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{"id":27828,"date":"2018-04-18T23:47:48","date_gmt":"2018-04-18T16:47:48","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=27828"},"modified":"2018-04-23T09:45:28","modified_gmt":"2018-04-23T02:45:28","slug":"bai-tap-trac-nghiem-hinh-hoc-12-bai-2-phuong-trinh-mat-phang-phan-8","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-bai-2-phuong-trinh-mat-phang-phan-8\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 B\u00e0i 2: Ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t ph\u1eb3ng (ph\u1ea7n 8)"},"content":{"rendered":"

C\u00e2u 36:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, hai m\u1eb7t ph\u1eb3ng 3x + 2y – mz + 2m – 7 = 0 v\u00e0 (5m + 1)x + (m + 3)y – 2z – 10 = 0. Tr\u00f9ng nhau khi v\u00e0 ch\u1ec9 khi:<\/p>\n

A. m = -4 \u00a0\u00a0\u00a0C. m = 1<\/p>\n

B. m = -6\/5 \u00a0\u00a0\u00a0D. Kh\u00f4ng c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a m th\u1ecfa m\u00e3n<\/p>\n

C\u00e2u 37:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho \u0111i\u1ec3m A(1;2;-3) v\u00e0 m\u1eb7t ph\u1eb3ng (P) c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x – 2y + 2z + 1 = 0 . Kho\u1ea3ng c\u00e1ch t\u1eeb A \u0111\u1ebfn m\u1eb7t ph\u1eb3ng (P) l\u00e0:<\/p>\n

 <\/p>\n

\"\"<\/p>\n

C\u00e2u 38:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai m\u1eb7t ph\u1eb3ng song song (P): 4x – 3y – 8 = 0 v\u00e0 (Q): 8x – 6y – 1 = 0 . Kho\u1ea3ng c\u00e1ch gi\u1eefa hai m\u1eb7t ph\u1eb3ng (P) v\u00e0 (Q) l\u00e0:<\/p>\n

\"\"<\/p>\n

C\u00e2u 39:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, t\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m M c\u00e1ch \u0111\u1ec1u hai m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9 (Oxy) v\u00e0 (Oxz) l\u00e0 hai m\u1eb7t ph\u1eb3ng c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n

A. y+z=0 v\u00e0 y-z=0\u00a0\u00a0\u00a0C. x+z=0 v\u00e0 x-z=0<\/p>\n

B. x+y=0 v\u00e0 x-y=0\u00a0\u00a0\u00a0D. y+2z=0 v\u00e0 y-2z=0<\/p>\n

C\u00e2u 40:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, t\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m c\u00e1ch \u0111\u1ec1u hai m\u1eb7t ph\u1eb3ng (P): x + 3y – 4z + 1 = 0 v\u00e0 (Q): x + 3y – 4z + 7 = 0 l\u00e0 :<\/p>\n

A. x + 3y – 4z + 8 = 0 \u00a0\u00a0\u00a0C. x + 3y – 4z + 4 = 0<\/p>\n

B. x + 3y – 4z + 6 = 0\u00a0\u00a0\u00a0D. x + 3y – 4z – 6 = 0<\/p>\n

C\u00e2u 41:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, t\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m M c\u00e1ch \u0111\u1ec1u hai m\u1eb7t ph\u1eb3ng (P): 2x + 3y + z – 1 = 0 v\u00e0 (Q): 3x + y + 2z – 3 = 0 l\u00e0 hai m\u1eb7t ph\u1eb3ng c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 :<\/p>\n

A. x – 2y + z – 2 = 0 v\u00e0 5x + 4y + 4z – 4 = 0<\/p>\n

B. x – 2y + z – 2 = 0 v\u00e0 5x + 4y + 3z – 4 = 0<\/p>\n

C. x – 3y + z – 2 = 0 v\u00e0 5x + 4y + 3z – 4 = 0<\/p>\n

D. x + 2y + z – 2 = 0 v\u00e0 5x + 4y + 3z – 4 = 0<\/p>\n

C\u00e2u 42:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, bi\u1ebft r\u1eb1ng tr\u1ee5c Ox song song v\u1edbi m\u1eb7t ph\u1eb3ng (P) : y + z – 1 = 0 . Kho\u1ea3ng c\u00e1ch gi\u1eefa Ox v\u00e0 m\u1eb7t ph\u1eb3ng (P) l\u00e0 :<\/p>\n

 <\/p>\n

\"\"<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
36-C<\/td>\n37-A<\/td>\n38-B<\/td>\n39-A<\/td>\n40-C<\/td>\n41-B<\/td>\n42-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 36:<\/b><\/p>\n

Hai m\u1eb7t ph\u1eb3ng 3x + 2y – mz + 2m – 7 = 0 v\u00e0 (5m + 1)x + (m + 3)y – 2z – 10 = 0 tr\u00f9ng nhau khi v\u00e0 ch\u1ec9 khi t\u1ed3n t\u1ea1i m\u1ed9t s\u1ed1 th\u1ef1c k sao cho :<\/p>\n

\"\"<\/p>\n

C\u00e2u 37:<\/b><\/p>\n

\"\"<\/p>\n

C\u00e2u 38:<\/b><\/p>\n

L\u1ea5y m\u1ed9t \u0111i\u1ec3m M(2 ;0 ;0)\u2208(P). V\u00ec hai m\u1eb7t ph\u1eb3ng (P) v\u00e0 (Q) song song n\u00ean ta c\u00f3 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 39:<\/b><\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a hai m\u1eb7t ph\u1eb3ng (Oxy) v\u00e0 (Oxz) l\u1ea7n l\u01b0\u1ee3t l\u00e0 z = 0 v\u00e0 y = 0.<\/p>\n

\u0110i\u1ec3m M(x ;y ;z) c\u00e1ch \u0111\u1ec1u hai m\u1eb7t ph\u1eb3ng \u0111\u00f3 khi v\u00e0 ch\u1ec9 khi<\/p>\n

\"\"<\/p>\n

C\u00e2u 40:<\/b><\/p>\n

\u0110i\u1ec3m M(x,y,z) c\u00e1ch \u0111\u1ec1u hai m\u1eb7t ph\u1eb3ng (P) v\u00e0 (Q) khi v\u00e0 ch\u1ec9 khi<\/p>\n

\"\"<\/p>\n

=> |x + 3y – 4z + 1| = |x + 3y – 4z + 7|<\/p>\n

<=> x + 3y – 4z + 4 = 0<\/p>\n

C\u00e2u 41:<\/b><\/p>\n

\u0110i\u1ec3m M(x,y,z) c\u00e1ch \u0111\u1ec1u hai m\u1eb7t ph\u1eb3ng (P) v\u00e0 (Q) khi v\u00e0 ch\u1ec9 khi :<\/p>\n

\"\"<\/p>\n

C\u00e2u 42:<\/b><\/p>\n

V\u00ec Ox song song v\u1edbi m\u1eb7t ph\u1eb3ng (P) v\u00e0 O thu\u1ed9c Ox n\u00ean ta c\u00f3 :<\/p>\n

\"\"<\/p>\n

\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 36:\u00a0Trong kh\u00f4ng gian Oxyz, hai m\u1eb7t ph\u1eb3ng 3x + 2y – mz + 2m – 7 = 0 v\u00e0 (5m + 1)x + (m + 3)y – 2z – 10 = 0. Tr\u00f9ng nhau khi v\u00e0 ch\u1ec9 khi: A. m = -4 \u00a0\u00a0\u00a0C. m = 1 B. m = -6\/5 \u00a0\u00a0\u00a0D. Kh\u00f4ng c\u00f3 gi\u00e1 […]<\/p>\n","protected":false},"author":3,"featured_media":27829,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 B\u00e0i 2: Ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t ph\u1eb3ng (ph\u1ea7n 8)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-bai-2-phuong-trinh-mat-phang-phan-8\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12 \u2013 B\u00e0i 2: Ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t ph\u1eb3ng (ph\u1ea7n 8)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 36:\u00a0Trong kh\u00f4ng gian Oxyz, hai m\u1eb7t ph\u1eb3ng 3x + 2y – mz + 2m – 7 = 0 v\u00e0 (5m + 1)x + (m + 3)y – 2z – 10 = 0. Tr\u00f9ng nhau khi v\u00e0 ch\u1ec9 khi: A. m = -4 \u00a0\u00a0\u00a0C. m = 1 B. m = -6\/5 \u00a0\u00a0\u00a0D. 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Tr\u00f9ng nhau khi v\u00e0 ch\u1ec9 khi: A. m = -4 \u00a0\u00a0\u00a0C. m = 1 B. m = -6\/5 \u00a0\u00a0\u00a0D. 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