C\u00e2u 1:<\/b>\u00a0\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
c\u00f3 bao nhi\u00eau \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn?<\/p>\n
A.1 \u00a0\u00a0\u00a0 B. 2 \u00a0\u00a0\u00a0 C.3 \u00a0\u00a0\u00a0 D.4<\/p>\n
C\u00e2u 2:<\/b>\u00a0T\u00ecm m\u1ec7nh \u0111\u1ec1 sai trong c\u00e1c m\u1ec7nh \u0111\u1ec1 sau:<\/p>\n
A. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
c\u00f3 m\u1ed9t ti\u1ec7m c\u1eadn \u0111\u1ee9ng v\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang.<\/p>\n
B. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
c\u00f3 m\u1ed9t ti\u1ec7m c\u1eadn \u0111\u1ee9ng v\u00e0 kh\u00f4ng c\u00f3 ti\u1ec7m c\u1eadn ngang<\/p>\n
C. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng x = 3 v\u00e0 ti\u1ec7m c\u1eadn ngang<\/p>\n
D. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
c\u00f3 m\u1ed9t ti\u1ec7m c\u1eadn \u0111\u1ee9ng v\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang.<\/p>\n
C\u00e2u 3:<\/b>\u00a0Cho h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
c\u00f3 \u0111\u1ed3 th\u1ecb (C). Ch\u1ecdn m\u1ec7nh \u0111\u1ec1 \u0111\u00fang trong c\u00e1c<\/p>\n
m\u1ec7nh \u0111\u1ec1 sau:<\/p>\n
A. \u0110\u01b0\u1eddng y = 2 l\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang c\u1ee7a (C).<\/p>\n
B. \u0110\u01b0\u1eddng y = 1 l\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang c\u1ee7a (C).<\/p>\n
C. \u0110\u01b0\u1eddng x = – 2 l\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn \u0111\u1ee9ng c\u1ee7a (C).<\/p>\n
D. \u0110\u01b0\u1eddng x = 3 l\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang c\u1ee7a (C).<\/p>\n
C\u00e2u 4:<\/b>\u00a0T\u00ecm t\u1ea5t c\u1ea3 c\u00e1c gi\u00e1 tr\u1ecb th\u1ef1c c\u1ee7a tham s\u1ed1 m sao cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
A. m > 0 \u00a0\u00a0\u00a0B. m \u2265 1 \u00a0\u00a0\u00a0 C. m > 1 \u00a0\u00a0\u00a0 D. Kh\u00f4ng c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a m<\/p>\n
H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b><\/p>\n <\/p>\n Suy ra x = 1 v\u00e0 l\u00e0 hai ti\u1ec7m c\u1eadn \u0111\u1ee9ng c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<\/p>\n <\/p>\n l\u00e0 ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1. Ch\u1ecdn \u0111\u00e1p \u00e1n C<\/p>\n C\u00e2u 2:<\/b><\/p>\n <\/p>\n n\u00ean \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn ngang y=0 . Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n C\u00e2u 3:<\/b><\/p>\n Ta c\u00f3<\/p>\n <\/p>\n => l\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<\/p>\n <\/p>\n => l\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<\/p>\n <\/p>\n => x = 2 l\u00e0 ti\u1ec7m c\u1eadn \u0111\u1ee9ng c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n C\u00e2u 4:<\/b><\/p>\n Ta c\u00f3<\/p>\n <\/p>\n V\u1eady v\u1edbi m > 1 th\u00ec \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n <\/p>\n c\u00f3 hai ti\u1ec7m c\u1eadn ngang.<\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n C.<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 bao nhi\u00eau \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn? A.1 \u00a0\u00a0\u00a0 B. 2 \u00a0\u00a0\u00a0 C.3 \u00a0\u00a0\u00a0 D.4 C\u00e2u 2:\u00a0T\u00ecm m\u1ec7nh \u0111\u1ec1 sai trong c\u00e1c m\u1ec7nh \u0111\u1ec1 sau: A. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 m\u1ed9t ti\u1ec7m c\u1eadn \u0111\u1ee9ng v\u00e0 m\u1ed9t ti\u1ec7m c\u1eadn ngang. B. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 m\u1ed9t ti\u1ec7m c\u1eadn \u0111\u1ee9ng v\u00e0 […]<\/p>\n","protected":false},"author":3,"featured_media":27947,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 1-C<\/td>\n 2-B<\/td>\n 3-B<\/td>\n 4-C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n