C\u00e2u 7:<\/b>\u00a0L\u01b0u l\u01b0\u1ee3ng xe v\u00e0o h\u1ea7m cho b\u1edfi c\u00f4ng th\u1ee9c<\/p>\n
<\/p>\n
trong \u0111\u00f3 v (km\/h) l\u00e0 v\u1eadn t\u1ed1c trung b\u00ecnh c\u1ee7a c\u00e1c xe khi v\u00e0o h\u1ea7m. V\u1edbi gi\u00e1 tr\u1ecb x\u1ea5p x\u1ec9 n\u00e0o c\u1ee7a v th\u00ec l\u01b0u l\u01b0\u1ee3ng xe l\u00e0 l\u1edbn nh\u1ea5t?<\/p>\n
A. 26 \u00a0\u00a0\u00a0 B.27 \u00a0\u00a0\u00a0 C. 28 \u00a0\u00a0\u00a0 D. 29<\/p>\n
C\u00e2u 8:<\/b>\u00a0\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 n\u00e0o sau \u0111\u00e2y c\u00f3 h\u00ecnh d\u1ea1ng nh\u01b0 h\u00ecnh b\u00ean?<\/p>\n
<\/p>\n
A. y = x3<\/sup>\u00a0+ 3x + 1<\/p>\n B. y = x3<\/sup>\u00a0– 3x + 1<\/p>\n C. y = -x3<\/sup>\u00a0– 3x + 1<\/p>\n D. y = – x3<\/sup>\u00a0+ 3x + 1<\/p>\n C\u00e2u 9:<\/b>\u00a0S\u1ed1 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n <\/p>\n A. 3 \u00a0\u00a0\u00a0 B.2 \u00a0\u00a0\u00a0 C. 1\u00a0\u00a0\u00a0D.4<\/p>\n C\u00e2u 10:<\/b>\u00a0G\u1ecdi M v\u00e0 m t\u01b0\u01a1ng \u1ee9ng l\u00e0 gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t v\u00e0 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1 y = 2sin2<\/sup>x – cosx + 1 th\u00ec M.m b\u1eb1ng<\/p>\n A. 0 \u00a0\u00a0\u00a0B. 25\/8 \u00a0\u00a0\u00a0 C. 25\/4 \u00a0\u00a0\u00a0D. 2<\/p>\n C\u00e2u 11:<\/b>\u00a0H\u00e0m s\u1ed1 n\u00e0o sau \u0111\u00e2y l\u00e0 h\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean R<\/p>\n <\/p>\n C\u00e2u 12:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = -x2<\/sup>\u00a0– 4x + 3 c\u00f3 \u0111\u1ed3 th\u1ecb (C). N\u1ebfu ti\u1ebfp tuy\u1ebfn t\u1ea1i M c\u1ee7a (C) c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng 8 th\u00ec ho\u00e0nh \u0111\u1ed9 \u0111i\u1ec3m M l\u00e0:<\/p>\n A. 12 \u00a0\u00a0\u00a0B. -6 \u00a0\u00a0\u00a0C. -1\u00a0\u00a0\u00a0 D. 5<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 7:<\/b><\/p>\n X\u00e9t<\/p>\n <\/p>\n <\/p>\n H\u00e0m s\u1ed1 \u0111\u1ea1t gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t t\u1ea1i v \u2248 27 .<\/p>\n C\u00e2u 9:<\/b><\/p>\n H\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng x = \u00b12 v\u00e0 ti\u1ec7m c\u1eadn ngang y=0<\/p>\n C\u00e2u 10:<\/b><\/p>\n M=2; m=0 => M.m=0.<\/p>\n C\u00e2u 12:<\/b><\/p>\n y\u2019 = -2x – 4 = 8 => x = -6.<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 7:\u00a0L\u01b0u l\u01b0\u1ee3ng xe v\u00e0o h\u1ea7m cho b\u1edfi c\u00f4ng th\u1ee9c trong \u0111\u00f3 v (km\/h) l\u00e0 v\u1eadn t\u1ed1c trung b\u00ecnh c\u1ee7a c\u00e1c xe khi v\u00e0o h\u1ea7m. V\u1edbi gi\u00e1 tr\u1ecb x\u1ea5p x\u1ec9 n\u00e0o c\u1ee7a v th\u00ec l\u01b0u l\u01b0\u1ee3ng xe l\u00e0 l\u1edbn nh\u1ea5t? A. 26 \u00a0\u00a0\u00a0 B.27 \u00a0\u00a0\u00a0 C. 28 \u00a0\u00a0\u00a0 D. 29 C\u00e2u 8:\u00a0\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 […]<\/p>\n","protected":false},"author":3,"featured_media":27718,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 7-B<\/td>\n 8-A<\/td>\n 9-A<\/td>\n 10-A<\/td>\n 11-A<\/td>\n 12-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n