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{"id":27399,"date":"2018-04-17T17:55:36","date_gmt":"2018-04-17T10:55:36","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=27399"},"modified":"2018-04-17T17:55:36","modified_gmt":"2018-04-17T10:55:36","slug":"chuong-2-bai-tap-trac-nghiem-giai-tich-12-phuong-trinh-mu-va-phuong-trinh-logarit-phan-2","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-2-bai-tap-trac-nghiem-giai-tich-12-phuong-trinh-mu-va-phuong-trinh-logarit-phan-2\/","title":{"rendered":"Ch\u01b0\u01a1ng 2 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Ph\u01b0\u01a1ng tr\u00ecnh m\u0169 v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh l\u00f4garit (Ph\u1ea7n 2)"},"content":{"rendered":"

C\u00e2u 6:<\/b>\u00a0Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh logx = log(x + 3) – log(x – 1)<\/p>\n

A. x = 1\u00a0\u00a0\u00a0B. x = 3\u00a0\u00a0\u00a0C. x = 4 \u00a0\u00a0\u00a0D. x = -1, x = 3<\/p>\n

C\u00e2u 7:<\/b>\u00a0Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh log\u221a2<\/sub>(x + 1) = log2<\/sub>(x2<\/sup>\u00a0+ 2) – 1<\/p>\n

A. x = 1\u00a0\u00a0\u00a0B. x = 0\u00a0\u00a0\u00a0C. x = 0, x = -4\u00a0\u00a0\u00a0D. x = 0, x = 1<\/p>\n

C\u00e2u 8:<\/b>\u00a0Cho bi\u1ebft logb<\/sub>2x + logx<\/sub>2b = 1, b > 0, b \u2260 1, x \u2260 1. Khi \u0111\u00f3 x b\u1eb1ng:<\/p>\n

A. b \u00a0\u00a0\u00a0B. \u221ab\u00a0\u00a0\u00a0 C. 1\/b \u00a0\u00a0\u00a0 D. 1\/b2<\/sup><\/p>\n

C\u00e2u 9:<\/b>\u00a0Cho bi\u1ebft 2x<\/sup>\u00a0= 8y + 1<\/sup>\u00a0v\u00e0 9y<\/sup>\u00a0= 3x – 9<\/sup>\u00a0. T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a x + y<\/p>\n

A. 21 \u00a0\u00a0\u00a0 B. 18\u00a0\u00a0\u00a0C. 24 \u00a0\u00a0\u00a0D. 27<\/p>\n

C\u00e2u 10:<\/b>\u00a0Gi\u1ea3 s\u1eed x, y l\u00e0 hai s\u1ed1 th\u1ef1c th\u1ecfa m\u00e3n \u0111\u1ed3ng th\u1eddi 3x2\u00a0– 2xy<\/sup>\u00a0= 1 v\u00e0 2log3<\/sub>x = log3<\/sub>(y + 3). T\u00ednh x + y<\/p>\n

A. 9\/4 \u00a0\u00a0\u00a0 B. 3\/2 \u00a0\u00a0\u00a0C. 3\u00a0\u00a0\u00a0D. 9<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
6-B<\/td>\n7-B<\/td>\n8-A<\/td>\n9-D<\/td>\n10-C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 6:<\/b><\/p>\n

\u0110i\u1ec1u ki\u1ec7n x > 1. Khi \u0111\u00f3 ph\u01b0\u01a1ng tr\u00ecnh t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi<\/p>\n

logx(x – 1) = log(x + 3) <=> x(x – 1) = x + 3 <=> x2<\/sup>\u00a0– 2x – 3 = 0<\/p>\n

\"\"<\/p>\n

Lo\u1ea1i nghi\u1ec7m x = -1 do kh\u00f4ng th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n. Ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 m\u1ed9t nghi\u1ec7m x = 3.<\/p>\n

Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n

Ch\u00fa \u00fd: C\u0169ng nh\u01b0 \u1edf v\u00ed d\u1ee5 5, sai l\u1ea7m h\u1ecdc sinh d\u1ec5 g\u1eb7p b\u00e0i n\u00e0y l\u00e0 do ch\u1ee7 quan mu\u1ed1n ti\u1ebft ki\u1ec7m th\u1eddi gian m\u00e0 qu\u00ean \u0111\u1eb7t \u0111i\u1ec1u ki\u1ec7n, d\u1eabn t\u1edbi kh\u00f4ng lo\u1ea1i \u0111\u01b0\u1ee3c nghi\u1ec7m x = -1 v\u00e0 ch\u1ecdn ph\u01b0\u01a1ng \u00e1n nhi\u1ec5u D.<\/p>\n

C\u00e2u 7:<\/b><\/p>\n

\u0110i\u1ec1u ki\u1ec7n x > -1. Khi \u0111\u00f3 ph\u01b0\u01a1ng tr\u00ecnh t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi<\/p>\n

2log2<\/sub>(x + 1) = log2<\/sub>(x2<\/sup>\u00a0+ 2)<\/p>\n

\"\"<\/p>\n

\"\"<\/p>\n

Ch\u1ecdn \u0111\u00e1p \u00e1n B<\/p>\n

C\u00e2u 8:<\/b><\/p>\n

\"\"<\/p>\n

<=> (logb<\/sub>x – 1)2<\/sup>\u00a0= 0 <=> logb<\/sub>x = 1 <=> x = b . Ch\u1ecdn \u0111\u00e1p \u00e1n A.<\/p>\n

Ch\u00fa \u00fd. Kh\u00e1c v\u1edbi c\u00e1c v\u00ed d\u1ee5 tr\u00ean, c\u00e1c bi\u1ebfn \u0111\u1ed5i trong v\u00ed d\u1ee5 n\u00e0y kh\u00f4ng l\u00e0m m\u1edf r\u1ed9ng mi\u1ec1n x\u00e1c \u0111\u1ecbnh c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh (x > 0). Do \u0111\u00f3 ta \u0111\u00e3 kh\u00f4ng nh\u1ea5t thi\u1ebft ph\u1ea3i \u0111\u1eb7t \u0111i\u1ec1u ki\u1ec7n x > 0. Trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p vi\u1ec7c b\u1ecf qua \u0111\u1eb7t \u0111i\u1ec1u ki\u1ec7n s\u1ebd l\u00e0m \u0111\u01a1n gi\u1ea3n h\u01a1n v\u00e0 ti\u1ebft ki\u1ec7m th\u1eddi gian.<\/p>\n

C\u00e2u 9:<\/b><\/p>\n

2x<\/sup>\u00a0= 8y + 1<\/sup>\u00a0=> 2x<\/sup>\u00a0= 23y + 3<\/sup>\u00a0=> x = 3y + 3<\/p>\n

9y<\/sup>\u00a0= 3x – 9<\/sup>\u00a0=> 2y = x – 9<\/p>\n

T\u1eeb (1) v\u00e0 (2) t\u00ecm \u0111\u01b0\u1ee3c x = 21, y = 6. V\u1eady x + y =27.<\/p>\n

Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n

C\u00e2u 10:<\/b><\/p>\n

\u0110i\u1ec1u ki\u1ec7n x > 0, y > -3. Ta c\u00f3: 3x2\u00a0– 2xy<\/sup>\u00a0= 1 <=> x2<\/sup>\u00a0– 2xy = 0 <=> x(x – 2y) = 0 <=> x – 2y = 0 (x > 0) <=> x = 2y (1)<\/p>\n

2log3<\/sub>x = log3<\/sub>( y + 3) <=> log3<\/sub>x2<\/sup>\u00a0= log3<\/sub>(y + 3) <=> x2<\/sup>\u00a0= y + 3 (2)<\/p>\n

Th\u1ebf (1) v\u00e0o (2) ta \u0111\u01b0\u1ee3c<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 6:\u00a0Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh logx = log(x + 3) – log(x – 1) A. x = 1\u00a0\u00a0\u00a0B. x = 3\u00a0\u00a0\u00a0C. x = 4 \u00a0\u00a0\u00a0D. x = -1, x = 3 C\u00e2u 7:\u00a0Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh log\u221a2(x + 1) = log2(x2\u00a0+ 2) – 1 A. x = 1\u00a0\u00a0\u00a0B. x = 0\u00a0\u00a0\u00a0C. x = 0, x = -4\u00a0\u00a0\u00a0D. […]<\/p>\n","protected":false},"author":3,"featured_media":27400,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nCh\u01b0\u01a1ng 2 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Ph\u01b0\u01a1ng tr\u00ecnh m\u0169 v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh l\u00f4garit (Ph\u1ea7n 2)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-2-bai-tap-trac-nghiem-giai-tich-12-phuong-trinh-mu-va-phuong-trinh-logarit-phan-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 2 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Ph\u01b0\u01a1ng tr\u00ecnh m\u0169 v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh l\u00f4garit (Ph\u1ea7n 2)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 6:\u00a0Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh logx = log(x + 3) – log(x – 1) A. x = 1\u00a0\u00a0\u00a0B. x = 3\u00a0\u00a0\u00a0C. x = 4 \u00a0\u00a0\u00a0D. x = -1, x = 3 C\u00e2u 7:\u00a0Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh log\u221a2(x + 1) = log2(x2\u00a0+ 2) – 1 A. x = 1\u00a0\u00a0\u00a0B. x = 0\u00a0\u00a0\u00a0C. x = 0, x = -4\u00a0\u00a0\u00a0D. 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