B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 \u0110\u1ec1 ki\u1ec3m tra ch\u01b0\u01a1ng 2 (ph\u1ea7n 3)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-de-kiem-tra-chuong-2-phan-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 \u0110\u1ec1 ki\u1ec3m tra ch\u01b0\u01a1ng 2 (ph\u1ea7n 3)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 15:\u00a0Cho l\u0103ng tr\u1ee5 \u0111\u1ee9ng ABC.A1B1c1\u00a0c\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1ea1nh b\u1eb1ng nhau. Bi\u1ebft l\u0103ng tr\u1ee5 n\u1ed9i ti\u1ebfp h\u00ecnh tr\u1ee5 (H). 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{"id":28580,"date":"2018-04-25T23:38:43","date_gmt":"2018-04-25T16:38:43","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=28580"},"modified":"2018-04-25T23:38:43","modified_gmt":"2018-04-25T16:38:43","slug":"bai-tap-trac-nghiem-hinh-hoc-12-de-kiem-tra-chuong-2-phan-3","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-de-kiem-tra-chuong-2-phan-3\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 \u0110\u1ec1 ki\u1ec3m tra ch\u01b0\u01a1ng 2 (ph\u1ea7n 3)"},"content":{"rendered":"

C\u00e2u 15:<\/b>\u00a0Cho l\u0103ng tr\u1ee5 \u0111\u1ee9ng ABC.A_{1<\/sub>B_{1<\/sub>c_{1<\/sub>\u00a0c\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1ea1nh b\u1eb1ng nhau. Bi\u1ebft l\u0103ng tr\u1ee5 n\u1ed9i ti\u1ebfp h\u00ecnh tr\u1ee5 (H). T\u1ec9 s\u1ed1 di\u1ec7n t\u00edch xung quanh v\u00e0 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0 :<\/p>\n}}}

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C\u00e2u 16:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 \u0111\u00e1y ABC l\u00e0 tam gi\u00e1c vu\u00f4ng c\u00e2n \u0111\u1ec9nh A v\u00e0 SA = SB = SC = 3a . G\u00f3c gi\u1eefa m\u1eb7t ph\u1eb3ng (SAB) v\u00e0 m\u1eb7t \u0111\u00e1y l\u00e0 60^{o<\/sup>\u00a0. H\u00ecnh tr\u1ee5 (H) c\u00f3 m\u1ed9t \u0111\u01b0\u1eddng tr\u00f2n \u0111\u00e1y ngo\u1ea1i ti\u1ebfp tam gi\u00e1c ABC v\u00e0 m\u1ed9t \u0111\u00e1y ch\u1ee9a \u0111i\u1ec3m S. Th\u1ec3 t\u00edch kh\u1ed1i tr\u1ee5 sinh b\u1edfi h\u00ecnh tr\u1ee5 l\u00e0 :<\/p>\n}

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C\u00e2u 17:<\/b>\u00a0M\u1ed9t kh\u1ed1i tr\u1ee5 c\u00f3 chi\u1ec1u cao b\u1eb1ng 20cm v\u00e0 b\u00e1n k\u00ednh \u0111\u00e1y l\u00e0 10cm. Ng\u01b0\u1eddi ta k\u1ebb hai b\u00e1n k\u00ednh OA v\u00e0 O\u2019B\u2019 l\u1ea7n l\u01b0\u1ee3t n\u1eb1m tr\u00ean hai \u0111\u00e1y sao cho g\u00f3c gi\u1eefa hai \u0111\u01b0\u1eddng th\u1eb3ng ch\u1ee9a hai b\u00e1n k\u00ednh b\u1eb1ng 30^{o<\/sup>\u00a0. C\u1eaft kh\u1ed1i tr\u1ee5 b\u1edfi m\u1ed9t m\u1eb7t ph\u1eb3ng ch\u1ee9a \u0111\u01b0\u1eddng th\u1eb3ng AB\u2019 v\u00e0 song song v\u1edbi tr\u1ee5c c\u1ee7a kh\u1ed1i tr\u1ee5 \u0111\u00f3. Tr\u01b0\u1eddng h\u1ee3p n\u00e0o v\u1ec1 di\u1ec7n t\u00edch c\u1ee7a thi\u1ebft di\u1ec7n sau \u0111\u00e2y th\u1ecfa m\u00e3n :<\/p>\n}

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C\u00e2u 18:<\/b>\u00a0Cho h\u00ecnh tr\u1ee5 c\u00f3 \u0111\u00e1y l\u00e0 hai \u0111\u01b0\u1eddng tr\u00f2n t\u00e2m O v\u00e0 O\u2019, b\u00e1n k\u00ednh \u0111\u00e1y b\u1eb1ng chi\u1ec1u cao v\u00e0 b\u1eb1ng a. Tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n \u0111\u00e1y t\u00e2m O l\u1ea5y \u0111i\u1ec3m A, tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n \u0111\u00e1y t\u00e2m O\u2019 l\u1ea5y \u0111i\u1ec3m B sao cho AB = 2a. Th\u1ec3 t\u00edch kh\u1ed1i t\u1ee9 di\u1ec7n OO\u2019AB l\u00e0 :<\/p>\n

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C\u00e2u 19:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 \u0111\u00e1y ABC l\u00e0 tam gi\u00e1c vu\u00f4ng \u0111\u1ec9nh A v\u00e0 AB = 2AC = 4a . Bi\u1ebft r\u1eb1ng m\u1eb7t ph\u1eb3ng (SBC) vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (ABC) v\u00e0 hai c\u1ea1nh SA, SC c\u00f9ng t\u1ea1o v\u1edbi m\u1eb7t ph\u1eb3ng (ABC) m\u1ed9t g\u00f3c l\u00e0 30^{o<\/sup>\u00a0. B\u00e1n k\u00ednh m\u1eb7t c\u1ea7u ngo\u1ea1i ti\u1ebfp h\u00ecnh ch\u00f3p l\u00e0 :<\/p>\n}

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C\u00e2u 20:<\/b>\u00a0Cho m\u1eb7t c\u1ea7u t\u00e2m O b\u00e1n k\u00ednh R. Trong t\u1ea5t c\u1ea3 c\u00e1c kh\u1ed1i h\u1ed9p ch\u1eef nh\u1eadt n\u1eb1m trong m\u1eb7t c\u1ea7u, th\u1ec3 t\u00edch l\u1edbn nh\u1ea5t c\u00f3 th\u1ec3 c\u1ee7a kh\u1ed1i h\u1ed9p ch\u1eef nh\u1eadt l\u00e0 :<\/p>\n

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H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
15-A<\/td>\n 16-A<\/td>\n 17-B<\/td>\n 18-C<\/td>\n 19-D<\/td>\n 20-A<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"
C\u00e2u 15:\u00a0Cho l\u0103ng tr\u1ee5 \u0111\u1ee9ng ABC.A1B1c1\u00a0c\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1ea1nh b\u1eb1ng nhau. Bi\u1ebft l\u0103ng tr\u1ee5 n\u1ed9i ti\u1ebfp h\u00ecnh tr\u1ee5 (H). T\u1ec9 s\u1ed1 di\u1ec7n t\u00edch xung quanh v\u00e0 di\u1ec7n t\u00edch to\u00e0n ph\u1ea7n c\u1ee7a h\u00ecnh tr\u1ee5 l\u00e0 : C\u00e2u 16:\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 \u0111\u00e1y ABC l\u00e0 tam gi\u00e1c vu\u00f4ng c\u00e2n \u0111\u1ec9nh A v\u00e0 SA = SB […]<\/p>\n","protected":false},"author":3,"featured_media":28581,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 \u0110\u1ec1 ki\u1ec3m tra ch\u01b0\u01a1ng 2 (ph\u1ea7n 3)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-de-kiem-tra-chuong-2-phan-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 \u0110\u1ec1 ki\u1ec3m tra ch\u01b0\u01a1ng 2 (ph\u1ea7n 3)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 15:\u00a0Cho l\u0103ng tr\u1ee5 \u0111\u1ee9ng ABC.A1B1c1\u00a0c\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1ea1nh b\u1eb1ng nhau. Bi\u1ebft l\u0103ng tr\u1ee5 n\u1ed9i ti\u1ebfp h\u00ecnh tr\u1ee5 (H). 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