C\u00e2u 8:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 AB = AC, g\u00f3c BAC = 120o<\/sup>\u00a0. H\u00ecnh chi\u1ebfu c\u1ee7a S l\u00ean (ABC) tr\u00f9ng v\u1edbi trung \u0111i\u1ec3m c\u1ee7a BC. T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p, bi\u1ebft r\u1eb1ng SA = 2a v\u00e0 SA t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c b\u1eb1ng 45o<\/sup><\/p>\n <\/p>\n C\u00e2u 9:<\/b>\u00a0T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh, SA vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y, AB = a, BC = a\u221a3, AC = 2a , SC t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c 45o<\/sup><\/p>\n <\/p>\n C\u00e2u 10:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 \u0111\u00e1y l\u00e0 tam gi\u00e1c \u0111\u1ec1u c\u1ea1nh b\u1eb1ng 2a, (SAB)\u22a5(ABC), tam gi\u00e1c SAB c\u00e2n \u1edf S, m\u1eb7t (SBC) t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c b\u1eb1ng 60o<\/sup>\u00a0. T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p \u0111\u00f3.<\/p>\n <\/p>\n C\u00e2u 11:<\/b>\u00a0T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt, SAB l\u00e0 tam gi\u00e1c \u0111\u1ec1u c\u1ea1nh b\u1eb1ng 2a v\u00e0 thu\u1ed9c m\u1eb7t ph\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y, m\u1eb7t b\u00ean (SDC) t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c b\u1eb1ng 60o<\/sup><\/p>\n <\/p>\n C\u00e2u 12:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 \u0111\u00e1y l\u00e0 tam gi\u00e1c vu\u00f4ng c\u00e2n \u1edf B, AB = a, SA = a\u221a2 v\u00e0 SA vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y. G\u1ecdi (P) l\u00e0 m\u1eb7t ph\u1eb3ng qua A v\u00e0 vu\u00f4ng g\u00f3c SC, (P) c\u1eaft SB, SC l\u1ea7n l\u01b0\u1ee3t t\u1ea1i M, N. T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p S.ANM<\/p>\n <\/p>\n C\u00e2u 13:<\/b>\u00a0Cho h\u00ecnh l\u1eadp ph\u01b0\u01a1ng ABCD.A’B’C’D’ c\u00f3 c\u1ea1nh b\u1eb1ng a. L\u1ea5y M tr\u00ean AB sao cho MB = 2MA. T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p M.BC\u2019D<\/p>\n <\/p>\n C\u00e2u 14:<\/b>\u00a0T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh h\u1ed9p \u0111\u1ee9ng ABCD.A’B’C’D’ c\u00f3 AB = a, BC = a\u221a3 , AC=2a, m\u1eb7t ph\u1eb3ng (A\u2019BC) t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c 60o<\/sup><\/p>\n A. V = a3<\/sup>\u00a0\u00a0\u00a0\u00a0B. V = 2a3<\/sup>\u00a0\u00a0\u00a0C. V = 3a3<\/sup>\u00a0\u00a0\u00a0\u00a0D. V = 8a3<\/sup><\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 8:\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 AB = AC, g\u00f3c BAC = 120o\u00a0. H\u00ecnh chi\u1ebfu c\u1ee7a S l\u00ean (ABC) tr\u00f9ng v\u1edbi trung \u0111i\u1ec3m c\u1ee7a BC. T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p, bi\u1ebft r\u1eb1ng SA = 2a v\u00e0 SA t\u1ea1o v\u1edbi \u0111\u00e1y m\u1ed9t g\u00f3c b\u1eb1ng 45o C\u00e2u 9:\u00a0T\u00ednh th\u1ec3 t\u00edch V c\u1ee7a h\u00ecnh ch\u00f3p S.ABCD […]<\/p>\n","protected":false},"author":3,"featured_media":28795,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n\n\n
\n 8-A<\/td>\n 9-D<\/td>\n 10-B<\/td>\n 11-B<\/td>\n 12-C<\/td>\n 13-A<\/td>\n 14-C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n