C\u00e2u 1:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho d l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua \u0111i\u1ec3m M0<\/sub>(x0<\/sub>; y0<\/sub>; z0<\/sub>) v\u00e0 c\u00f3 vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng l\u00e0\u00a0u\u2192<\/i>\u00a0, v\u1edbi a, b, c kh\u00e1c 0. Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai?<\/p>\n A. Ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0:<\/p>\n <\/p>\n \n B. Ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0: x = x0<\/sub>\u00a0+ at, y = y0<\/sub>\u00a0+ bt, z = z0<\/sub>\u00a0+ at<\/p>\n C. \u0110\u01b0\u1eddng th\u1eb3ng d n\u1eb1m trong hai m\u1eb7t ph\u1eb3ng :(P): b(x – x0<\/sub>) – a(y – y0<\/sub>) = 0 v\u00e0 (Q): c(x – x0<\/sub>) – a(z – z0<\/sub>) = 0<\/p>\n D. Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0: a(x – x0<\/sub>) + b (y – y0<\/sub>) + c(z – z0<\/sub>) = 0<\/p>\n C\u00e2u 2:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho \u0111\u01b0\u1eddng th\u1eb3ng d \u0111i qua hai \u0111i\u1ec3m A(2; 3; -1), B(1; 2; 4) . Trong nh\u1eefng kh\u1eb3ng \u0111\u1ecbnh d\u01b0\u1edbi \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai?<\/p>\n A. AB\u2192<\/i>\u00a0= (-1; -1; 5) l\u00e0 m\u1ed9t vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d<\/p>\n B. Ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0:<\/p>\n \n <\/p>\n C. \u0110\u01b0\u1eddng th\u1eb3ng d n\u1eb1m trong hai m\u1eb7t ph\u1eb3ng: (P): x – y + 1 = 0, (Q): 5x + z = 0<\/p>\n D. Ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0:<\/p>\n \n <\/p>\n C\u00e2u 3:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai \u0111i\u1ec3m A(1; -2; 0), B(3; -5; 2) . Ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng AB l\u00e0:<\/p>\n \n <\/p>\n B. x = 2 + 3t, y = -3 – 5t, z = 2 + 2t<\/p>\n C. x = 3 + 2t, y = -5 – 3t, z = 2 + 2t<\/p>\n D. x = 1 + 2t, y = -2 + 3t, z = 2t<\/p>\n C\u00e2u 4:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho \u0111\u01b0\u1eddng th\u1eb3ng d \u0111i qua M(4;3;1) v\u00e0 song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng \u0394: x = 1 + 2t, y = 1 – 3t, z = 3 + 2t. Ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0:<\/p>\n \n <\/p>\n C\u00e2u 5:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d \u0111i qua \u0111i\u1ec3m M(-1;-2;3) v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (P): x – 2y + 3z – 1 = 0<\/p>\n <\/p>\n C\u00e2u 6:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho d l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua \u0111i\u1ec3m M(1;2;3) v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (Oxy). Trong nh\u1eefng kh\u1eb3ng \u0111\u1ecbnh d\u01b0\u1edbi \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai?<\/p>\n A. Ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0:<\/p>\n <\/p>\n B. \u0110\u01b0\u1eddng th\u1eb3ng d c\u00f3 m\u1ed9t vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng l\u00e0\u00a0u\u2192<\/i>\u00a0= (0; 0; 1)<\/p>\n C. \u0110\u01b0\u1eddng th\u1eb3ng d n\u1eb1m trong hai m\u1eb7t ph\u1eb3ng: (P): x – 1 = 0, (Q): y – 2 = 0<\/p>\n D. Ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0: x = 1, y = 2, z = 1<\/p>\n C\u00e2u 7:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, l\u1eadp ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d \u0111i qua \u0111i\u1ec3m M(2;1;-3) v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi hai \u0111\u01b0\u1eddng th\u1eb3ng:<\/p>\n <\/p>\n B. d: x = 2 + t, y = 1 – 9t, z = -3 – 3t<\/p>\n C. d: x = -2 + t, y = -1 – 9t, z = 3 – 3t<\/p>\n D. d: x = 2 + t, y = 1 + 9t, z = -3 -3t<\/p>\n C\u00e2u 8:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, l\u1eadp ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d \u0111i qua \u0111i\u1ec3m A(-2;3;1), vu\u00f4ng g\u00f3c v\u1edbi tr\u1ee5c Ox, \u0111\u00f4ng th\u1eddi d song song v\u1edbi m\u1eb7t ph\u1eb3ng: (P): x + 2y – 3z = 0<\/p>\n A. d: x = 2, y = -3 + 3t, z = -1 + 2t\u00a0\u00a0\u00a0C. d: x = -2, y = 3 + 3t, z = 1 + 2t<\/p>\n B. d: x = -2, y = 3 – 3t, z = 1 + 2t\u00a0\u00a0\u00a0D. \u0110\u00e1p \u00e1n kh\u00e1c<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 6:<\/b><\/p>\n V\u00ec \u0111\u01b0\u1eddng th\u1eb3ng d vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (Oxy) n\u00ean \u0111\u01b0\u1eddng th\u1eb3ng d c\u00f3 vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng l\u00e0 (0 ;0 ;1). T\u1eeb \u0111\u00f3 suy ra A l\u00e0 kh\u1eb3ng \u0111\u1ecbnh sai.<\/p>\n C\u00e2u 7:<\/b><\/p>\n <\/p>\n M\u1eb7t kh\u00e1c d \u0111i qua \u0111i\u1ec3m M(2 ;1 ;-3). V\u1eady ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0: x = 2 + t, y = 1 – 9t, z = -3 – 3t<\/p>\n C\u00e2u 8:<\/b><\/p>\n <\/p>\n M\u1eb7t kh\u00e1c d \u0111i qua \u0111i\u1ec3m A(-2 ;3 ;1). V\u1eady ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0: x = -2, y = 3 + 3t, z = 1 + 2t<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Trong kh\u00f4ng gian Oxyz, cho d l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua \u0111i\u1ec3m M0(x0; y0; z0) v\u00e0 c\u00f3 vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng l\u00e0\u00a0u\u2192\u00a0, v\u1edbi a, b, c kh\u00e1c 0. Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai? A. Ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d l\u00e0: B. Ph\u01b0\u01a1ng tr\u00ecnh tham s\u1ed1 c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng […]<\/p>\n","protected":false},"author":3,"featured_media":27735,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n\n\n
\n 1-D<\/td>\n 2-C<\/td>\n 3-C<\/td>\n 4-B<\/td>\n 5-D<\/td>\n 6-A<\/td>\n 7-B<\/td>\n 8-C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n