C\u00e2u 1:<\/b>\u00a0K\u1ebft lu\u1eadn n\u00e0o sau \u0111\u00e2y v\u1ec1 t\u00ednh \u0111\u01a1n \u0111i\u1ec7u c\u1ee7a h\u00e0m s\u1ed1<\/p>\n

<\/p>\n

A. H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean c\u00e1c kho\u1ea3ng (-\u221e; 3) v\u00e0 (3; +\u221e) .<\/p>\n

B. H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn tr\u00ean R\\{3}<\/p>\n

C. H\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean c\u00e1c kho\u1ea3ng (-\u221e; 3) v\u00e0 (3; +\u221e)<\/p>\n

D. H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn tr\u00ean R\\{3}<\/p>\n

C\u00e2u 2:<\/b>\u00a0T\u00ecm kho\u1ea3ng ngh\u1ecbch bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 sau: y = -x^{4<\/sup>\u00a0– 2x3<\/sup>\u00a0+ 3<\/p>\n}

A. (-\u221e; 0)\u00a0\u00a0\u00a0 B. (0; +\u221e)\u00a0\u00a0\u00a0C. R \u00a0\u00a0\u00a0 D. (1; +\u221e)<\/p>\n

C\u00e2u 3:<\/b>\u00a0T\u00ecm m \u0111\u1ec3 h\u00e0m s\u1ed1<\/p>\n

<\/p>\n

t\u0103ng tr\u00ean t\u1eebng kho\u1ea3ng x\u00e1c \u0111\u1ecbnh c\u1ee7a<\/p>\n

A. m \u2265 1\u00a0\u00a0\u00a0B. m \u2260 1 \u00a0\u00a0\u00a0C. m > 1 \u00a0\u00a0\u00a0D. m \u2264 1<\/p>\n

C\u00e2u 4:<\/b>\u00a0T\u00ecm gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t c\u1ee7a m \u0111\u1ec3 h\u00e0m s\u1ed1 y = x^{3<\/sup>\u00a0+ 3x2<\/sup>\u00a0– mx – 4 \u0111\u1ed3ng bi\u1ebfn tr\u00ean kho\u1ea3ng (-\u221e; 0)<\/p>\n}

A. m = -3\u00a0\u00a0\u00a0B. m < -3\u00a0\u00a0\u00a0C. m \u2264 -3 \u00a0\u00a0\u00a0 D. m \u2265 -3<\/p>\n

C\u00e2u 5:<\/b>\u00a0H\u00e0m s\u1ed1<\/p>\n

<\/p>\n

c\u00f3 t\u1ea5t c\u1ea3 bao nhi\u00eau \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn?<\/p>\n

A. 1\u00a0\u00a0\u00a0B. 2\u00a0\u00a0\u00a0C. 3\u00a0\u00a0\u00a0D. 4<\/p>\n

C\u00e2u 6:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = x^{3<\/sup>\u00a0– 3x2<\/sup>\u00a0+ 1. T\u00edch c\u1ee7a gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i v\u00e0 c\u1ef1c ti\u1ec3u c\u1ee7a h\u00e0m s\u1ed1 b\u1eb1ng bao nhi\u00eau?<\/p>\n}

A. -6\u00a0\u00a0\u00a0B. -3\u00a0\u00a0\u00a0C. 3\u00a0\u00a0\u00a0D. 4<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n

1-C<\/td>\n

2-B<\/td>\n

3-A<\/td>\n

4-A<\/td>\n

5-C<\/td>\n

6-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0K\u1ebft lu\u1eadn n\u00e0o sau \u0111\u00e2y v\u1ec1 t\u00ednh \u0111\u01a1n \u0111i\u1ec7u c\u1ee7a h\u00e0m s\u1ed1 A. H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean c\u00e1c kho\u1ea3ng (-\u221e; 3) v\u00e0 (3; +\u221e) . B. H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn tr\u00ean R\\{3} C. H\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean c\u00e1c kho\u1ea3ng (-\u221e; 3) v\u00e0 (3; +\u221e) D. H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn tr\u00ean […]<\/p>\n","protected":false},"author":3,"featured_media":27696,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n