c \u03c91<\/sub> = 100 rad\/s v\u00e0 \u03c92<\/sub> = 400rad\/s. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t tr\u00ean b\u1eb1ng<\/p>\n

A.<\/strong> 0,9. B. <\/strong>0,75. C. <\/strong>0,83. D. <\/strong>0,8.<\/p>\n

\"De<\/a><\/p>\n

Theo Hoc.vtc.vn<\/p>\n","protected":false},"excerpt":{"rendered":"

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