Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 1 (Ph\u1ea7n 1)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 1 (Ph\u1ea7n 1)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0Cho h\u00e0m s\u1ed1 y = – x3\u00a0+ 3x2\u00a0– 3x + 1, m\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang? A. H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn. B. H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn C. 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H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 1 C\u00e2u 2:\u00a0H\u00e0m s\u1ed1: l\u00e0 […]","og_url":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/","og_site_name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam","article_published_time":"2018-04-18T10:56:02+00:00","og_image":[{"width":195,"height":52,"url":"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/1-264.png","type":"image\/png"}],"author":"H\u00e0 Trang","twitter_card":"summary_large_image","twitter_misc":{"Written by":"H\u00e0 Trang","Est. reading time":"3 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/","url":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/","name":"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 1 (Ph\u1ea7n 1)","isPartOf":{"@id":"https:\/\/lop12.edu.vn\/#website"},"datePublished":"2018-04-18T10:56:02+00:00","dateModified":"2018-04-18T10:56:02+00:00","author":{"@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45"},"breadcrumb":{"@id":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/lop12.edu.vn\/"},{"@type":"ListItem","position":2,"name":"Ch\u01b0\u01a1ng 1 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 1 (Ph\u1ea7n 1)"}]},{"@type":"WebSite","@id":"https:\/\/lop12.edu.vn\/#website","url":"https:\/\/lop12.edu.vn\/","name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/lop12.edu.vn\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45","name":"H\u00e0 Trang","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","caption":"H\u00e0 Trang"},"url":"https:\/\/lop12.edu.vn\/author\/trangvth2\/"}]}},"_links":{"self":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/27724"}],"collection":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/comments?post=27724"}],"version-history":[{"count":1,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/27724\/revisions"}],"predecessor-version":[{"id":27732,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/27724\/revisions\/27732"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media\/27725"}],"wp:attachment":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media?parent=27724"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/categories?post=27724"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/tags?post=27724"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}

{"id":27724,"date":"2018-04-18T17:56:02","date_gmt":"2018-04-18T10:56:02","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=27724"},"modified":"2018-04-18T17:56:02","modified_gmt":"2018-04-18T10:56:02","slug":"chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/","title":{"rendered":"Ch\u01b0\u01a1ng 1 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 1 (Ph\u1ea7n 1)"},"content":{"rendered":"

C\u00e2u 1:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = – x^{3<\/sup>\u00a0+ 3x^{2<\/sup>\u00a0– 3x + 1, m\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang?<\/p>\n}}

A. H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn.<\/p>\n

B. H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn<\/p>\n

C. H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 1<\/p>\n

D. H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 1<\/p>\n

C\u00e2u 2:<\/b>\u00a0H\u00e0m s\u1ed1:<\/p>\n

$\"\"$ <\/p>\n

l\u00e0 h\u00e0m h\u1eb1ng tr\u00ean kho\u1ea3ng n\u00e0o sau \u0111\u00e2y?<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 3:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = x^{2<\/sup>\u00a0– 2|x| + 2 v\u00e0 c\u00e1c m\u1ec7nh \u0111\u1ec1<\/p>\n}

(1) H\u00e0m s\u1ed1 tr\u00ean li\u00ean t\u1ee5c tr\u00ean R<\/p>\n

(2) H\u00e0m s\u1ed1 tr\u00ean c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i x = 0<\/p>\n

(3) H\u00e0m s\u1ed1 tr\u00ean \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 0.<\/p>\n

(4) H\u00e0m s\u1ed1 tr\u00ean \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 0.<\/p>\n

(5) H\u00e0m s\u1ed1 tr\u00ean l\u00e0 h\u00e0m ch\u1eb5n<\/p>\n

(6) H\u00e0m s\u1ed1 tr\u00ean c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i duy nh\u1ea5t m\u1ed9t \u0111i\u1ec3m<\/p>\n

Trong c\u00e1c m\u1ec7nh \u0111\u1ec1 tr\u00ean, s\u1ed1 m\u1ec7nh \u0111\u1ec1 \u0111\u00fang l\u00e0<\/p>\n

A.1\u00a0\u00a0\u00a0 B. 2 \u00a0\u00a0\u00a0 C.3\u00a0\u00a0\u00a0 D. 4<\/p>\n

C\u00e2u 4:<\/b>\u00a0Cho h\u00e0m s\u1ed1<\/p>\n

$\"\"$ <\/p>\n

v\u00e0 c\u00e1c m\u1ec7nh \u0111\u1ec1 sau<\/p>\n

(1) H\u00e0m s\u1ed1 tr\u00ean nh\u1eadn \u0111i\u1ec3m I(1;-1) l\u00e0m t\u00e2m \u0111\u1ed1i x\u1ee9ng,<\/p>\n

(2) H\u00e0m s\u1ed1 tr\u00ean nh\u1eadn \u0111\u01b0\u1eddng th\u1eb3ng y = -x l\u00e0m tr\u1ee5c \u0111\u1ed1i x\u1ee9ng.<\/p>\n

(3) H\u00e0m s\u1ed1 tr\u00ean nh\u1eadn y = -1 l\u00e0 ti\u1ec7m c\u1eadn \u0111\u1ee9ng.<\/p>\n

(4) H\u00e0m s\u1ed1 tr\u00ean lu\u00f4n \u0111\u1ed3ng bi\u1ebfn tr\u00ean R .<\/p>\n

Trong s\u1ed1 c\u00e1c m\u1ec7nh \u0111\u1ec1 tr\u00ean, s\u1ed1 m\u1ec7nh \u0111\u1ec1 sai l\u00e0<\/p>\n

A. 1 \u00a0\u00a0\u00a0 B.2 \u00a0\u00a0\u00a0 C.3 \u00a0\u00a0\u00a0D. 4<\/p>\n

C\u00e2u 5:<\/b>\u00a0Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau v\u1ec1 h\u00e0m s\u1ed1<\/p>\n

$\"\"$ <\/p>\n

kh\u1eb3ng \u0111\u1ecbnh n\u00e0o l\u00e0 \u0111\u00fang?<\/p>\n

A. H\u00e0m s\u1ed1 c\u00f3 \u0111i\u1ec3m c\u1ef1c ti\u1ec3u l\u00e0 x = 0<\/p>\n

B. H\u00e0m s\u1ed1 c\u00f3 hai \u0111i\u1ec3m c\u1ef1c \u0111\u1ea1i l\u00e0 x = \u00b11<\/p>\n

C. C\u1ea3 A v\u00e0 B \u0111\u1ec1u \u0111\u00fang;<\/p>\n

D. C\u1ea3 A v\u00e0 B \u0111\u1ec1u sai,<\/p>\n

C\u00e2u 6:<\/b>\u00a0Trong c\u00e1c m\u1ec7nh \u0111\u1ec1 sau, h\u00e3y t\u00ecm m\u1ec7n \u0111\u1ec1 sai:<\/p>\n

A. H\u00e0m s\u1ed1 y = -x^{3<\/sup>\u00a0+ 3x^{2<\/sup>\u00a0– 3 c\u00f3 c\u1ef1c \u0111\u1ea1i v\u00e0 c\u1ef1c ti\u1ec3u;<\/p>\n}}

B. H\u00e0m s\u1ed1 y = x^{3<\/sup>\u00a0+ 3x + 1 c\u00f3 c\u1ef1c tr\u1ecb;<\/p>\n}

C. H\u00e0m s\u1ed1<\/p>\n

$\"\"$ <\/p>\n

kh\u00f4ng c\u00f3 c\u1ef1c tr\u1ecb;<\/p>\n

D. H\u00e0m s\u1ed1<\/p>\n

$\"\"$ <\/p>\n

\u0111\u1ed3ng bi\u1ebfn tr\u00ean t\u1eebng kho\u1ea3ng x\u00e1c \u0111\u1ecbnh.<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
1-A<\/td>\n 2-A<\/td>\n 3-C<\/td>\n 4-B<\/td>\n 5-C<\/td>\n 6-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
C\u00e2u 1:<\/b><\/p>\n
y’ = -3x^{2<\/sup>\u00a0+ 6x – 3 = -3(x – 1)^{2<\/sup>\u00a0\u2264 0 \u2200x \u2208 R. H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn.<\/p>\n}}
C\u00e2u 2:<\/b><\/p>\n
\u0110i\u1ec1u ki\u1ec7n cos(x\/2) \u2260 0 <=> x \u2260 \u03c0 + 2k\u03c0 (k \u2208 Z)<\/p>\n
$\"\"$ <\/p>\n
$\"B\u00e0i$ <\/p>\n
H\u00e0m s\u1ed1 l\u00e0 h\u00e0m h\u1eb1ng x \u2260 \u03c0 +2k\u03c0 (k \u2208 Z)<\/p>\n
C\u00e2u 3:<\/b><\/p>\n
M\u1ec7nh \u0111\u1ec1 1, 4, 5 \u0111\u00fang. M\u1ec7nh \u0111\u1ec1 2, 3, 6 sai.<\/p>\n
C\u00e2u 4:<\/b><\/p>\n
+ H\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng x=1 v\u00e0 ti\u1ec7m c\u1eadn ngang y=-1 M\u1ec7nh \u0111\u1ec1 1 \u0111\u00fang, m\u1ec7nh \u0111\u1ec1 3 sai.<\/p>\n
+ V\u00ec \u0111\u01b0\u1eddng th\u1eb3ng y=-x l\u00e0 m\u1ed9t ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c t\u1ea1o b\u1edfi 2 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn n\u00ean \u0111\u01b0\u1eddng th\u1eb3ng y=-x l\u00e0 m\u1ed9t tr\u1ee5c \u0111\u1ed1i x\u1ee9ng c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1. M\u1ec7nh \u0111\u1ec1 2 \u0111\u00fang.<\/p>\n
+ H\u00e0m s\u1ed1 c\u00f3 t\u1eadp x\u00e1c \u0111\u1ecbnh l\u00e0 R\\{1}, n\u00ean h\u00e0m s\u1ed1 kh\u00f4ng th\u1ec3 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn tr\u00ean R.M\u1ec7nh \u0111\u1ec1 4 sai.<\/p>\n","protected":false},"excerpt":{"rendered":"
C\u00e2u 1:\u00a0Cho h\u00e0m s\u1ed1 y = – x3\u00a0+ 3×2\u00a0– 3x + 1, m\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang? A. H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn. B. H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn C. H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i t\u1ea1i x = 1 D. H\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 1 C\u00e2u 2:\u00a0H\u00e0m s\u1ed1: l\u00e0 […]<\/p>\n","protected":false},"author":3,"featured_media":27725,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nCh\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 1 (Ph\u1ea7n 1)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-1-phan-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 1 (Ph\u1ea7n 1)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0Cho h\u00e0m s\u1ed1 y = – x3\u00a0+ 3x2\u00a0– 3x + 1, m\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang? 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