B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 - B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 6)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-chuong-2-bai-1-khai-niem-ve-mat-tron-xoay-phan-6\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 - B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 6)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 24:\u00a0Cho h\u00ecnh l\u1eadp ph\u01b0\u01a1ng ABCD.A’B’C’D’ c\u00f3 AC\u2019 = 3a. 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{"id":28731,"date":"2018-04-27T15:54:11","date_gmt":"2018-04-27T08:54:11","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=28731"},"modified":"2018-04-27T15:54:11","modified_gmt":"2018-04-27T08:54:11","slug":"bai-tap-trac-nghiem-hinh-hoc-12-chuong-2-bai-1-khai-niem-ve-mat-tron-xoay-phan-6","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-chuong-2-bai-1-khai-niem-ve-mat-tron-xoay-phan-6\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 – B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 6)"},"content":{"rendered":"

C\u00e2u 24:<\/b>\u00a0Cho h\u00ecnh l\u1eadp ph\u01b0\u01a1ng ABCD.A’B’C’D’ c\u00f3 AC\u2019 = 3a. Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n c\u00f3 \u0111\u1ec9nh l\u00e0 t\u00e2m O c\u1ee7a h\u00ecnh vu\u00f4ng A’B’C’D’ v\u00e0 \u0111\u00e1y l\u00e0 h\u00ecnh tr\u00f2n ngo\u1ea1i ti\u1ebfp h\u00ecnh vu\u00f4ng ABCD l\u00e0:<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 25:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c \u0111\u1ec1u S.ABCD c\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1ea1nh b\u1eb1ng nhau v\u00e0 b\u1eb1ng a. Th\u1ec3 t\u00edch kh\u1ed1i n\u00f3n ngo\u1ea1i ti\u1ebfp h\u00ecnh ch\u00f3p l\u00e0:<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 26:<\/b>\u00a0Cho h\u00ecnh h\u1ed9p ch\u1eef nh\u1eadt ABCD.A’B’C’D’ c\u00f3 AB = AD = a, AB’ = 2a . Di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n c\u1ee7a h\u00ecnh tr\u1ee5 ngo\u1ea1i ti\u1ebfp h\u00ecnh h\u1ed9p l\u00e0:<\/p>\n

A. \u03c0a^{2<\/sup>(1 + \u221a6)\u00a0\u00a0\u00a0B. \u03c0a^{2<\/sup>(1 + \u221a3)\u00a0\u00a0\u00a0C. \u03c0a^{2<\/sup>(1 + \u221a2)\u00a0\u00a0\u00a0D. 2\u03c0a^{2<\/sup><\/p>\n}}}}

C\u00e2u 27:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 SA \u22a5 (ABCD), ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt. G\u00f3c gi\u1eefa SC v\u00e0 m\u1eb7t \u0111\u00e1y l\u00e0 30^{o<\/sup>\u00a0. H\u00ecnh tr\u1ee5 (H) c\u00f3 m\u1ed9t \u0111\u00e1y ngo\u1ea1i ti\u1ebfp h\u00ecnh ch\u1eef nh\u1eadt ABCD v\u00e0 m\u1ed9t \u0111\u00e1y ch\u1ee9a \u0111i\u1ec3m S. Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0:<\/p>\n}

$\"\"$ <\/p>\n

C\u00e2u 28:<\/b>\u00a0G\u1ecdi V l\u00e0 th\u1ec3 t\u00edch c\u1ee7a m\u1ed9t kh\u1ed1i tr\u1ee5 v\u00e0 V\u2019 l\u00e0 th\u1ec3 t\u00edch kh\u1ed1i l\u0103ng tr\u1ee5 tam gi\u00e1c \u0111\u1ec1u n\u1ed9i ti\u1ebfp kh\u1ed1i tr\u1ee5 \u0111\u00f3. T\u00ednh t\u1ec9 s\u1ed1 V\/V’ ta \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 n\u00e0o sau \u0111\u00e2y?<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 29:<\/b>\u00a0Cho h\u00ecnh n\u00f3n \u0111\u1ec9nh I v\u00e0 \u0111\u01b0\u1eddng tr\u00f2n \u0111\u00e1y t\u00e2m O. Chi\u1ec1u cao c\u1ee7a h\u00ecnh n\u00f3n b\u1eb1ng a, g\u00f3c \u1edf \u0111\u1ec9nh l\u00e0 120^{o<\/sup>\u00a0. A, B n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n t\u00e2m O sao cho AB = a. Th\u1ec3 t\u00edch c\u1ee7a kh\u1ed1i t\u1ee9 di\u1ec7n IABO l\u00e0:<\/p>\n}

$\"\"$ <\/p>\n

C\u00e2u 30:<\/b>\u00a0M\u1ed9t h\u00ecnh tr\u1ee5 c\u00f3 b\u00e1n k\u00ednh \u0111\u00e1y b\u1eb1ng a v\u00e0 c\u00f3 thi\u1ebft di\u1ec7n c\u1eaft b\u1edfi m\u1eb7t ph\u1eb3ng qua tr\u1ee5c l\u00e0 m\u1ed9t h\u00ecnh vu\u00f4ng. Th\u1ec3 t\u00edch kh\u1ed1i l\u0103ng tr\u1ee5 t\u1ee9 gi\u00e1c \u0111\u1ec1u n\u1ed9i ti\u1ebfp h\u00ecnh tr\u1ee5 l\u00e0:<\/p>\n

A. 4\u03c0a^{3<\/sup>\u00a0\u00a0\u00a0B. 4a^{3<\/sup>\u00a0\u00a0\u00a0C. 4a^{3<\/sup>\/3\u00a0\u00a0\u00a0D. 2a^{3<\/sup><\/p>\n}}}}

C\u00e2u 31:<\/b>\u00a0M\u1ed9t kh\u1ed1i tr\u1ee5 c\u00f3 b\u00e1n k\u00ednh \u0111\u00e1y b\u1eb1ng a v\u00e0 c\u00f3 chi\u1ec1u cao a\u221a3. g\u1ecdi A, B l\u1ea7n l\u01b0\u1ee3t l\u00e0 hai \u0111i\u1ec3m tr\u00ean hai \u0111\u01b0\u1eddng tr\u00f2n \u0111\u00e1y sao cho g\u00f3c gi\u1eefa AB v\u00e0 tr\u1ee5c c\u1ee7a kh\u1ed1i tr\u1ee5 b\u1eb1ng 30^{o<\/sup>\u00a0. G\u00f3c c\u1ee7a hai \u0111\u01b0\u1eddng th\u1eb3ng l\u1ea7n l\u01b0\u1ee3t ch\u1ee9a hai b\u00e1n k\u00ednh c\u1ee7a hai \u0111\u00e1y qua A, B l\u00e0:<\/p>\n}

A. 90^{o<\/sup>\u00a0\u00a0\u00a0\u00a0B. 60^{o<\/sup>\u00a0\u00a0\u00a0\u00a0C. 45^{o<\/sup>\u00a0\u00a0\u00a0D. 30^{o<\/sup><\/p>\n}}}}

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
24-A<\/td>\n 25-A<\/td>\n 26-A<\/td>\n 27-B<\/td>\n 28-B<\/td>\n 29-D<\/td>\n 30-B<\/td>\n 31-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
C\u00e2u 24:<\/b><\/p>\n
T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 AC’ = 3a => AB = a\u221a3. X\u00e9t h\u00ecnh n\u00f3n th\u1ecfa m\u00e3n \u0111\u1ec1 b\u00e0i ta c\u00f3 : h = AA’ = a\u221a3;<\/p>\n
$\"\"$ $\"\"$ $\"\"$ $\"\"$ <\/p>\n","protected":false},"excerpt":{"rendered":"
C\u00e2u 24:\u00a0Cho h\u00ecnh l\u1eadp ph\u01b0\u01a1ng ABCD.A’B’C’D’ c\u00f3 AC\u2019 = 3a. Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n c\u00f3 \u0111\u1ec9nh l\u00e0 t\u00e2m O c\u1ee7a h\u00ecnh vu\u00f4ng A’B’C’D’ v\u00e0 \u0111\u00e1y l\u00e0 h\u00ecnh tr\u00f2n ngo\u1ea1i ti\u1ebfp h\u00ecnh vu\u00f4ng ABCD l\u00e0: C\u00e2u 25:\u00a0Cho h\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c \u0111\u1ec1u S.ABCD c\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1ea1nh b\u1eb1ng nhau v\u00e0 b\u1eb1ng a. […]<\/p>\n","protected":false},"author":3,"featured_media":28732,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 - B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 6)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-chuong-2-bai-1-khai-niem-ve-mat-tron-xoay-phan-6\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 Ch\u01b0\u01a1ng 2 - B\u00e0i 1: Kh\u00e1i ni\u1ec7m v\u1ec1 m\u1eb7t tr\u00f2n xoay (Ph\u1ea7n 6)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 24:\u00a0Cho h\u00ecnh l\u1eadp ph\u01b0\u01a1ng ABCD.A’B’C’D’ c\u00f3 AC\u2019 = 3a. Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n c\u00f3 \u0111\u1ec9nh l\u00e0 t\u00e2m O c\u1ee7a h\u00ecnh vu\u00f4ng A’B’C’D’ v\u00e0 \u0111\u00e1y l\u00e0 h\u00ecnh tr\u00f2n ngo\u1ea1i ti\u1ebfp h\u00ecnh vu\u00f4ng ABCD l\u00e0: C\u00e2u 25:\u00a0Cho h\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c \u0111\u1ec1u S.ABCD c\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1ea1nh b\u1eb1ng nhau v\u00e0 b\u1eb1ng a. 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