2<\/sup>\u00a0+ 1. Ba ti\u1ebfp tuy\u1ebfn t\u1ea1i giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng y = x – 2 c\u00f3 t\u1ed5ng c\u00e1c h\u1ec7 s\u1ed1 g\u00f3c l\u00e0:<\/p>\nA. 15\u00a0\u00a0\u00a0 B. 33 \u00a0\u00a0\u00a0C. 36\u00a0\u00a0\u00a0 D. 17<\/p>\n
C\u00e2u 17:<\/b>\u00a0Ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m c\u1ef1c ti\u1ec3u c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n
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A. song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng x = 1 \u00a0\u00a0\u00a0 B. song song v\u1edbi tr\u1ee5c ho\u00e0nh<\/p>\n
C. c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c d\u01b0\u01a1ng \u00a0\u00a0\u00a0 D. c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng -1<\/p>\n
C\u00e2u 18:<\/b>\u00a0Cho h\u00e0m s\u1ed1 y = x3<\/sup>\u00a0+ 3x2<\/sup>\u00a0+ 3x + 1 c\u00f3 \u0111\u1ed3 th\u1ecb (C) . Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a (C) t\u1ea1i giao \u0111i\u1ec3m c\u1ee7a (C) v\u1edbi tr\u1ee5c tung l\u00e0:<\/p>\nA. y = 8x + 1 \u00a0\u00a0\u00a0B. y = 3x + 1 \u00a0\u00a0\u00a0C. y = -8x + 1 \u00a0\u00a0\u00a0D. y = 3x -1<\/p>\n
H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n| 13-B<\/td>\n | 14-A<\/td>\n | 15-D<\/td>\n | 16-A<\/td>\n | 17-B<\/td>\n | 18-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 13:\u00a0Gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1 A. 1\u00a0\u00a0\u00a0 B. 7\/3 \u00a0\u00a0\u00a0 C. 2\u00a0\u00a0\u00a0 D. 1\/3 C\u00e2u 14:\u00a0Gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1 A. 2\u221a – 2 \u00a0\u00a0\u00a0 B. 9\/10 \u00a0\u00a0\u00a0 C. 2\u221a2 – 1 \u00a0\u00a0\u00a0 D. 1 – 2\u221a2 C\u00e2u 15:\u00a0T\u00ecm m \u0111\u1ec3 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t c\u1ee7a tr\u00ean \u0111o\u1ea1n [0; 1] […]<\/p>\n","protected":false},"author":3,"featured_media":27683,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n Ch\u01b0\u01a1ng 1 - \u0110\u1ec1 ki\u1ec3m tra Gi\u1ea3i t\u00edch 12 ch\u01b0\u01a1ng 1 (Ph\u1ea7n 3)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-de-kiem-tra-giai-tich-12-chuong-1-phan-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - \u0110\u1ec1 ki\u1ec3m tra Gi\u1ea3i t\u00edch 12 ch\u01b0\u01a1ng 1 (Ph\u1ea7n 3)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 13:\u00a0Gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1 A. 1\u00a0\u00a0\u00a0 B. 7\/3 \u00a0\u00a0\u00a0 C. 2\u00a0\u00a0\u00a0 D. 1\/3 C\u00e2u 14:\u00a0Gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1 A. 2\u221a – 2 \u00a0\u00a0\u00a0 B. 9\/10 \u00a0\u00a0\u00a0 C. 2\u221a2 – 1 \u00a0\u00a0\u00a0 D. 1 – 2\u221a2 C\u00e2u 15:\u00a0T\u00ecm m \u0111\u1ec3 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t c\u1ee7a tr\u00ean \u0111o\u1ea1n [0; 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