Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (Ph\u1ea7n 2)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-khao-sat-su-bien-thien-va-ve-do-thi-ham-so-phan-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (Ph\u1ea7n 2)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 6:\u00a0Cho h\u00e0m s\u1ed1 Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 t\u1ea1i \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh y” = 0 l\u00e0 C\u00e2u 7:\u00a0Cho h\u00e0m s\u1ed1 T\u00ecm ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb (C), bi\u1ebft ti\u1ebfp tuy\u1ebfn \u0111\u00f3 song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng y = 3x -1 A. y […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-khao-sat-su-bien-thien-va-ve-do-thi-ham-so-phan-2\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - 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{"id":27892,"date":"2018-04-19T12:26:38","date_gmt":"2018-04-19T05:26:38","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=27892"},"modified":"2018-04-19T12:26:38","modified_gmt":"2018-04-19T05:26:38","slug":"chuong-1-bai-tap-trac-nghiem-giai-tich-12-khao-sat-su-bien-thien-va-ve-do-thi-ham-so-phan-2","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-khao-sat-su-bien-thien-va-ve-do-thi-ham-so-phan-2\/","title":{"rendered":"Ch\u01b0\u01a1ng 1 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (Ph\u1ea7n 2)"},"content":{"rendered":"

C\u00e2u 6:<\/b>\u00a0Cho h\u00e0m s\u1ed1<\/p>\n

$\"\"$ <\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 t\u1ea1i \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh y” = 0 l\u00e0<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 7:<\/b>\u00a0Cho h\u00e0m s\u1ed1<\/p>\n

$\"\"$ <\/p>\n

T\u00ecm ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb (C), bi\u1ebft ti\u1ebfp tuy\u1ebfn \u0111\u00f3 song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng y = 3x -1<\/p>\n

A. y = 3x + 1 \u00a0\u00a0\u00a0B. y = 3x – 29\/3 \u00a0\u00a0\u00a0 C. 3x + 20 \u00a0\u00a0\u00a0 D. C\u1ea3 A v\u00e0 B \u0111\u00fang<\/p>\n

C\u00e2u 8:<\/b>\u00a0G\u1ecdi M, N l\u00e0 giao \u0111i\u1ec3m c\u1ee7a<\/p>\n

$\"\"$ <\/p>\n

Khi \u0111\u00f3 ho\u00e0nh \u0111\u1ed9 trung \u0111i\u1ec3m c\u1ee7a I c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MN b\u1eb1ng<\/p>\n

A. 2 \u00a0\u00a0\u00a0 B.1 \u00a0\u00a0\u00a0 C. 0 \u00a0\u00a0\u00a0 D. -1<\/p>\n

C\u00e2u 9:<\/b>\u00a0T\u00ecm m \u0111\u1ec3 ph\u01b0\u01a1ng tr\u00ecnh x^{3<\/sup>\u00a0+ 3x^{2<\/sup>\u00a0= m c\u00f3 ba nghi\u1ec7m ph\u00e2n bi\u1ec7t<\/p>\n}}

A. m > 4 \u00a0\u00a0\u00a0B. m < 0 \u00a0\u00a0\u00a0C. 0 \u2264 m \u2264 4 \u00a0\u00a0\u00a0D. 0 < m < 4<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
6-A<\/td>\n 7-D<\/td>\n <\/td>\n <\/td>\n <\/td>\n <\/td>\n <\/td>\n <\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
C\u00e2u 6:<\/b><\/p>\n
Ta c\u00f3<\/p>\n
y’ = x^{2<\/sup>\u00a0+ 2x; y” = 2x + 2 => y” = 0 <=> x = -1 => -4\/3, y'(-1) = -1<\/p>\n}
Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 t\u1ea1i \u0111i\u1ec3m x = -1 l\u00e0:<\/p>\n
$\"\"$ <\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n A.<\/p>\n
C\u00e2u 7:<\/b><\/p>\n
Ta c\u00f3 y’ = x^{2<\/sup>\u00a0– 4x + 3. Ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb (C) song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng y = 3x – 1 n\u00ean h\u1ec7 s\u1ed1 g\u00f3c c\u1ee7a ti\u1ebfp tuy\u1ebfn l\u00e0 k = 3.<\/p>\n}
X\u00e9t y’ = 3 <=> x^{2<\/sup>\u00a0– 4x = 0<\/p>\n}
$\"\"$ <\/p>\n
Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb t\u1ea1i A(0;1) c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c k = 3 l\u00e0 y = 3x + 1<\/p>\n
Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb t\u1ea1i B(4; 7\/3) c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c k = 3 l\u00e0 y = 3x – 29\/3 .<\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n
C\u00e2u 8:<\/b><\/p>\n
X\u00e9t ph\u01b0\u01a1ng tr\u00ecnh ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m<\/p>\n
$\"\"$ <\/p>\n
Giao \u0111i\u1ec3m c\u1ee7a hai \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 l\u00e0 M(x_{1<\/sub>; y_{1<\/sub>), N(x_{2<\/sub>; y_{2<\/sub>) v\u1edbi x_{1<\/sub>, x_{2<\/sub>\u00a0l\u00e0 nghi\u1ec7m ph\u01b0\u01a1ng tr\u00ecnh (1). Do \u0111\u00f3<\/p>\n}}}}}}
$\"\"$ <\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n
C\u00e2u 9:<\/b><\/p>\n
X\u00e9t h\u00e0m s\u1ed1<\/p>\n
y = f(x) = x^{3<\/sup>\u00a0+ 3x^{2<\/sup>\u00a0(C)<\/p>\n}}
\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng nh\u01b0 h\u00ecnh b\u00ean.<\/p>\n
$\"\"$ <\/p>\n
x^{3<\/sup>\u00a0+ 3x^{2<\/sup>\u00a0= m c\u00f3 ba nghi\u1ec7m ph\u00e2n bi\u1ec7t<\/p>\n}}
<=> \u0110\u01b0\u1eddng th\u1eb3ng y = m c\u1eaft \u0111\u1ed3 th\u1ecb (C) t\u1ea1i ba \u0111i\u1ec3m ph\u00e2n bi\u1ec7t <=> 0 < m < 4<\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n","protected":false},"excerpt":{"rendered":"
C\u00e2u 6:\u00a0Cho h\u00e0m s\u1ed1 Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 t\u1ea1i \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh y” = 0 l\u00e0 C\u00e2u 7:\u00a0Cho h\u00e0m s\u1ed1 T\u00ecm ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb (C), bi\u1ebft ti\u1ebfp tuy\u1ebfn \u0111\u00f3 song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng y = 3x -1 A. y […]<\/p>\n","protected":false},"author":3,"featured_media":27893,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nCh\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (Ph\u1ea7n 2)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-khao-sat-su-bien-thien-va-ve-do-thi-ham-so-phan-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - 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