B\u00e0i 1 (trang 120 SGK Sinh 11):<\/b>\u00a0\u0110i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng l\u00e0 g\u00ec? \u0110i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh nh\u01b0 th\u1ebf n\u00e0o?<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
– \u0110i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng l\u00e0 s\u1ef1 bi\u1ebfn \u0111\u1ed5i \u0111i\u1ec7n th\u1ebf ngh\u1ec9 \u1edf m\u00e0ng t\u1ebf b\u00e0o t\u1eeb ph\u00e2n c\u1ef1c sang m\u1ea5t ph\u00e2n c\u1ef1c, \u0111\u1ea3o c\u1ef1c v\u00e0 t\u00e1i ph\u00e2n c\u1ef1c.<\/p>\n
– S\u1ef1 h\u00ecnh th\u00e0nh \u0111i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng:<\/p>\n
+ Khi \u1edf giai \u0111o\u1ea1n \u0111i\u1ec7n th\u1ebf ngh\u1ec9, \u1edf m\u1eb7t ngo\u00e0i m\u00e0ng t\u1ebf b\u00e0o t\u00edch \u0111i\u1ec7n d\u01b0\u01a1ng c\u00f2n m\u1eb7t trong m\u00e0ng t\u00edch \u0111i\u1ec7n \u00e2m.<\/p>\n
+ Khi b\u1ecb k\u00edch th\u00edch, c\u1ed5ng Na+<\/sup>\u00a0m\u1edf r\u1ed9ng n\u00ean Na+<\/sup>\u00a0t\u1eeb b\u00ean ngo\u00e0i m\u00e0ng di chuy\u1ec3n v\u00e0o trong m\u00e0ng t\u1ebf b\u00e0o (qu\u00e1 tr\u00ecnh Na+<\/sup>\u00a0\u0111i v\u00e0o g\u00e2y n\u00ean m\u1ea5t ph\u00e2n c\u1ef1c \u1edf hai b\u00ean m\u00e0ng t\u1ebf b\u00e0o), sau \u0111\u00f3 m\u1ed9t kho\u1ea3ng th\u1eddi gian ng\u1eafn, khi l\u01b0\u1ee3ng Na+<\/sup>\u00a0\u0111\u1ee7 l\u1edbn s\u1ebd l\u00e0m cho b\u00ean trong m\u00e0ng t\u00edch \u0111i\u1ec7n d\u01b0\u01a1ng v\u00e0 b\u00ean ngo\u00e0i m\u00e0ng t\u00edch \u0111i\u1ec7n \u00e2m (giai \u0111o\u1ea1n \u0111\u1ea3o c\u1ef1c).<\/p>\n + C\u1ed5ng K+<\/sup>\u00a0m\u1edf r\u1ed9ng h\u01a1n c\u00f2n c\u1ed5ng Na+<\/sup>\u00a0\u0111\u00f3ng l\u1ea1i, K+<\/sup>\u00a0\u0111i t\u1eeb trong m\u00e0ng t\u1ebf b\u00e0o ra ngo\u00e0i (t\u00e1i ph\u00e2n c\u1ef1c).<\/p>\n B\u00e0i 2 (trang 120 SGK Sinh 11):<\/b>\u00a0\u0110\u00e1nh d\u1ea5u X v\u00e0o \u00f4 \u25ad cho c\u00e1c \u00fd \u0111\u00fang v\u1ec1 \u0111i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng.<\/p>\n \u25ad A – Trong giai \u0111o\u1ea1n m\u1ea5t ph\u00e2n c\u1ef1c, Na+<\/sup>\u00a0khu\u1ebfch t\u00e1n t\u1eeb trong ra ngo\u00e0i t\u1ebf b\u00e0o.<\/p>\n \u25ad B – Trong giai \u0111o\u1ea1n m\u1ea5t ph\u00e2n c\u1ef1c, Na+<\/sup>\u00a0khu\u1ebfch t\u00e1n t\u1eeb ngo\u00e0i v\u00e0o trong t\u1ebf b\u00e0o.<\/p>\n \u25ad C – Trong giai \u0111o\u1ea1n t\u00e1i ph\u00e2n c\u1ef1c, Na+<\/sup>\u00a0khu\u1ebfch t\u00e1n t\u1eeb trong ra ngo\u00e0i t\u1ebf b\u00e0o.<\/p>\n \u25ad D – Trong giai \u0111o\u1ea1n t\u00e1i ph\u00e2n c\u1ef1c, K+<\/sup>\u00a0khu\u1ebfch t\u00e1n t\u1eeb ngo\u00e0i v\u00e0o trong t\u1ebf b\u00e0o.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110\u00e1p \u00e1n: B.<\/p>\n B\u00e0i 3 (trang 120 SGK Sinh 11):<\/b>\u00a0So s\u00e1nh c\u00e1ch lan truy\u1ec1n c\u1ee7a xung th\u1ea7n kinh tr\u00ean s\u1ee3i th\u1ea7n kinh kh\u00f4ng c\u00f3 bao mi\u00ealin v\u00e0 c\u00f3 bao mi\u00ealin.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" B\u00e0i 1 (trang 120 SGK Sinh 11):\u00a0\u0110i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng l\u00e0 g\u00ec? \u0110i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh nh\u01b0 th\u1ebf n\u00e0o? L\u1eddi gi\u1ea3i: – \u0110i\u1ec7n th\u1ebf ho\u1ea1t \u0111\u1ed9ng l\u00e0 s\u1ef1 bi\u1ebfn \u0111\u1ed5i \u0111i\u1ec7n th\u1ebf ngh\u1ec9 \u1edf m\u00e0ng t\u1ebf b\u00e0o t\u1eeb ph\u00e2n c\u1ef1c sang m\u1ea5t ph\u00e2n c\u1ef1c, \u0111\u1ea3o c\u1ef1c v\u00e0 t\u00e1i ph\u00e2n c\u1ef1c. – S\u1ef1 […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1324],"tags":[1486,1485],"yoast_head":"\n\n\n
\n <\/td>\n Lan truy\u1ec1n tr\u00ean s\u1ee3i th\u1ea7n kinh c\u00f3 bao mi\u00ealin<\/th>\n Lan truy\u1ec1n tr\u00ean s\u1ee3i th\u1ea7n kinh kh\u00f4ng c\u00f3 bao mi\u00ealin<\/th>\n<\/tr>\n \n C\u00e1ch lan truy\u1ec1n<\/td>\n Nh\u1ea3y c\u00f3c, t\u1eeb eo Ranvie n\u00e0y sang eo Ranvie kh\u00e1c<\/td>\n Li\u00ean t\u1ee5c t\u1eeb v\u00f9ng n\u00e0y sangv\u00f9ng kh\u00e1c k\u1ec1 b\u00ean<\/td>\n<\/tr>\n \n T\u1ed1c \u0111\u1ed9 lan truy\u1ec1n<\/td>\n Nhanh<\/td>\n Ch\u1eadm<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n