C\u00e2u 1:<\/b>\u00a0T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c<\/p>\n
<\/p>\n
C\u00e2u 2:<\/b>\u00a0R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c<\/p>\n
<\/p>\n
vi\u1ebft k\u1ebft qu\u1ea3 sao cho c\u00e1c l\u0169y th\u1eeba \u0111\u1ec1u d\u01b0\u01a1ng<\/p>\n
<\/p>\n
C\u00e2u 3:<\/b>\u00a0N\u1ebfu x > y > 0 th\u00ec<\/p>\n
<\/p>\n
C\u00e2u 4:<\/b>\u00a0N\u1ebfu x \u2265 0 th\u00ec<\/p>\n
<\/p>\n
b\u1eb1ng<\/p>\n
<\/p>\n
C\u00e2u 5:<\/b>\u00a0Bi\u1ec3u th\u1ee9c<\/p>\n
<\/p>\n
b\u1eb1ng bi\u1ec3u th\u1ee9c n\u00e0o d\u01b0\u1edbi \u0111\u00e2y?<\/p>\n
A. a-2<\/sup>\u00a0+ b-2<\/sup> \u00a0\u00a0\u00a0B. a-2<\/sup>\u00a0– b-2<\/sup>\u00a0\u00a0\u00a0\u00a0C. a2<\/sup>\u00a0+ b2<\/sup> \u00a0\u00a0\u00a0D. a-6<\/sup>\u00a0– b-6<\/sup><\/p>\n C\u00e2u 6:<\/b>\u00a0Cho a v\u00e0 b l\u00e0 2 s\u1ed1 d\u01b0\u01a1ng th\u1ecfa m\u00e3n \u0111\u1ed3ng th\u1eddi ab<\/sup>\u00a0= ba<\/sup>\u00a0v\u00e0 b=9a. T\u00ecm a.<\/p>\n <\/p>\n C\u00e2u 7:<\/b>\u00a0Bi\u1ebft (a + a-1<\/sup>)2<\/sup>\u00a0= 3. T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a a3<\/sup>\u00a0+ a-3<\/sup>\u00a0.<\/p>\n A.0\u00a0\u00a0\u00a0B. 1 \u00a0\u00a0\u00a0C. 2\u00a0\u00a0\u00a0D. 3.<\/p>\n C\u00e2u 8:<\/b>\u00a0Bi\u1ebft r\u1eb1ng x = 1 + 2t<\/sup>\u00a0v\u00e0 y = 1 + 2-t<\/sup>\u00a0. H\u00e3y bi\u1ec3u di\u1ec5n y theo x.<\/p>\n <\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b><\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n D<\/p>\n C\u00e2u 2:<\/b><\/p>\n <\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n C\u00e2u 3:<\/b><\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n C .<\/p>\n C\u00e2u 4:<\/b><\/p>\n <\/p>\n C\u00e1ch kh\u00e1c:<\/p>\n <\/p>\n \u0110\u00e1p \u00e1n B<\/p>\n C\u00e2u 5:<\/b><\/p>\n S\u1eed d\u1ee5ng h\u1eb1ng \u0111\u1eb3ng th\u1ee9c \u03b12<\/sup>\u00a0– \u03b22<\/sup>\u00a0= (\u03b1 + \u03b2)(\u03b1 – \u03b2), ta c\u00f3<\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n C\u00e2u 6:<\/b><\/p>\n Th\u1ebf b=9a v\u00e0o \u0111\u1eb3ng th\u1ee9c c\u00f2n l\u1ea1i ta \u0111\u01b0\u1ee3c<\/p>\n a9a<\/sup>\u00a0= (9a)a<\/sup>\u00a0=> (a9<\/sup>)a<\/sup>\u00a0=> a9<\/sup>\u00a0= 9a => a8<\/sup>\u00a0= 9 ( do a > 0)<\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n B<\/p>\n C\u00e2u 7:<\/b><\/p>\n S\u1eed d\u1ee5ng h\u1eb1ng \u0111\u1eb3ng th\u1ee9c ta c\u00f3<\/p>\n <\/p>\n M\u1eb7t kh\u00e1c<\/p>\n <\/p>\n => a3<\/sup>\u00a0+ a-3<\/sup>\u00a0.Ch\u1ecdn \u0111\u00e1p \u00e1n A.<\/p>\n C\u00e2u 8:<\/b><\/p>\n T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3<\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c C\u00e2u 2:\u00a0R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c vi\u1ebft k\u1ebft qu\u1ea3 sao cho c\u00e1c l\u0169y th\u1eeba \u0111\u1ec1u d\u01b0\u01a1ng C\u00e2u 3:\u00a0N\u1ebfu x > y > 0 th\u00ec C\u00e2u 4:\u00a0N\u1ebfu x \u2265 0 th\u00ec b\u1eb1ng C\u00e2u 5:\u00a0Bi\u1ec3u th\u1ee9c b\u1eb1ng bi\u1ec3u th\u1ee9c n\u00e0o d\u01b0\u1edbi \u0111\u00e2y? A. a-2\u00a0+ b-2 \u00a0\u00a0\u00a0B. a-2\u00a0– b-2\u00a0\u00a0\u00a0\u00a0C. a2\u00a0+ b2 \u00a0\u00a0\u00a0D. a-6\u00a0– […]<\/p>\n","protected":false},"author":3,"featured_media":27653,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 1-D<\/td>\n 2-B<\/td>\n 3-C<\/td>\n 4-B<\/td>\n 5-B<\/td>\n 6-B<\/td>\n 7-A<\/td>\n 8-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n