C\u00e2u 1:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = f(x) c\u00f3 \u0111\u1ed3 th\u1ecb nh\u01b0 h\u00ecnh v\u1ebd. \u0110i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 l\u00e0<\/p>\n
<\/p>\n
A. M(0; 2) \u00a0\u00a0\u00a0B. N(-2; -14)<\/p>\n
C. P(2; -14) \u00a0\u00a0\u00a0 D. N(-2; -14) v\u00e0 P(2; -14)<\/p>\n
C\u00e2u 2:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = f(x) x\u00e1c \u0111\u1ecbnh, li\u00ean t\u1ee5c tr\u00ean R v\u00e0 c\u00f3 b\u1ea3ng bi\u1ebfn thi\u00ean<\/p>\n
<\/p>\n
M\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang?<\/p>\n
A. H\u00e0m s\u1ed1 c\u00f3 \u0111\u00fang hai c\u1ef1c tr\u1ecb<\/p>\n
B. H\u00e0m s\u1ed1 c\u00f3 \u0111i\u1ec3m c\u1ef1c ti\u1ec3u l\u00e0 -2<\/p>\n
C. H\u00e0m s\u1ed1 c\u00f3 gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i b\u1eb1ng 0.<\/p>\n
D. H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 0 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = -1 v\u00e0 x = 1<\/p>\n
C\u00e2u 3:<\/b>\u00a0T\u00ecm a, b, c sao cho h\u00e0m s\u1ed1 y = x3<\/sup>\u00a0+ ax2<\/sup>\u00a0+ bx + c c\u00f3 gi\u00e1 tr\u1ecb b\u1eb1ng 0 khi x = 1 v\u00e0 \u0111\u1ea1t c\u1ef1c tr\u1ecb khi b\u1eb1ng 0 khi x = -1 .<\/p>\n <\/p>\n C\u00e2u 4:<\/b>\u00a0Trong c\u00e1c m\u1ec7nh \u0111\u1ec1 sau, m\u1ec7nh \u0111\u1ec1 n\u00e0o \u0111\u00fang?<\/p>\n N\u1ebfu f'(x0<\/sub>) = 0 th\u00ec x0<\/sub>\u00a0l\u00e0 \u0111i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1.<\/p>\n B. N\u1ebfu f'(x0<\/sub>) = 0 th\u00ec x0<\/sub>\u00a0l\u00e0 \u0111i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a h\u00e0m s\u1ed1.<\/p>\n C. N\u1ebfu f'(x0<\/sub>) = 0 v\u00e0 f”(x0<\/sub>) > 0 th\u00ec x0<\/sub>\u00a0l\u00e0 \u0111i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a h\u00e0m s\u1ed1.<\/p>\n D. N\u1ebfu f(x) c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i x0<\/sub>\u00a0v\u00e0 f\u2019(x) \u0111\u1ed5i d\u1ea5u khi x \u0111i qua x0<\/sub>\u00a0th\u00ec x0<\/sub>\u00a0l\u00e0 \u0111i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1.<\/p>\n C\u00e2u 5:<\/b>\u00a0T\u00ecm t\u1ea5t c\u1ea3 c\u00e1c gi\u00e1 tr\u1ecb c\u1ee7a tham s\u1ed1 m \u0111\u1ec3 h\u00e0m s\u1ed1 y = x3<\/sup>\u00a0– 2x2<\/sup>\u00a0+mx + 1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 1.<\/p>\n A.m = -1\u00a0\u00a0\u00a0 B. m = 1 \u00a0\u00a0\u00a0 C. m = 4\/3 \u00a0\u00a0\u00a0 D. Kh\u00f4ng t\u1ed3n t\u1ea1i.<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b><\/p>\n D\u1ef1a v\u00e0o \u0111\u1ecbnh ngh\u0129a c\u1ef1c tr\u1ecb.<\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n A.<\/p>\n C\u00e2u 2:<\/b><\/p>\n D\u1ef1a v\u00e0o \u0111\u1ecbnh ngh\u0129a c\u1ef1c tr\u1ecb v\u00e0 b\u1ea3ng bi\u1ebfn thi\u00ean.<\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n C\u00e2u 3:<\/b><\/p>\n S\u1eed d\u1ee5ng gi\u1ea3 thi\u1ebft v\u00e0 \u0111i\u1ec1u ki\u1ec7n c\u1ea7n c\u1ee7a c\u1ef1c tr\u1ecb ta c\u00f3<\/p>\n y(1) = 0; y'(-1) = 0; y(-1) = 0<\/p>\n <\/p>\n => a = 1; b = -1; c = -1<\/p>\n V\u1edbi a = 1; b = -1; c = -1 th\u00ec h\u00e0m s\u1ed1 \u0111\u00e3 cho tr\u1edf th\u00e0nh y = x3<\/sup>\u00a0+ x2<\/sup>\u00a0– x – 1<\/p>\n Ta c\u00f3 y’ = 3x2<\/sup>\u00a0+ 2x – 1, y” = 6x + 2. V\u00ec y”=(-1) = -4 < 0 n\u00ean h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = -1 . V\u1eady a = 1; b = -1; c = -1 l\u00e0 c\u00e1c gi\u00e1 tr\u1ecb c\u1ea7n t\u00ecm.<\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n C.<\/p>\n C\u00e2u 4:<\/b><\/p>\n Xem l\u1ea1i \u0111i\u1ec1u ki\u1ec7n c\u1ea7n v\u00e0 \u0111\u1ee7 \u0111\u1ec3 c\u00f3 c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1.<\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n C\u00e2u 5:<\/b><\/p>\n Ta c\u00f3 y’ = 3x2<\/sub>\u00a0– 4x + m<\/p>\n H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c tr\u1ecb t\u1ea1i x = 1 th\u00ec y'(1) => m = 1<\/p>\n V\u1edbi m = 1 th\u00ec h\u00e0m s\u1ed1 \u0111\u00e3 cho tr\u1edf th\u00e0nh y = x3<\/sup>\u00a0– 2x2<\/sup>\u00a0+ x + 1<\/p>\n Ta c\u00f3 y’ = 3x2<\/sup>\u00a0– 4x + 1, y” = 6x – 4 V\u00ec y”(1) = 2 > n\u00ean h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 1.<\/p>\n Do v\u1eady kh\u00f4ng c\u00f3 m th\u1ecfa m\u00e3n. Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n Ch\u00fa \u00fd. Sai l\u1ea7m c\u00f3 th\u1ec3 g\u1eb7p ph\u1ea3i: khi gi\u1ea3i y'(1) = 0 => m = 1 \u0111\u00e3 v\u1ed9i k\u1ebft lu\u1eadn m\u00e0 kh\u00f4ng ki\u1ec3m tra l\u1ea1i, d\u1eabn \u0111\u1ebfn ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Cho h\u00e0m s\u1ed1 y = f(x) c\u00f3 \u0111\u1ed3 th\u1ecb nh\u01b0 h\u00ecnh v\u1ebd. \u0110i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 l\u00e0 A. M(0; 2) \u00a0\u00a0\u00a0B. N(-2; -14) C. P(2; -14) \u00a0\u00a0\u00a0 D. N(-2; -14) v\u00e0 P(2; -14) C\u00e2u 2:\u00a0Cho h\u00e0m s\u1ed1 y = f(x) x\u00e1c \u0111\u1ecbnh, li\u00ean t\u1ee5c tr\u00ean R v\u00e0 c\u00f3 b\u1ea3ng bi\u1ebfn […]<\/p>\n","protected":false},"author":3,"featured_media":28072,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 1-A<\/td>\n 2-D<\/td>\n 3-C<\/td>\n 4-D<\/td>\n 5-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n