C\u00e2u 34:<\/b>\u00a0T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh thang c\u00e2n. C\u1ea1nh \u0111\u00e1y AB=a, c\u1ea1nh \u0111\u00e1y CD = 3a, g\u00f3c ADC = 45o<\/sup>\u00a0, SA vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y v\u00e0 SB t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c b\u1eb1ng 60o<\/sup><\/p>\n <\/p>\n C\u00e2u 35:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh vu\u00f4ng, SA vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y, SA = AB. M\u1eb7t ph\u1eb3ng qua A v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi SC, c\u1eaft SB, SC, SD l\u1ea7n l\u01b0\u1ee3t \u1edf B\u2019, C\u2019, D\u2019. T\u00ednh t\u1ec9 s\u1ed1 k gi\u1eefa th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.AB\u2019C\u2019D\u2019 v\u00e0 th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.ABCD.<\/p>\n <\/p>\n C\u00e2u 36:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh vu\u00f4ng, SA vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y, SA=AB=a. M\u1eb7t ph\u1eb3ng qua A v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi SC, c\u1eaft SB, SC, SD l\u1ea7n l\u01b0\u1ee3t t\u1ea1i B\u2019, C\u2019, D\u2019. T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p S.AB\u2019C\u2019D\u2019<\/p>\n <\/p>\n C\u00e2u 37:<\/b>\u00a0G\u1ecdi (H) l\u00e0 h\u00ecnh ch\u00f3p c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh. (H\u2019) l\u00e0 h\u00ecnh ch\u00f3p c\u00f3 \u0111\u01b0\u1ee3c t\u1eeb (H) b\u1eb1ng c\u00e1ch t\u0103ng chi\u1ec1u cao c\u1ee7a (H) l\u00ean 2 l\u1ea7n v\u00e0 gi\u1ea3m k\u00edch th\u01b0\u1edbc c\u00e1c c\u1ea1nh \u0111\u00e1y c\u1ee7a (H) \u0111i 2 l\u1ea7n. T\u00ednh t\u1ec9 s\u1ed1 k gi\u1eefa th\u1ec3 t\u00edch (H\u2019) v\u00e0 th\u1ec3 t\u00edch (H).<\/p>\n A. k = 1\/2 \u00a0\u00a0\u00a0B. k=1 \u00a0\u00a0\u00a0C. k=2\u00a0\u00a0\u00a0D. k=4<\/p>\n C\u00e2u 38:<\/b>\u00a0G\u1ecdi (H) l\u00e0 h\u00ecnh ch\u00f3p c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh. (H\u2019) l\u00e0 h\u00ecnh ch\u00f3p c\u00f3 \u0111\u01b0\u1ee3c t\u1eeb (H) b\u1eb1ng c\u00e1ch gi\u1ea3m chi\u1ec1u cao c\u1ee7a (H) xu\u1ed1ng 2 l\u1ea7n v\u00e0 t\u0103ng k\u00edch th\u01b0\u1edbc c\u00e1c c\u1ea1nh \u0111\u00e1y c\u1ee7a (H) l\u00ean 2 l\u1ea7n. T\u00ednh t\u1ec9 s\u1ed1 k gi\u1eefa th\u1ec3 t\u00edch (H\u2019) v\u00e0 th\u1ec3 t\u00edch (H).<\/p>\n A. k = 1\/2\u00a0\u00a0\u00a0B. k=1\u00a0\u00a0\u00a0C. k=2\u00a0\u00a0\u00a0D. k=4<\/p>\n C\u00e2u 39:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD, g\u1ecdi A’, B’, C’, D’ theo th\u1ee9 t\u1ef1 l\u00e0 trung \u0111i\u1ec3m c\u1ee7a c\u00e1c c\u1ea1nh b\u00ean SA, SB, SC, SD . T\u00ednh t\u1ec9 s\u1ed1 k gi\u1eefa th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.A’B’C’D’ v\u00e0 th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.ABCD.<\/p>\n A. k = 1\/6\u00a0\u00a0\u00a0B. k = 1\/8 \u00a0\u00a0\u00a0C. k = 1\/12 \u00a0\u00a0\u00a0D. k = 1\/16<\/p>\n C\u00e2u 40:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD, g\u1ecdi M, N, P, Q theo th\u1ee9 t\u1ef1 l\u00e0 trung \u0111i\u1ec3m c\u1ee7a c\u00e1c c\u1ea1nh AB, BC, CD, DA . T\u00ednh t\u1ec9 s\u1ed1 k gi\u1eefa th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.MNPQ v\u00e0 th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.ABCD.<\/p>\n A. k = 1\/2 \u00a0\u00a0\u00a0B. k = 1\/4\u00a0\u00a0\u00a0C. k = 1\/6 \u00a0\u00a0\u00a0D. k = 1\/8<\/p>\n C\u00e2u 41:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh. G\u1ecdi M, N, P theo th\u1ee9 t\u1ef1 l\u00e0 trung \u0111i\u1ec3m c\u1ee7a c\u00e1c c\u1ea1nh BC, CD, SC. T\u00ednh t\u1ec9 s\u1ed1 k gi\u1eefa th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p P.MNC v\u00e0 th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.ABCD.<\/p>\n A. k = 1\/6 \u00a0\u00a0\u00a0B. k = 1\/8\u00a0\u00a0\u00a0C. k = 1\/12\u00a0\u00a0\u00a0D. k = 1\/16<\/p>\n C\u00e2u 42:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh. G\u1ecdi M, N, P theo th\u1ee9 t\u1ef1 l\u00e0 trung \u0111i\u1ec3m c\u1ee7a c\u00e1c c\u1ea1nh BC, CD, SC. T\u00ednh t\u1ec9 s\u1ed1 k gi\u1eefa th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p P.BMND v\u00e0 th\u1ec3 t\u00edch h\u00ecnh ch\u00f3p S.ABCD.<\/p>\n A. k = 1\/6 \u00a0\u00a0\u00a0B. k = 1\/8 \u00a0\u00a0\u00a0C. k = 3\/16\u00a0\u00a0\u00a0D. k = 1\/16<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 35:<\/b><\/p>\n D\u1ec5 th\u1ea5y B\u2019, D\u2019 t\u01b0\u01a1ng \u1ee9ng l\u00e0 trung \u0111i\u1ec3m c\u1ee7a SB, SD, SB \u22a5 BC.<\/p>\n <\/p>\n C\u00e2u 36:<\/b><\/p>\n \u00c1p d\u1ee5ng b\u00e0i t\u1eadp tr\u00ean VS.AB’C’D’<\/sub>\u00a0= (1\/6).VS.ABCD<\/sub><\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 34:\u00a0T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh thang c\u00e2n. C\u1ea1nh \u0111\u00e1y AB=a, c\u1ea1nh \u0111\u00e1y CD = 3a, g\u00f3c ADC = 45o\u00a0, SA vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y v\u00e0 SB t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c b\u1eb1ng 60o C\u00e2u 35:\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh vu\u00f4ng, SA vu\u00f4ng g\u00f3c v\u1edbi […]<\/p>\n","protected":false},"author":3,"featured_media":28866,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n\n\n
\n 34-B<\/td>\n 35-D<\/td>\n 36-C<\/td>\n 37-A<\/td>\n 38-C<\/td>\n 39-B<\/td>\n 40-A<\/td>\n 41-D<\/td>\n 42-C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n