B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 - B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 5)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-chuong-2-bai-1-khai-niem-ve-mat-tron-xoay-phan-5\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 - B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 5)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 17:\u00a0Cho h\u00ecnh tr\u1ee5 c\u00f3 chi\u1ec1u cao b\u1eb1ng 2a v\u00e0 di\u1ec7n t\u00edch xung quanh l\u00e0 \u03c0a2\u00a0. b\u00e1n k\u00ednh \u0111\u00e1y c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0: C\u00e2u 18:\u00a0Cho kh\u1ed1i tr\u1ee5 c\u00f3 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n 5\u03c0a2\u00a0v\u00e0 b\u00e1n k\u00ednh \u0111\u00e1y l\u00e0 a. 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{"id":28742,"date":"2018-04-27T15:58:44","date_gmt":"2018-04-27T08:58:44","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=28742"},"modified":"2018-04-27T15:58:44","modified_gmt":"2018-04-27T08:58:44","slug":"bai-tap-trac-nghiem-hinh-hoc-12-chuong-2-bai-1-khai-niem-ve-mat-tron-xoay-phan-5","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-chuong-2-bai-1-khai-niem-ve-mat-tron-xoay-phan-5\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 – B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 5)"},"content":{"rendered":"

C\u00e2u 17:<\/b>\u00a0Cho h\u00ecnh tr\u1ee5 c\u00f3 chi\u1ec1u cao b\u1eb1ng 2a v\u00e0 di\u1ec7n t\u00edch xung quanh l\u00e0 \u03c0a^{2<\/sup>\u00a0. b\u00e1n k\u00ednh \u0111\u00e1y c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0:<\/p>\n}

$\"\"$ <\/p>\n

C\u00e2u 18:<\/b>\u00a0Cho kh\u1ed1i tr\u1ee5 c\u00f3 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n 5\u03c0a^{2<\/sup>\u00a0v\u00e0 b\u00e1n k\u00ednh \u0111\u00e1y l\u00e0 a. Th\u1ec3 t\u00edch kh\u1ed1i tr\u1ee5 l\u00e0:<\/p>\n}

A. 3\u03c0a^{3<\/sup>\/2 \u00a0\u00a0\u00a0B. \u03c0a^{3<\/sup>\/2\u00a0\u00a0\u00a0C. \u03c0a^{3<\/sup>\u00a0\u00a0\u00a0D. 3\u03c0a^{3<\/sup><\/p>\n}}}}

C\u00e2u 19:<\/b>\u00a0H\u00ecnh tr\u1ee5 (H) c\u00f3 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n l\u00e0 8\u03c0(cm^{2<\/sup>) v\u00e0 th\u1ec3 t\u00edch kh\u1ed1i tr\u1ee5 l\u00e0 3\u03c0(cm^{3<\/sup>) . T\u00ednh chi\u1ec1u cao c\u1ee7a h\u00ecnh tr\u1ee5 ta \u0111\u01b0\u1ee3c bao nhi\u00eau k\u1ebft qu\u1ea3?<\/p>\n}}

A. 1\u00a0\u00a0\u00a0B. 2\u00a0\u00a0\u00a0C. 3\u00a0\u00a0\u00a0D. 4<\/p>\n

C\u00e2u 20:<\/b>\u00a0H\u00ecnh tr\u1ee5 (H) c\u00f3 t\u1ec9 s\u1ed1 di\u1ec7n t\u00edch xung quanh v\u00e0 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n l\u00e0 1\/3 . Bi\u1ebft r\u1eb1ng th\u1ec3 t\u00edch kh\u1ed1i tr\u1ee5 l\u00e0 4\u03c0 . B\u00e1n k\u00ednh \u0111\u00e1y c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0:<\/p>\n

A. 2\u00a0\u00a0\u00a0B. 3\u00a0\u00a0\u00a0C. \u221a6 \u00a0\u00a0\u00a0D. \u221a7<\/p>\n

C\u00e2u 21:<\/b>\u00a0Ta d\u00f9ng hai h\u00ecnh ch\u1eef nh\u1eadt c\u00f3 c\u00f9ng k\u00edch c\u1ee1 \u0111\u1ec3 l\u00e0m th\u00e0nh hai h\u00ecnh tr\u1ee5 (H1) v\u00e0 (H2) b\u1eb1ng c\u00e1ch quay c\u00e1c h\u00ecnh ch\u1eef nh\u1eadt \u0111\u00f3, l\u1ea7n l\u01b0\u1ee3t theo chi\u1ec1u d\u00e0i v\u00e0 chi\u1ec1u r\u1ed9ng. T\u1ec9 s\u1ed1 hai di\u1ec7n t\u00edch xung quanh h\u00ecnh tr\u1ee5 (H1) v\u00e0 h\u00ecnh tr\u1ee5 (H2) l\u00e0:<\/p>\n

A. 2\u00a0\u00a0\u00a0B. 1\u00a0\u00a0\u00a0C. 1\/2 \u00a0\u00a0\u00a0D. 1\/4<\/p>\n

C\u00e2u 22:<\/b>\u00a0Cho h\u00ecnh n\u00f3n c\u00f3 \u0111\u01b0\u1eddng cao h = 10cm v\u00e0 thi\u1ebft di\u1ec7n c\u1eaft b\u1edfi m\u1eb7t ph\u1eb3ng qua tr\u1ee5c c\u1ee7a h\u00ecnh n\u00f3n l\u00e0 m\u1ed9t tam gi\u00e1c \u0111\u1ec1u. Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n l\u00e0:<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 23:<\/b>\u00a0Cho kh\u1ed1i n\u00f3n tr\u00f2n xoay c\u00f3 \u0111\u01b0\u1eddng cao h = 20cm, b\u00e1n k\u00ednh \u0111\u00e1y r = 25cm. M\u1ed9t m\u1eb7t ph\u1eb3ng (P) \u0111i qua \u0111\u1ec9nh v\u00e0 c\u00e1ch t\u00e2m O c\u1ee7a \u0111\u00e1y m\u1ed9t kho\u1ea3ng l\u00e0 12cm. Di\u1ec7n t\u00edch thi\u1ebft di\u1ec7n c\u1ee7a (P) v\u1edbi kh\u1ed1i n\u00f3n l\u00e0:<\/p>\n

A. 100\u03c0(cm^{2<\/sup>) \u00a0\u00a0\u00a0B. 100(cm^{2<\/sup>)\u00a0\u00a0\u00a0C. 300(cm^{2<\/sup>)\u00a0\u00a0\u00a0D. 500(cm^{2<\/sup>)<\/p>\n}}}}

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
17-D<\/td>\n 18-A<\/td>\n 19-B<\/td>\n 20-A<\/td>\n 21-B<\/td>\n 22-B<\/td>\n 23-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
C\u00e2u 17:<\/b><\/p>\n
T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3:<\/p>\n
$\"\"$ $\"\"$ $\"\"$ <\/p>\n","protected":false},"excerpt":{"rendered":"
C\u00e2u 17:\u00a0Cho h\u00ecnh tr\u1ee5 c\u00f3 chi\u1ec1u cao b\u1eb1ng 2a v\u00e0 di\u1ec7n t\u00edch xung quanh l\u00e0 \u03c0a2\u00a0. b\u00e1n k\u00ednh \u0111\u00e1y c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0: C\u00e2u 18:\u00a0Cho kh\u1ed1i tr\u1ee5 c\u00f3 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n 5\u03c0a2\u00a0v\u00e0 b\u00e1n k\u00ednh \u0111\u00e1y l\u00e0 a. 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