C\u00e2u 1:<\/b>\u00a0Cho kh\u1ed1i n\u00f3n tr\u00f2n xoay c\u00f3 b\u00e1n k\u00ednh \u0111\u00e1y r, \u0111\u01b0\u1eddng sinh l v\u00e0 \u0111\u01b0\u1eddng cao h. C\u00f4ng th\u1ee9c t\u00ednh th\u1ec3 t\u00edch kh\u1ed1i n\u00f3n l\u00e0:<\/p>\n
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C\u00e2u 2:<\/b>\u00a0H\u00ecnh n\u00f3n (N) c\u00f3 \u0111\u01b0\u1eddng sinh g\u1ea5p hai l\u1ea7n \u0111\u01b0\u1eddng cao. G\u00f3c \u1edf \u0111\u1ec9nh c\u1ee7a h\u00ecnh n\u00f3n l\u00e0:<\/p>\n
A. 120o<\/sup>\u00a0\u00a0\u00a0\u00a0B. 90o<\/sup>\u00a0\u00a0\u00a0C. 60o<\/sup>\u00a0\u00a0\u00a0\u00a0D. 30o<\/sup><\/p>\n C\u00e2u 3:<\/b>\u00a0H\u00ecnh n\u00f3n c\u00f3 chi\u1ec1u cao b\u1eb1ng 4\/3 b\u00e1n k\u00ednh \u0111\u00e1y. T\u1ec9 s\u1ed1 gi\u1eefa di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n v\u00e0 di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n l\u00e0:<\/p>\n A. 4\/3\u00a0\u00a0\u00a0B. 5\/7\u00a0\u00a0\u00a0C. 8\/5\u00a0\u00a0\u00a0D. 9\/5<\/p>\n C\u00e2u 4:<\/b>\u00a0H\u00ecnh n\u00f3n c\u00f3 g\u00f3c \u1edf \u0111\u1ec9nh l\u00e0 90o<\/sup>\u00a0v\u00e0 c\u00f3 di\u1ec7n t\u00edch xung quanh l\u00e0 \u03c0\u221a2 . \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng cao c\u1ee7a h\u00ecnh n\u00f3n l\u00e0:<\/p>\n A. 1\u00a0\u00a0\u00a0B. \u221a2\u00a0\u00a0\u00a0C. 1\/\u221a2 \u00a0\u00a0\u00a0D. 2<\/p>\n C\u00e2u 5:<\/b>\u00a0Cho h\u00ecnh n\u00f3n tr\u00f2n xoay c\u00f3 \u0111\u01b0\u1eddng cao h=15cm v\u00e0 b\u00e1n k\u00ednh \u0111\u00e1y r = 20cm. Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n l\u00e0:<\/p>\n A. 1000\u03c0(cm2<\/sup>)\u00a0\u00a0\u00a0B. 250\u03c0(cm2<\/sup>) \u00a0\u00a0\u00a0C. 375\u03c0(cm2<\/sup>)\u00a0\u00a0\u00a0D. 500\u03c0(cm2<\/sup>)<\/p>\n C\u00e2u 6:<\/b>\u00a0Cho kh\u1ed1i n\u00f3n tr\u00f2n xoay c\u00f3 \u0111\u01b0\u1eddng cao h = 20cm v\u00e0 \u0111\u01b0\u1eddng sinh l = 25cm . Th\u1ec3 t\u00edch kh\u1ed1i n\u00f3n l\u00e0:<\/p>\n A. 1500\u03c0(cm3<\/sup>)\u00a0\u00a0\u00a0B. 2500\u03c0(cm3<\/sup>)\u00a0\u00a0\u00a0C. 3500\u03c0(cm3<\/sup>)\u00a0\u00a0\u00a0D. 4500\u03c0(cm3<\/sup>)<\/p>\n C\u00e2u 7:<\/b>\u00a0Tam gi\u00e1c ABC vu\u00f4ng \u0111\u1ec9nh A c\u00f3 AB = 2AC. Quay tam gi\u00e1c ABC quanh tr\u1ee5c AB th\u00ec \u0111o\u1ea1n g\u1ea5p kh\u00fac ACB t\u1ea1o ra h\u00ecnh n\u00f3n (N1) v\u00e0 quay tam gi\u00e1c ABC quanh tr\u1ee5c AC th\u00ec \u0111o\u1ea1n g\u1ea5p kh\u00fac ABC t\u1ea1o ra h\u00ecnh n\u00f3n (N2). T\u1ec9 s\u1ed1 di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n (N1) v\u00e0 di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n (N2) l\u00e0:<\/p>\n A. 1\/4\u00a0\u00a0\u00a0B. 1\/2\u00a0\u00a0\u00a0C. 1\u00a0\u00a0\u00a0D. 2<\/p>\n C\u00e2u 8:<\/b>\u00a0Cho kh\u1ed1i n\u00f3n tr\u00f2n xoay c\u00f3 g\u00f3c \u1edf \u0111\u1ec9nh l\u00e0 60o<\/sup>\u00a0v\u00e0 \u0111\u01b0\u1eddng sinh l = 6cm. Th\u1ec3 t\u00edch c\u1ee7a kh\u1ed1i n\u00f3n l\u00e0:<\/p>\n A. 9\u03c0\u221a3(cm3<\/sup>)\u00a0\u00a0\u00a0B. 27\u03c0\u221a3(cm3<\/sup>)\u00a0\u00a0\u00a0C. 27\u03c0(cm3<\/sup>)\u00a0\u00a0\u00a0D. 3\u03c0\u221a3(cm3<\/sup>)<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b><\/p>\n Theo c\u00f4ng th\u1ee9c ta c\u00f3 \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C<\/p>\n C\u00e2u 2:<\/b><\/p>\n G\u1ecdi 2\u03b1 l\u00e0 g\u00f3c \u1edf \u0111\u1ec9nh c\u1ee7a h\u00ecnh n\u00f3n. T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3:<\/p>\n <\/p>\n C\u00e2u 3:<\/b><\/p>\n T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3<\/p>\n <\/p>\n C\u00e2u 4:<\/b><\/p>\n T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3: 2\u03b1 = 90o<\/sup>\u00a0=> \u03b1 45o<\/sup>\u00a0= > h = r; l = r\u221a2<\/p>\n Di\u1ec7n t\u00edch xung quang c\u1ee7a h\u00ecnh n\u00f3n l\u00e0 : Sxq<\/sub>\u00a0= \u03c0rl = \u03c0r2<\/sup>\u221a2 = \u03c0\u221a2 => r = 1 => h = 1<\/p>\n C\u00e2u 5:<\/b><\/p>\n T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 : h = 15; r = 20<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Cho kh\u1ed1i n\u00f3n tr\u00f2n xoay c\u00f3 b\u00e1n k\u00ednh \u0111\u00e1y r, \u0111\u01b0\u1eddng sinh l v\u00e0 \u0111\u01b0\u1eddng cao h. C\u00f4ng th\u1ee9c t\u00ednh th\u1ec3 t\u00edch kh\u1ed1i n\u00f3n l\u00e0: C\u00e2u 2:\u00a0H\u00ecnh n\u00f3n (N) c\u00f3 \u0111\u01b0\u1eddng sinh g\u1ea5p hai l\u1ea7n \u0111\u01b0\u1eddng cao. G\u00f3c \u1edf \u0111\u1ec9nh c\u1ee7a h\u00ecnh n\u00f3n l\u00e0: A. 120o\u00a0\u00a0\u00a0\u00a0B. 90o\u00a0\u00a0\u00a0C. 60o\u00a0\u00a0\u00a0\u00a0D. 30o C\u00e2u 3:\u00a0H\u00ecnh n\u00f3n c\u00f3 chi\u1ec1u […]<\/p>\n","protected":false},"author":3,"featured_media":28758,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n\n\n
\n 1-C<\/td>\n 2-A<\/td>\n 3-C<\/td>\n 4-A<\/td>\n 5-D<\/td>\n 6-A<\/td>\n 7-B<\/td>\n 8-A<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n