Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: S\u1ef1 \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 1)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: S\u1ef1 \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 1)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] nh\u01b0 h\u00ecnh v\u1ebd. T\u00ecm kho\u1ea3ng \u0111\u1ed3ng bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = sinx v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] C\u00e2u 2:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = -x3\u00a0nh\u01b0 h\u00ecnh v\u1ebd. H\u00e0m s\u1ed1 y = -x3\u00a0ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng: A. 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T\u00ecm kho\u1ea3ng \u0111\u1ed3ng bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = sinx v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] C\u00e2u 2:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = -x3\u00a0nh\u01b0 h\u00ecnh v\u1ebd. H\u00e0m s\u1ed1 y = -x3\u00a0ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng: A. (-1;0) \u00a0\u00a0\u00a0 […]","og_url":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/","og_site_name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam","article_published_time":"2018-04-19T09:53:25+00:00","og_image":[{"width":292,"height":143,"url":"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/1-287.png","type":"image\/png"}],"author":"H\u00e0 Trang","twitter_card":"summary_large_image","twitter_misc":{"Written by":"H\u00e0 Trang","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/","url":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/","name":"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: S\u1ef1 \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 1)","isPartOf":{"@id":"https:\/\/lop12.edu.vn\/#website"},"datePublished":"2018-04-19T09:53:25+00:00","dateModified":"2018-04-19T09:53:25+00:00","author":{"@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45"},"breadcrumb":{"@id":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/lop12.edu.vn\/"},{"@type":"ListItem","position":2,"name":"Ch\u01b0\u01a1ng 1 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: S\u1ef1 \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 1)"}]},{"@type":"WebSite","@id":"https:\/\/lop12.edu.vn\/#website","url":"https:\/\/lop12.edu.vn\/","name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/lop12.edu.vn\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45","name":"H\u00e0 Trang","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","caption":"H\u00e0 Trang"},"url":"https:\/\/lop12.edu.vn\/author\/trangvth2\/"}]}},"_links":{"self":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/28121"}],"collection":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/comments?post=28121"}],"version-history":[{"count":1,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/28121\/revisions"}],"predecessor-version":[{"id":28128,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/28121\/revisions\/28128"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media\/28122"}],"wp:attachment":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media?parent=28121"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/categories?post=28121"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/tags?post=28121"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}

{"id":28121,"date":"2018-04-19T16:53:25","date_gmt":"2018-04-19T09:53:25","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=28121"},"modified":"2018-04-19T16:53:25","modified_gmt":"2018-04-19T09:53:25","slug":"chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/","title":{"rendered":"Ch\u01b0\u01a1ng 1 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: S\u1ef1 \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 1)"},"content":{"rendered":"

C\u00e2u 1:<\/b>\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] nh\u01b0 h\u00ecnh v\u1ebd.<\/p>\n

$\"\"$ <\/p>\n

T\u00ecm kho\u1ea3ng \u0111\u1ed3ng bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = sinx v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2]<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 2:<\/b>\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = -x^{3<\/sup>\u00a0nh\u01b0 h\u00ecnh v\u1ebd. H\u00e0m s\u1ed1 y = -x^{3<\/sup>\u00a0ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng:<\/p>\n}}

A. (-1;0) \u00a0\u00a0\u00a0 B. (-\u221e;0)<\/p>\n

C. (0;+\u221e) \u00a0\u00a0\u00a0D. (-1;1)<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 3:<\/b>\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = -2\/x nh\u01b0 h\u00ecnh v\u1ebd. H\u00e0m s\u1ed1 y = -2\/x \u0111\u1ed3ng bi\u1ebfn tr\u00ean<\/p>\n

A. (-\u221e;0)\u00a0\u00a0\u00a0B. (-\u221e;0) \u222a (0;+\u221e)<\/p>\n

C. R \u00a0\u00a0\u00a0D. (-\u221e;0) v\u00e0 (0;+\u221e)<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 4:<\/b>\u00a0Cho h\u00e0m s\u1ed1 f(x) c\u00f3 \u0111\u1ea1o h\u00e0m f'(x) = \u221ax(x-1)(x+2)^{2<\/sup><\/p>\n}

K\u1ebft lu\u1eadn n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang?<\/p>\n

A. H\u00e0m s\u1ed1 f(x) ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng (-\u221e;1).<\/p>\n

B. H\u00e0m s\u1ed1 f(x) \u0111\u1ed3ng bi\u1ebfn tr\u00ean c\u00e1c kho\u1ea3ng (-\u221e;0) v\u00e0 (1;+\u221e).<\/p>\n

C. H\u00e0m s\u1ed1 f(x) \u0111\u1ed3ng bi\u1ebfn tr\u00ean c\u00e1c kho\u1ea3ng v\u00e0 (1;+\u221e).<\/p>\n

D. H\u00e0m s\u1ed1 f(x) \u0111\u1ed3ng bi\u1ebfn tr\u00ean c\u00e1c kho\u1ea3ng (1;+\u221e).<\/p>\n

C\u00e2u 5:<\/b>\u00a0Kho\u1ea3ng ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = x^{3<\/sup>\/3 – 2x^{2<\/sup>\u00a0+ 3x + 5 l\u00e0:<\/p>\n}}

A. (1;3) \u00a0\u00a0\u00a0 B.(-\u221e; 1) \u222a (3; +\u221e)\u00a0\u00a0\u00a0 C. (-\u221e; 1) v\u00e0 (3; +\u221e) \u00a0\u00a0\u00a0 D. (1;+\u221e)<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
1-A<\/td>\n 2-C<\/td>\n 3-D<\/td>\n 4-D<\/td>\n 5-A<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
C\u00e2u 1:<\/b><\/p>\n
Tr\u00ean kho\u1ea3ng (-\u03c0\/2; \u03c0\/2) \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111i l\u00ean t\u1eeb tr\u00e1i sang ph\u1ea3i.<\/p>\n
Tr\u00ean kho\u1ea3ng (\u03c0\/2 ; 3\u03c0\/2) \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111i xu\u1ed1ng t\u1eeb tr\u00e1i sang ph\u1ea3i.<\/p>\n
Do \u0111\u00f3 h\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean kho\u1ea3ng (-\u03c0\/2; \u03c0\/2)<\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n A.<\/p>\n
C\u00e2u 2:<\/b><\/p>\n
Tr\u00ean kho\u1ea3ng (-\u221e;0) \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111i l\u00ean t\u1eeb tr\u00e1i sang ph\u1ea3i.<\/p>\n
Do \u0111\u00f3 h\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng (0;+\u221e), Ch\u1ecdn \u0111\u00e1p \u00e1n C.<\/p>\n
C\u00e2u 3:<\/b><\/p>\n
\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111i l\u00ean t\u1eeb tr\u00e1i sang ph\u1ea3i tr\u00ean hai kho\u1ea3ng (-\u221e;0) v\u00e0 (0;+\u221e)<\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n
Ghi ch\u00fa. Nh\u1eefng sai l\u1ea7m c\u00f3 th\u1ec3 g\u1eb7p trong qu\u00e1 tr\u00ecnh l\u00e0m b\u00e0i:<\/p>\n
– Kh\u00f4ng ch\u00fa \u00fd t\u1eadp x\u00e1c \u0111\u1ecbnh n\u00ean ch\u1ecdn \u0111\u00e1p \u00e1n C.<\/p>\n
– Kh\u00f4ng ch\u00fa \u00fd \u0111\u1ecbnh ngh\u0129a c\u1ee7a h\u00e0m \u0111\u1ed3ng bi\u1ebfn n\u00ean ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n
C\u00e2u 4:<\/b><\/p>\n
B\u1ea3ng x\u00e9t d\u1ea5u :<\/p>\n
$\"\"$ <\/p>\n
V\u1eady f(x) \u0111\u1ed3ng bi\u1ebfn tr\u00ean kho\u1ea3ng (1;+\u221e) v\u00e0 ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng (0;1). Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n
C\u00e2u 5:<\/b><\/p>\n
$\"B\u00e0i$ <\/p>\n
B\u1ea3ng x\u00e9t d\u1ea5u y\u2019 :<\/p>\n
$\"\"$ <\/p>\n
V\u1eady h\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng (1;3). Ch\u1ecdn \u0111\u00e1p \u00e1n A.<\/p>\n","protected":false},"excerpt":{"rendered":"
C\u00e2u 1:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] nh\u01b0 h\u00ecnh v\u1ebd. T\u00ecm kho\u1ea3ng \u0111\u1ed3ng bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = sinx v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] C\u00e2u 2:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = -x3\u00a0nh\u01b0 h\u00ecnh v\u1ebd. H\u00e0m s\u1ed1 y = -x3\u00a0ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng: A. (-1;0) \u00a0\u00a0\u00a0 […]<\/p>\n","protected":false},"author":3,"featured_media":28122,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nCh\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: S\u1ef1 \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 1)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-su-dong-bien-nghich-bien-cua-ham-so-phan-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: S\u1ef1 \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 1)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] nh\u01b0 h\u00ecnh v\u1ebd. T\u00ecm kho\u1ea3ng \u0111\u1ed3ng bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = sinx v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] C\u00e2u 2:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = -x3\u00a0nh\u01b0 h\u00ecnh v\u1ebd. H\u00e0m s\u1ed1 y = -x3\u00a0ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng: A. 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T\u00ecm kho\u1ea3ng \u0111\u1ed3ng bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = sinx v\u1edbi x \u2208 [- \u03c0\/2 ; 3\u03c0\/2] C\u00e2u 2:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = -x3\u00a0nh\u01b0 h\u00ecnh v\u1ebd. H\u00e0m s\u1ed1 y = -x3\u00a0ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng: A. 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