C\u00e2u 1:<\/b>\u00a0Cho c\u00e1c m\u1ec7nh \u0111\u1ec1 sau<\/p>\n
(1) \u0110\u01b0\u1eddng th\u1eb3ng y = y\u00a00<\/sub>\u00a0l\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x) n\u1ebfu<\/p>\n <\/p>\n (2) \u0110\u01b0\u1eddng th\u1eb3ng y = y\u00a00<\/sub>\u00a0l\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x) n\u1ebfu<\/p>\n <\/p>\n (3) \u0110\u01b0\u1eddng th\u1eb3ng x = x\u00a00<\/sub>\u00a0l\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn \u0111\u1ee9ng c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x) n\u1ebfu<\/p>\n <\/p>\n (4) \u0110\u01b0\u1eddng th\u1eb3ng x = x\u00a00<\/sub>\u00a0l\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn \u0111\u1ee9ng c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x) n\u1ebfu<\/p>\n <\/p>\n Trong c\u00e1c m\u1ec7nh \u0111\u1ec1 tr\u00ean, s\u1ed1 m\u1ec7nh \u0111\u1ec1 \u0111\u00fang l\u00e0:<\/p>\n A.1 \u00a0\u00a0\u00a0 B. 2 \u00a0\u00a0\u00a0 C. 3 \u00a0\u00a0\u00a0 D. 4<\/p>\n C\u00e2u 2:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = f(x) c\u00f3<\/p>\n <\/p>\n Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh d\u01b0\u1edbi \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o l\u00e0 \u0111\u00fang?<\/p>\n A. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 kh\u00f4ng c\u00f3 ti\u1ec7m c\u1eadn ngang.<\/p>\n B. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 \u0111\u00fang m\u1ed9t ti\u1ec7m c\u1eadn ngang.<\/p>\n C. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 hai ti\u1ec7m c\u1eadn ngang l\u00e0 y = 1 v\u00e0 y = -1<\/p>\n D. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 hai ti\u1ec7m c\u1eadn ngang l\u00e0 x = 1 v\u00e0 x = -1<\/p>\n C\u00e2u 3:<\/b>\u00a0T\u00ecm t\u1ea5t c\u1ea3 c\u00e1c gi\u00e1 tr\u1ecb th\u1ef1c c\u1ee7a m \u0111\u1ec3 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n <\/p>\n c\u00f3 hai ti\u1ec7m c\u1eadn ngang<\/p>\n A.Kh\u00f4ng t\u1ed3n t\u1ea1i \u00a0\u00a0\u00a0 B. m < 0 \u00a0\u00a0\u00a0 C. m = 0 \u00a0\u00a0\u00a0 D. m > 0<\/p>\n C\u00e2u 4:<\/b>\u00a0Cho h\u00e0m s\u1ed1<\/p>\n <\/p>\n Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o \u0111\u00fang?<\/p>\n A. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 kh\u00f4ng c\u00f3 ti\u1ec7m c\u1eadn ngang.<\/p>\n B. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 \u0111\u00fang m\u1ed9t ti\u1ec7m c\u1eadn ngang.<\/p>\n C. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 hai ti\u1ec7m c\u1eadn ngang l\u00e0 y = 3 v\u00e0 y = -1<\/p>\n D. \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 hai ti\u1ec7m c\u1eadn ngang l\u00e0 x = 3 v\u00e0 x = -1<\/p>\n C\u00e2u 5:<\/b>\u00a0\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n <\/p>\n c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau ti\u1ec7m c\u1eadn?<\/p>\n A. 0 \u00a0\u00a0\u00a0 B. 1 \u00a0\u00a0\u00a0 C. 2 \u00a0\u00a0\u00a0 D. 3<\/p>\n C\u00e2u 6:<\/b>\u00a0H\u00e0m s\u1ed1 n\u00e0o sau \u0111\u00e2y c\u00f3 \u0111\u1ed3 th\u1ecb nh\u1eadn \u0111\u01b0\u1eddng th\u1eb3ng x = 0 l\u00e0m ti\u1ec7m c\u1eadn \u0111\u1ee9ng?<\/p>\n <\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b><\/p>\n D\u1ef1a v\u00e0o \u0111\u1ecbnh ngh\u0129a m\u1ec7nh \u0111\u1ec1 1 sai v\u00e0 m\u1ec7nh \u0111\u1ec1 2, 3, 4 \u0111\u00fang.<\/p>\n C\u00e2u 2:<\/b><\/p>\n T\u1eeb \u0111\u1ecbnh ngh\u0129a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 \u0111\u00fang m\u1ed9t ti\u1ec7m c\u1eadn ngang l\u00e0 y=1<\/p>\n C\u00e2u 3:<\/b><\/p>\n <\/p>\n \u0110\u1ec3 h\u00e0m s\u1ed1 c\u00f3 hai ti\u1ec7m c\u1eadn ngang th\u00ec m > 0.<\/p>\n C\u00e2u 4:<\/b><\/p>\n H\u00e0m s\u1ed1 c\u00f3 \u0111\u00fang m\u1ed9t ti\u1ec7m c\u1eadn ngang y=3.<\/p>\n C\u00e2u 5:<\/b><\/p>\n V\u00ec x \u2265 -3, n\u00ean ta ch\u1ec9 x\u00e9t tr\u01b0\u1eddng h\u1ee3p x \u2192 +\u221e<\/p>\n <\/p>\n => y = 0 l\u00e0 ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<\/p>\n <\/p>\n C\u00e2u 6:<\/b><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Cho c\u00e1c m\u1ec7nh \u0111\u1ec1 sau (1) \u0110\u01b0\u1eddng th\u1eb3ng y = y\u00a00\u00a0l\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x) n\u1ebfu (2) \u0110\u01b0\u1eddng th\u1eb3ng y = y\u00a00\u00a0l\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x) n\u1ebfu (3) \u0110\u01b0\u1eddng th\u1eb3ng x = x\u00a00\u00a0l\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn \u0111\u1ee9ng c\u1ee7a […]<\/p>\n","protected":false},"author":3,"featured_media":27932,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 1-C<\/td>\n 2-B<\/td>\n 3-D<\/td>\n 4-B<\/td>\n 5-C<\/td>\n 6-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n