C\u00e2u 8:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho ba vect\u01a1<\/p>\n
<\/p>\n
Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o \u0111\u00fang?<\/p>\n
<\/p>\n
C\u00e2u 9:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai vect\u01a1\u00a0a\u2192<\/i>\u00a0= (x1<\/sub>, y1<\/sub>, z1<\/sub>),\u00a02\u2192<\/i>\u00a0= (x2<\/sub>, y2<\/sub>, z2<\/sub>) thay \u0111\u1ed5i. Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh d\u01b0\u1edbi \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o \u0111\u00fang?<\/p>\n <\/p>\n C\u00e2u 10:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho tam gi\u00e1c ABC c\u00f3 t\u1ecda \u0111\u1ed9 c\u00e1c \u0111i\u1ec3m l\u00e0: A(xA<\/sub>; yA<\/sub>, zA<\/sub>), B(xB<\/sub>; yB<\/sub>, zB<\/sub>), CA(xC<\/sub>; yC<\/sub>, zC<\/sub>) . G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC, G l\u00e0 tr\u1ecdng t\u00e2m tam gi\u00e1c ABC. Kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y l\u00e0 sai?<\/p>\n <\/p>\n C\u00e2u 11:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai \u0111i\u1ec3m A, B c\u00f3 t\u1ecda \u0111\u1ed9 c\u00e1c \u0111i\u1ec3m A(xA<\/sub>; yA<\/sub>, zA<\/sub>), B(xB<\/sub>; yB<\/sub>, zB<\/sub>). T\u1ecda \u0111\u1ed9 trung \u0111i\u1ec3m M c\u1ee7a \u0111o\u1ea1n th\u1eb3ng AB l\u00e0:<\/p>\n <\/p>\n C\u00e2u 12:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho tam gi\u00e1c ABC c\u00f3 A(1;2;0), B(-4;5;3), C(3;-10;-6). T\u1ecda \u0111\u1ed9 tr\u1ecdng t\u00e2m G c\u1ee7a tam gi\u00e1c ABC l\u00e0:<\/p>\n A. (0;-1;-1)\u00a0\u00a0\u00a0B. (0;-3;-3)\u00a0\u00a0\u00a0C.(0;-2;-2)\u00a0\u00a0\u00a0D. \u0110\u00e1p \u00e1n kh\u00e1c<\/p>\n C\u00e2u 13:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho tam gi\u00e1c ABC c\u00f3 A(2;3;-1), B(1;3;2), G(2;-3;-1) l\u00e0 tr\u1ecdng t\u00e2m c\u1ee7a tam gi\u00e1c ABC. T\u1ecda \u0111\u1ed9 c\u1ee7a \u0111i\u1ec3m C l\u00e0:<\/p>\n A. (3;-15;-4)\u00a0\u00a0\u00a0B. (-1;-9;-2)\u00a0\u00a0\u00a0C. (-3;15;4)\u00a0\u00a0\u00a0D. (1;9;2)<\/p>\n C\u00e2u 14:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho ba vect\u01a1<\/p>\n <\/p>\n T\u1ecda \u0111\u1ed9 c\u1ee7a vect\u01a1<\/p>\n <\/p>\n A. (4;3;9)\u00a0\u00a0\u00a0B. (4;3;21)\u00a0\u00a0\u00a0C. (2;-1;10)\u00a0\u00a0\u00a0D. (4;-1;10)<\/p>\n C\u00e2u 15:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai \u0111i\u1ec3m A(1;3;-1), B(5;4;-4). Kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 B l\u00e0:<\/p>\n A. (4; 1; -3)\u00a0\u00a0\u00a0B. \u221a26\u00a0\u00a0\u00a0C. 2\u221a2\u00a0\u00a0\u00a0D. \u221a66<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 8:\u00a0Trong kh\u00f4ng gian Oxyz, cho ba vect\u01a1 Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o \u0111\u00fang? C\u00e2u 9:\u00a0Trong kh\u00f4ng gian Oxyz, cho hai vect\u01a1\u00a0a\u2192\u00a0= (x1, y1, z1),\u00a02\u2192\u00a0= (x2, y2, z2) thay \u0111\u1ed5i. Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh d\u01b0\u1edbi \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o \u0111\u00fang? C\u00e2u 10:\u00a0Trong kh\u00f4ng gian Oxyz, cho tam gi\u00e1c ABC c\u00f3 t\u1ecda \u0111\u1ed9 […]<\/p>\n","protected":false},"author":3,"featured_media":28233,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n\n\n
\n 8-D<\/td>\n 9-C<\/td>\n 10-D<\/td>\n 11-C<\/td>\n 12-A<\/td>\n 13-A<\/td>\n 14-B<\/td>\n 15-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"