C\u00e2u 1:<\/b>\u00a0Tam gi\u00e1c ABC vu\u00f4ng c\u00e2n \u0111\u1ec9nh A c\u00f3 c\u1ea1nh huy\u1ec1n l\u00e0 a. Quay tam gi\u00e1c ABC quanh tr\u1ee5c AB th\u00ec \u0111o\u1ea1n g\u1ea5p kh\u00fac ACB t\u1ea1o th\u00e0nh h\u00ecnh n\u00f3n (N). Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n (N) l\u00e0:<\/p>\n
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C\u00e2u 2:<\/b>\u00a0H\u00ecnh n\u00f3n (N) c\u00f3 \u0111\u01b0\u1eddng sinh g\u1ea5p hai l\u1ea7n b\u00e1n k\u00ednh \u0111\u00e1y. G\u00f3c \u1edf \u0111\u1ec9nh c\u1ee7a h\u00ecnh n\u00f3n l\u00e0 :<\/p>\n
A. 120o<\/sup>\u00a0\u00a0\u00a0\u00a0B. 60o<\/sup>\u00a0\u00a0\u00a0C. 30o<\/sup>\u00a0\u00a0\u00a0D. 0o<\/sup><\/p>\n C\u00e2u 3:<\/b>\u00a0H\u00ecnh n\u00f3n c\u00f3 chi\u1ec1u cao b\u1eb1ng \u0111\u01b0\u1eddng k\u00ednh \u0111\u00e1y. T\u1ec9 s\u1ed1 gi\u1eefa di\u1ec7n t\u00edch xung quanh v\u00e0 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n c\u1ee7a h\u00ecnh n\u00f3n b\u1eb1ng :<\/p>\n <\/p>\n C\u00e2u 4:<\/b>\u00a0M\u1ed9t chi\u1ebfc ph\u1ec5u \u0111\u1ef1ng d\u1ea7u h\u00ecnh n\u00f3n c\u00f3 chi\u1ec1u cao l\u00e0 30cm v\u00e0 \u0111\u01b0\u1eddng sinh l\u00e0 50cm. Gi\u1ea3 s\u1eed r\u1eb1ng l\u01b0\u1ee3ng d\u1ea7u m\u00e0 chi\u1ebfc ph\u1ec5u \u0111\u1ef1ng \u0111\u01b0\u1ee3c ch\u00ednh l\u00e0 th\u1ec3 t\u00edch c\u1ee7a kh\u1ed1i n\u00f3n. Khi \u0111\u00f3 trong c\u00e1c l\u01b0\u1ee3ng d\u1ea7u sau \u0111\u00e2y, l\u01b0\u1ee3ng d\u1ea7u n\u00e0o l\u1edbn nh\u1ea5t chi\u1ebfc ph\u1ec5u c\u00f3 th\u1ec3 \u0111\u1ef1ng \u0111\u01b0\u1ee3c :<\/p>\n A. 150720\u03c0(cm3<\/sup>)\u00a0\u00a0\u00a0B. 50400\u03c0(cm3<\/sup>)<\/p>\n C. 16000\u03c0(cm3<\/sup>)\u00a0\u00a0\u00a0D. 12000\u03c0(cm3<\/sup>)<\/p>\n C\u00e2u 5:<\/b>\u00a0Cho h\u00ecnh tr\u1ee5 c\u00f3 \u0111\u01b0\u1ee3c khi quay h\u00ecnh c\u1eef\\h\u1eef nh\u1eadt ABCD quanh tr\u1ee5c AB. Bi\u1ebft r\u1eb1ng AB = 2AD = 2a. Th\u1ec3 t\u00edch kh\u1ed1i tr\u1ee5 \u0111\u00e3 cho theo a l\u00e0 :<\/p>\n A. 2\u03c0a3<\/sup>\u00a0\u00a0\u00a0B.\u03c0a3<\/sup>\u00a0\u00a0\u00a0C. 2\u03c0a3<\/sup>\u00a0\/3\u00a0\u00a0\u00a0D.\u03c0a3<\/sup>\u00a0\/2<\/p>\n C\u00e2u 6:<\/b>\u00a0Cho h\u00ecnh tr\u1ee5 c\u00f3 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n l\u00e0 7\u03c0a2<\/sup>\u00a0v\u00e0 b\u00e1n k\u00ednh \u0111\u00e1y l\u00e0 a. Chi\u1ec1u cao c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0:<\/p>\n A. 3a\/2\u00a0\u00a0\u00a0B. 2a \u00a0\u00a0\u00a0C. 5a\/3\u00a0\u00a0\u00a0D. 5a\/2<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Tam gi\u00e1c ABC vu\u00f4ng c\u00e2n \u0111\u1ec9nh A c\u00f3 c\u1ea1nh huy\u1ec1n l\u00e0 a. Quay tam gi\u00e1c ABC quanh tr\u1ee5c AB th\u00ec \u0111o\u1ea1n g\u1ea5p kh\u00fac ACB t\u1ea1o th\u00e0nh h\u00ecnh n\u00f3n (N). Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n (N) l\u00e0: C\u00e2u 2:\u00a0H\u00ecnh n\u00f3n (N) c\u00f3 \u0111\u01b0\u1eddng sinh g\u1ea5p hai l\u1ea7n b\u00e1n k\u00ednh \u0111\u00e1y. G\u00f3c \u1edf \u0111\u1ec9nh […]<\/p>\n","protected":false},"author":3,"featured_media":28774,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n\n\n
\n 1-C<\/td>\n 2-B<\/td>\n 3-D<\/td>\n 4-C<\/td>\n 5-A<\/td>\n 6-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n