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{"id":28055,"date":"2018-04-19T16:20:44","date_gmt":"2018-04-19T09:20:44","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=28055"},"modified":"2018-04-19T16:20:44","modified_gmt":"2018-04-19T09:20:44","slug":"chuong-1-bai-tap-trac-nghiem-giai-tich-12-cuc-tri-cua-ham-so-phan-3","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-cuc-tri-cua-ham-so-phan-3\/","title":{"rendered":"Ch\u01b0\u01a1ng 1 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: C\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 3)"},"content":{"rendered":"

C\u00e2u 1:<\/b>\u00a0Cho h\u00e0m s\u1ed1 f c\u00f3 \u0111\u1ea1o h\u00e0m l\u00e0 f'(x) = x(x+1)2<\/sup>(x-2)4<\/sup>\u00a0v\u1edbi m\u1ecdi x \u2208 R. S\u1ed1 \u0111i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 f l\u00e0:<\/p>\n

A. 0 \u00a0\u00a0\u00a0 B. 1 \u00a0\u00a0\u00a0 C. 2 \u00a0\u00a0\u00a0 D.3<\/p>\n

C\u00e2u 2:<\/b>\u00a0\u0110i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a h\u00e0m s\u1ed1 y = -x3<\/sup>\u00a0– 3x2<\/sup>\u00a0+ 1 l\u00e0:<\/p>\n

A. x = 0 \u00a0\u00a0\u00a0 B. x = -2 \u00a0\u00a0\u00a0 C. x = 2 \u00a0\u00a0\u00a0D. Kh\u00f4ng t\u1ed3n t\u1ea1i<\/p>\n

C\u00e2u 3:<\/b>\u00a0\u0110i\u1ec3m c\u1ef1c ti\u1ec3u c\u1ee7a h\u00e0m s\u1ed1 y = x4<\/sup>\u00a0+ 4x2<\/sup>\u00a0+ 2 l\u00e0:<\/p>\n

A. x = 1 \u00a0\u00a0\u00a0 B. x = \u221a2 \u00a0\u00a0\u00a0 C. x = 0 \u00a0\u00a0\u00a0 D. Kh\u00f4ng t\u1ed3n t\u1ea1i<\/p>\n

C\u00e2u 4:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = x3<\/sup>\u00a0– 2x2<\/sup>\u00a0– 1 (1) v\u00e0 c\u00e1c m\u1ec7nh \u0111\u1ec1<\/p>\n

(1) \u0110i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 (1) l\u00e0 x = 0 ho\u1eb7c x = 4\/3<\/p>\n

(2) \u0110i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 (1) l\u00e0 x = 0 v\u00e0 x = 4\/3<\/p>\n

(3) \u0110i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (1) l\u00e0 x = 0 v\u00e0 x = 4\/3<\/p>\n

(4) C\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 (1) l\u00e0 x = 0 v\u00e0 x = 4\/3<\/p>\n

Trong c\u00e1c m\u1ec7nh \u0111\u1ec1 tr\u00ean, s\u1ed1 m\u1ec7nh \u0111\u1ec1 sai l\u00e0:<\/p>\n

A.0 \u00a0\u00a0\u00a0 B.1 \u00a0\u00a0\u00a0 C.2 \u00a0\u00a0\u00a0 D.3<\/p>\n

C\u00e2u 5:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = x4<\/sup>\u00a0– 2x2<\/sup>\u00a0– 2 (2). Kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang?<\/p>\n

A. H\u00e0m s\u1ed1 (2) \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i y = -2<\/p>\n

B. H\u00e0m s\u1ed1 (2) \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i t\u1ea1i y = -2<\/p>\n

C. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (2) c\u00f3 \u0111i\u1ec3m c\u1ef1c \u0111\u1ea1i l\u00e0 y = -2<\/p>\n

D. H\u00e0m s\u1ed1 (2) c\u00f3 gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i l\u00e0 y = -2<\/p>\n

C\u00e2u 6:<\/b>\u00a0H\u00e0m s\u1ed1 y = cosx \u0111\u1ea1t c\u1ef1c tr\u1ecb t\u1ea1i nh\u1eefng \u0111i\u1ec3m<\/p>\n

\"\"<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
1-B<\/td>\n2-A<\/td>\n3-C<\/td>\n4-D<\/td>\n5-D<\/td>\n6-A<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 1:<\/b><\/p>\n

Ta c\u00f3<\/p>\n

\"\"<\/p>\n

B\u1ea3ng bi\u1ebfn thi\u00ean<\/p>\n

\"\"<\/p>\n

D\u1ef1a v\u00e0o b\u1ea3ng bi\u1ebfn thi\u00ean ta th\u1ea5y h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 0. V\u1eady h\u00e0m s\u1ed1 c\u00f3 m\u1ed9t c\u1ef1c tr\u1ecb<\/p>\n

C\u00e2u 2:<\/b><\/p>\n

Ta c\u00f3 y’ = -3x2<\/sup>\u00a0– 6x, y” = -6x – 6 .<\/p>\n

X\u00e9t<\/p>\n

\"\"<\/p>\n

y”(0) = -6 < 0; y”(-2) = 6 > 0<\/p>\n

Do \u0111\u00f3 h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 0<\/p>\n

C\u00e2u 3:<\/b><\/p>\n

Ta c\u00f3: y’ = 4x3<\/sup>\u00a0+ 8x, y” = 12x2<\/sup>\u00a0+ 8. y’ = 0 <=> 4x(x2<\/sup>\u00a0+ 2) = 0 <=> x = 0<\/p>\n

y”(0) = 2 > 0. Do \u0111\u00f3 h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 0<\/p>\n

C\u00e2u 4:<\/b><\/p>\n

Ta c\u00f3: y’ = 3x2<\/sup>\u00a0– 4x, y” = 6x – 4;<\/p>\n

\"\"<\/p>\n

y”(0) = -4 < 0; y”(4\/3) = 4 > 0. Do \u0111\u00f3 h\u00e0m s\u1ed1 c\u00f3 hai c\u1ef1c tr\u1ecb l\u00e0 x = 0 v\u00e0 x = 4\/3<\/p>\n

C\u00e2u 5:<\/b><\/p>\n

Ta c\u00f3: y’ = 4x3<\/sup>\u00a0– 4x, y” = 12x2<\/sup>\u00a0– 4<\/p>\n

\"\"<\/p>\n

y”(-1) = 8 > 0; y”(1) = 8 > 0<\/p>\n

Do \u0111\u00f3 h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 0 v\u00e0 c\u00f3 gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i l\u00e0 y(0)=-2<\/p>\n

C\u00e2u 6:<\/b><\/p>\n

y’ = -sinx; y” = -cosx. y’ = 0 <=> -sinx = 0 <=> x = k\u03c0<\/p>\n

y”(k\u03c0) = \u00b11. Do \u0111\u00f3 h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c tr\u1ecb t\u1ea1i x = k\u03c0<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 1:\u00a0Cho h\u00e0m s\u1ed1 f c\u00f3 \u0111\u1ea1o h\u00e0m l\u00e0 f'(x) = x(x+1)2(x-2)4\u00a0v\u1edbi m\u1ecdi x \u2208 R. S\u1ed1 \u0111i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 f l\u00e0: A. 0 \u00a0\u00a0\u00a0 B. 1 \u00a0\u00a0\u00a0 C. 2 \u00a0\u00a0\u00a0 D.3 C\u00e2u 2:\u00a0\u0110i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a h\u00e0m s\u1ed1 y = -x3\u00a0– 3×2\u00a0+ 1 l\u00e0: A. x = 0 \u00a0\u00a0\u00a0 B. x […]<\/p>\n","protected":false},"author":3,"featured_media":28056,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nCh\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: C\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 3)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-cuc-tri-cua-ham-so-phan-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: C\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 (Ph\u1ea7n 3)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0Cho h\u00e0m s\u1ed1 f c\u00f3 \u0111\u1ea1o h\u00e0m l\u00e0 f'(x) = x(x+1)2(x-2)4\u00a0v\u1edbi m\u1ecdi x \u2208 R. 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